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Honors Physics , Pg 1
Honors Physics Honors Physics VectorsVectors
Chapter Problems All problems prior to Mixed review
Vector addition graphically
A vector can be represented by an arrow tipped line segment
Honors Physics , Pg 2
Vectors...Vectors...
There are two common ways of indicating that something is a vector quantity:
Boldface notation: AA
“Arrow” notation:
A A =A
A
A“Hat”
Notation
Honors Physics , Pg 3
Vectors...Vectors...
The components of rr are it’s (x,y,z) coordinates. rr = (rx ,ry ,rz ) = (x,y,z)
Consider this in 2-D (since it’s easier to draw):rx = x = r cos ry = y = r sin
y
x
(x,y)
where r = |rr |
rr arctan( y / x )
NOTE: The book uses instead of . No big deal.
Honors Physics , Pg 4
Vectors...Vectors...
The magnitude (length) of rr is found using Pythagoras’ theorem:
r r x y2 2
rr y
x
The length of a vector clearly does notnot depend on it’s direction.
Honors Physics , Pg 5
Angle Determination using the UNIT CircleAngle Determination using the UNIT Circle
90 degrees
Resultant Vector ‘C’
0 degrees
180 degrees
270 degrees
degrees
Honors Physics , Pg 6
Angle Determination using the UNIT CircleAngle Determination using the UNIT Circle
90 degrees
Resultant Vector ‘C’
0 degrees
180 degrees
270 degrees
degrees
degrees
Honors Physics , Pg 7
Vector addition:Vector addition:
Consider the vectors AA and BB. Find AA + BB.
AA
BB
AA BB AA BB
CC = AA + BB
Vectors can be added by placing the head of one vector at the head of another vector
» When adding two or more vectors, neither the length or the direction is changed
» The sum of the vectors is found by drawing a RESULTANT vector from the tail of the first vector to the head of the last (beginning to end)
We can arrange the vectors as we want, as long as we maintain their length and direction !!
See text: 3-2 and 3-3
Honors Physics , Pg 8
Addition of several vectorsAddition of several vectors
Two students are pulling concurrently (same place, same time)5 N , 0 degrees and 7 N, 270 degrees on a 20kg oscilloscope (assume a frictionless surface)
a) determine the direction of motion
b) determine the net force and acceleration of the scope
5 N 0 degrees
7 N 270 degrees
Honors Physics , Pg 9
Addition of several vectorsAddition of several vectors
5 N 0 degrees
7 N 270 degrees
Add vectors head to tail and draw resultant
With recognition that a right angle exists, the Pythagorean theorem and SOHCAHTOA can be used
Honors Physics , Pg 10
Addition of several vectorsAddition of several vectors
5N,0 deg
7N 270 degr r 5 7 8 62 2 .
tan = 7/5
= 54.5 degrees but using unit circle as a reference the correct angle which describes the true direction of the resultant should be either 305.5 or -54.5 degrees
NOTE:
Honors Physics , Pg 11
Addition of several vectorsAddition of several vectors
Two students are pulling concurrently (same place, same time)5 N , 0 degrees and 7 N, 270 degrees on a 20kg oscilloscope (assume a frictionless surface)
a) determine the direction of motion
b) determine the net force and acceleration of the scope
5 N 0 degrees
7 N 270 degrees Resultant: NET FORCE: 8.6N,305.5 degrees
Honors Physics , Pg 12
Addition of several vectorsAddition of several vectors
The direction of the acceleration will be in the same direction of the NET FORCE
b) determine the net force and acceleration of the scope
a=F(net)/m = 8.6N/20kg = .43 m/s2 ,305.5 degrees
5 N 0 degrees
7 N 270 degrees Resultant: NET FORCE: 8.6N,305.5 degrees
Honors Physics , Pg 13
Addition of several vectors Addition of several vectors What if the angle between the vectors is not 90 degrees?What if the angle between the vectors is not 90 degrees?
Vector resolution and components verses trig laws of cosines and sines
Two students are pulling concurrently (same place, same time)5 N , 10 degrees and 7 N, 300 degrees on a 20kg oscilloscope such that it accelerates at .3 m/s2
a) determine the direction of motion
b) determine the net force and coefficient of friction between the scope and the floor
5 N 10 degrees
7 N 300 degrees
Honors Physics , Pg 14
Vector addition using components:Vector addition using components:
Consider CC = AA + BB.
(a) CC = (Ax ii + Ay jj ) + (Bx i i + By jj ) = (Ax + Bx )ii + (Ay + By )jj
(b) CC = (Cx ii + Cy jj ) Comparing components of (a) and (b):
Cx = Ax + Bx
Cy = Ay + By CC
BxAA
ByBB
Ax
Ay
Honors Physics , Pg 15
Frictionless Inclined planeFrictionless Inclined plane
Vector view of FFTOT = maa
parallelparallel
mgN
ma
See text: 6-4
perpendicular
Honors Physics , Pg 16
Inclined Plane without Friction:Inclined Plane without Friction:
Draw free-body diagram:
parallelparallel
perpendicularperpendicular
mgN
ma
See text: 6-4
See example p124.
Honors Physics , Pg 17
Inclined plane...Inclined plane...
Consider xx and y y components of FFTOT = maa :
Parallel components
mg sin = ma
a / g = sin
See text: 6-4
parallelparallel
perpendicularperpendicular mg
N
ma
mg sin
Honors Physics , Pg 18
Inclined plane...Inclined plane...
Consider xx and y y components of FFTOT = maa :
Perpendicular components
perpen perpen N = mg cos
See text: 6-4
parallelparallel
perpendicularperpendicular
mg cos
mgN
ma
Honors Physics , Pg 19
Static Friction:Static Friction:
So far we have considered friction acting when something moves.We also know that it acts in un-moving “static” systems:
See text: 6-4
In these cases, the force provided by friction will depend on the configuration of the system (i.e. angle of the plane).
Honors Physics , Pg 20
Inclined plane...Inclined plane...
Vector view of FFTOT = maa
llll
mgN KN
ma
See text: 6-4
Honors Physics , Pg 21
Inclined Plane with Friction:Inclined Plane with Friction:
Draw free-body diagram:
parallelparallel
perpendicularperpendicular
mgN
KNma
See text: 6-4
See example p124.
Honors Physics , Pg 22
Inclined plane...Inclined plane...
Consider ii and j j components of FFTOT = maa :
parallelparallel mg sin KN = ma
perpen perpen N = mg cos
mg sin Kmg cos = ma
a / g = sin Kcos
mg
N
KN
ma
mg sin
mg cos
See text: 6-4
parallelparallel
perpendicularperpendicular
Honors Physics , Pg 23
Static Friction...Static Friction...
mg
N
ma = 0 (block is not moving)
The force provided by friction, fF , depends on as long as the block is “static”.
fF
mg sin ff
(Newtons 2nd law along x-axis)
See example p126: Static Friction
See text: 6-4
Honors Physics , Pg 24
Static Friction...Static Friction... Definition: The maximum possible force that the friction between two objects can provide is fMAX =
sN, where s is the “static coefficient of friction”.
We can find s by increasing the ramp angle until the block slides:
M mg
N
SN In this case:
ma = mg sin MSmg cos M
Stan M
See text: 6-4
See example p126 Static Friction
Honors Physics , Pg 25
Inclined plane...Inclined plane...
Vector view of FFTOT = maa
llll
mgN KN
ma
See text: 6-4
Honors Physics , Pg 26
Inclined Plane with Friction:Inclined Plane with Friction:
Draw free-body diagram:
parallelparallel
perpendicularperpendicular
mgN
KNma
See text: 6-4
See example p124.
Honors Physics , Pg 27
Inclined plane...Inclined plane...
Consider components of FFTOT = maa :
parallelparallel mg sin KN = ma
perpen perpen N = mg cos
mg sin Kmg cos = ma
a / g = sin Kcos
mg
N
KN
ma
mg sin
mg cos
See text: 6-4
parallelparallel
perpendicularperpendicular