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Honors Chemistry FINAL EXAM Review Packet Here are separate jing videos to show you how to do the following 25 problems. The formulas and equations below will be given to you on the exam (both parts) so you need not include them on your yellow “cheat sheet…”)
Honors Chemistry Final Exam – Equations and Tables you may find useful…
log = = PV = nRT R = 62.4 or 0.0821 or 8.314
M = Mtot = Q = mcT mcT = mcT Q = mHf/v D = m/V pH = - log [H+] pOH = - log [OH-] [H+][OH-] = 1.0e-14 pH + pOH = 14.00 K = oC + 273
mava2 = mbvb
2 E = h c = h = 6.626 x 10-34 Js c = 3.00 x 108 m/s mave = m1%1 + m2%2 + ... MaVa = MbVb PT = PA + PB + … PA = PTXA Six strong acids: HCl, HBr, HI, HNO3, HClO4, H2SO4
N0 0.301 t Nt t ½
P1V1 P2V2 T1 T2
L torr mol K
L atm mol K
L kPa mol K
For water (H2O)
cs = 2.09 cl = 4.18 cg = 2.08 mp = 0.0°C bp = 100.0°C Hf = 334 J/g Hv = 2257 J/g For ethanol (C2H6O)
cs = 1.39 cl = 2.45 cg = 1.70 mp = -114.3°C bp = 78.4°C Hf = 109 J/g Hv = 841 J/g
moles solute liters solution
M1V1 + M2V2 + … V1 + V2 + …
The Paper part of the final exam will be comprised of just 11 questions. The first question on the exam will be a lab. It is a lab that you have not done, but one that you could have done on the first day of the year without knowing any chemistry! It is mostly a matter of following directions, careful observation and deductive reasoning. The remaining ten questions will come from the following 25 examples. Be aware that there will be at least three different versions of the exam. So, if there are two or three that you do not know how to do, you may get lucky and end up with a version of the test that doesn’t have them on it! Or... you may not. To try to make all versions have the same level of difficulty, I will try to use an equal number of easy and hard questions on each.
1. 6 Write the correct products for each of the following reactions. (No need to balance the overall equations.) a) K + P4 → b) O2 + C2H2 → c) Ba(NO3)2 + H3PO4 → d) O2 + FeBr3 →
K3P CO2 + H2O Ba3(PO4)2 + HNO3 Fe2O3 + Br2
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25. The specific heat lab is done and the data at right are collected. What value does this give for the specific heat of X? _________ (0.295J/g*C)
Mass of empty cup………..…. 4.56 g Mass of cup & cool water… 31.67 g Temp of cool water………….. 19.8*C Final temp after mixing……. 31.4*C Mass of cup, water & X……… 95.34 g Temp of boiling water….….. 101.5*C
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