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7/22/2019 From BS5950 to EC3
1/40
rom o
Chiew Sing-PingSchool of Civil and Environmental En ineerin
Nanyang Technological University, Singapore
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Basis of design combination of actions
Structural analysis imperfections &-
Member design beam & columnuc ng
Web bearin & bucklin
Shear buckling & plate girder w
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Trend is to use higher grade and better quality
EC3 has additional ductility requirements
compare o . . . n erms o
stress ratio, elongation and strain ratio. It is okay for hot-rolled steel but will be difficult
- -
section.
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uc y equ remen
Normal Strength Steelf < 460 N/mm2
High Strength Steel460 < f < 700 N/mm2
fu/fy 1.10
fu/fy 1.05 ( EC3-1-12) u y . or p as c ana ys s
elongation at failure not
fu/fy 1.10 ( UK NA to EC3-1-12)
elon ation at failure not
u 15 y ( y is the yieldless than 10%
15 s ra n,
y=
y
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-
f
fyUpper
yLower
tress
u Strainy
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-
f
fyUpper
yLower
tress
amount of plastic deformation
represented by shaded area under the
curve
u Strainy
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Problem 1 Steel for Cold ForminSome product standards only have requirements on the nominal
yield and tensile strengths, or their minimum values. The stress
ratio calculated according to these nominal values cannot comply
with the EC3 ductility requirement.
Standard Grade Nominal yieldstrength (MPa)
Nominal tensilestrength (MPa)
Stress ratio
AS1397
G450 450 480 1.07
G500 500 520 1.04
G550 550 550 1.00
AS 1595 CA 500 500 510 1.02
S 550MC 550 600 1.09
EN 10149-2 .
S 650MC 650 700 1.08
S 700MC 700 750 1.07
EN 10326 S550GD 550 560 1.02
.
AS 1397: Steel sheet and strip hot-dip zinc-coated or aluminium/zinc-coated
AS 1595: Cold-rolled, unalloyed, steel sheet and strip
EN 10149-2: Hot-rolled flat products made of high yield strength steel for cold forming
EN 10326: Continuously hot-dip coated strip and sheet of structural steels
ISO 4997: Cold-reduced carbon steel sheet of structural quality
steel for profile metal decks and purlins
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Problem 2 Cold Formed Sections
Most standards only have requirements on the range of tensile. .
face problem with EC3 ductility requirement, for e.g. S355J2H in BS
EN10219: fy>355 MPa and 470 MPa
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Mechanical Pro erties due to Cold Workin
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Typical Curve with no distinct Yield Point
- gain in yield and loss in ductility due to cold working
ss
Rm
Str p
Rt
StrainAgt AtA
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Toughness Requirement
To prevent sudden brittle fracture failure, both adopteda s mp e eeme - o-sa s y es gn approac y
ensuring the maximum permitted thickness value is
adequate notch toughness, taking into account factors
, , ,
member shape and detail, stress level and strain rate.
, - -
for brittle fracture using fracture mechanics in addition
.
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SteelQuality
Grade
(Ed= 0.75 fy) (t)
(Ed = 0.5 fy) (t)
(Ed )> 0.3 fy) (t)
10 (20)C 0C 10 (20)C 0C 20C 0C
S275
JR 55 45 80 70 71 50J0 75 65 115 95 103 71
J2 110 95 155 130 148 103
M,N 135 110 180 155 178 124
ML,NL 185 160 200 200 250 178
JR 40 35 65 55 50 35
S355
J0 60 50 95 80 72 50
J2 90 75 135 110 104 72
M,N 110 90 155 135 124 86
Notes: (1) The units for the thickness values are mm.
ML,NL 155 130 200 180 179 124
e g es re erence empera ure a a owe s .
(3) This comparison is done under generally welded and high stress condition
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load combinations are given in Table 2 of BS5950.
Fundamental combination of actions can be determined
from Eqns. 6.10, 6.10a or 6.10b of EN1990.
+++> 1i
ik,i,iQ,k,1Q,1p1
jk,kG, QQPG (6.10)
Action due to
prestressing
Leading variable
action
Non-leading variable
actions
Permanent
actions
From SS NA of EN1990= .
0= 0.7 for the imposed load;
G = 1.35 for unfavorable permanent action;
Q = . or ea ng or non- ea ng var a e ac on.
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Combination of Actions
Combination Design Action
Dead & imposed 1.4Gk+ 1.6Qk 1.35Gk+ 1.5Qk
Dead & wind 1.4G + 1.4W 1.35G + 1.5W
Dead, imposed & wind 1.2Gk+ 1.2Qk+ 1.2Wk 1.35Gk+ 1.05Qk+ 1.50Wkor
1.35Gk+ 1.50Qk+ 0.75Wk
Gk= permanent action; Qk= imposed variable action; Wk= wind variable action
Example: Gk= 20 kN; Qk= 10 kN; Wk= 8 kN
Design Action
BS5950 EN1990Dead & imposed 44.0 kN 42.0 kN
Dead, imposed & wind 45.6 kN 49.5 kN or 48.0 kN
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-
Global imperfections for frames and bracing systems,
such as global initial sway imperfections =0hm in
Local im erfections for members
The effects of local imperfections in members are
generally incorporated within the formulae given for .
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Frame Im erfection in BS5950
BS5950 uses the notional horizontal force (NHF) concept to
F3 F3
a ow or rame mper ec on suc as ac o rame ver ca y
F2F2 F2
=
F1F1 F1
1 n 200 = 0.5%
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Global Im erfection in EC3
EC3 uses the same concept but called it equivalenthorizontal force (EHF) to allow for initial sway imperfection
(lack of verticality) in frame
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Combination of Actions
CombinationDesign Action
BS5950 EC3
Dead & imposed 1.4Gk + 1.6Qk + NHF 1.35Gk + 1.5Qk + EHF
*ea w n . k . k no . k . k
Dead, imposed & wind 1.2Gk + 1.2Qk+ 1.2Wk* (no NHF) 1.35Gk + 1.05Qk+ 1.50Wk + EHF
or
1.35Gk + 1.50Qk+ 0.75Wk+ EHF
In BS5950, minimum Wk is 1% of factored dead load;
this is to provide a minimum level of robustness but
why no NHF when the wind is blowing?
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Structural Anal sis - Terminolo
First-order analysis: Equilibrium equations are written
in terms of the geometry of the undeformedstructure,
geometrical non-linearity not considered Second-order anal sis: E uilibrium e uations are
written in terms of the geometry of the deformed
structure, geometrical non-linearity considered Elastic analysis: Material properties is assumed to be
elastic and often linear
Inelastic analysis: Inelastic material properties
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T es of tructural Anal sis
First-order, second-order, elastic and inelastic analyses y : x u y,
represents conditions under normal service loads very well
considered. It produces good representation of destabilizing
-
First order inelastic analysis: Geometrical nonlinearity
abruptly (e.g. onset of plastic hinge)
Second order inelastic anal sis: Both eometrical and
material nonlinearity are considered. Enable you to tracethe behavior of the structure up to ultimate state and failure
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Level of Non-Linearit
nd. , , , . . ,John Wiley & Sons, 2000
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BS5950 EC3
.
First-order elastic analysis (initial
geometry and influence of deformation
not considered)
First-order analysis
Elastic global analysis
First-order plastic analysis (small axial
forces & no instability effects)
Plastic global analysis
Using first-order analysis, if:
Second-order elastic analysis (can use
simplified methods such as amplified
cr 10 for elastic analysis
methods for sway sensitive frames
where 4 < cr< 10)
cr= Fcr/Fed, Fcr is the elastic critical
buckling load
Other advanced analyses (generallynot covered)
Second-order analysis (influence ofgeometrical deformation taken into
account)
Allowed more advanced analyses
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-
The frame P-big effect is allowed for in BS5950 using either one of thefollowing 2 methods:
Amplified sway method - the sway moments are multiplied by an,
Effective length method - the actual sway effective lengths from thecharts in Annex E are used.
The column P-small effect is allowed for in BS5950 indirectly through
- .
Note: Although EC3 also allows amplified sway moment or effective
length approach, less guidance is given. Unlike BS5950 which
facilitates hand calculations, EC3 focuses on global second-order
. .
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-
Simplified method:Amplified the sway moments
Exact method:Moments about minor axis only:
-
1++yy
yy
xy
xx
C
C
Zp
m
Zp
m
P
FIn-planebuckling 11
++cy
c
cy
yy
cy
c
PF
M
m
PF In-planebuckling
way e ective length rom Annex E
Lateral-torsional
buckling
15.0 +cy
yyx
cx M
Mm
P
Fc Out-of-planebuckling
1++yyLTLT
MmMmFc
Moment about major axis only:
15.01
++ cxxcFMmF In-plane
bcy
cxcxcx
15.0 + LTLTMm
P
FcOut-of-plane
bucklincy
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Rigorous method:
=
General method:
x
Mb = PbZxMb = PbSx,eff for class 3
1M
y
yLTRd,b WM =
1
b b x,eff
For non-uniform moment or unequal
LT ,2LT
2LTLT
LT
+
2 fWen momen :
Mx Mb/mLT and Mx Mcxwhere LT is imperfection factor
++= LTLTLTLT ,,
cr
LTM
=
where Pb determined by
LT = u v(w)0.5LE/ry
depending on which buckling curves
(Figure 6.4 of EC3)
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Member Desi n Com ressive Resistance
BS5950 EC3
Pc =pcAg for class 1, 2 & 3 for class 1, 2 & 31M
y
Rd,b
AfN
=
Pc =pcsAeff for class 4 for class 41M
yeff
Rd,bN
=
c
based on the strut curve, slenderness
& design strengthpy
buckling mode1
=
= L/r r= (I/A)0.5
but 1,0
+
.
where is imperfection factor( )
++=2
2,015,0cr
yeff
N
f=
depending on buckling curves (EC3 has
5 curves).
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EC3 offers no formulae and gives no guidance on how to calculateNcrand Mcr.
.
2EI5.0
22 Tcrw GIIEI
2
cr
crL
=221
=
zZcr
crEIIL
where Lcr is the effective length and C1 is the correction factor for
non-uniform and unequal end moments. Unlike BS5950, EC3 does
uniform moment factors.
W b B i d B kli
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Web Bearin and Bucklin
BS5950-1 requires two independent checks for web bearing
with these two failure modes for the web subjected to a
transverse force.
However, unlike BS5950, EC3 does not take unrestrainedflan e into account flan e free to swa or rotate .
Flange free to sway
sideways
Flange rotation
relative to the web
W b B i d B kli
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Web Bearin and Bucklin
BS5950 EC3e ear ng: bw = 1 + n pyw
Web buckling:
es s ance o we aga ns
transverse force in which their
compression flange is adequately
for unstiffened web &
c> 0.7d restrained in the lateral direction:
bwx Pt
P25
=
weffyw tLf
For unstiffened web & c< 0.7d
n11M
Rd
eff
resistance against transverse force:bwe
x Pdnkbd
P)(4.1
.
1 +=
= 0.15.0 =
Pd
P7.0
=
yeF
wFcr
tEkF
3
9.0= ywwyFftl
=
Ew cr
Web Bearin and B cklin
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Web Bearin and Bucklin
EC3 has no equations to calculate stiff bearing length except saying the
over which the applied load is effectively distributed at a slope of 1:1,
and Ss should not be larger than hw. (EC3-1-5, clause 6.3.1)
BS5950-1 EC3-1-5
The Straits Times, 3 Augus t 2004The Straits Times, 3 Augus t 2004
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Shear Bucklin and Plate Girder
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Shear Bucklin and Plate Girder
BS 5950-1 Web with depth-to-thickness ratio d/t > 62 is susceptible
to shear buckling.
Shear buckling resistance Vb of the thin web is taken as w
Vb
= Vw
= d t qw
where d is the depth of the web;
t is the web thickness
qw is the shear buckling strength of the web
Shear Bucklin and Plate Girder
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Shear Bucklin and Plate Girder
EC3-1-5 Web with hw/tgreater than should be checked for
resistance to shear buckling.
The design resistance for shear buckling is taken as:
(5.1),,,3
wywRdbfRdbwRdb
thfVVV +=
in which the contribution from the web and flanges are:
(5.2)1
, 3 M
wyww
Rdbw V =
(5.3)
=
22
, 1Edyfff
Rdbf
MftbV
,1 RdfM
Shear Bucklin Resistance
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Shear Bucklin Resistance
Stiffener spacing ratio, a/d (a/hw) = 1, fy = 275 N/mm2
160
180
)0.6275=165 EC3 rigid end post TFA
140
(N/mm qw (BS5950-2000)TFA
EC3 non-rigid end post TFA
100gthqw
qcr(BS5950-1990) No TFA
60arstre
61
71
55.7
20
40sh
28
0
0 50 100 150 200 250 300
.
we ep - o- c ness ra o w
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the applied shear forcesTension Field Action TFA
when elastic critical
shear buckling
resistance is
exceeded
Tension field action is mobilized in both BS5950 and EC3 torealize much hi her shear bucklin resistance of the thin web
Wh the fuss over Hollow Section Joint?
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Wh the fuss over Hollow Section Joint?
Hollow section joints can be very flexible because they are unstiffened!
Designing unstiffened welded hollow section joints is a skilled task and must
be done at member design stage.
Potential Failure Modes
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Potential Failure Modes
Mode A: Plastic failure of
Mode B: Punching shear
failure of the chord facethe chord face
Mode D: Local buckling of
the web member
Potential Failure Modes
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Potential Failure Modes
Mode E: Overall shear failureof the chord
Mode F: Local buckling ofthe chord walls
Mode G: Local bucklin ofthe chord face
Verification
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Verification
Topic BS5950 EC3
Material
uc y Toughness
Basis - combination of actions Im erfections
analysis
Second-order effects
em er uc ng eam co umn Web bearing & buckling Shear buckling & Plate girder Hollow section oints
Final oncludin Remarks
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Final oncludin Remarks
-adequate and safe for use in the short term.
.
EC3 is more comprehensive but its terminology,
sym o s an va ues are very eren an mu p e
documents are needed. Re-training is absolutely necessary in view of time
frame and ma nitude of chan e involvin man
design codes and documents. .