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Engine Measurements Part 1Rating Energy Sources
Force:
Energy:
Work:
Power:
Torque:
Is a Push or Pull against an object (does not need to move)Measured in: Pounds (lbs) or Neutons (N)
Potential, the ability to do Work
Energy put to some useful purpose
Measured in: Foot-Pounds (ftlbs) or Neutons-Meters (NM)Calculation: Force X Distance
Work completed in a given amount of timeCalculation: Force X Distance TimeMeasured in: Foot-Pounds (ftlbs) or Neutons-Meters (NM) sec sec
A twisting and turning force (does not need to move)
Calculation: Force X Distance
Measured in: Foot-Pounds (ftlbs) or Neutons-Meters (NM)
Engine Measurements Part 1!! Calculating POWER !!
Force = 3,000 lbsDistance = 50 ftTime = 10 secPower = ?
Power = Force X Distance Time
Power = 3,000 lbs X 50 ft 10 sec
Power = 15,000 ft lbs 10 sec
Power = 1,500 ftlbs/sec
1 Horse Power = 550 ftlbs/se
Therefore
Power = 1,500 ftlbs/sec 550 ftlbs/sec
Answer = 27.3 HP
50 ft
3,000 lbs10 sec
HP ??
Engine Measurements Part 1
Force = 1.8 NeutonsDistance = 30 metersTime = 1.1 secPower = ?
Power = Force X Distance Time
Power = 1.8 N X 30 M 1.1 sec
Power = 49.1 NM/sec
Answer = 49.1 NM/sec or 49.1 Watts
Power = 54 NM 1.1 sec
1 NM/sec = 1 Watt
F.Y.I. 1 HP = 746 Watts
Answer in Imp = .07 HP
HP = 49.1 NM/sec 746 NM/sec
1.8 Neutons 30Meters
1.1 Sec
Power ?
Engine Measurements Part 1
Force = 8,000 lbsDistance = 50 ftTime = ? secPower = 50 HP
Power = Force X Distance Time
50 HP = 8,000 lbs X 50 ft ? sec
1 Horse Power = 550 ftlbs/se
Answer = 1.5 seconds
50 HP = 40,000 ftlbs ? sec
27,500 ftlbs/sec = 40,000 ftlbs 1 ? sec
27,500 x ? = 40,000 x 1
27,500 x ? = 40,000 27,500 27,500
? = 1.5
50 ft
8,000 lbs
50 HP
Time ??
Engine Measurements Part 1!! Calculating TORQUE !!
Torque = Force X Distance18”
12 lbs
T = 12 lbs X 18 in
Answer: T = 216 inlbs
In ftlbs ?
T = 12 lbs X 1.5 ft
Answer: T = 18 ftlbs
! Big Difference between ft lbs and in lbs !
Engine Measurements Part 1!! Calculating TORQUE !!
“The Big Mistake”
“ Torque = Force X Distance “
Engine Measurements Part 2Piston Displacement
PD = the volume the piston displaces or sweeps out from BDC to TDC.
(How much A/F is drawn in?)
Volume Cylinder =
R X H2
PD = ( Bore/2 )
2X Stroke X # of Cylinders
Engine Measurements Part 2
! Calculating Piston Displacement !
Ex #1 Bore = 75 mm Stroke = 100 mm
PD = (B/2) x S x # cyl2
PD = (75 mm/2) x 100 mm x 12
PD = 44156.3 mm 3
Answer in cm3
1 cm =3
1,000 mm3
Therefore 44156.3 mm 1000 mm
3
3
Answer = 44.15 cm or CC3
1 cm
1 cm
1 cm
1 cm x 1cm x 1cm = 1 cm3
1 cm = 10 mm
Therefore:
10mm x 10mm x 10mm = 1000mm3
More Impressive 50 CC !!
Engine Measurements Part 2
Ex #2 Bore = 3.5 “ Stroke = 4” 8 cyl engine
PD = (B/2) x S x # cyl2
PD = (3.5”/2) x 4” x 82
PD = 307.72 in 3
Answer in CC
1 in =3
16.4 cm3
Therefore : 307.72 in x 16.4 in 33
Answer = 5046.7 cm or 5000 CC3
1 in
1 in
1 in
1 in x 1 in x 1 in = 1 in3
or 307 cuin
1 in = 2.54 cm
2.54cm x 2.54cm x 2.54cm = 16.4 cm3Answer in Liters
1 liter = Therefore:
1000 CC
5000 cc = 5.0 L
! Calculating Piston Displacement !
Engine Measurements Part 2Compression Ratio's
CR = the comparison of the volume at BDC compared to TDC ( how much the air fuel mixture is compressed )
Largest determining factor for amount of power a motor produces The more a A/F mixture is compressed the more Power !!
CR Ratio = Volume at BDCVolume at TDC
PD + Combustion Chamber Displacement Combustion Chamber Displacement
CR = PD + VCC VCC
=
CombustionChamber
Displacement
PistonDisplacement
CombustionChamber
Displacement
Engine Measurements Part 2! Calculating Compression Ratio’s !
Ex #1 PD = 65.6 CC VCC = 8.2 CC
CR =PD + VCC VCC
CR = 65.6 CC + 8.2 CC 8.2 CC
CR = 9 to 1 or 9:1
Engine Measurements Part 2! Calculating Compression Ratio’s !
Ex #2 Bore = 3.5” Stroke = 3.5” 4 cyl VCC = 4.5 cin
CR =PD + VCC VCC
CR =PD + 4.5 cin 4.5 cin
PD = (B/2) x S x # cyl2
PD = (3.5”/2) x 3.5” x 1 cyl2
PD = 33.7 cin
CR =33.7 cin + 4.5 cin 4.5 cin
CR = 8.5 to 1 or 8.5:1
