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7/27/2019 hwk8_key.pdf
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Homework 8
1. Solve Laplaces equation inside a circular annulus (a < r< b) subject to theboundary conditions
(a) u(a,) = f(), u(b,) = g()
(b)u
r(a,) = 0, u(b,) = g()
If there is a solvability condition, state it and explain it physically.
Answer
The shape of domain suggest us to use the polar coordinate system, in which the
Laplaces equation is expressed as
1rr
rur
+ 1
r2
2
u2
= 0
Assume u(r,) = ()G(r),
r
G(r)
d
dr
rdG
dr
=
1
d2
d2=
Using periodic boundary conditions for , we have
() = an cos(n) +bn sin(n), = n2, n = 0,1,2,
Ifn> 0,
G(r) = cnrn +dnrn
otherwise,
G(r) = c0 +d0 ln(r).
Note that we do not know whether G(0) is finite or not.
(a) Assume u = u1 +u2, where u1 and u2 satisfies
u1 = 0 u2 = 0 (1)
u1(a,) = f() u2(a,) = 0 (2)
u1(b,) = 0 u2(b,) = g() (3)
It is implied by u1(b,) = 0 that G(b) = 0. For n> 0, we get
dn = cnb2n
and we simply choose
cn = bn, dn = b
n.
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Ifn = 0, we can choose
c0 = ln(b), d0 = 1.
Now u1 could be written as
u1(r,) = a0 ln(r/b) +
n=1
(an cos(n) +bn sin(n))((r/b)n (r/b)n)
Applying u1(a,) = f(),
u1(a,) =a0 ln(a/b)+
n=1
(an cos(n)+bn sin(n))((a/b)n(a/b)n) = f()
Coefficientsan and bn could be determined by calculating the Fourier seriesof f(). Calculation ofu2(r,) is similar.
(b) There is already enough homogeneous boundary conditions we can use.
No need to separate u into two functions. It is implied byu
r(a,) = 0 that
dG
dr(a) = 0.
Thus ifn> 0cnna
n1 ndnan1 = 0
and we can choose
cn = an, dn = a
n.
When n = 0,d0/a = 0,
and the only choice we have is d0 = 0.
This result in
u(r,) = a0 +
n=1
(an cos(n) +bn sin(n))((r/a)n + (a/r)n),
and
u(b,) = a0 +
n=1
(an cos(n) +bn sin(n))((b/a)n + (a/b)n) = g().
You should know how to calculate an and bn.
2. Consider
f(x) =
0 x< x0
1/ x0 < x< x0 +
0 x> x0 +
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Assume thatL < x < L, x0 > L and x0 + < L. Determine the complex
Fourier coefficients cn. Show that cn = cnAnswer
cn =1
2L
ZLL
f(x)einx/Ldx (4)
=1
2L
Zx0+x0
einx/Ldx (5)
=1
2L
L
ineinx/L|x0+x0 (6)
=einx0/L
i2n
ein/L1
(7)
cn =einx0/L
i2n
ein/L1
= cn
3. Using the maximum principles for Laplaces equation, prove that the solution of
Poissons equation 2u = g(x,y), subject to u(x,y) = f(x,y) on the boundary, isunique.
Answer
Read section 2.5.4 in the textbook.
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