Ideal Gases and the Ideal Gas Law

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    IDEAL GASES AND THE IDEAL GAS LAW

    This p age looks a t the assumptions w hich are made in the KineticTheory a bout ideal gases, and takes a n introductory look a t theIdeal Gas Law: pV = nRT. This i s intended only a s a n introductionsuitable for chemistry s tudents a t about UK A level standard (for 16- 18 year olds), and so there is n o attempt to derive the ideal gaslaw using physics-style calculations.

    Kinetic Theory assumptions a bout ideal gases

    There is n o such thing a s a n ideal gas, of course, but many g asesbehave approximately a s i f they were ideal at ordinary w orkingtemperatures a nd pressures. Real gases a re dealt with in moredetail on another page.

    The assumptions a re:

    • Gases ar e made u p o f molecules w hich a re in constantrandom motion in straight lines.

    • The molecules behave a s r igid spheres.

    • Pressure is d ue t o collisions b etween the molecules a nd thewalls o f the container.

    • All collisions, both between the molecules themselves, andbetween the molecules a nd the walls o f the container, are

    perfectly elastic. (That means that there is no loss of kineticenergy during the collision.)

    • The temperature of the gas i s p roportional to the averagekinetic e nergy o f the molecules.

    And then two absolutely key assumptions, because these are the

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    two most important ways in which real gases d iffer from idealgases:

    • There are no (or entirely n egligible) intermolecular forcesbetween the gas m olecules.

    • The volume o ccupied by the molecules t hemselves i sentirely negligible relative to the volume of the container.

    The Ideal Gas E quation

    The ideal gas e quation is:

    pV = nRT

    On the w hole, this is an easy eq uation to remember and u se. Theproblems l ie almost entirely in the units. I am assuming below thatyou are working in strict SI units ( as y ou will be if you are doing aUK-based e xam, for example).

    Exploring the va rious t erms

    Pressure, p

    Pressure is m easured in pascals, Pa - sometimes exp ressed a snewtons pe r square m etre, N m -2 . These m ean exact ly the samething.

    Be careful if you are given pressures i n kPa (kilopascals). Forexample, 150 kP a is 15 0,000 P a. You must make that conversionbefore you use the ideal gas e quation.

    Should you want to co nvert from other pressure m easurements:

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    • 1 atmosphere = 101,325 Pa

    • 1 bar = 100 kPa = 1 00,000 Pa

    Volume, V

    This i s t he most likely p lace for you to go wrong when you use thisequation. That's because the SI unit of volume is the cubic m etre,m3 - not cm 3 or dm 3.

    1 m 3 = 1000 dm 3 = 1 ,000,000 cm 3

    So if you are inserting values of volume into the equation, you rsthave to convert them into cubic m etres.

    You would have t o divide a vo lume in dm 3 by 1 000, or in cm 3 by amillion.

    Similarly, if you are working out a volume using the equation,remember to covert the answer in c ubic m etres into dm 3 or cm 3 ifyou need to - this t ime by m ultiplying by a 1000 or a million.

    If you get this w rong, you are going to end up with a silly a nswer,out by a factor of a thousand or a million. So it is usually fairlyobvious if you have d one so mething wrong, and you ca n ch eckback ag ain.

    Number of moles, n

    This i s e asy, of course - it is j ust a number. You already k now thatyou work it out by dividing the mass i n grams b y the mass of onemole in grams.

    You will most often use the ideal gas e quation by rst making thesubstitution to give:

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    I don't recommend that you remember the ideal gas e quation in thisform, but you must be condent that you can convert it into thisform.

    The g as constant, R

    A value for R will be given you if you need it, or you can look i t up ina data source. The SI value for R is 8 .31441 J K -1 mol -1 .

    Note: You may come across o ther values f or this w ith different units.A commonly used o ne in the p ast was 82 .053 cm 3 atm K -1 mol -1 . Theunits t ell you that the v olume would be in c ubic ce ntimetres a nd thepressure in atmospheres. Unfortunately t he units i n the SI versionaren't so obviously helpful.

    The temperature, T

    The temperature has t o be in kelvin. Don't forget to add 273 if youare given a temperature in degrees C elsius.

    Using the ideal gas equation

    Calculations u sing the ideal gas e quation are included in mycalculations b ook ( see the link a t the very b ottom of the page), and

    I can't repeat them here. There are, however, a couple ofcalculations t hat I haven't done in the book which give a reasonableidea of how the ideal gas e quation works.

    The m olar volume at stp

    If you have done simple calculations f rom equations, you have

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    The molar volume of an ideal gas i s t herefore 22.4 dm 3 a t stp.

    And, of course, you could redo this c alculation to nd the volume of1 mole of an ideal gas a t room temperature and pressure - or anyother temperature a nd pressure.

    Finding the relative formula mass of a gas from its density

    This i s a bout as t ricky a s i t gets u sing the ideal gas e quation.

    The density o f ethane is 1 .264 g dm -3 a t 20°C and 1 atmosphere.Calculate the relative formula mass o f ethane.

    The d ensity value m eans that 1 dm 3 of ethane weighs 1. 264 g .

    Again, before we do a nything e lse, get the awkward units so rtedout.

    A pressure o f 1 a tmosphere is 10 1325 Pa.

    The volume o f 1 dm 3 has t o be converted to cubic m etres, by

    dividing by 1000. We h ave a volume o f 0.001 m3

    .

    The temperature is 29 3 K.

    Now put all the numbers i nto the form of the ideal gas e quationwhich lets yo u work with m asses, and rearrange i t to work out themass of 1 mole.

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    The mass o f 1 mole of anything is si mply the relative formula massin grams.

    So the relative formula mass o f ethane is 3 0.4, to 3 sig gs.

    Now, if you add up the relative formula mass o f ethane, C 2H6 us ingaccurate va lues o f relative a tomic m asses, you g et an a nswer of30.07 to 4 signicant gures. Which is d ifferent from our answer -so w hat's w rong?

    There are two possibilities.

    • The density va lue I have used may not be correct. I did thesum again using a slightly different value quoted at adifferent temperature from another source. This t ime I got ananswer of 30.3. So the density va lues m ay not be entirelyaccurate, but they are b oth giving much the same sort ofanswer.

    • Ethane isn't an ideal gas. Well, of course it isn't an ideal gas- there's n o such thing! However, assuming that the densityvalues are close to correct, the error is within 1% of what youwould expect. So although ethane isn't exactly b ehaving likean ideal gas, it isn't far off.

    If you need to know about real gases, now is a good time to readabout them.