8/18/2019 Inertia Base Isolator Selection

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CALCULATION FOR INERTIA BASE

1

DIMENSON OF INERTIA BASE

Length

Width

Height

2.70 m

0.86 m

0.15 m

2.

VOLUME

OF INERTIA BASE

v LxW xH

= 2.70 m x 0.86 m x 0.15 m

= 0.348 m

3

or

0.348 m

3

x 35 .31

v = 12.28 Ft

3

3. WEIGHT OF INERTIA BASE, w

w =

weight

Concrete

+

weight

Steel

wt

Concrete = 12.28

Ft

3

x 150

bsl

Ft

3

= 1,842

Ibs or

837

kgs

wt

Steel = 160 Ibs

or

7

kgs refer to

Data Sheet)

w = 837

kgs +

73

kgs

= 910

kgs

4. LOAD ON

SPRING

Total Load = wt Inertia Base

+

wt Pump and Motor

+

wt Fittings

+

Hydraulic Load

.wt

Inertia

Base = 910

kgs

wt

Pump and

Motor

assembly = 752 kgs

wt

Pipe and Fittings = 240

kgs approximate)

Hydraulic Load = Pump Head x Cross-sectional Area

of

pipe

160

ftH20

x 0.0304

kgjcm

 

j

feetH20

x pi 10.12cmf =1,567

kgs

Total Load =910

+

752 + 240 + 1567 =

A69

kgs

Load per

spring

=

3,469

kgsj 4 = 867 kgs

Spring Capacity =1000 kgs x 4 nos