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    PHYSICS SECTION -1

    [STRAIGHT OBJECTIVE TYPE]

    Q.1 to Q.6 has four choices (A), (B), (C), (D) out of which ONLY ONE is correct.

    Q.1 In the diagram shown, a wire carries current I. What is the value of the

    (as in Ampere's law) on the helical loop shown in the figure? The integration

    in done in the sense shown. The loop has N turns and part of helical loop on

    which arrows are drawn is outside the plane of paper.

    (A) 0(NI) (B) 0(I) (C*) 0(NI) (D) Zero

    Q.2 A projectile is thrown with velocity U = 20m/s 5% at an angle 60. If the projectile falls back on

    the ground at the same level then which of following can not be a possible answer for range.

    Consider g = 10m/s2.

    (A*) 39.0 m (B) 37.5 m (C) 34.6 m (D) 32.0 m

    [Sol. R = = 20 = = R = 200 = 2

    20 2 < R < 20 + 31.1m < R < 38.1 m ]

    Q.3 A sports car accelerates from zero to a certain speed in t seconds. How long does it take for it to

    accelerate to twice that speed starting from rest, assuming the power of the engine to be constant

    (independent of velocity) and neglecting any resistance to motion?

    (A) t sec. (B) 2t sec. (C) 3t sec. (D*) 4t sec.

    [Sol. v is doubled t is 4 times ]

    Q.4 A man can swim in still water at a speed of 5 km/hr. He wants to cross a river 6 km wide, flowing at

    the rate of 4 km/hr. If he heads in a direction making an angle of 127 with stream direction, then he

    will reach a point on the other bank

    (A) upstream at a distance of 1.5 km (B*) downstream at a distance of 1.5 km

    (C) directly on the other side of the bank (D) downstream at a distance of 2 km

    Q.5 A conducting sphere of radius R and a concentric thick spherical

    shell of inner radius 2R and outer radius 3R is shown in figure. A

    charge +10Q is given to the shell and inner sphere is earthed. Then

    charge on inner sphere is

    (A*) 4Q (B) 10Q (C) zero (D) none

    Q.6

    Figure shows P vs V curve for various processes performed on an ideal gas. All the processes are

    polytropic (PVm = constant). For 1, m = 1; for 2, m = 0.5; for 3, m = 1; for 4, m = 1.25 and for 5, m

    = .

    (A) Molar heat capacity (C) for process 2, C < Cp

    (B*) Molar heat capacity for process (1) is

    (C) Molar heat capacity for process 5 is C > Cv

    (D) Any polytropic process that lies between 3 & 4 will have positive heat capacity

    I

    g120sin202

  • www.amplitude.edu.in Page - 3

    SECTION-2

    [MULTIPLE OBJECTIVE TYPE]

    Q.7 to Q.12 has four choices (A), (B), (C), (D) out of which ONE OR MORE THAN ONE is/are correct.

    Q.7 There is a fixed positive charge Q at O and A and B are points equidistant from O. A positive charge

    + q is taken slowly by an external agent from A to B along the line AC and then along the line CB.

    (A*) The total work done on the charge is zero

    (B*) The work done by the electrostatic force from A to C is negative

    (C*) The work done by the electrostatic force from C to B is positive

    (D) The work done by electrostatic force in taking the charge from A to B is dependent on the actual

    path followed.

    Q.8 The following figure shows a block of mass m suspended from a fixed point by means of a vertical

    spring. The block is oscillating simple harmonically and carries a charge q. There also exists a

    uniform electric field in the region. Consider four different cases. The electric field is zero, in case-1,

    downward in case-2, upward in case-3 and downward in case-4. The speed at mean position is same

    in all cases. Select the correct alternative(s).

    (A*) Time periods of oscillation are equal in case-1 and case-3

    (B*) Amplitudes of displacement are same in case-2 and case-3

    (C*) The maximum elongation (increment in length from natural length) is maximum in case-4.

    (D*) Time periods of oscillation are equal in case-2 and case-4

    [Sol. (A) Only equilibrium position changes. Time period remains same T = .

    (B) v at mean position is same amplitude will be same.

    (C) In case - 4 Eaquilibrium position x0 = .]

    Q.9 A thin cylindrical metal rod is bent into a ring with a small gap as

    shown in figure. On heating the system

    (A) decreases, r and d increases (B) increases

    (C*) d & r increases (D*) is constant,

    [Sol. d' = d(1+ T) = +ive (coefficient of linear expansion)

    r' = r(1+ T) = +ive (coefficient of linear expansion) ]

    Q

    O

    BA

    C

    m,q

    k

    km

    2

    22 mv2

    1kx

    2

    1

    k

    mg3

  • www.amplitude.edu.in Page - 4

    Q.10 In the diagram shown, a particle of charge +Q and mass M is projected making an angle with the

    vertical line. Draw the possible path on which the charge will move. Above the dark line magnetic

    field is B1 and below it is B2. (Consider all possible cases for values of B1 and B2)

    (A*) (B)

    (C) (D)

    [Sol. Radius R1 =

    In a given field radius should be same for every entry. So B & C are not possible. ]

    Q.11 The springs are identical and initially relaxed. The block is pushed to left and released.

    (A*) The time period of oscillation T = 2

    (B) T = 2

    (C*) If one of the springs is removed, time period increases

    (D) If one of the springs is removed, time period decreases.

    [Sol. keq = k + k = 2k

    T = 2

    If one spring is removed.

    keq = k

    T = 2 T increases.]

    Q.12 The equivalent resistance between the terminal points

    A and B in the network shown in figure is

    (A*) (B)

    (C) (D)

    B1

    B2

    V

    O

    v

    O O

    O

    1qB

    mv

    k km

    k2

    m

    k

    m

    k2

    m

    km

    5

    R7

  • www.amplitude.edu.in Page - 5

    SECTION-3

    [COMPREHENSION TYPE]

    Q.13 to Q.18 are based upon a paragraph. Each question has four choices (A), (B), (C), (D) out of which

    ONLY ONE is correct.

    Paragraph for question nos. 13 to 15

    Experiments with a charged capacitor

    A capacitor and a Pendulum

    We begin with an uncharged, isolated, parallel plate capacitor having its plates maintained at a fixed

    distance apart and with an isolated independent voltage source. By connecting the two plates of the

    uncharged capacitor momentarily to the independent voltage source and then disconnecting the

    source, we are left with a charged and isolated capacitor. A small ball of cork , covered with a

    conducting foil, is suspended by an insulating thread between the two plates of the capacitor as a

    simple pendulum.

    If the ball is initially at rest and is closer to the positive plate, it will be slightly attracted to that plate

    because of induction. On contact with the positive plate, some of the plate's positive charge is

    transferred to the ball by charge sharing. The positively charged ball then is repelled by the positive

    plate and attracted to the negative plate. Upon reaching the negative plate, the kinetic energy of the

    ball is completely converted into thermodynamic internal energy of the negative plate. The positive

    charge on the ball neutralizes some of the negative charge on the negative plate. The ball also then

    becomes negatively charged by charge sharing and subsequently is repelled by the negative plate and

    attracted back to the positive plate.

    The process continues with the electric pendulum swinging back and forth between the two plates

    until essentially all of the charge on the capacitor is neutralized and the capacitor is discharged. We

    imagine positive charge transferred one way, negative charge the other way until the two plates are

    discharged. We observe that the force between the plates decreases with each swing of the

    pendulum, confirming our account of the neutralization or discharge of the two plates. Once

    discharged, the field between them is zero, they do not exert electric force on each other.

    Q.13 During the swinging of the charged ball

    (A*) the current is from left to right

    (B) the current is from right to left

    (C) the current is from left to right during when ball moves to the left and the current is from right to

    left when ball moves to the right

    (D) the current is from right to left during when ball moves to the left and the current is from left to

    right when ball moves to the right.

    Q.14 Consider the moment when the ball leaves the positive plate taking away a charge of 0.01C, leaving

    a charge of 8.85C on the positive plate. The tension in the string, when the ball reaches the lowest

    conducting ball

    Insulating thread

    +|Q| |Q|

  • www.amplitude.edu.in Page - 6

    position for the first time is nearly. (Assume the distance between the plates is 1cm and length of the

    thread is 1m, area of the plates is 1m2 and mass of ball is 1mg).

    (A) 6 105 N (B) 3 105 N (C*) 11 105 N (D) 105 N

    Q.15 If the initial charge on the capacitor plates is 10C, and the capacitance of the capacitor is 10F, the

    total change in thermodynamics internal energy of the left plate is :

    (A) 5J (B*) 2.5J (C) 10J (D) 7.5J

    Paragraph for question nos. 16 to 18

    The accelerations of the three masses A, B and C are a1, a2 and a3 as shown in figure. Friction

    coefficient between all surfaces is 0.5. Pulleys are smooth. (Given mA = 1kg, mB = 1kg, mC = 2kg.)

    Then, give the answer of following questions.

    Q. 16 The value of a1 is :

    (A) (B*) (C) (D) 0

    Q. 17 The value of a2 is :

    (A*) (B) (C) (D) 0

    Q. 18 The value of a3 is :

    (A) (B) (C) (D*) 0

    [Sol.

    Suppose only block (A) and (B) move

    2T = ma

    2mg T = 2m . 2a ----------------------

    3.5mg = 9 ma

    a1 = a = g & a2 = 2a = g

    T = 2mg 2m . = mg < ]

    SECTION-4

    [MATCH THE COLUMN

    C

    B

    A

  • www.amplitude.edu.in Page - 7

    Q.19 In the circuit, both capacitors are identical. Column I indicates action done on capacitor 1 and

    Column II indicates effect on capacitor 2. Select correct alternative.

    Column I Column II

    (A) Plates are moved further apart. (P) Amount of charge on left plate increases

    (B) Area increased (Q) Potential difference increases

    (C) Left plate is earthed (R) Amount of charge on right plate

    decreases

    (D) It's Plates are short circuited (S) None of the above effects

    [Ans. (A) R, (B) P, Q (C) S, (D) P, Q ]

    Q.20 In the following four situations, mass M of 1kg is kept in equilibrium. k = 100 N/m in all cases.

    What speed can be given to mass M vertically so that inextensible string S does not become slack in

    subsequent motion. Consider that pulley is ideal and string is massless :

    Column-I Column-II

    (A) (the block is attached to spring by an inextensible thread) (P) 1 ms1

    (B) (Q) 0.5 ms1

    (C) (1 kg block is attached to the spring) (R) 0.25 ms1

    (D) (S) 2 ms1

    [Ans. (A)-P,Q,R ; (B)-R ; (C)-P,Q,R ; (D)-P,Q,R,S]

  • www.amplitude.edu.in Page - 8

    2x

    0

    54 xxdt)t(ft

    8

    19cotcot

    8

    13tantan

    7

    46coscos

    7

    33sinsin 1111

    9x7x2log 2

    )1xx( 2

    MATHEMATICS SECTION -1

    [STRAIGHT OBJECTIVE TYPE]

    Q.1 to Q.6 has four choices (A), (B), (C), (D) out of which ONLY ONE is correct.

    Q.1 Number of 4 digit numbers of the form N = abcd which satisfy following three conditions

    (i) 4000 N < 6000 (ii) N is a multiple of 5 (iii) 3 b < c 6

    is equal to

    (A) 12 (B) 18 (C*) 24 (D) 48

    [Sol. We have N = abcd

    First place a can be filled in 2 ways i.e. 4, 5 (4000 N < 6000)

    For b and c, total possibilities are '6' (3 b < c 6)

    i.e. 34, 35, 36, 45, 46, 56

    Last place d can be filled in 2 ways i.e. 0, 5 (N is a multiple of 5)

    Hence total numbers = 2 6 2 = 24 Ans.]

    Q.2 Let f : (0, ) R be a continuous function such that F(x) = .

    If F (x2) = x4 + x5, then is equal to

    (A) 216 (B*) 219 (C) 222 (D) 225

    [Sol. We have F(x2) = ....(1)

    On differentiating both the sides w.r.t. x, we get

    2x (x2) f (x2) = 4x3 + 5x4

    f (x2) = 2 + x ....(2)

    = = 24 + = 24 + (15)(13) = 24 + 195 = 219

    Hence = 219 Ans.]

    Q.3 If =

    where a and b are in their lowest form, then (a + b) equals

    (A) 17 (B*) 20 (C) 23 (D) 28

    [Sol. On solving, we get = 13 + 7 = 20 Ans.]

    Q.4 The domain of definition of f(x) = is

    (A) R (B) R {0} (C*) R {0, 1} (D) R {1}

    [Hint: x2 x + 1 1 x 0 or 1]

    x

    0

    dt)t(ft

    12

    1r

    2 )r(f

    b

    a

    12

    1r

    2 )r(f

    12

    1r

    r2

    52

    2

    )13)(12(

    2

    5

    12

    1r

    2 )r(f

  • www.amplitude.edu.in Page - 9

    Q.5 The number of points at which the function f (x) = (x | x |)2 (1 x + | x |)2 is not differentiable

    in the interval ( 3, 4) is (A*) Zero (B) One (C) Two (D) Three

    [Sol. We have f (x) =

    Clearly f(x) is continuous as well as derivable x R.]

    Q.6 Let f (x) is a continuous function which takes positive values for x 0 and satisfy dt = x

    with f (1) = . Then the value of equals

    (A) 1 (B) (C*) (D)

    [Sol. We have = x ....(1)

    Differentiating both the sides of equation (1) w.r.t. x, we get

    f (x) = + ; Let f (x) = y2 f ' (x) = 2y

    y2 = x 2y + y y2 = x + y y2 y = x

    = dy = ; ln = ln cx = cx

    1 = cx = 1 cx y =

    = ....(1)

    If x = 1, f (1) = (given)

    1 c = ; c = 1

    = f (x) = ( ) = Ans. ]

  • www.amplitude.edu.in Page - 10

    SECTION -2

    [MULTIPLE OBJECTIVE TYPE]

    Q.7 to Q.12 has four choices (A), (B), (C), (D) out of which ONE OR MORE THAN ONE is/are correct.

    Q. 7 Let l1 = and l2 = . Then

    (A*) both l1 and l2 are less than

    (B*) one of the two limits is rational and other irrational.

    (C*) l2 > l1

    (D*) l2 is greater than 3 times of l1.

    [Sol. l1 = = 1

    l2 = = = Ans.

    Note: >

    Q. 8 Let f : R R defined by f (x) = cos1 ( { x })

    where {x} is fractional part function. Then which of the following is/are correct?

    (A*) f is many one but not even function. (B*) Range of f contains two prime numbers.

    (C) f is aperiodic. (D*) Graph of f does not lie below xaxis. [Sol. We have f(x) = cos1 ({x}) Df = R

    As 0 {x} < 1 R

    1 < {x}

    So Rf =

    Clearly, f is neither even nor odd.

    But f (x + 1) = f (x) f is periodic with period 1.

    Q.9 The first term of an infinite geometric series is 21. The second term and the sum of the series are

    both positive integers. The possible value(s) of the second term can be

    (A*) 12 (B*) 14 (C*) 18 (D*) 20

    [Sol. Let the series be 21, 21r, 21r2, ........

    Sum = is a positive integer

    also 21r is a positive integer

    S = as 21r N hence 21 21r must be an integer

    also 21r < 21

    hence 21 21r may be equal to 1, 3, 7 or 9 (think!) i.e. must be a divisor of (21)(21)

    hence 21 21r = 1 or 3 or 7 or 9 21r = 20, 18, 14 or 12 Ans.]

    Q. 10 Let xi (i = 1, 2 ..... n) be the roots of the equation xn + 3xn1 + 5xn2 + ..... + 2n+1 = 0 and

    f (x) = ax2 + bx + c = 0 (a, b, c R & a 0) possess + i as a root ( R and 0),

    then is

    (A) always negative if n is odd

    (B*) always positive if n is even

    (C*) may be positive or negative if n is odd

    (D) may be negative or positive if n is even

  • www.amplitude.edu.in Page - 11

    [Sol. Given roots of f (x) are imaginary and hence possible graph of f (x) can be

    f(x) has no real roots D < 0

    f(xi) > 0 or f(xi) < 0 xi

    If n is even then number of terms are even and hence for both the graphs.

    If n is odd then for the (i) graph and for the (ii) graph (C)]

    Q. 11 Let f : A B and g : B C be two functions and gof : A C is defined. Then which of the

    following statement(s) is true?

    (A) If gof is onto then f must be onto.

    (B) If f is into and g is onto then gof must be onto function.

    (C*) If gof is one-one then g is not necessarily one-one.

    (D) If f is injective and g is surjective then gof must be bijective mapping.

    [Sol. (A) We have f : A B,

    g : B C

    and gof : A C

    (A)

    (B)

    (C)

    clearly gof is one-one but g is many one function

    (D)

    As (gof)1 = (f 1og1) ]

    Q. 12 Let f (x) = x + f (t)dt. Then which of the following alternative(s) is/are correct?

    (A) = 2 (B*) f ' = 1

    (C*) f is continuous and derivable on R. (D) maximum value of f(x) does not exist.

    [Sol. We have f(x) = x + x

    Af g

    B C

    Af g

    B C

    AF

    Bg

    C

    Af g

    B C

  • www.amplitude.edu.in Page - 12

    Y

    Y

    X XO

    8 4

    8

    2

    Graph of y = sin 4x

    f(x) = (1 + A) x Bx2 ... (1) where A = and B =

    Now A = = A = 2B ; A = ....(2)

    |||ly B = = B = 2(A + 1) ;

    B = (A+1) ....(3)

    On solving (2) and (3), we get A = , B =

    from equation (1), we get, f(x) = x x2 f '(x) = x

    f ' = = + = = 1. ]

    SECTION-3

    [COMPREHENSION TYPE]

    Q.13 to Q.18 are based upon a paragraph. Each question has four choices (A), (B), (C), (D) out of which

    ONLY ONE is correct.

    Paragraph for question nos. 13 to 15

    Consider f, g and h be three real valued function defined on R.

    Let f (x) = sin 3x + cos x, g (x) = cos 3x + sin x and h (x) = f2(x) + g2(x)

    Q.13 The length of a longest interval in which the function y = h (x) is increasing, is

    (A) (B*) (C) (D)

    Q.14 General solution of the equation h (x) = 4, is

    (A*) (4n + 1) (B) (8n + 1) (C) (2n + 1) (D) (7n + 1) where n I

    Q.15 Number of point(s) where the graphs of the two function, y = f (x) and y = g (x) intersects in [0, ],

    is

    (A) 2 (B) 3 (C*) 4 (D) 5

    [Sol.

    (i)

    We have h(x) = 2 + 2sin 4x

    Clearly h(x) is periodic function with period and from above graph, the length of a longest interval

    in which the function y = h(x) is increasing = = = .

    (ii) We have h (x) = 4

    2 + 2 sin 4x = 4 sin 4x = 1]

    4x = 2n + = (4n + 1) x = (4n + 1) , n I

    (iii) We have f(x) = g(x), so sin 3x + cos x = cos 3x + sin x

    (sin 3x sin x) = (cos 3x cos x)

    2cos 2x sin x = 2sin 2x sin x

  • www.amplitude.edu.in Page - 13

    8

    7,

    8

    5,

    8

    3,

    8

    2sin x [cos 2x + sin 2x] = 0

    Either sin x = 0 or tan 2x = 1

    x = 0, , or 2x = ,

    x = , .

    Hence number of solutions = four (And solutions are x = 0, , , ]

    Alternative

    We have sin 3x + cos x = cos 3x + sinx

    (sin 3x cos 3x)2 = (sin x cos x)2

    sin 6x sin 2x = 0

    2 cos 4x sin 2x = 0

    Either cos 4x = 0 or sin 2x = 0 x = (2n + 1) or x =

    x = 0, , but does not satisfy hence x = 0 or .

    Also x = Only x = and will satisfy]

    Paragraph for question nos. 16 to 18

    Consider a rational function f (x) = and a quadratic function

    g (x) = (1 + m)x2 2(1 + 3m)x 2(1 + m) where m is a parameter.

    Q. 16 Which one of the following statement does not hold good for the rational function f (x)?

    (A) It is a continuous function. (B) It has only one asymptote.

    (C) It has exactly one maxima and one minima. (D*) f (x) is monotonic in (0, )

    Q.17 If , has exactly two distinct real solutions then the integral value of 'k' can be

    (A*) 0 (B) 1 (C) 1 (D) 5

    Q.18 If the range of the function f (x) lies between the roots of g (x) = 0 then the number of integral values

    of m equals

    (A) 7 (B) 8 (C*) 9 (D) 10

    [Sol. f (x) = = 1

    f ' (x) = 8 = 8 =

    f ' (x) = 0 x = 2 or 2

    f (2) = = =

    f (2) = = 5

    Hence range of f (x) is

    the graph of y = f (x) is as shown hence f(x) 5

    0)4y)(4y3(0)y2()4y(

    0y16)4y(4

    0DRx

    0y4x)4y(2yx

    4x2x

    x8yLet

    22

    22

    2

    2

    k)x(fcotcot1

  • www.amplitude.edu.in Page - 14

    (i) obviously f is continuous and has y = 1 as its asymptote with one maxima and one minima

    and f is non monotonic in (0, ) D is incorrect.

    Ans. (D)

    ii) cot (cot1f(x)) = k

    f (x) = k

    y = k and y = f (x)

    hence only y = 0 cuts the graph at two distinct points

    Ans. (A)

    (iii) now g(x) = 0

    x2 x = 0

    or g(x) = x2 x 2 = 0

    as range of f (x) is

    so one root of g (x) is less than and other is greater than 5

    g < 0 and g (5) < 0

    now g = + < 0

    = 1+ < 0

    = < 0

    = < 0

    = < 0

    g (5) < 0

    25 < 0 ; 23 < 0 ; < 0

    < 0 ; > 0

    m {2, 3, 4, 5, 6, 7, 8, 9, 10} ]

    Ans. C

    1/3 5

  • www.amplitude.edu.in Page - 15

    SECTION-4

    [MATCH THE COLUMN]

    "Match the Column" type. Column-I contains Four entries and column-II contains Five entries. Entry of

    column - I are to be matched with one or more than one entries of column - II or vice versa.

    Q.19 Column - I Column-II

    (A) f(x) = sin22x 2sin2x (P) Range contains no natural number

    (B) f(x) = (Q) Range contains atleast one integer

    (C) f(x) = (R) Many one but not even function

    (D) f(x) = tan1 (S) Both many one and even function

    (T) Periodic but not odd function

    [Sol. We have f(x) = sin22x 2sin2x, x R = 4sin2x cos2x 2sin2x = 4sin2x (1 sin2x) 2sin2x = 2sin2x 4sin4x

    = 4 = 4

    f(x) = 4

    Clearly range of 'f' =

    Also f( x) = f(x) So f is even function

    Also f is periodic with period .

    [Ans. (A) P,Q,S,T (B) Q,R (C) P,Q,S (D) P,S ]

    Q. 20 Consider the quadratic trinomial f (x) = 2x2 10px + 7p 1, where p is a parameter. Find the range of p in the following conditions given in column-I.

    Column-I Column-II

    (A) If both roots of f (x) = 0 are confined in ( 1, 1) then (P)

    (B) Exactly one root of f (x) = 0 lies in (1, 1) (Q)

    (C) Both roots of f (x) = 0 are greater than 1 (R)

    (D) One root of f (x) = 0 is greater than 1 and other root of (S)

    f (x) = 0 is less than 1

    (T)

    [Sol. f (x) = 2x2 10px + 7p 1 = 0 (A) f (1) > 0 ; f (1) > 0

    D 0 and 1 < < 1

    f (1) = 2 + 10p + 7p 1 > 0 or 17p > 1 p > ....(i)

    f (1) = 2 10p + 7p 1 > 0 or 1 > 3p p < ....(ii)

    D 0

    100p2 8(7p 1) 0 100p2 56p + 8 0 25p2 14p + 2 0

    which is always true p R ....(iii)

    1 < < 1 2 < 5p < 2 < p < ....(iv)

    )x(sinsin1

    ))x(sin(cosnl

    3x

    1x2

    2

  • www.amplitude.edu.in Page - 16

    (B) f (1) f (1) < 0 (17p + 1) (1 3p) < 0

    (3p 1)(17p + 1) > 0

    if f (1) = 0 then p =

    now if p = , 2x2 x + 1 = 0 6x2 10x + 4 = 0 3x2 5x + 2 = 0

    3x(x 1) 2(x 1) = 0; x = 1 or x = which lies in (1, 1) hence p =

    again if f (1) = 0 then p = ;

    if p = then

    2x2 + x + 1 = 0 34x2 + 10x 24 = 0 17x2 + 5x 12 = 0

    17x2 + 17x 12x 12 = 0 17x(x + 1) 12(x + 1) = 0 (x + 1)(17x 12) = 0

    x = 1; x = which lies in (1, 1)

    hence p or p

    (C) D 0, p R

    f (1) > 0, i.e. p <

    > 1 > 1 p > p

    (D) f (1) < 0

    and f (1) < 0

    p < and p > no solution ]

    [Ans. (A) R; (B) S ; (C) Q ; (D) Q]

  • www.amplitude.edu.in Page - 17

    CHEMISTY SECTION-1

    [STRAIGHT OBJECTIVE TYPE]

    Q.1 to Q.6 has four choices (A), (B), (C), (D) out of which ONLY ONE is correct.

    Q.1 Pick out the correct statement among the following:

    According to Aufbau principle, the maximum number of electrons in

    Statement I : Outermost shell is 2

    Statement II : Outermost shell is 8

    Statement III : Penultimate shell is 18

    Statement IV : Pre-penultimate shell is 32

    (A) I, IV (B) I, II & IV (C*) II, III & IV (D) I, II

    Q.2 An alkene CnH2n is converted by a reduction procedure to CnH2n +2. The % change in the

    molecular weight = 3.57. What is the value of n?

    (A) 2 (B) 3 (C) 4 (D) 5

    Q.3 PhMgBr + 2PhCHO A B

    B is

    (A) Ph2CHOH (B*) Ph3COH (C) PhCH2OH (D) PhO

    Q. 4 Liquid A and B form an ideal solution and the former has stronger intermolecular forces. If XA and

    A are the mole fractions of A in the solution and vapour in equilibrium, then

    (A) = 1 (B) > 1 (C*) < 1 (D) XA + XA = 1

    Q. 5 Which of the following has been arranged in the increasing order of freezing point?

    (A) 0.025 M KNO3 < 0.1 M NH2CSNH2 < 0.05 M BaCl2 < 0.1 M NaCl

    (B*) 0.1 M NaCl < 0.05 M BaCl2 < 0.1 M NH2CSNH2 < 0.025 M KNO3

    (C) 0.1 M NH2CSNH2 < 0.1 M NaCl < 0.05 M BaCl2 < 0.025 M KNO3

    (D) 0.025 M KNO3 < 0.05 M BaCl2 < 0.1 M NaCl < 0.1 M NH2CSNH4

    Q. 6 Octahedral complex of Cr(III) will be

    (A) sp3d

    2 in case of weak field ligand (B) d

    2sp

    3 in case of strong field ligand

    (C*) d2sp

    3 always (D) sp

    3d

    2 always

    OH2

  • www.amplitude.edu.in Page - 18

    SECTION-2

    [MULTIPLE OBJECTIVE TYPE]

    Q.7 to Q.12 has four choices (A), (B), (C), (D) out of which ONE OR MORE THAN ONE is/are correct.

    Q.7 Which of the following complex(s) are having correct name ?

    (A*) K[Pt(NH3)Cl5] Potassium amminepentachloridoplatinate (IV)

    (B*) [Ag(CN)2] Dicyanidoargentate (I) ion

    (C*) K3[Cr(C2O4)3] Potassium trioxalatochromate (III)

    (D) Na2[Ni(EDTA)]Sodium ethylenediaminetetraacetatonickel (II)

    Q.8 In which of the following set has same bond order.

    (A*) N2 , O22+ , NO+ , (B*) O2, N2

    2 , NO

    (C*) NO, N2, O2

    + (D) None of these

    Q.9 Select option(s) in which incorrect major product is shown:

    (A*)

    (B*)

    (C) PhCH = CHMe

    (D*)

    Q. 10 Which of the following is/are not the units of gas constant, R?

    (A*) dynes K1 mol

    1 (B) ergs deg

    1 mol

    1

    (C*) cm3 K

    1 mol

    1 (D) kPa dm

    3 K

    1 mol

    1

    Q. 11 To 10 mL of 1 M BaCl2 solution 5 mL of 0.5 M K2SO4 is added. BaSO4 is precipitated out. What

    will happen?

    (A) Freezing point will increase (B*) Boiling point will increase

    (C*) Freezing point will lower down. (D) Boiling point will lower down

    Q. 12 The following is a graph plotted between the vapour pressure of two volatile liquids against their

    respective mole fractions.

    Which of the following statement is/are correct?

    (A*) When A = 1 and B = 0, then P = (B*) When B = 1 and A = 0, then P = (C) When A = 1 and B = 0, then P < (D) When B = 1 and A = 0, then P >

    OH

    43POH.conc

    OAc

    3

    32

    NEt|

    CHCHCHPh

    4

    2

    CCl

    Br

    Me

    Me

    Br

    Br

    H

    H

  • www.amplitude.edu.in Page - 19

    SECTION-3

    [COMPREHENSION TYPE]

    Q.13 to Q.18 are based upon a paragraph. Each question has four choices (A), (B), (C), (D) out of which

    ONLY ONE is correct.

    Paragraph for question nos. 13 to 15

    Answer the following questions based on given reaction.

    Products.

    Q.13 Total number of theoratically products (including stereo) are

    (A) 4 (B) 6 (C*) 8 (D) 10

    Q.14 How many products are resolvable.

    (A) 2 (B) 4 (C) 5 (D*) 6

    Q.15 How many fractions are present on fractional distillation?

    (A) 4 (B*) 5 (C) 6 (D) 8

    [Sol.4 = 8

    Sol.5 = 6

    Sol.6 = 5 ]

    )nationmonochlori(

    h

    Cl2

    ClCl

    Cl

    Cl

    2 1 41

    Cl

    2

    Cl

    4

    ClCl

    Cl Cl

    Et Et

    Cl

    1 1 1 11

  • www.amplitude.edu.in Page - 20

    Paragraph for question nos. 16 to 18

    The ideal gas equation, PV = nRT is not obeyed by real gases under certain conditions. The deviation

    from ideal behavior was attributed to the fact that Pideal is related to Preal by the equation

    Pideal = Preal +

    In this is a measure of intermolecular interaction between gaseous molecules that gives rise to non-ideal behavior.

    Again the volume correction was introduced by taking in to account the volume occupied by gaseous

    molecules and the effective volume is (V nb), where nb represents the volume occupied by n moles of molecules of real gas.

    Van der Waals equation of real gases is written as (V nb) = nRT

    Q. 16 The ven der Waals equation for real gases will reduce to which one of the following forms under conditions of relatively high pressure?

    (A) PV = RT Pb (B*) PV = RT + Pb (C) PV = RT (D) PV = RT

    Q. 17 If the value of a van der Waals constant for a gas X is greater than that of another gas Y, then (A) strength of van der Waals forces for X is less than that of Y. (B) strength of ven der Waals forces for both X and Y is same. (C*) Gas X can be liquefied easily in comparison to Y (D) Gas Y can be liquefied easily then the gas X

    Q. 18 The van der Waals equation for a gas that has non-zero value of force of attraction between molecules but has the molecules to be point masses, will become

    (A) PV = nRT + nbP (B) P(V nb) (C) PV = nRT (D*) PV = nRT

    SECTION-4

    [MATCH THE COLUMN]

    "Match the Column" type. Column-I contains Four entries and column-II contains FOUR entries. Entry of

    column - I are to be matched with one or more than one entries of column - II or vice versa.

    Q.19 Column I Column II

    (A) B2H6 (P) Can act as Lewis acid.

    (B) BF3 (Q) Intramolecular Lewis acid-base interaction.

    (C) ICl3 (R) Nonpolar.

    (D) SiF4 (S) Nonplanar.

    (T) Can undergo dimerisation.

    [Ans. (A) P, R, S ; (B) P, Q, R ; (C) P, T ; (D) P, Q, R, S ]

    Q. 20 Column I Column II

    (Reactant and product) (Reagents)

    (A) (P) KI + Acetone

    (B) (Q) Zn + CH3COOH

  • www.amplitude.edu.in Page - 21

    (C) (R) EtOK + EtOH

    (D) (S) ONa + OH

    Ans. A-S, B-R, C-R, D-S]