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Escape velocity The condition for escape is to have KE > U Far from earth, “g” decreases so U = mgh

Escape velocity The condition for escape is to have KE > U Far from earth, g decreases so U = mgh

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Page 1: Escape velocity The condition for escape is to have KE > U Far from earth, g decreases so U = mgh

Escape velocityThe condition for escape is to have

KE > U

Far from earth, “g” decreases so U = mgh

Page 2: Escape velocity The condition for escape is to have KE > U Far from earth, g decreases so U = mgh

Energy and GravityTo get into orbit and object has to be launched _____ enough.

The speed needed to achieve orbit is called __________ velocity.

The speed needed to outright break free of a planets gravity (a.k.a. “to leave orbit) is called ____________.

You should be able to create formulas for these velocities using Physics formulas we have already learned…..

fast

orbital

Escape velocity

Page 3: Escape velocity The condition for escape is to have KE > U Far from earth, g decreases so U = mgh

Conservative ForcesA force is called “conservative” if ………..

• …..work is independent of path, and depends only on position.

• When it gets back to the same spot, ∆E =0. It does no net work on an object moving around a closed path. Conservative

GravitySpring ForceElectric Force

NonconservativeFrictionTension

Normal ForceAir resistance

Magnetism

Page 4: Escape velocity The condition for escape is to have KE > U Far from earth, g decreases so U = mgh

Conservation of Mechanical Energy

• Energy can not be created or destroyed, it just changes forms.

Page 5: Escape velocity The condition for escape is to have KE > U Far from earth, g decreases so U = mgh

• If this person starts from rest, holding the rope horizontal, swings downward and lets the rope go at the bottom, can we use conservation of energy even though there is tension on him?

• Yes, because T is perpendicular to the direction of motion and does no work.

• If he is 4 m from the surface of the water when he jumps and 0.8 m when he lets go, find vf.

Page 6: Escape velocity The condition for escape is to have KE > U Far from earth, g decreases so U = mgh

• Find vf

• 46.2m/s

Page 7: Escape velocity The condition for escape is to have KE > U Far from earth, g decreases so U = mgh

A 120 kg crate is on a flatbed truck that is moving with a=+1.5m/s2. The crate does not slip as the truck

covers a distance of d = 65m. What is the total work done by all forces acting on the

crate?

Page 8: Escape velocity The condition for escape is to have KE > U Far from earth, g decreases so U = mgh

A 58 kg skier is coasting down a 250 slope. A kinetic frictional force Fk = 70N opposes her motion. Near the top of the slope her speed is vo = 3.6 m/s. Determine her speed vf at a point that is displaces 57m down the hill.

Page 9: Escape velocity The condition for escape is to have KE > U Far from earth, g decreases so U = mgh

1.Since work is force x distance find the ΣF2.How much of it is in the direction of motion?3.Multiply that part of the force by the distance it is applied over.

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