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Final Review 1-13-12 1. The original and sale price of an item are shown below. During which week did the price change the most? 2. Which graph has a negative slope? a. b. C. D. Day Original Sale Week 1 $25 $15 Week 2 $30 $25 Week 3 $28 $25 Week 4 $45 $39 Week 5 $42 $33

Final Review 1-13-12

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Final Review 1-13-12. 1. The original and sale price of an item are shown below. During which week did the price change the most? 2. Which graph has a negative slope? a.b.C. D. . Interim Review 1-13-12. - PowerPoint PPT Presentation

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Page 1: Final  Review  1-13-12

Final Review 1-13-121. The original and sale price of an item are shown below. During which week did the price change the most?

2. Which graph has a negative slope?

a. b. C. D.

Day Original SaleWeek 1 $25 $15Week 2 $30 $25Week 3 $28 $25Week 4 $45 $39Week 5 $42 $33

Page 2: Final  Review  1-13-12

Interim Review 1-13-12

3. What is the slope of the line joining the points (6, -3) and (8,6)?

4. Simplify : 12x – 4y + 7x – 8y

5. p. 162 #68

6. p. 162 #66

7. p. 162 #67

8. p. 162 # 65

Page 3: Final  Review  1-13-12

3.1 Graphing Linear EquationsObjectives:By the end of the period, with an 85% accuracy,

students will be able to:

Determine whether an equation is written in standard form

Graph linear equation using the x- and y-intercepts

Graph linear equations by making a table

Page 4: Final  Review  1-13-12

Linear EquationsA linear equation is the equation of a line. It

can be written in 3 different ways.Standard-Form (Today’s focus)Slope-Intercept FormPoint-Slope Form

Linear equations in Standard Form are written in the form Ax + By = C and must satisfy 4 criteria:

A ≥ 0 A and B are not both zero A, B and C are integers whose greatest

common factor is 1. The exponents for each variable should

equal 1.

Page 5: Final  Review  1-13-12

Determine whether the equation is a linear equation. If so, write the equation in standard form and identify A, B and C.

a. 4xy + 2y = 7

b. 2x = 3y + 3

c. y = 4 – 3x

d. p. 159 #1 x = y - 5

e. p. 159 #13 5x + y2 = 25

IDENTIFYING LINEAR EQUATIONS

Page 6: Final  Review  1-13-12

Example 1 BTo write the equation with integer coefficients, multiply each term by 4.

Answer: This is a linear equation.

Original equation

Multiply each side of the equation by 4.

3x – 4y = 32 Simplify.The equation is now in standard form, where A = 3, B = –4, and C = 32.

Identify Linear Equations

Page 7: Final  Review  1-13-12

Graphing Using Interceptsx-intercept - The x-coordinate where the

graph crosses the x axis. To find the x-intercept, let y = 0.

y-intercept - The y-coordinate where the graph crosses the y axis.To find the y-intercept, let x = 0.

Page 8: Final  Review  1-13-12

Example Graph by Using Intercepts

Graph 4x – y = 4 using the x-intercept and the y-intercept.To find the x-intercept, let y = 0.

4x – y =4 Original equation4x – 0 = 4 Replace y with 0.

4x =4 Simplify.x =1 Divide each side by 4.

To find the y-intercept, let x = 0.4x – y = 4 Original equation

4(0) – y =4 Replace x with 0.–y =4 Simplify.

y = –4 Divide each side by –1.

Page 9: Final  Review  1-13-12

Graphing Using Intercepts2x+ 5y = 10

x-intercept y-interceptLet y = 0

2x + 5y = 10 2x + 5(0) = 10 2x + 0 = 10 2x = 10 2 2 x = 5 x-intercept x –int. is the point (5,0)

Let x = 0

2x + 5y = 10 2(0) + 5y = 10 0 + 5y = 10 5y = 10 5 5 y = 2 y-intercept

y-int. is the point (0,2)

Page 10: Final  Review  1-13-12

Graphing Using Intercepts7. y = 4 + x

x-intercept y-interceptLet y = 0

y = 4 + x 0 = 4 + x -4 -4 . -4 = x x-intercept

x-int. is the point (-4,0)

Let x = 0

y = 4 + x y = 4 + 0 y = 4 y-intercept

y-int. is the point (0, 4)

Page 11: Final  Review  1-13-12

Graphing Using Intercepts25. x = 5y + 5

x-intercept y-interceptLet y = 0

x = 5y + 5 x = 5(0) + 5 x = 0 + 5

x = 5 x-intercept x –int. is the point (5,0)

Let x = 0

x = 5y + 5 0 = 5y + 5 -5 - 5 -5 = 5y -5 -5 -1 = y y-intercept y-int. is the point (0, -1)

Page 12: Final  Review  1-13-12

Example:Find the x- and y-intercepts of the graphed segment.A. x-intercept is 10;

y-intercept is 250B. x-intercept is 10;

y-intercept is 10C. x-intercept is 250;

y-intercept is 10D. x-intercept is 5;

y-intercept is 10

Page 13: Final  Review  1-13-12

Example ANALYZE TABLES Jules has a gas card for a local gas station. The table shows the function relating the amount of money on the card and the number of times he has stopped to purchase gas.

A. Determine the x- and y-intercepts of the graph of the function. A. x-intercept is 5; y-intercept is 125B. x-intercept is 5; y-intercept is 5C. x-intercept is 125; y-intercept is 5D. x-intercept is 5; y-intercept is 10

Page 14: Final  Review  1-13-12

Example B. Describe what the y-intercept of 125 means in the previous problem.

A. It represents the time when there is no money left on the card.

B. It represents the number of gas stops.

C. At time 0, or before any gas stops, there was $125 on the card.

D. This cannot be determined.

Page 15: Final  Review  1-13-12

Individual PracticeDo p. 159 - 160 5, 6, 19, 21 and 12

Page 16: Final  Review  1-13-12

9. Graph x + 2y = 4

first get y by itself

x + 2y = 4 -x -x 2y = -x + 4 2 2 2 y = -1x + 2 2

Graphing By Making A Table

Page 17: Final  Review  1-13-12

X y = -1x + 2

2

y (x, y)

--4

-2

0

2

4

Page 18: Final  Review  1-13-12

p. 159 Graph each equation. x = 3

Vertical line through the x axis at 3.

Example like 9.y = 5

Horizontal line through the y axis at 5.

Page 19: Final  Review  1-13-12

Example: Graph using a tableY = 2x + 3

Graphing By Making A Table

Page 20: Final  Review  1-13-12

x y = 2x + 3 y (x, y)

-2 Y = 2(-2) + 3

-1

0

1

2

Page 21: Final  Review  1-13-12

Homework 1-13Read 3-1 Take NotesP. 159 14-28 even,

Read 3-1 Take Notes