FEA Plate Bending

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    PLATE BENDING FREQUENCIES VIA THE FINITE ELEMENT METHOD

    WITH RECTANGULAR ELEMENTS

    Revision A

    By Tom Irvine

    Email: [email protected]

    May 6, 2011

    Rectangular Plate in Bending

    Figure 1.

    Stiffness Matrix

    Let u represent the out-of-plane displacement. The total strain energy of the plate is

    dxdyyx

    u12

    y

    u

    x

    u2

    y

    u

    x

    u

    2

    DU

    b

    0

    a

    0

    22

    2

    2

    2

    22

    2

    22

    2

    2

    (1)

    a

    b

    Y

    X0

    k l

    mn

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    Note that the plate stiffness factor D is given by

    )1(12EhD

    2

    3

    (2)

    where

    E = elastic modulus

    h = plate thickness

    = Poisson's ratio

    The plate has one translational and two rotational degrees-of-freedom at each corner, for a total of 12degrees-of-freedom. The two rotational components are about the x and y-axes respectively.

    Let the four corners be labeled k, l, m, and n, as shown in Figure 1.

    The rotation components at the corner 1are

    x

    u

    llx (3)

    y

    u

    l

    ly (4)

    The displacement equation has 12 constants to enforce 12 continuity conditions.

    312

    311

    310

    29

    28

    37

    265

    24321

    xyayxayaxyayxa

    xayaxyaxayaxaa)t,y,x(u

    (5)

    The displacement equation can be written as

    Z}A{)t,y,x(u T (6)

    where

    121110987654321T aaaaaaaaaaaa}A{ (7)

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    33322322T xyyxyxyyxxyxyxyx1}Z{ (8)

    The strain energy is thus

    Adxdy)y,x(SA2

    DU

    b

    0

    a

    0

    T (9)

    where

    22

    2

    2

    2

    22

    2

    22

    2

    2

    yx

    u12

    y

    u

    x

    u2

    y

    u

    x

    u)y,x(S

    (10)

    Again,

    312

    311

    310

    29

    28

    37

    265

    24321

    xyayxayaxyayxa

    xayaxyaxayaxaa)t,y,x(u

    (11)

    312

    211

    298

    27542 yayxa3yaxya2xa3yaxa2a)t,y,x(u

    x

    (12)

    212

    311

    2109

    28653 xya3xaya3xya2xaya2xaa)t,y,x(u

    y

    (13)

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    The displacement and derivatives at each corner are

    1a}t,0,0{u (14)

    2a}t,0,0{

    x

    u

    (15)

    3a}t,0,0{y

    u

    (16)

    )a(a)a(a)a(a)a(}t,0,a{u 73

    42

    21 (17)

    )a(a3)a(a2)a(}t,0,a{x

    u7

    242

    (18)

    )a(a)a(a)a(a)a(}t,0,a{y

    u11

    38

    253

    (19)

    312

    311

    310

    29

    28

    37

    265

    24321

    ababaabaababaa

    aabaabaaabaaaa}t,b,a{u

    (20)

    )a(b)a(ba3)a(b)a(ab2)a(a3)a(b)a(a2)a(}t,b,a{x

    u12

    311

    29

    287

    2542

    (21)

    )a(ab3)a(a)a(b3)a(ab2)a(a)a(b2)a(a)a(}t,b,a{y

    u12

    211

    310

    298

    2653

    (22)

    310

    2631 b)a(b)a(b)a()a(}t,b,0{u (23)

    312

    2952 b)a(b)a(b)a()a(}t,b,0{

    x

    u

    (24)

    )a(b3)a(b2)a(}t,b,0{y

    u10

    263

    (25)

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    The displacement vector for element i is

    ynxnnymxmmylxllykxkki uuuu}u{ T (26)

    The displacement vector can be written as

    AB}u{ i (27)

    where

    00b3000b200100

    b00b000b0010

    00b000b00b01

    ab3ab3ab22a0b2a0100

    bba30bab2a30ba2010

    abbababbaabababa1

    0a00a00a0100

    00000a300a2010

    00000a00a0a1

    000000000100

    000000000010

    000000000001

    ]B[

    2

    32

    32

    232

    3222

    33322322

    32

    2

    32

    (28)

    Solve for A .

    i}u{BA 1 (29)

    Let

    1B]c[ (30)

    i}u{cA (31)

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    The strain energy is thus

    i}u{cdxdy)y,x(Scu2

    DU

    b

    0

    a

    0

    TT (32)

    The kinetic energy is

    dxdyu2

    hK

    b

    0

    a

    0

    2

    (33)

    Recall the displacement equation

    Z}A{)t,y,x(u T (34)

    The velocity is

    Z}A{u T (35)

    }A{ZZ}A{]u[ TT2 (36)

    Recall

    i}u{cA (37)

    ii }u{cZZc}u{]u[ TTT2

    (38)

    Let

    TZZ)y,x(P (39)

    ii }u{c)y,x(Pc}u{]u[ TT2

    (40)

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    The kinetic energy is thus

    ii }u{cdxdy)y,x(Pc}u{2

    hK

    b

    0

    a

    0

    TT

    (41)

    The virtual work due to the nodal forces and moment is

    iiii }F{}u{}u{}F{W T (42)

    where

    ynxnnymxmmylxllykxkki MMFMMFMMFMMF}F{ T

    (43)

    Hamiltons principle yields the equation of motion.

    i}F{}u]{k[}u]{m[ ii (44)

    The respective local mass and stiffness matrices are

    ]c[dxdy)y,x(P]c[h]m[ b

    0

    a

    0

    T (45)

    ]c[dxdy)y,x(S]c[D]k[ b

    0

    a

    0

    T (46)

    The local matrices can then be assembled into global matrices. Then boundary conditions can be

    applied.

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    The generalized eigenvalue problem is

    0U}]M[]K[{ 2 (47)

    where

    K is the global stiffness matrix

    M is the global mass matrix

    is the natural frequency

    U is the corresponding mode shape

    Note that there is a natural frequency and mode shape for each degree-of-freedom.

    References

    1. W. Soedel,Vibrations of Shells and Plates, Third Edition (Dekker Mechanical Engineering),Third Edition, Marcel Dekker, New York, 2004.

    2. R. Blevins,Formulas for Natural Frequency and Mode Shape,Krieger, Malabar, Florida,

    1979. See Table 11-6.

    http://www.amazon.com/gp/product/0824756290/ref=as_li_qf_sp_asin_tl?ie=UTF8&tag=vibrationdata-20&link_code=as3&camp=211189&creative=373489&creativeASIN=0824756290http://www.amazon.com/gp/product/0824756290/ref=as_li_qf_sp_asin_tl?ie=UTF8&tag=vibrationdata-20&link_code=as3&camp=211189&creative=373489&creativeASIN=0824756290http://www.amazon.com/gp/product/0824756290/ref=as_li_qf_sp_asin_tl?ie=UTF8&tag=vibrationdata-20&link_code=as3&camp=211189&creative=373489&creativeASIN=0824756290http://www.amazon.com/gp/product/1575241846/ref=as_li_qf_sp_asin_tl?ie=UTF8&tag=vibrationdata-20&link_code=as3&camp=211189&creative=373489&creativeASIN=1575241846http://www.amazon.com/gp/product/1575241846/ref=as_li_qf_sp_asin_tl?ie=UTF8&tag=vibrationdata-20&link_code=as3&camp=211189&creative=373489&creativeASIN=1575241846http://www.amazon.com/gp/product/1575241846/ref=as_li_qf_sp_asin_tl?ie=UTF8&tag=vibrationdata-20&link_code=as3&camp=211189&creative=373489&creativeASIN=1575241846http://www.amazon.com/gp/product/1575241846/ref=as_li_qf_sp_asin_tl?ie=UTF8&tag=vibrationdata-20&link_code=as3&camp=211189&creative=373489&creativeASIN=1575241846http://www.amazon.com/gp/product/0824756290/ref=as_li_qf_sp_asin_tl?ie=UTF8&tag=vibrationdata-20&link_code=as3&camp=211189&creative=373489&creativeASIN=0824756290
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    APPENDIX A

    Mass Matrix Core

    33322322

    3

    3

    3

    2

    2

    3

    2

    2

    Txyyxyxyyxxyxyxyx1

    xy

    yx

    y

    xyyx

    x

    y

    xy

    x

    y

    x

    1

    }Z}{Z{

    (A-1)

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    62446524334542334323

    44264334256332452343

    6436542335432433

    52345423324432233222

    43254233245322342232

    3463324562345343

    5335432234322322

    4224432234322322

    33532234522342232

    423432233222

    324322342232

    33322322

    T

    yxyxxyyxyxyxxyyxyxxyyxxyyxyxyxyxyxyxyxyxyxyxyxyx

    xyyxyxyyxyxyxyyxyxyy

    yxyxxyyxyxyxxyyxyxxyyxxy

    yxyxyxyxyxyxyxyxyxyxyxyx

    yxyxyxyxyxxyxyxxyxxx

    xyyxyxyyxyxyxyyxyxyy

    yxyxxyyxyxyxxyyxyxxyyxxy

    yxyxyxyxyxxyxyxxyxxx

    xyyxyxyyxyxyxyyxyxyy

    yxyxxyyxyxxxyyxxxyxx

    xyyxyxyyxxyxyxyx1

    }Z}{Z{

    (A-2)

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    APPENDIX B

    Stiffness Matrix Core

    Again,

    33322322T xyyxyxyyxxyxyxyx1}Z{ (B-1)

    The derivatives are

    3222T

    yyx30yxy2x30yx2010x

    Z

    (B-2)

    0xy600y2x6002000x

    ZT

    2

    2

    (B-3)

    2322T

    xy3xy3xy2x0y2x0100y

    Z

    (B-4)

    xy60y6x200200000y

    ZT

    2

    2

    (B-5)

    22T

    2

    y3x30y2x20010000yx

    Z

    (B-6)

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    12

    0xy600y2x6002000

    0

    xy6

    0

    0

    y2

    x6

    00

    2

    0

    0

    0

    x

    Z

    x

    ZT

    2

    2

    2

    2

    (B-7)

    000000000000

    0yx3600xy12yx3600xy12000

    000000000000

    000000000000

    0xy1200y4xy1200y40000yx3600xy12x3600x12000

    000000000000

    000000000000

    0xy1200y4x12004000

    000000000000

    000000000000

    000000000000

    x

    Z

    x

    Z

    2222

    22

    22

    T

    2

    2

    2

    2

    (B-8)

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    13

    xy60y6x200200000

    xy6

    0

    y6

    x2

    0

    0

    20

    0

    0

    0

    0

    y

    Z

    y

    ZT

    2

    2

    2

    2

    (B-9)

    2222

    22

    22

    T

    2

    2

    2

    2

    yx360xy36yx1200xy1200000

    000000000000

    xy360y36xy1200y1200000

    yx120xy12x400x400000

    000000000000

    000000000000

    xy120y12x400400000

    000000000000

    000000000000

    000000000000

    000000000000

    000000000000

    y

    Z

    y

    Z

    (B-10)

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    14

    2222

    222222

    22

    22

    22

    T

    2

    2

    2

    2T

    2

    2

    2

    2

    yx360xy36yx1200xy1200000

    0yx3600xy12yx3600xy12000

    xy360y36xy1200y1200000

    yx120xy12x400x400000

    0xy1200y4xy1200y4000

    0yx3600xy12x3600x12000

    xy120y12x400400000

    000000000000

    0xy1200y4x12004000

    000000000000

    000000000000000000000000

    y

    Z

    y

    Z

    x

    Z

    x

    Z

    (B-11)

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    15

    xy60y6x200200000

    0

    xy6

    0

    0

    y2

    x6

    0

    0

    2

    0

    0

    0

    y

    Z

    x

    ZT

    2

    2

    2

    2

    (B-12)

    000000000000

    yx360xy36yx1200xy1200000

    000000000000

    000000000000

    xy120y12xy400y400000

    yx360xy36x1200x1200000

    000000000000

    000000000000

    xy120y12x400400000

    000000000000

    000000000000

    000000000000

    y

    Z

    x

    Z

    2222

    22

    22

    T

    2

    2

    2

    2

    (B-13)

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    0yx3600xy12yx3600xy12000

    yx360xy36yx1200xy1200000

    0xy3600y12xy3600y12000

    0yx1200xy4x1200x4000

    xy120y12xy400y400000

    yx360xy36x1200x1200000

    0xy1200y4x12004000

    000000000000

    xy120y12x400400000

    000000000000

    000000000000000000000000

    x

    Z

    y

    Z

    y

    Z

    x

    Z

    2222

    2222

    22

    22

    22

    22

    T

    2

    2

    2

    2T

    2

    2

    2

    2

    (B-16)

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    18

    22

    2

    2

    T22

    y3x30y2x20010000

    y3

    x3

    0

    y2

    x2

    0

    0

    1

    0

    0

    0

    0

    yx

    Z

    yx

    Z

    (B-17)

    422322

    224232

    322

    232

    22

    T22

    y9yx90y6xy600y30000

    yx9x90yx6x600x30000

    000000000000

    y6yx60y4xy400y20000

    xy6x60xy4x400x20000

    000000000000

    000000000000

    y3x30y2x20010000

    000000000000

    000000000000

    000000000000

    000000000000

    yx

    Z

    yx

    Z

    (B-18)

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    Let 12

    42222222322222

    22224222223222

    2222

    3222222

    2232222

    2222

    22

    T22

    T

    2

    2

    2

    2T

    2

    2

    2

    2T

    2

    2

    2

    2T

    2

    2

    2

    2

    y9yx36yx9yx36xy36y6yx12xy6xy12yx36xy12y3xy12000

    yx9yx36x9yx36xy36yx6yx12x6xy12yx36xy12x3xy12000

    xy36xy36y36xy12y12xy36y120y12000

    y6yx12yx6yx12xy12y4x4xy4xy4x12x4y2x4000

    xy6xy12x6xy12y12xy4xy4x4y4xy12y4x2y4000

    yx36yx36xy36x12xy12x36x120x12000

    xy12xy12y12x4y4x12404000

    y3x30y2x20010000

    xy12xy12y12x4y4x12404000

    000000000000

    000000000000

    000000000000

    yx

    Z

    yx

    Z

    x

    Z

    y

    Z

    y

    Z

    x

    Z

    y

    Z

    y

    Z

    x

    Z

    x

    Z

    (B-19)

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    APPENDIX C

    Example 1

    Consider an aluminum plate, with dimensions 4 x 6 x 0.125 inches. The plate is simply-supported on

    all sides.

    The natural frequencies are

    ,3,2,1n,,3,2,1m,b

    n

    a

    m

    h

    D 22

    (C-1)

    inlbf1789

    )2^3.01(12

    3)^in125.0)(2^in/lbf07e0.1(

    )1(12

    EhD

    2

    3

    (C-2)

    sec^2/in^3lbf05-3.238e

    )in125.0(sec^2/in^4lbf)386/1.0(h

    (C-3)

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    ,3,2,1n,,3,2,1m,in4

    n

    in6

    m

    sec^2/in^3lbf05-3.238e

    inlbf1789 22

    mn

    (C-4)

    Table C-1. Natural Frequencies,Hand Calculation

    fn(Hz) m n

    1054 1 1

    2027 2 1

    3243 1 2

    3649 3 1

    4216 2 2

    Now perform a finite element analysis with 13 nodes along the X-axis and 9 nodes along the Y-axis.

    The analysis is performed using the mass and stiffness matrices derived in the main text, as

    implemented in Matlab script: plate_fea.m

    The fundamental mode shape is shown in Figure C-1. The natural frequency comparison is shown in

    Table C-2.

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    Figure C-1.

    Table C-2. Natural Frequencies

    Mode

    Hand

    Calculationfn(Hz)

    FEAfn(Hz)

    1 1054 1049

    2 2027 2006

    3 3243 3223

    4 3649 3603

    5 4216 4136

    01

    23

    4

    56

    0

    1

    2

    3

    4

    0

    50

    100

    Mode 1 fn= 1049 Hz

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    APPENDIX D

    Example 2

    Repeat example 1 but change the boundary conditions such that the corners are pinned. The edges

    are otherwise free.

    The fundamental frequency is 291 Hz using the hand calculation formula from Reference 2.

    Again, the analysis is performed using the mass and stiffness matrices derived in the main text, as

    implemented in Matlab script: plate_fea.m

    The natural frequency comparison is shown in Table D-1. The mode shapes are shown in the

    following figures.

    Table D-1. Natural Frequencies

    Mode

    Hand

    Calculation

    fn(Hz)

    FEA

    fn(Hz)

    1 291 294

    2 - 708

    3 - 852

    4 - 1110

    5 - 1739

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    Figure D-1.

    Figure D-2.

    0 1

    2 3

    4 5

    6

    0

    1

    2

    3

    4

    0

    20

    40

    60

    80

    100

    Mode 1 fn= 294.2 Hz

    0

    1

    2

    3

    4

    5

    6

    0

    1

    2

    3

    4

    -150

    -100

    -50

    0

    50

    100

    150

    Mode 2 fn= 708 Hz

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    Figure D-3.

    Figure D-4.

    0 1 2

    3 4 5 6

    0

    1

    2

    3

    4

    -80

    -60

    -40

    -20

    0

    20

    40

    60

    80

    Mode 3 fn= 852.3 Hz

    0

    1

    2

    3

    4

    5

    6

    0

    0.5

    1

    1.5

    2

    2.5

    3

    3.5

    4

    -60

    -40

    -20

    0

    20

    40

    60

    80

    100

    Mode 4 fn= 1110 Hz

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    Figure D-5.

    0

    1

    2

    3

    4

    5

    6

    0

    0.5

    1

    1.5

    2

    2.5

    3

    3.5

    4

    -100

    -50

    0

    50

    100

    Mode 5 fn= 1739 Hz