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Do Now Pass out the calcs.. Work on Practice EOC Week # 13 Block 4 ONLY: Pick up a homework answer key from the back table and correct your homework. Do yo thang...

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Do Now. Pass out the calcs .. Work on Practice EOC Week # 13 Block 4 ONLY: Pick up a homework answer key from the back table and correct your homework. Do yo thang. Do Now. Pass out the calcs .. Pick a homework answer from the table and correct your homework form last night. - PowerPoint PPT Presentation

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Page 1: Do Now

Do Now

• Pass out the calcs..• Work on Practice EOC Week # 13 • Block 4 ONLY: Pick up a homework answer key

from the back table and correct your homework.

• Do yo thang...

Page 2: Do Now

Do Now

• Pass out the calcs..• Pick a homework answer from the table and

correct your homework form last night. • Solve the following problem by completing the

square. 4y2 + 4y - 7 = 0

• Do yo thing...

Answer: -1.91, 0.91

Page 3: Do Now

Do Now• Pass out the calcs..• Hand your advertisement activity into the tray.• Work out the following TCAP question on a sheet of notebook paper.

Write an explanation next to EACH answer as to why or not you chose that answer.

Page 4: Do Now

Objective:

• So solve quadratic equations using the

QUADRATIC FORMULA!

Page 5: Do Now

Quadratic Formula

• To use this formula your equation must be in this form… ax2 + bx + c

Page 6: Do Now

Quadratic Formula

Page 7: Do Now

The FUN song…

• http://spongebob.nick.com/videos/clip/promo-spongebash-fun-song.html

Page 8: Do Now

EXAMPLE 1 Standardized Test Practice

What are the solutions of 3x2 + 5x = 8?

–1 and – A 83

B –1 and 83 C 1 and – 8

3 D 1 and 83

SOLUTION

Write original equation.3x2 + 5x = 8

Write in standard form.3x2 + 5x – 8 = 0

Quadratic formula ±x = –b b2 – 4ac2a

Page 9: Do Now

EXAMPLE 1 Standardized Test Practice

Substitute values in the

quadratic formula: a = 3, b = 5,

and c = –8.

Simplify.= –5± 1216

Simplify the square root.= –5 ± 116

The solutions of the equation are –5 + 116 = 1 and

–5 – 116

= – 83

The correct answer is C. ANSWER

x = –5 ± 52 – 4(3)(–8)

2(3)

Page 10: Do Now

EXAMPLE 2 Solve a quadratic equation

2x2 – 7 = x

2x2 – x – 7 = 0

Solve 2x2 – 7 = x.

Write original equation.

Write in standard form.

Quadratic formulax =

b2 – 4ac+ ––b2a

Substitute values in the quadratic formula: a = 2, b = –1, and c = –7.

Simplify.

– (–1) –+ ( –1)2 – 4(2)(–7)

2(2)=

4=+ –1 57

Page 11: Do Now

EXAMPLE 2 Solve a quadratic equation

Write the equation in standard form, 2x2 – x – 7 = 0. Then graph the related function y = 2x2 – x – 7. The x-intercepts are about –1.6 and 2.1. So, each solution checks.

ANSWER

1 + 57 2.14 and 1 – 4

–1.64.4

The solutions are

CHECK

57

Page 12: Do Now

GUIDED PRACTICE for Examples 1and 2

Solve the equation by Quadratic Formula.

1. x2 – 8x + 16 = 0

ANSWER 4

2. 3n2 – 5n = –1

ANSWER 0.23, 1.43

3. 4z2 = 7z + 2

ANSWER 0.25, 2

Page 13: Do Now

EXAMPLE 3 Use the quadratic formula

y = 10x2 – 94x + 3900

4200 = 10x2 – 94x – 3900

0 = 10x2 – 94x – 300

Write function.

Substitute 4200 for y.

Write in standard form.

SOLUTION

For the period 1971 2001, the number y of films produced in the world can be modeled by the function y = 10x2 94x + 3900 where x is the number of years since 1971. In what year were 4200 films produced?

FILM PRODUCTION

Page 14: Do Now

EXAMPLE 3 Use the quadratic formula

Substitute values in the quadratic formula: a = 10, b = –94, and c = –300.

20,83694 + –20

= Simplify.

The solutions of the equation are:

ANSWER There were 4200 films produced about 12 years after 1971, or in 1983.

x = (–94)2 – 4 (10)(–300)–(–94)

+ –2(10)

94 + 20,836

2012 94 – 20,836

20–3.and

Page 15: Do Now

Methods for Solving the Quadratic Formula…

• Pg. 673

Page 16: Do Now

EXAMPLE 4 Choose a solution method

Tell what method you would use to solve the quadraticequation. Explain your choice(s).

a. 10x2 – 7 = 0

SOLUTION

a. The quadratic equation can be solved using square roots because the equation can be written in the form x2 = d.

Page 17: Do Now

Choose a solution methodEXAMPLE 4

b. The equation can be solved by factoring because the expression x2 + 4x can be factored easily. Also, the equation can be solved by completing the square because the equation is of the form ax2 + bx + c = 0 where a = 1 and b is an even number.

Tell what method you would use to solve the quadraticequation. Explain your choice(s).

b. x2 + 4x = 0

SOLUTION

Page 18: Do Now

Choose a solution methodEXAMPLE 4

c. The quadratic equation cannot be factored easily, and completing the square will result in many fractions. So, the equation can be solved using the quadratic formula.

Tell what method you would use to solve the quadraticequation. Explain your choice(s).

c. 5x2 + 9x – 4 = 0

SOLUTION

Page 19: Do Now

GUIDED PRACTICE for Example 4

Tell what method you would use to solve the quadraticequation. Explain your choice(s).

SOLUTION

Factoring because the expression factors easily.

5. x2 + x – 6 = 0

Page 20: Do Now

GUIDED PRACTICE for Example 4

Tell what method you would use to solve the quadraticequation. Explain your choice(s).

SOLUTION

Factoring because the expression factors easily. Using square roots is another option since the equation can be written in the form x2 = d.

6. x2 – 9 = 0

Page 21: Do Now

GUIDED PRACTICE for Example 4

Tell what method you would use to solve the quadraticequation. Explain your choice(s).

SOLUTION

Completing the square because the equation is of the form ax2 + bx = c where a = 1 and b is an even number. Another method is the quadratic formula since the equation does not factor easily.

7. x2 + 6x = 5

Page 22: Do Now

Exit Ticket:

What are the solutions to the following equations? 1.2x2 + 7x = 9 2.3x2 – 1 = x

How can you choose which method to you use finding the roots to an equation?