3
Fe 3+ + SCN FeSCN 2+ 3. KSCN = colourless , Fe(NO 3 ) 3 = colourless mixed = brown, red, rusty, etc. , FeSCN 2+ provides the colour 10. 2- Darker brown , (more SCN ) shift right (toward FeSCN 2+ ) 3- Darker brown , (more Fe 3+ ) shift right (toward FeSCN 2+ ) 4- Lighter brown , (less Fe 3+ ) shift left (away from FeSCN 2+ ) 11. None (they are all the same) , Only temperature changes Kc

Fe 3+ + SCN – FeSCN 2+ 3.KSCN = colourless, Fe(NO 3 ) 3 = colourless mixed = brown, red, rusty, etc., FeSCN 2+ provides the colour 10. 2- Darker brown,

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Page 1: Fe 3+ + SCN – FeSCN 2+ 3.KSCN = colourless, Fe(NO 3 ) 3 = colourless mixed = brown, red, rusty, etc., FeSCN 2+ provides the colour 10. 2- Darker brown,

Fe3+ + SCN– FeSCN2+

3. KSCN = colourless, Fe(NO3)3 = colourlessmixed = brown, red, rusty, etc. , FeSCN2+ provides the colour

10. 2- Darker brown , (more SCN–) shift right (toward FeSCN2+)

3- Darker brown , (more Fe3+) shift right (toward FeSCN2+)

4- Lighter brown , (less Fe3+) shift left (away from FeSCN2+)

11. None (they are all the same) , Only temperature changes Kc

Page 2: Fe 3+ + SCN – FeSCN 2+ 3.KSCN = colourless, Fe(NO 3 ) 3 = colourless mixed = brown, red, rusty, etc., FeSCN 2+ provides the colour 10. 2- Darker brown,

Equilibrium LabEquilibrium Lab12 Fe3+ SCN– FeSCN2+ SCN– = None* Fe3+ = Na2HPO4**

Fe3+ = Fe(NO3)3***

*(With SCN–, only a SCN– will reestablish equilibrium. None of these chemicals work. (addition of Na2HPO4 can decrease FeSCN2+ to

its original [ ], but not the others).**Fe3+ has been increased. The only way to

reestablish equilibrium is to decrease Fe3+.***Fe3+ has decreased. The only way to

reestablish equilibrium is to increase Fe3+.

Page 3: Fe 3+ + SCN – FeSCN 2+ 3.KSCN = colourless, Fe(NO 3 ) 3 = colourless mixed = brown, red, rusty, etc., FeSCN 2+ provides the colour 10. 2- Darker brown,

The Haber processThe Haber process• A second application of Le chatelier’s

principle (film = 10 min)

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