Dispatch

DispatchSimplify1. b ( 4b – 1) + 10b

2. x ( 3x – 5 ) + 7 ( x2 – 2x + 9)

3. (4a2b3c2)3

10x2 – 19x + 63

64a6b9c6

4b2 + 9b

Multiplying Polynomials

Objective: We will be able to multiply polynomials using the Distributive Property, FOIL Method, and Magic Box Method.

Standard: 10.0

Concept Task

(x + 3)(x + 2)

x2 + 5x + 6

(8d + 3)(5d + 2)40d2 + 31d + 6

GP (x + 3)(x + 2)

(x + 3)(x + 2) = x(x)

x2 + 2x + 3x + 6

x2 + 5x + 6

Step 1: DP

Step 2: CLT

+ x(2) + 3(x) + 3(2)

DISTRIBUTIVE PROPERTY

LETS REVIEW SOME VOCABULARY

(x + 3)(x + 2)

x2 + 5x + 6

Quadratic Term

Linear Term

Constant Term

Coefficient

YT

(2m + 2)(3m – 3)

(y – 2)(y + 8)

4h2 + 33h + 35

y2 + 6y - 16

6m2 – 6

The length of a rectangle is 4h + 5 and width h + 7. What is the area?

(4h – 2)(4h – 1)

GP (y + 4)(y – 3)

(y + 4)(y – 3)

F: First TermO: Outer TermI: Inner TermL: Last Term

F(y)(y)

O(y)(-3)

I(4)(y)

L(4)(-3)

y2 -3y + 4y - 12

y2 + y - 12

FOIL METHOD

GP (7x – 4)(5x – 1)

(7x – 4)(5x – 1)


F(7x)(5x)

O(7x)(-1)

I(-4)(5x)

L(-4)(-1)

35x2 – 7x -20x + 4

35x2 -27x + 4

FOIL METHOD

YT (2w – 5)(w + 7)

(5m – 6)(5m – 6)

25m2 – 60m + 36

2w2 + 9w – 35


MAGIC BOX METHOD

(p – 4)(p + 2)GP

p – 4

p

+2

-4pp2

2p -8p2 – 2p – 8

X

MAGIC BOX METHOD

(5a – 2)(2a – 3)GP

5a – 2

2a

– 3

-4a10a2

– 15p 610a2 – 19p + 6

X

YT (3c + 1)(c – 2)

(d – 1)(5d – 4)

(4c + 1)(2c + 1)

MAGIC BOX METHOD

GP

3c + 1

c

– 2

c3c2

-6c -23c2 – 5c – 2

(3c + 1)(c – 2)

X

MAGIC BOX METHOD

GP

d – 1

5d

– 4

–5d 5d2

-4d 45d2 – 9d + 4

(d – 1)(5d – 4)

X

MAGIC BOX METHOD

GP

4c + 1

2c

+1

2c 8c2

4c 18c2 + 6c + 1

(4c + 1)(2c + 1)

X

Daily Practice

Study Guide Intervention WorksheetPg. 97 1-18 EVEN

REMINDER: QUIZ TOMORROW PERIOD 1 1/18/13

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What if we have…..

(p + 4)(p2 + 2p – 7)

(p3) + (2p2) (-7p) (4p2) (8p) (-28)

p3 + 6p2 + p – 28

p( p2 + 2p – 7) + 4(p2 + 2p – 7)

YT (2w – 5)(w + 7)

(5m – 6)(5m – 6)

100r2 – 16

25m2 – 60m + 36

2w2 + 9w – 35


The length of a rectangle is 10r – 4. The width is 10r + 4. What is the Area of the Rectangle?

1. A2. B3. C4. D

A. x2 + x – 6

B. x2 – x – 6

C. x2 + x + 6

D. x2 + x + 5

A. Find (x + 2)(x – 3).

1. A2. B3. C4. D

A. 5x2 – 8x + 30

B. 6x2 + 28x – 1

C. 6x2 – 8x – 30

D. 6x – 30

B. Find (3x + 5)(2x – 6).

DispatchSimplify1. Subtract (6p3 + 3p2 – 7p) from (p3 – 6p2 – 2p)

2.

Area= 2x2 + 3x – 20

-5p3 – 9p2 + 5p

PA #3 Problems

x + 4

2x – 5Write an expression to represent the area of the rectangle

GP (c – 9)(c + 3)

(c – 9)(c + 3)


F(c)(c)

O(c)(3)

I(-9)(c)

L(-9)(3)

c2 +3c -9c -27

c2 – 6c – 27

LETS REVIEW

(2x – 5)(3x2 – 4x + 1)

6x3 – 23x2 + 22x – 5

2x( 3x2 – 4x + 1) -5(3x2 – 4x + 1)

YT

(3k + 4)(7k2 + 2k – 9)3k( 7k2 + 2k – 9) + 4(7k2 + 2k – 9)

21k3 – 34k2 – 19k – 36

(n2 – 3n + 2 )(n2 + 5n – 4)

n4 + 2n3 – 17n2 + 22n – 8

n2(n2 + 5n – 4) – 3n(n2 + 5n – 4) + 2(n2 + 5n – 4)

YT

(y2 + 7y – 1)(y2 – 6y + 5)

y2(y2 – 6y + 5) + 7y(y2 – 6y + 5) – 1(y2 – 6y + 5)

y4 + y3 – 38y2 + 41y – 5

Daily Practice

Study Guide Intervention WorksheetPg. 98 1-14

GP The length of a rectangle is 8d + 3. The width is 5d + 2. What is the Area of the Rectangle?

(8d + 3)(5d + 2)F: First TermO: Outer TermI: Inner TermL: Last Term

F(8d)(5d)

O(8d)(2)

I(3)(5d)

L(3)(2)

40d2 + 16d +15d + 6

40d2 + 31d + 6

FOIL METHOD

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