Estimation of the spacers’ quantity
If there is no other rule to follow when calculating the spacers of the formwork one could use the empirical rule presented below!
RULES FOR ESTIMATING TE !UANTITTIES OF S"A#ERS AN$ RE%AR #AIRS
Superstructure and foundation beams! "# m of $linear spacers % # $pieces of point support’& in e'ery meter of $clear beam length’
(olumns! ") $pieces of point support’& per column
Shear walls! # m of $linear spacers’ in e'ery meter of the shear wall’s length
*oundation slabs and footings! "+,# m of $linear spacers’& in e'ery square meter of $clear slab area’
Slabs’ free edges! "+ m of $linear spacers’ % +m of $rebar chairs’ % + $piece of point support’& in e'ery edge meter 
Slabs’ supports! + m of $rebar chairs’ per meter of $e'ery slab support’
. 1 m of ‘linear spacers’ might be 1 m of a plastic spacer, or 5 special formed spacers, or any other number of local spacers, etc.
. 1m of ‘rebar chairs’ might be 3 four-legged point spacers, or 1 m of a folded wire mesh, or 2 pieces of impromptu steel rebar chairs, etc.
. 1 ‘piece of point support’ might be a properly formed plastic or concrete point support, or a peg, etc.
Foun&ation
linear spacers with thickness equal to /0 mm!
1//0 2 +00 %00 2 0) %# 2 0+ 2 +003 2 +# 4 ++#0 m
(onnecting beams!
linear spacers of /0 mm! # 2 /#0 2 #00 4 +5)0 m
point spacers of /0 mm! # 2 /#0 2 #00 6+5 pieces
%asement
(olumns! ) 2 / 4 7# pcs, of point support
Shear wall! 750 2 #0 2 # 4 +)00 m of linear spacers with thickness equal to # mm
8eams! "# 2 /#0 %750& 2 #0 4 #/00 m of linear spacers equal to # mm
"# 2 /#0 %750& 2 #0 4 #/ pieces of point spacers equal to # mm
Slab! 790 2 /0 2 +# 6 ##00 m of linear spacers with thickness equal to # mm
Groun& f'oor 
(olumns! ) 2 / 4 7# pcs, of point support
8eams! # 2 /#0 2 #0 4 +5)0 m of linear spacers equal to # mm
# 2 /#0 2 # 6 +5 pieces of point spacers equal to # mm
Slab! 7)0 2 00 2 +# 4 #7)0 m of linear spacers with thickness equal to # mm
Slab’s free edges!
750 2 +00 2 # 4 :#0 m of linear spacers with thickness equal to # mm
750 2 +00 2 # 4 :#0 m rebar chairs with height equal to ++0 mm
 
750 2 +00 2 # 6 ) pieces of point spacers equal to # mm
!uantities sum(   m
;inear spacers of /0 mm! ++#0 %+5)0 4 #)00
;inear spacers of # mm! +)00 % #/00 % ##00 % :#0 %+5)0 % #7)0 6 ++#00
<ebar chairs of ++0 mm!   4 :#0
  pieces
=oint spacers of # mm! 7# % #/ % ) % 7# % #/ 4 +#0
 
« Estimation of the reinforcements> quant ityGround floor ? 8eams »
 
Auant, "B&
;ength ";C'&
@iam, D
  lower 2
) 0,79 /5 +07,+5 0,0 /0,:
+0 0,5+: /9 #+/,#7 0,0 +7#,+
Sum - 9 - 0,0 +:#,)
Groun& f'oor , %eams
Sum - +5 - 0,0 )7,5
Sum - 5# - 0,0 79,7
Auant, "B&
;ength ";C'&
@iam, D
  Stir-rups +,#/ 70 7:,05 )
ESTIMATION OF RE%ARS
+5 +,)0 7# +00,50 0,0 +9,0
Sum - 7# - 0,0 +9,0
Sum - #/0 - 0,0 +7/,5
ESTIMATION OF #ON#RETE -m./
;e'el Superstructure *oundation Sum "m7&
Slabs - 8eams (olumns *ootings
8asement ,/+ 7,) ,+ +/,)
Slabs - 8eams (olumns *ootings
Ground floor 7+,:) +5,00 /:,)
8asement 7,#/ 7#,: #+,:# )9,)
 
D+0 +7#,0) - +):,++ - - - +:,:# 7+9,+9
D+# - - - - :5,+: 5+,+/ +/,5 +7:,70
D+/ - +9#,5 - - - - +9,## +9#,5
D+5 - - 79,0 - - +9:,+: 7:/,)7 9#,#7
Sum of  rebars
#5#,0: +9#,5 )#,+5 - :5,+: #),7+ +7,)7 +7:+,75
Stirrups Slabs 8eams (olumns Slabs *ootings 8eams "m& "gr&
 
D+0 - - - - - )5,7# +/0,00 )5,7#
Sum of  stirrups
- 9#,)9 709,:# - - )5,7# ++50,7/ /)),9#
SUM @@BCD @B HB * DBD JBJ @HBD CB@
Estimation of the concrete’s quantity
Groun& f'oor 
 S+! //0 2 00 2 0+) 4 795
 b+b#! # 2 1"00-# 2 0/0& 2 070 2 07#3 4 0)+
 +#7/ "part of the Qoint area&! / 2 "0/0 2 0/0 2 07#& 4 0#0
otal4 KHD mJ
(olumns
 (+#7/! / 2 "0/0 2 0/0 2 #0& 4 KC mJ
%asement
 S+! //0 2 00 2 0+) 4 795
 b+b#! # 2 1"00-# 2 0/0& 2 0# 2 07#3 4 05:
 b7sw! # 2 1"//0-# 2 0/0& 2 0# 2 07#3 4 0)
 (+#7/ "part of the Qoint area&! / 2 "0/0 2 07#& 4 0#0
otal 4 K mJ
(olumns
 (+#7/! / 2 "0/0 2 0/0 2 #0& 4 +50 m 7
 SR! 750 2 0# 2 #0 4 ##
otal 4 JK mJ
Foun&ation
*ootings *7/!
# 2 "+00 2 +00 2 00& %700 2 0) 2 00 4 ##:
 (8+#!
 
% # 2 "070 2 070 2 070& 4 +75)
 S*! //0 2 +00 2 070 % //0 2 070 2 070 4 +:+5
 (olumns "additional 'olume due to foundation depth equal to
050 m compared to the footings’ depth which is 00m&!
/ 2 "0/0 2 0/0 2 0+0& % 750 2 0# 2 0+0 4 0+/
"# 2 0+0 2 0+0 2 0#0 4 000/&
Sum 4 K mJ
Estimation of the formor>s’ quantity
In constructional works it is common practice to pay the technicians responsible for the form-work implementation based upon the quantity "in m 7& of casted concrete, owe'er the most proper way is to separate those two things therefore the following pages regard the estimation of the required moulds,
Groun& f'oor 
8eams ? Slabs m#   m@
S+! 7)0 2 00 ? / 2 0/0 2 0+0 % # 2 750 2 0+) 4 #0+75
b+b#! # 2 00 2 00 % # 2 "00-# 2 0/0& 2 07# % % # 2 /#0 2 0,70 4 +0#0)
columns "Qoints&! / 2 0/0 2 00 % / 2 0/0 2 07# % / 2 0+0 2 07# 4 +//0
  Tota' 4 JKD
/ 2 "0/0 2 0/0 2 #0& 4 KCCC
%asement
8eams ? Slabs m#   m@
S+! /0 2 790 - / 2 "0+ 2 0+& 4 +:/50
b+b#! # 2 100 2 00 %/#0 2 07#3 % /#0 2 0# 4 9:))
b7! //0 2 00 % 750 2 07# % 750 2 0# 4 /##
sw! //0 2 00 % 750 2 07# 4 77#
internal column sides / 2 # 2 0+ 2 07#& 4 07)/
  Tota' 4 JK@J
 
(olumns! / 2 "0/0 2 0/0 2 #0& ? # 2 "0# 2 #0& 4 +/:0
Shear wall sw! # 2 "750 2 #0& 4 +)000
  Tota' 4 J@KDC
  m@
*ootings *7/! 00 2 100 % # 2 +00 % 070 2 #3 4 )
(b+#! # 2 10:0 20+0 % /70 2 050 % 070 2 0703 # 2 1070 20+0 % 750 2 050 % 070 2 0703
4 +00/
S*/! "7)0 % //0& 2 070 % "750 % //0& 2 070 4 /)5
(olumns! # 2 # 10+0 2 070 %0+0 2 0+03 % %"//0%750 & 2 0+0
4 095
  Tota' 4 @KD
Estimation of the spacers’ quantity
If there is no other rule to follow when calculating the spacers of the formwork one could use the empirical rule presented below!
RULES FOR ESTIMATING TE !UANTITTIES OF S"A#ERS AN$ RE%AR #AIRS
Superstructure and foundation beams! "# m of $linear spacers % # $pieces of point support’& in e'ery meter of $clear beam length’
(olumns! ") $pieces of point support’& per column
Shear walls! # m of $linear spacers’ in e'ery meter of the shear wall’s length
*oundation slabs and footings! "+,# m of $linear spacers’& in e'ery square meter of $clear slab area’
Slabs’ free edges! "+ m of $linear spacers’ % +m of $rebar chairs’ % + $piece of point support’& in e'ery edge meter 
Slabs’ supports! + m of $rebar chairs’ per meter of $e'ery slab support’
. 1 m of ‘linear spacers’ might be 1 m of a plastic spacer, or 5 special formed spacers, or any other number of local spacers, etc.
. 1m of ‘rebar chairs’ might be 3 four-legged point spacers, or 1 m of a folded wire mesh, or 2 pieces of impromptu steel rebar chairs, etc.
 
linear spacers with thickness equal to /0 mm!
1//0 2 +00 %00 2 0) %# 2 0+ 2 +003 2 +# 4 ++#0 m
(onnecting beams!
linear spacers of /0 mm! # 2 /#0 2 #00 4 +5)0 m
point spacers of /0 mm! # 2 /#0 2 #00 6+5 pieces
%asement
(olumns! ) 2 / 4 7# pcs, of point support
Shear wall! 750 2 #0 2 # 4 +)00 m of linear spacers with thickness equal to # mm
8eams! "# 2 /#0 %750& 2 #0 4 #/00 m of linear spacers equal to # mm
"# 2 /#0 %750& 2 #0 4 #/ pieces of point spacers equal to # mm
Slab! 790 2 /0 2 +# 6 ##00 m of linear spacers with thickness equal to # mm
Groun& f'oor 
(olumns! ) 2 / 4 7# pcs, of point support
8eams! # 2 /#0 2 #0 4 +5)0 m of linear spacers equal to # mm
# 2 /#0 2 # 6 +5 pieces of point spacers equal to # mm
Slab! 7)0 2 00 2 +# 4 #7)0 m of linear spacers with thickness equal to # mm
Slab’s free edges!
750 2 +00 2 # 4 :#0 m of linear spacers with thickness equal to # mm
750 2 +00 2 # 4 :#0 m rebar chairs with height equal to ++0 mm
750 2 +00 2 # 6 ) pieces of point spacers equal to # mm
!uantities sum(   m
;inear spacers of /0 mm! ++#0 %+5)0 4 #)00
;inear spacers of # mm! +)00 % #/00 % ##00 % :#0 %+5)0 % #7)0 6 ++#00
<ebar chairs of ++0 mm!   4 :#0
  pieces
=oint spacers of # mm! 7# % #/ % ) % 7# % #/ 4 +#0