Electrochemistry One day sir, you may tax it - Michael Faraday,
in response to a question posed about the practical uses of
electricity.
Slide 2
Chapter Overview and Introduction
Slide 3
Chapter Learning Goals Balancing redox reactions (these are fun
). Finding voltages, gibbs free energy and equilibrium constants
for electrolytic and galvanic cells. Relate standard and
non-standard voltages Determining what will and will not undergo
redox reactions And much much more!!!
Slide 4
Real Life Explanation Goals Fuel cells Corrosion Electroplating
If we have time: battery alternatives: bacteria, viruses and other
cool things
Slide 5
Electrochemistry: A Definition Electro chemistry is the
intersection of electrical and chemical energy One species is
reduced, another is oxidized- a transfer of electrons from one (or
more) atoms to another.
Slide 6
Zn(s)+Cu 2+ (aq) Zn 2+ (aq)+ Cu(s) Electrons go from the Zn to
the Cu 2+
Slide 7
Electrochemistry Definitions
Slide 8
Learning Outcomes Define oxidation number, reduction,
oxidation, reducing agent and oxidation agent Identify the
oxidation number for species Identify the species being oxidized
Identify the species being reduced Identify the reducing agent
Identify the oxidation agent Before moving on to harder things,
make sure being able to do these things is automatic!!!!
Slide 9
Definitions Oxidation number: imaginary charge if the compound
was broken down into ions Oxidation number of atom in its elemental
state is zero Oxidation number of a monatomic ion is equal to its
charge Oxidation numbers of individual atoms must add up to the
charge on the whole molecule. Use this to find oxidation states of
ions you dont know, or that may have multiple possibilities. +0
+1
Slide 10
Oxidation state examples: Na 2 CrO 4 MnO 4 - Na= +1 (2)= +2 O=
-2 (4)= -8 -6 Neutral compound so Cr=+6 O= -2 (4)= -8 -8 Charge is
-1, so Mn=+7
Slide 11
Definitions Oxidized : Losing e -, increased charge Reduced :
Gaining e -, lowered charge Oxidizing Agent: Species which oxidizes
other compounds (and is thereby reduced)** Reducing Agent : Species
which reduces other compounds (and is thereby oxidized)** Anode :
Where oxidation takes place Cathode : where reduction takes place
+0 +1 Oxidized Reduced Reducing Agent Oxidizing Agent Anode Cathode
Memory Tricks: LEO the lion goes GER RED CAT / AN OX **Note: The
whole compound is the oxidizing/reducing agent.
Slide 12
Learning outcomes Learn to balance redox reactions in acidic or
basic solutions Using half reaction method Leaving the reactions
together You should know how to do both methods: Leaving reaction
together is always possible, but sometimes more difficult Half
reaction method is sometimes not possible.
Slide 13
Some methods are easier for different situations, be open to
switching ways! Half reaction method : couple of different
algorithms, pick one and stick with it. (I picked the one I think
is easiest for students) Leaving the reaction together: great for
when the species cant be separated. Sometimes its just easier.
there will be one where you HAVE to do this on the exam. Redox
Reactions- Balancing Two main methods
Slide 14
Step 1: write oxidation numbers for every species. Step 2:
identify which is being reduced and which is being oxidized Step 3:
separate into two separate half reactions, do steps 4-7 for each.
Step 4:First balance all elements EXCEPT H and O Step 5: Add H 2 O
to balance oxygen Step 6: Add H + to balance H If its a basic
solution add as many OH - to each side as needed to cancel H + into
H 2 O (can also be done after steps 7, 8, or 9, instead. Do
wherever is most convenient) Step 7: add electrons to balance
charges (oxidation states) Step 8: Look at both half reactions and
multiply each as needed to get the number of electons on both sides
to be equal. Step 9: Combine reactions together. Half method rules:
Use this as a checklist
Slide 15
Examples: Balance the following, identify which species is
oxidized, which is reduced, which is the oxidizing agent and which
is the reducing agent. Basic Acid solution
Slide 16
Balancing without separating Step 1: Write oxidation numbers.
Step 2: Balance all species that ARE NOT H or O Step 3: Identify
which species is being oxidized and which is reduced. Step 4:
Decide how many electrons are transferred in each. Step 5: Multiply
coefficients as needed to get the electrons transferred in the
Red/Ox to be equal Step 6: Balance O by adding water Step 7:
Balance H by adding H If its a basic solution add as many OH - to
each side as needed to cancel H + into H 2 O
Slide 17
Examples: Balance the following, identify which species is
oxidized, which is reduced, which is the oxidizing agent and which
is the reducing agent. Balance keeping it together in an acidic
solution Rebalance using this method in an acidic solution
Slide 18
Extra examples (podcasted) Cinnabar/vermillion Both Acidic and
Basic
Slide 19
Review Balancing redox reactions require that you account for
the exchange of electrons as well. You must have the same number of
electrons being transferred from one reaction to the other. Learn
at minimum the method for leaving reactions together. The half
reaction method is often very useful though too!
Slide 20
Introduction to electrochemical cells
Slide 21
Learning Outcomes Identify the components of a galvanic cell
Identify the components of a cell. Determining which reaction
happens in which part will be covered in the next section. Define
the difference between a galvanic and electrolytic cell.
Slide 22
Electrochemical cells Galvanic cell: an electrochemical cell
where a spontaneous chemical reaction is used to generate an
electric current Electrolytic cell: an electrochemical cell where a
non-spontaneous chemical reaction is occurring due to a supplied
electrical source. Anode Cathode Oxidation occurs at the Anode
Reduction occurs at the Cathode Memory trick: Red Cat An Ox
Slide 23
Galvanic cells: Questions Where is metal deposited? Copper
Which direction do the electrons flow? Anode to cathode Why must we
separate the reactions? In order to have the electrons do work Why
is the salt bridge necessary? Allow flow of anions and cations
Anode Cathode
Slide 24
Review Galvanic cells separate reactions. This allows the
electrons to flow from one area to the other doing work. You should
be able to identify the anode and cathode given the reactions But
how would we know which is which if not given the reactions
occurring? How do we know how much voltage we can get?
Slide 25
Cell Voltage.
Slide 26
Learning Outcomes Define EMF (electromotive force) or voltage
Identify the standard hydrogen electrode and how it is used as a
standard. Use table of values and half reactions to calculate the
EMF of a cell. Use the cell voltage to decide if a cell is
spontaneous or not.
Slide 27
Electromotive (EM) force Not really a force it is a voltage
Synonymous with cell voltage Listed values are E o red aka
reduction voltages E o red = - E o oxid These are standard values,
1atm or 1M
Slide 28
Electromotive (EM) force Listed values are E o red aka
reduction voltages E o red = - E o oxid EMF of a cell is the
difference in potential energy between the anode and cathode.
Slide 29
Standard Hydrogen Electrode We need a voltage to compare
everything too. The H 2 half reaction cell was chosen. Why do we
have a Pt electrode? Need an inert metal to conduct electrons
Standard potentials are calculated against the standard hydrogen
electrode!
Slide 30
Standard Hydrogen Electrode Why do we have a Pt electrode? Need
an inert metal to conduct electrons Standard potentials are
calculated against the standard hydrogen electrode!
Slide 31
Calculating Cell Voltage Two equivalent ways. Pick your
favorite and stick with it. Be very careful not to interchange
them!!! Why are these equivalent? Method 1: Method 2: E o red = - E
o oxid positive E o cell is a spontaneous reaction (galvanic cell)
negative E o cell is a non-spontaneous reaction (electrolytic
cell)
Slide 32
Calculating Cell Voltage Which is Anode/Cathode How do we
decide? spontaneous: E o cell = positive non-spontaneous: E o cell
=negative When reversing the sign of the anode (oxidation), they
must add to be positive. Copper=cathode Zinc= anode E o cu2+/Cu =
+0.34V E o Zn2+/Zn = -0.44V Calculate the cell voltage for a
spontaneous Zn/Zn 2+, Cu/Cu 2+ cell.
Slide 33
Calculating Cell Voltage: Calculate the cell voltage for a
spontaneous Zn/Zn 2+, Cu/Cu 2+ cell Logic 1: Logic 2: E o cell =E o
red_Cu2+/Cu - E o red_Zn E o cell =E o red_Cu2+/Cu + E o
oxidation_Zn E o cell =(+0.34V) - (-0.44V)= +.078 V E o cell
=(+0.34V)+(+0.44)= +0.78V
Slide 34
A typical alkaline battery has the following half reactions,
identify the cathode and anode and write the complete reaction and
find E 0. E 0 red = -1.28V E 0 red = 0.15V One needs to be
oxidized, when added together E red and E oxid need to add to be
positive Reverse so ZnO (aka Zn 2+ ) needs to be oxidized and is
therefore it is the anode E 0 ox = +1.28VE 0 red = 0.15V E 0 cell =
0.15V-(-1.28)= 1.43V Logic 1: Logic 2: E 0 red anode = -1.28V E 0
red cathode = 0.15V E 0 cell = 0.15V+(+1.28)= 1.43V Example:
Calculating Cell Voltage
Slide 35
Review Cell Voltages are calculated as the difference in
potential energy between the anode and cathode. (Pick your favorite
way of thinking about it, and stick with that) A spontaneous cell
will have a positive E o cell, while a non- spontaneous cell will
have a negative E o cell.
Slide 36
Electrochemistry:What will react? By looking at the table,
which species will react with each other.
Slide 37
Learning Outcomes Use what we already know to determine how you
can tell what species will readily react spontaneously by looking
at the table of E o red values.
Slide 38
Diagonal rule: Species on left reacts with any species on the
right that is lower than it. Diagonal Rule Why? Easily reduced
Easily oxidized
Slide 39
Example: Lets take 5 reactions Draw arrows next to the table
excerpt identifying the most likely substances to be reduced or
oxidized, and the best oxidizing and reducing agents. Give one
spontaneous combinations, and one non-spontaneous reactions, using
the above reactions (lots of available options). Easily reduced
Easily oxidized
Slide 40
Review On a standard reduction table with the highest reduction
values listed on top, species on the left will react with species
on the right of a reaction that is lower than it. This is because
species that are easily reduced make good oxidizing agents.
Slide 41
Cell Notation
Slide 42
Learning Outcomes Write the cell notation for a given cell.
Given the cell notation, write the half reactions.
Slide 43
Cell Diagram/Notation Single line denote phase change Double
line denote salt bridge Start with Anode on far left, work forward
in order youd encounter it
Slide 44
Cell Diagram Examples Write the cell diagram for a cell
consisting of Zn 2+ /Zn and Pt/H + /H 2 Anode Cathode
Slide 45
Review Example Combining everything weve learned.
Slide 46
Zinc/Tin Cell Example The standard reduction potential of a
zinc electrode is -0.76 V. Given that the standard potential of the
cell where Zn is oxidized and Sn 4+ is reduced to Sn 2+ is +0.91V
find the standard potential of the Sn 4+ /Sn 2+ half reaction and
write the cell diagram.
Slide 47
Electrochemistry and Thermodynamics
Slide 48
Learning Outcomes Using thermodynamic data (gibbs free energy
or enthalpy and entropy) calculate the E o cell. Calculate the
Gibbs free energy of a cell using E o cell. Calculate the
equilibrium constant from E o cell. Calculate E o cell from the
equilibrium constant.
Slide 49
Thermodynamics: Gibbs Free Energy We can use this to find the
Gibbs free energy of a reaction if we can measure/find E cell (or
of course vice versa) n= number of molesF=faradays constant= 96,500
J/(V*mol)
Slide 50
Example Calculate the standard free-energy change for the
following reaction at 25 o C using standard reduction
potentials.
Slide 51
Thermodynamics: Gibbs Free Energy What else does G equal? How
can we use this to relate K and G? Set them equal to each other.
Cleaning the equation up a bit:
Slide 52
Thermodynamics G and K Now put all the constants on one side
Filling in constants and solving
Slide 53
Example- Relating E and K; Calculate the pressure of H 2 in
atm, required to maintain equilibrium with respect to the following
reaction at 25 o C, Given that [Pb 2+ ]=0.035 and the solution is
buffered at pH 1.6
Slide 54
Nernst Equation Think way back to thermodynamics in Chem1B, how
did we relate G and G 0 ? But using the relation between G and E..
Rearranging OR NOTE: The difference between E and E o or G and G o
is that the o symbolizes standard state
Slide 55
Example Calculate the reaction quotient Q for the cell
reaction, given the measured values of the cell potential.
Slide 56
Review We can relate between E, G and K by using one of the
three equations we introduced in this section. For non standard
conditions, use the Nernst equation.
Slide 57
Applications of electrochemical cells.
Slide 58
Learning Outcomes Introduction to two types of batteries that
are commonly used. Specifics of these will not be tested. I.e.,
dont memorize the reactions. Identify anode and cathode of
batteries given the reactions that are occurring. Introduction to
fuel cells. Identify the anode and the cathode of a given fuel
cell
Slide 59
Dry Cell and Alkaline Batteries Dry Cell: Originally developed
Problems with corrosion and unstable current and voltage lead to
the development of the alkaline dry cell Used in a variety of
applications, but are not reachargable, limiting their utility in
many others Alkaline dry cells replace NH 4 Cl with NaOH or KOH Dry
Cell Anode Cathode
Slide 60
Lead Storage Batteries: Discharged Charged Anode Cathode
Overall i.e car battery Grids provide large surface area, low
specific energy- allows high current for short periods
Slide 61
Batteries Primary cells: non-rechargable Secondary cells:
rechargeable Specific energy: energy that can be generated divided
by mass Dry cell and alkaline batteries Lead acid cell: car battery
Grids provide large surface area, low specific energy- allows high
current for short periods
Slide 62
Fuel Cells Runs similarly to a battery However, reactants are
supplied continuously and only products are H 2 O Leads to less
waste and less weight Originally used space applications, now
provides backup power to many industrial applications, as well as
fuel cell cars.
Slide 63
Review, Recap and Note There are many many types of batteries.
Ive shown you two variations. Batteries can be tweaked to provide
more voltage, more current or various other desired outcomes.
Suggestion, look up some emerging research on batteries that
interest you and see if you can pick out how the reactions work,
and are similar or different to the ones we talked about.
Slide 64
Electrolytic Cells Review and Applications
Slide 65
Learning Outcomes Review the difference between an electrolytic
and galvanic cell. Determine the products at the anode and cathode
of an electrolytic cell.
Slide 66
Electrolytic cells: Reminder A cell that requires an outside
source of power. i.e. a non spontaneous cell. These can be
separated, like in previous cells, but can also be located in one
container. Power must be supplied!
Slide 67
More about electrolytic cells Anode and Cathode are often in
the same container and often only contain one electrolyte.
Reduction still occurs at cathode and oxidation still occurs at the
anode. Many uses, electrolysis, electroplating, ore purification,
ect
Slide 68
More about electrolytic cells Reminder: E, G, K are all
calculated the same. Non-spontaneous so E is negative. Applications
are the new: interesting part!
Slide 69
Electroplating Anode Cathode
Slide 70
Electroplating Example How many grams of aluminum can be
deposited by the passage of 105 C through an electrolytic cell? How
long does it take to deposit 0.63 g Ni on a decorative drawer
handle when 8.7 A are passed through a Ni(NO 3 ) 2 solution Use
dimensional analysis. Important things to know: 1 C= 1 amp*sec
F=9.6485x10 4 C/mol
Slide 71
Corrosion How can we stop this? Give the O 2 something else to
react with!!!! Fe 3+ precipitates out as Fe 2 O 3 H 2 O
Slide 72
Stopping Corrosion: Galvanizing Galvanizing: Put a Zinc coating
on it. Zinc is more reactive, it becomes the anode, Aka gets
oxidized instead of the Iron Zinc is sacrificial metal Boats, wire,
roofing, anything where you need to stop corrosion. E o Zn2+/Zn =
-0.76 E o Fe2+/Fe = -0.44 E o Fe3+/Fe2+ = +0.77
Slide 73
Review Electrolytic cells are much like galvanic cells only
because they are non-spontaneous, they must have a power source.
The E o is negative. Electrolytic cells are used for applications
such as galvanizing or electroplating metals.
Slide 74
Many important biological reactions involve electron transfer.
Because the pH of bodily fluids is close to 7,the biological
standard potential of an electrode E, E*, is measured at pH=7. a)
Calculate the biological standard potential for the reducion of
hydrogen ions to hydrogen gas, and the reduction of nitrate ions to
NO gas. Calculate the biological standard potential E* for the
reduction of the biomolecule NAD+ to NADH in aqueous solution. The
reduction half reaction under thermodynamic standard conditions is
NAD + (aq)+H + (aq)+2e - NADH (aq), with E o = -0.099V. The
pyruvate ion, CH 3 C(=O)CO 2 -, is formed during the metabolism of
glucose in the body. The ion has a chain of three carbon atoms. The
central carbon atom has a double bond to a terminal oxygen atom and
one of the end carbon atoms is bonded to two oxygen atoms in a
carboxylate group. Draw the Lewis structure of the pyruvate ion and
assign a hybridization scheme to each carbon atom. The lactate ion
has a similar structure to the pyruvate ion, except that the
central carbon is no attached to an OH group: CH 3 CH(OH)CO 2 -.
Draw the Lewis structure of the lactate ion and assign a
hybrization scheme to the central carbon atom. During exercise the
pyruvate ion is converted to lactate ion in the body by coupling to
the half reaction for NADH given above. For the half reaction
pyruvate+2H + +2e - lactate, E*=-0.190 V. Write the cell reaction
for the spontaneous reaction that occurs between these two
biological couples and calculate E* and E o for the overall
reaction. Calculate the standard Gibbs free energy of reaction for
the overall reactions in the above reaction. Calculate the
equilibrium constant at 25 o C for the reaction. Long electrochem
problem (done on podcast)