Mathematics/Form 3/Marking Scheme/Track 1/2014/Page 1 of 4

FORM 3 MARKING SCHEME TRACK 1 Notes for Marking of Scripts Types of Marks • M(ethod) marks are awarded for knowing a correct method of solution and attempting to

apply it. Method marks cannot be lost for arithmetic mistakes. They can only be awarded if the method used would have led to the correct answer had not an arithmetic mistake been made. In general a correct method is implied by a correct answer and therefore when a correct answer is given and no work is shown, no method marks are lost.

• A(ccuracy) marks are given for correct answer only (c.a.o.) Incorrect answers, even though nearly correct, score no marks. Accuracy marks are also awarded for incorrect answers which are correctly followed through (f.t.) from an incorrect previous answer, provided that f.t. is indicated in the marking scheme. No method (M) or accuracy (A) marks are awarded when a wrong method leads to a correct answer.

• B marks are accuracy marks awarded for specific results or statements independent of the method used.

Misreading M marks can still be earned (unless that part of the question is trivialized) but the final A marks are lost. Crossed out working An answer or working that is crossed out and not replaced is marked as if it was not crossed out. If the answer or working is replaced, then the crossed out answer or working is ignored and should not be considered for marking. Units In general, missing or inaccurate units are not penalised unless otherwise indicated in the marking scheme. Other ! Incorrect working or statement following a correct answer is ignored. ! Marks are not sub-divisible; no half marks may be awarded. ! Other abbreviations used:

• o.e. (or equivalent) • e.e.o.o. (each error or omission)

Markers are advised to indicate the M, A or B marks awarded in the body of the script and then write their total in the margin. The total mark for each question should be written in the table included at the top of page 1 of the main paper. This measure facilitates the moderation of papers.

ST. CLARE COLLEGE SECONDARY SCHOOL - PEMBROKE

HALF-YEARLY EXAMINATIONS FEBRUARY 2014

Mathematics/Form 3/Marking Scheme/Track 1/2014/Page 2 of 4

NON-CALCULATOR PAPER (do not penalise if unit is omitted) Non-Calculator

No Answers Marks & Guidelines Total

1 2 22

M1 M1

2

2 Correct Shading B1 B1 2

3   a) !

! b) !

! B1 B1

2

4 Smallest first 5.32 67.004 89.2 104.3 808.04

A3 all correct A2 three correct A1 two correct

3

5 a) 8y + 4 b) 9x + 3y B1 B1 2

6 a) 3(x + 10y) b) 7(x + 3y) B2 B2 4

7 14 4

B1 B1

2

8 Square with 4 lines of symmetry Oval with 2 lines of symmetry

B1 Correct drawing B1 Correct drawing

2

9 0.13 77

B1 B1

2

10 a) 2 hours

b) 𝑆𝑝𝑒𝑒𝑑 =   !""!

= 100km/h

B1

M2 A1

4

Mathematics/Form 3/Marking Scheme/Track 1/2014/Page 3 of 4

MAIN PAPER No Answers Marks & Guidelines Total

1

285.47 285 88.84255737 89 19.84210526 20

B6 One mark each

6

2 𝐴𝐵 = 6𝑐𝑚  ± 1𝑚𝑚 ∠𝐶𝑨𝐵 = 60°  ± 5° ∠𝐶𝑩𝐴 = 60°  ± 5° Perpendicular Bisector of line AB

B1 M2 M2 M1

6

3

34.6 40 240 241.8

0.5   0.02     0.4   0.25   0.75     0.2   0.25   0.4   0.5   0.75  

B3 (-1 e.e.o.o) B6 (-1 e.e.o.o)

9

4 a) 30− 20 𝒙 = 𝟏𝟎 b) 28− 3 = 25 25÷ 5   𝒙 = 𝟓

M2 Seen or Implied A1 M1 Seen or implied M1 Seen or Implied A1

6

5 𝐴𝑟𝑒𝑎  𝑟𝑒𝑐𝑡𝑎𝑛𝑔𝑙𝑒 = 6×2 = 12𝑚! 𝑃𝑒𝑟𝑖𝑚𝑒𝑡𝑒𝑟  𝑟𝑒𝑐𝑡𝑎𝑛𝑔𝑙𝑒 = 6+ 2+ 6+ 2 = 16𝑚 𝐴𝑟𝑒𝑎  𝑡𝑟𝑖𝑎𝑛𝑔𝑙𝑒 = 3×4÷ 2 =  6𝑚! 𝑃𝑒𝑟𝑖𝑚𝑒𝑡𝑒𝑟  𝑡𝑟𝑖𝑎𝑛𝑔𝑙𝑒 = 3+ 4+ 5 = 12𝑚 𝑉𝑜𝑙𝑢𝑚𝑒 = 4×4×4 𝑉𝑜𝑙𝑢𝑚𝑒  𝑜𝑓  𝐶𝑢𝑏𝑒 = 64𝑚! 𝐴𝑟𝑒𝑎  𝑜𝑓  𝑐𝑟𝑜𝑠𝑠  𝑠𝑒𝑐𝑡𝑖𝑜𝑛 = 12÷ 2 = 6 𝑉𝑜𝑙𝑢𝑚𝑒 = 𝐴𝑟𝑒𝑎  𝑜𝑓  𝐶𝑆×𝑙 = 8×6 = 48𝑚!

M1 A1 M1 A1 M1 A1 M1 A1 M1 Seen or Implied A1 M1 Seen or Implied M1 A1

13

Mathematics/Form 3/Marking Scheme/Track 1/2014/Page 4 of 4

No Answers Marks & Guidelines Total

6 38, 43, 48, 53 ×5 +2 20×5 = 100 100+ 3 = 103

B3 (-1 e.e.o.o.) B1 B1 M1 A1

7

7

Correct plotting of straight line graph 𝑔𝑟𝑎𝑑𝑖𝑒𝑛𝑡 = 1 𝑦 − 𝑖𝑛𝑡𝑒𝑟𝑐𝑒𝑝𝑡 = 2

𝑥 −2 −1 0 1 2 3 𝑥 −2 −1 0 1 2 3 2 2 2 2 2 2 2 𝑦 0 1 2 3 4 5

B4 (-1 e.e.o.o) B4 (-1 e.e.o.o) B1 B1

10

8 𝑦 = 2×2+ 5 𝑦 = 4+ 5 𝑦 = 9 𝑦 = 2+ 4+ 7 𝑦 = 6+ 7 𝑦 = 13

M1 M1 A1 M1 M1 A1

6

9a

b

c

𝐴𝐵 = 7.5𝑐𝑚 𝐶𝐷 = 4.8𝑐𝑚 𝐸𝐹 = 6.6𝑐𝑚 40° 50° 45° 5×1000 =  5000 ml 200÷ 100 =  2 m 15000÷ 1000 =  15 Kg

B1 B1 B1 B1 B1 B1 M1 A1 M1 A1 M1 A1

12