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1
gravimetric =
measuring
mass
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Silica gel goes from blue to
pink as it absorbs moisture
Can be
regenerated
in
oven
Anhydrous sodium sulfate
gets clumpy as it absorbs
water
More Information about desiccants including common interferentsand regeneration temperature can be found at:
http://www.jtbaker.com/techlib/documents/3045.html
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Coverage Types of gravimetry
Steps in gravimetric analysis
Precipitation
gravimetry
Properties
of
precipitates
and
precipitants
Solubility consideration & Impurity of
precipitates Mechanism of precipitate formation
Calculations with gravimetry & applications
3
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Gravimetric
Method
of
Analysis
Quantitative methods that are based on determining the
mass of
a
pure
element
or
compound
to
which
the
analyte
is
chemically related.
Based on mass measurements made with an analytical
balance
that
produces
highly
accurate
and
precise
data. Any method in which the signal is mass or change in
mass.
There
are
several
types
of
gravimetric
analysis;
precipitation gravimetry, volatilization gravimetry, and
electrogravimetry . The other two methods are gravimetric
titrimetry and atomic mass spectrometry.
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Types
of
Gravimetry
Precipitation gravimetry: method in which the signal is the mass of precipitate. E.g.. Direct determination of Cl‐ by precipitation as AgCl
Electrogravimetry: method in which the signal is the
mass of an electrodeposit on the cathode or anode in
an electrochemical cell. E.g.. Oxidation of Pb2+ and its
deposition as
PbO2 on
the
anode.
Reduction
of
Cu2+ as
Cu deposits on the cathode.
Volatilization gravimetry: method in which the loss of a
volatile species gives rise to the signal (mass). Thermal or
chemical
energy
is
used
to
remove
such
volatile
compounds. E.g Determine C in organic cmpd by CO2using chemical energy and measuring mass difference.
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Precipitation
Gravimetry
6
Cl- + Ag+ AgCl ppt
Mass AgCl precipitate is directly related to
%Cl- in the water sample
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7
General
Steps
in
Gravimetry
Dry and weigh sample
Dissolve sample
Add precipitating reagent in excess
Coagulate precipitate usually by heating
Filtration-separate ppt from mother liquor
Wash precipitate (peptization) Dry and weigh to constant weight
7
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Precipitation
Gravimetry
The analyte is converted to a stable and pure precipitate of known
composition. For example: Ca determination method in natural waters by
Association of
Official
Analytical
Chemist.
Ca2+ in natural water sample directly related to CaO
8
NH3
+H2C2O4
2NH4
+
+C2O4
2-
Ca2+
+ C2O42-
CaC2O4 (s)
CaC2O4 (s) CaO(s)+CO(g)+ CO2(g)
Ca2+
CaO
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1. Properties of Precipitates
Low solubility
‐ No significant loss of the analyte occurs during
filtration and
washing
High purity
Stable under atmospheric conditions
Known composition
After drying and ignition, known chemical composition
Easy to
separate
from
reaction
mixture
and
filtered
and
washed free of impurities
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2.
Precipitating
Reagents:
precipitants Gravimetric precipitating agent should react specifically
or at least selectively with the analyte.
Specific reagents react only with a single chemical species. E.g.. Dimethylglyoxime, is a specific reagent that only precipitates Ni2+ ions from alkaline solutions.
Selective reagents are more common and reacts with a
limited number of species. E.g.. AgNO3, the common
ions
that
it
precipitates
from
acidic
solutions
are
Cl‐
,
Br‐
, I‐ and SCN‐.
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Table
1.0
Selected
Gravimetric
Method
for
Inorganic
Cations
Based
on
Precipitation
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Table
1.0
Selected
Gravimetric
Method
for
Inorganic
Anions
Based
on
Precipitation
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Organic precipitating agents are chelating agents.
They form insoluble metal chelates.
©Gary Christian,
Anal yt ical Chemistry,6th Ed. (Wiley)
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3.
Solubility
considerations
Factors responsible for solubility loss of precipitates
a.. Composition of
solution
in
which
ppt
forms
b.. pH of solution
c.. Solvent type (aqueous and non‐aqueous)
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a. Composition of Solution
● Add only enough precipitating reagent till the precipitation is in
dynamic equilibrium, any extra addition of precipitants will increase
solubility of ppt’s.
● Ag+ can be determined gravimetrically by adding Cl‐ as a precipitant forming AgCl precipitate.
Consider the equilibrium:
Ag+
(aq) + Cl
‐
(aq)
↔
AgCl
(s) One might conclude that addition of Cl‐ at equilibrium would
increase precipitation
however, it has been
observed that an increase in
the equilibrium
concentration
of
Cl‐
forms more soluble chlorides and increases solubility of the AgCl ppt (fig..)
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b.
pH
2..pH of solution in which the ppt forms. For example
hydroxides ppts as Fe(OH)3 are more soluble at low
pH’s
were
[OH
‐
]
is
small.
Why? At lower pH’s [H+] is greater therefore more
electrostatic attraction of H+ to ppt OH‐ occurs, breaking the ppt OH bond and solvation occurs. Like
wise ppt’s
containing
acidic
ions
are
more
soluble
at
higher pH’s were [H+] is low. Explain.
What is solvation?
Electrostatic attraction
of
+ and
– charged
ends
to
the
ppt ions and dissolving the ppt.
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c.
Solvent Type
..solubility can be affected by solvent type (aqueous or non‐aqueous solvents)
Aqueous‐ a
solution
with
water
as
the
solvent,
ppt
solubility is greater in this solution because the water molecules stabilize the ions by solvation process.
Non‐aqueous
‐ solution
with
no
water
mainly
organic
solvents. Organic solvents have poorer solvating ability leads to smaller solubility product.
List some
examples
of
aqueous
and
non
‐aqueous
solvents and explain how solvent type effects solubility of precipitates.
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4. Mechanism of Precipitate Formation
Precipitates form by nucleation and by particle growth. If nucleationpredominates, a large number of very fine particles results; if particlegrowth predominates, a smaller number of larger particles is obtained.
In nucleation, a few ions, atoms, or molecules come together to form stable solid . Often these nuclei form on the surface of suspendedsolid contaminants, such as dust particles.
Further precipitation then involves a competition between additionalnucleation and growth on existing nuclei.
If nucleation predominates, a precipitate containing a large number of small particles results; if growth predominates, a smaller number of
larger particles is produced. The rate of nucleation is believed to increase vastly with increasing
relative super saturation. On the contrary, the rate of particle growth isonly moderately enhanced by high relative super saturations.
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5. Experimental Control of Particle Size
a,. Super‐saturation
Problems faced
during
Precipitation
ProcessDuring the precipitation process, super saturation occurs
(this should be minimized) followed by nucleation and
precipitation.
Supersaturated solution is an unstable solution that contains a high
solute
concentration.
With
time
super
saturation
is
relieved by precipitation of the excess solute.
Experimental variables that minimize supersaturation
and thus produce crystalline precipitates include◦Precipitate from hot solutions (increase Temperature)◦Precipitate from dilute solutions◦Slow addition of precipitating agent with good stirring
◦Controlling pH
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b.
Colloidal
Precipitates
Colloids are so small to hold on a filter and they can
settle down in solution as well due to Brwonian motion
(stochastic process,
random
fluctuation).
In
order
to
have the colloids filterable, we can coagulate or agglomerate.
Coagulation of Colloids: It can be hastened by heating, stirring and adding an electrolyte.
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6. Impurity of precipitates: Coprecipitation
Precipitation gravimetry is based on knownstoichiometry between the analyte mass and ppt mass ,
therefore precipitate must be free of impurities. Greatest source of impurities results from chemical orphysical interactions occurring at the ppt surface.
A ppt is generally crystalline with a well defined latticestructure of cations and anions.
Those cations or anions at the surface carry respectively
a (+) or (–) ve charge as a result of incompletecoordination. Example AgCl Any impurity in the ppt must be removed before taking
its weight.
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Coprecipitation:
Inclusion
and
Occlusion
A phenomenon in which otherwise soluble compounds areremoved from solution during precipitate formation.
There are four types of co‐precipitation: Inclusion, surfaceadsorption and occlusion.
Inclusion: chemical species similar to precipitating ions may substitute into the chemical lattice via chemical adsorption. Thisis very difficult to remove but recrystallization process often
minimizes. Surface adsorption: soluble compound is carried out of solution on
the surface of coagulated colloid particle. Such easily bound watercan be removed via digestion in mother liquor.
Occlusion: a compound is trapped within a pocket formed duringrapid crystal growth.
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8. Applications of Gravimetric Methods
Gravimetric methods have been developed for mostinorganic anions and cations as well as neutral speciessuch as water, sulfur dioxide, carbon dioxide, andiodine.
A variety of organic substances can also be easily determined gravimetrically. Examples: lactose in milkproducts, salicylates in drug formulations, nicotine in
pesticides etc.
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Inorganic Precipitating Agents: Table 12‐2 in the
textbook.
Reducing Agents: Table 12‐3 shows the reagents can
convert the an analyte to its elemental form. Organic Precipitating Agents: There are numerous
examples of this type. In one form of organic reagents,
they produce sparingly soluble non‐ionic coordinationcompounds; In the other forms products with largely
ionic bonds.
Organic Functional Group Analysis: See Table 12
‐
4in the textbook
Volatilization Gravimetry: Based on volatilization
such as water and carbon dioxide determination.26
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Organic precipitants
27
N
OH
+ Mg2+
N
O
N
O
Mg
2 2H+
8-Hydroxquinoline (oxine)
Dimethylglyoxime
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28
What Do We Get Out of Gravimetry?
• % of analyte, % A
• %A = weight of analyte x 100weight of sample
• weight of ppt directly obtained ->?A
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How Do We Get %A?
• % A = weight of ppt x gravimetric factor (G.F.) x 100
weight of sample
• G.F. = Molar mass of analyte X a (mol analyte/mol ppt)
Molar mass of precipitate b
• a: mole analyte; b. mole precipitate
• Hence, a/b give mole ration fraction
• G.F. = # grams of analyte per 1 gram
precipitate
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The Gravimetric Factor
• G.F. = Mr. analyte X a (mol analyte/mol ppt)
Mr. precipitate b
• Analyte ppt G.F.?
CaO CaCO3
FeS BaSO4
PbCl2 PbCrO4
UO2(NO3)2.6H2O U3O8
Cr2O3 Ag2CrO4
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Gravimetric Factor
• Analyte ppt G.F.CaO CaCO3 CaO/CaCO3 x 1/1
FeS BaSO4 FeS/BaSO4 x 1/1
PbCl2 PbCrO4 PbCl2/PbCrO4 x 1/1UO2(NO3)2 U3O8 3UO2(NO3)2/U3O8 x 3/1
Cr 2O3 Ag2Cr O4 Cr 2O3/2Ag2CrO4 x 1/2
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Example 10.1:
An ore is analyzed for the manganese
content by converting the manganese to
Mn3O4 and weighing it. If 1.52-g sample
yields Mn3O4 weighing 0.126-g, what
would be the percent Mn2O3 in thesample? The percent Mn?
Molar mass:
Mn2O3=157.9; Mn3O4= 228.8; Mn=54.94
Ref: Gary D Christian 6th ed p-323
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33
Example 10.2:
Orthophosphate (PO33-) is determined by
weighing as ammonium phosphomolybdate,
(NH4)PO4.12MoO3. Calculate the
percentage P and P2O5 if 1.1682-g
precipitate ere obtained from a 0.2711-gsample.
Molar mass:
(NH4)PO4.12MoO3 =1876.5; P2O5= 141.95;
P=30.97
Ref: Gary D Christian 6th ed p-323
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34
Example 10.3:
The Aluminum in a 0.910g sample of impure
ammonium aluminum sulfate was precipitated
with aqueous ammonia as the hydrous
Al2O3.xH2O. The precipitate was filtered and
ignited at 1000oC to give anhydrous Al2O3,which weighed 0.2001g.
Express the result of this analysis in terms of:
a. % Al2O3 b. % Al in the sample.
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Example 10.4 An iron ore was analyzed by dissolving a
1.1324-g sample in concentrated HCl. The
resulting solution was diluted with waterand iron (III) was precipitated as the
hydrous oxide Fe2O3.xH2O by the additionof NH3. After filtration and washing the
precipitate was ignited to give 0.5394-g of
pure Fe2O3 (159.69 g/mol). Calculate the % Fe (55.847 g/mol), %
Fe3O
4(231.54 g/mol) in the sample.
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Example: 10.5
The calcium in a 200.0 mL sample of a natural water
was determined
by
precipitating
the
cation as
CaC2O4. The precipitate was filtered, washed, and
ignited in a crucible with an empty mass of 26.6002
g.
The mass
of
the
crucible
plus
CaO (fwt 56.077
g/mol) was 26.7134 g. Calculate the concentration
of Ca (fwt 40.078 g/mol) in the water in units of
grams per
100
mL.
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Example 10.6
An iron ore was analyzed by dissolving a 1.1324 g
sample in concentrated HCl. The resulting
solution was
diluted
with
water,
and
the
iron(III)
was precipitated as the hydrous oxide Fe2O3.xH2O
by addition of NH3. After filtration and washing, the residue was ignited at high temperature to give
0.5394 g pure
Fe2O3 (fwt 159.69
g/mol).
Calculate
(a) the % Fe (fwt 55.847 g/mol) and (b) % Fe3O4
(fwt 231.54 g/mol) in the sample.
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Example 10.7
A 0.2356 g sample containing only NaCl (fwt 58.44
g/mol) and BaCl2 (fwt 208.23 g/mol) yielded 0.4637
g of
dried
AgCl (fwt 143.32
g/mol).
Calculate
the
percent of each halogen compound in the sample.
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More
Review
Questions1. Treatment of a 0.2500‐g sample of impure potassium chloride with an excess of AgNO3
resulted in the formation of 0.2912‐g of AgCl. Calculate the percentage of KCl in the
sample. (Molar mass AgCl 143.321 g/mol, KCl 74.551 g/mol)
2. An
iron
ore
was
analyzed
by
dissolving
a 1.1324
‐g sample
in
concentrated
HCl.
The
resulting solution was diluted with water and iron (III) was precipitated as the hydrous oxide Fe2O3.xH2O by the addition of NH3. After filtration and washing the precipitate was ignited to give 0.5394‐g of pure Fe2O3 (159.69 g/mol).
3. Calculate the % Fe (55.847 g/mol), % Fe‐3O4 (231.54 g/mol) in the sample.
The aluminum content of an alloy is determined gravimetrically by precipitating it to
Al(C9H6ON)3. If a 1.021‐g sample yielded 0.1862‐g of precipitate, what is the percent aluminum in the alloy?
4. State the problem often faced during precipitation process. How can you as chemists minimize it?
5. What are the steps involved in gravimetric analysis?