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Gases © 2012 Pearson Education, Inc. Gases • Made up of particles that have (relatively) large amounts of ________ • No definite _______ or___________ • Due to a large amount of empty space, gases are easily __________

Gases © 2012 Pearson Education, Inc. Gases Made up of particles that have (relatively) large amounts of ________ No definite _______ or___________ Due

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Gases

© 2012 Pearson Education, Inc.

Gases

• Made up of particles that have (relatively) large amounts of ________

• No definite _______ or___________

• Due to a large amount of empty space, gases are easily __________

Gases

© 2012 Pearson Education, Inc.

Gases

• Made up of particles that have (relatively) large amounts of _energy__

• No definite _shape_ or___volume__

• Due to a large amount of empty space, gases are easily _compressed_____

Gases

© 2012 Pearson Education, Inc.

4 Quantities to define the state of a gas

• Quantity-moles

• Temperature in Kelvin

• Volume in liters

• Pressure in atmosphere.

Gases

© 2012 Pearson Education, Inc.

• Pressure is the amount of force applied to an area:

Pressure

• Atmospheric pressure is the weight of air per unit of area.

P =FA

Gases

© 2012 Pearson Education, Inc.

Pressure

• A pressure is exerted when gas particles collide with the walls of any container it is held in.

Units

• 1.00 atm=

• 760. mm Hg=

• 760. torr=

• 1.01 x 105 Pa=

• 101.325 kPa

Gases

© 2012 Pearson Education, Inc.

Units of Pressure

• mmHg or torr– These units are literally the difference in the heights measured in mm (h) of two connected columns of mercury.

• Atmosphere1.00 atm = 760 torr

Gases

© 2012 Pearson Education, Inc.

Manometer

The manometer is used to measure the pressure of a gas in a container.

Gases

© 2012 Pearson Education, Inc.

Standard Pressure

• Normal atmospheric pressure at sea level is referred to as standard pressure.

• It is equal to– 1.00 atm

– 760 torr (760 mmHg)– 101.325 kPa

Gases

© 2012 Pearson Education, Inc.

Exercise 1

• The pressure of a gas is measured at 49 torr. Represent this pressure in both atmospheres, mm Hg and pascals: (6.4 x

102 atm, 6.7x 105 Pa)

Gases

© 2012 Pearson Education, Inc.

Kinetic-Molecular Theory

This is a model that aids in our understanding of what happens to gas particles as environmental conditions change.

Gases

© 2012 Pearson Education, Inc.

Main Tenets of Kinetic-Molecular Theory

1.Gases consist of large numbers of tiny particles that are in constant, random motion.

Gases

© 2012 Pearson Education, Inc.

Main Tenets of Kinetic-Molecular Theory

2. Collisions between particles are elastic (the average kinetic energy is remains constant following a collision)

This seems to explain the observation that gases, when left alone in a container, don’t seems to lose energy, and don’t spontaneously convert to a liquid.

Gases

© 2012 Pearson Education, Inc.

Main Tenets of Kinetic-Molecular Theory

Energy can be transferred between molecules during collisions, but the average kinetic energy of the molecules does not change with time, as long as the temperature of the gas remains constant.

Gases

© 2012 Pearson Education, Inc.

Main Tenets of Kinetic-Molecular Theory

3. The Attractive and repulsive intermolecular forces between gas molecules are very weak, and are nearly negligible, except when they collide.

Gases

© 2012 Pearson Education, Inc.

Main Tenets of Kinetic-Molecular Theory

4.The combined volume of all the molecules of the gas is negligible relative to the total volume in which the gas is contained.

. This seems to explain why gases are compressible.

Gases

© 2012 Pearson Education, Inc.

Main Tenets of Kinetic-Molecular Theory

5. Average kinetic energy of molecules is proportional to its Kelvin Temperature.

ALL CALCULATIONS INVOLVING TEMPERATURE OF GASES MUST BE CONVERTED TO KELVIN TEMPERATURE

Gases

© 2012 Pearson Education, Inc.

• The pressure of the gas is caused by the collision of the molecules with the walls of the cylinder. The magnitude of the pressure depends on the frequency and the force of the collisions.

• The temperature of the gas depends on the average kinetic energy of the molecules

Gases

© 2012 Pearson Education, Inc.

Boyle’s LawThe volume of a fixed quantity of gas at constant temperature is inversely proportional to the pressure. P1V1

= k or P1V1 = P2 V2

Gases

© 2012 Pearson Education, Inc.

P and V are Inversely Proportional

A plot of V versus P results in a curve.Since

V = k (1/P)This means a plot of V versus 1/P will be a straight line.

PV = k

Gases

© 2012 Pearson Education, Inc.

Exercise 1 Boyles Law

• SO2 is a gas that plays a central role in the formation of acid rain, is found in the exhaust of automobiles and power plants. Consider 1.53 L of SO2 at a pressure of 5.6 x 103 Pa. If the pressure is changed to 1.5 x 10 6 PA, what is the new volume of the gas?

Gases

© 2012 Pearson Education, Inc.

Exercise 2

• If a 1.23 L sample of a gas at 53.0 torr is put under pressure up to a value of 240. torr at a constant temperature, what is the new volume?

Gases

© 2012 Pearson Education, Inc.

Charles’s Law

• The volume of a fixed amount of gas at constant pressure is directly proportional to its absolyute temperature IN KELVIN!.

Gases

© 2012 Pearson Education, Inc.

Charles’s Law

• So,

• It is a direct proportion. A plot of V versus T will be a straight line.

VT

= k

Gases

© 2012 Pearson Education, Inc.

Gay Lussac

• P1 T2 = P2 T1

Gases

© 2012 Pearson Education, Inc.

Combined Gas Law

• P1 V1T2 = P2V2 T1

• Notice the , laws are alphabetical (Boyle P and V, Charles V and T and Gay Lussac T and P (missing variable is held constant

Gases

© 2012 Pearson Education, Inc.

The Quantity-Volume Relationship

• Gay-Lussacs Law of combining volumes- at a given temperature and pressure, the volumes of gases that react with each other are ratios of small whole numbers

• Avogadro’s law-equal volumes of gases at the same temp and press contan the same number of molecules!!

Gases

© 2012 Pearson Education, Inc.

Avogadro’s Law• The volume of a gas at constant temperature

and pressure is directly proportional to the number of moles of the gas.

• Mathematically, this means V = kn

Gases

© 2012 Pearson Education, Inc.

Example 1

If we have a 17.5 L container which holds 0.60 mol of O2 gas at

a pressure of 1 atm and a temperature of 25 C, and all of the O2 is converted to O3, what is the

volume of the ozone?

Gases

© 2012 Pearson Education, Inc.

• If 2.11 g Ne gas occupies a volume of 12.0 L at 28.0 C. What volume will 6.58 g of Neon occupy under the same conditions?

Gases

© 2012 Pearson Education, Inc.

Ideal-Gas Equation

V 1/P (Boyle’s law)V T (Charles’s law)V n (Avogadro’s law)

• So far we’ve seen that

• Combining these, we get

V nTP

Gases

© 2012 Pearson Education, Inc.

Ideal-Gas Equation

The constant of proportionality is known as R, the gas constant.

Gases

© 2012 Pearson Education, Inc.

Ideal-Gas Equation

The relationship

then becomes

nTP

V

nTP

V = R

or

PV = nRT

Gases

© 2012 Pearson Education, Inc.

Ideal gas law

• Most useful when gases are behaving ideally (under conditions that the molecules will not be attracted to each other. This occurs at :

• High temperatures and low pressure

Gases

© 2012 Pearson Education, Inc.

Ideal gas Law Example 1

• A sample of nitrogen gas (N2) has a volume of 9.95 L at a temperature of 1.00 C and 1.75 atm.

• Calculate moles of N2 in this sample

• Calculate molecules N2 in this sample

Gases

© 2012 Pearson Education, Inc.

Other Gas Laws

Example 1.• A sample of methane gas has a pressure

of 455 torr at a temperature of -7.5 C and a volume of 2.25 L. If the conditions are changed so that the temperature rises to 21.0 C and and the pressure increases to 437 torr, what will be the new volume of the sample?

•  

Gases

© 2012 Pearson Education, Inc.

Other Gas Laws

• Example 2

A sample of helium gas has a volume of 16.2 L and a pressure of 1.81 atm. The gas is compressed to a volume of 8.1 L. Calculate the final pressure of the gas (assume constant temperature)

Gases

© 2012 Pearson Education, Inc.

• Example 3

• Calculate the volume of 1 mole of a gas at STP.

• This is the molar volume of a gas at STP!!! Very good to know!!

Gases

© 2012 Pearson Education, Inc.

Densities of Gases

If we divide both sides of the ideal-gas equation by V and by RT, we get

nV

PRT

=

Gases

© 2012 Pearson Education, Inc.

• We know that– Moles molecular mass = mass

Densities of Gases

• So multiplying both sides by the molecular mass () gives

n = m

PRT

mV

=

Gases

© 2012 Pearson Education, Inc.

Gases

© 2012 Pearson Education, Inc.

Molecular Mass

We can manipulate the density equation (in g/L) to enable us to find the molecular mass of a gas:

becomes

PRT

d =

dRTP =

Gases

© 2012 Pearson Education, Inc.

Density of gases

• The molar mass of air is approximately 29 g/mol at STP. What is its density?

Gases

© 2012 Pearson Education, Inc.

Gas density/Molar Mass• The density of a gas was measured at

1.50 atm and 27 C and found to be 1.95 g/L. Calculate the molar mass of the gas.

Gases

© 2012 Pearson Education, Inc.

The density of air at room temperature (22C) and 1 atm pressure is 1.19 g/L. What is the molar mass of air?

Gases

© 2012 Pearson Education, Inc.

Gases

© 2012 Pearson Education, Inc.

3 gases less dense than air

Neon, hydrogen, methane, ammonia, helium,

Gases

© 2012 Pearson Education, Inc.

3 gases more dense than air

CO2, O2 , propane

Gases

© 2012 Pearson Education, Inc.

• The density of a gas was measured at 1.50 atm and 27 C and found to be 1.95 g/L. Is this gas, carbon dioxide, oxygen, or neon?

Gases

© 2012 Pearson Education, Inc.

Dalton’s Law ofPartial Pressures

• In a mixture of gases, the total pressure exerted by the mixture is equal to the sum of the individual partial pressures of each gas.

• In other words,

Ptotal = P1 + P2 + P3 + …

Gases

© 2012 Pearson Education, Inc.

Partial Pressures

• When one collects a gas over water, there is water vapor mixed in with the gas.

• To find only the pressure of the desired gas, one must subtract the vapor pressure of water from the total pressure.

Gases

© 2012 Pearson Education, Inc.

Partial Pressures

The total pressure at constant T and V is determined by the total number of moles of gas present, it is not important if it is just

one gas or a mixture of many gases.

• .

Gases

© 2012 Pearson Education, Inc.

Partial Pressures

Assuming ideal gas behavior, the pressure in a mixture of gases is Ptotal = ntotal (RT/V)

• .

Gases

© 2012 Pearson Education, Inc.

• Calculate the number of moles of hydrogen present, in a 0.641 L mixture of Hydrogen and water vapor, at 21.0 C, that has a total pressure of 750. torr, given that the vapor pressure of water at this temperature is 20.0 torr.

Gases

© 2012 Pearson Education, Inc.

• Example 2

• 3.00 liters of carbon monoxide gas at a pressure of 199 kPa and 1.00L of carbon dioxide gas at a pressure of 300 kPa are injected into a 1.25 L container. Assuming no reaction between the two gases, what is the total pressure of the container?

Gases

© 2012 Pearson Education, Inc.

Example 3The partial pressure of a gas was observed to be 156 torr in air with a total atmospheric pressure of 743 torr. Calculate the mole fraction of this gas.

Gases

© 2012 Pearson Education, Inc.

Dalton’s Law II The partial pressure was observed to be 156 torr

in air with a total atmospheric pressure of 743 torr. Calculate the mole fraction

• Moles of gas and pressure are directly proportional. Pressure fraction will equal mole fraction.

• 156 torr/743 torr= mole fraction=.210

Gases

© 2012 Pearson Education, Inc.

Gases

© 2012 Pearson Education, Inc.

• A sample of solid potassium chlorate (KClO3) was heated in a test tube and decomposed by the following reaction: 2 KClO3 2 KCl + 3 O2 The oxygen produced was collected by displacement of water at 22 C at a total pressure of 754 torr. The volume of gas collected was 0.650 L, and the vapor pressure of water at 22 C is 21 torr. Calculate the partial pressure of O2 in the gas collected and the mass of KClO3 in the

sample that was decomposed.

Gases

© 2012 Pearson Education, Inc.

• Example 2

• A sample of propane (C3H8) having a volume of 3.25 L at 22 C and a pressure of 1.33 at, was mixed with a sample of oxygen gas having a volume of 15.5 L at 25 C and 1.25 atm. The mixture was then ignites to form CO2 and water. Calculate the volume of CO2 formed at a pressure of 1.50 atm and a temperature of 125 C.

Gases

© 2012 Pearson Education, Inc.

Main Tenets of Kinetic-Molecular Theory

The average kinetic energy of the molecules is proportional to the absolute temperature. Changing the temp changes the shape of the curve, but not the area beneath it

Gases

© 2012 Pearson Education, Inc.

Gases

© 2012 Pearson Education, Inc.

Root Mean Square Velocity

Gases

© 2012 Pearson Education, Inc.

Root Mean Squared Velocity

• The square root of the avergages of the squares of the speeds of all of the particles in a gas sample at a particular temperature

• R- 8.31 T- Kelvin temperature

• M-molar mass gas

Gases

© 2012 Pearson Education, Inc.

Exercise 19: Root Mean Square Velocity

• Calculate the rms velocity for the following gases at 25 C, and at 50C– He

– O2

– Rn

Gases

© 2012 Pearson Education, Inc.

• Quantitatively, what can be said about the rms speed as it relates to the molar mass of a gas and the temperature of the gas

Gases

© 2012 Pearson Education, Inc.

Diffusion

Diffusion is the spread of one substance throughout a space or throughout a second substance.

Gases

© 2012 Pearson Education, Inc.

Graham’s Law of Effusion and Diffusion

Effusion is the escape of gas molecules through a tiny hole into an evacuated space.

Gases

© 2012 Pearson Education, Inc.

Effusion

The difference in the rates of effusion for helium and nitrogen, for example, explains why a helium balloon would deflate faster.

Gases

© 2012 Pearson Education, Inc.

Graham's Law

KE1 KE2=

1/2 m1v12 1/2 m2v2

2=

=m1

m2

v22

v12

m1

m2

v22

v12

=v2

v1

=

Gases

© 2012 Pearson Education, Inc.

Rate of effusion gas 1 = M2

Rate of effusion gas 2 M 1

Gases

© 2012 Pearson Education, Inc.

Exercise 20 Calculate the ratio of effusion rates of H2 and UF6

• Rate H2 =

Rate UF6

Gases

© 2012 Pearson Education, Inc.

Real Gases

In the real world, the behavior of gases only conforms to the ideal-gas equation at relatively high temperature and low pressure.

Gases

© 2012 Pearson Education, Inc.

Real Gases

Even the same gas will show wildly different behavior under high pressure at different temperatures.

Gases

© 2012 Pearson Education, Inc.

Deviations from Ideal Behavior

The assumptions made in the kinetic-molecular model (negligible volume of gas molecules themselves, no attractive forces between gas molecules, etc.) break down at high pressure and/or low temperature.

Gases

© 2012 Pearson Education, Inc.

Corrections for Nonideal Behavior

• The ideal-gas equation can be adjusted to take these deviations from ideal behavior into account.

• The corrected ideal-gas equation is known as the van der Waals equation.

Gases

© 2012 Pearson Education, Inc.

The van der Waals Equation

) (V − nb) = nRTn2aV2(P +