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July 2014 DocID025436 Rev 1 1/16 16 AN4381 Application note Current sharing in parallel diodes Introduction The use of diodes in parallel is commonly found in power electronic design. An important consideration for this practice is the current sharing between diodes due to the difference of electrical characteristics. This application note highlights the cause of the behavior of several diodes are connected in parallel. Some recommendations will be given to help the designer to produce a safe design. An electro-thermal model is described which simulates the current and junction temperature of each diode for given application conditions. This tool is illustrated using an example. www.st.com

Current sharing in parallel diodes - STMicroelectronics · Current sharing AN4381 6/16 DocID025436 Rev 1 Equation 11 VF1(IF1,Tj1) = VF2(IF2,Tj2) = … = VFn(IFn,Tjn) Tj2 = … = Tjn

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Page 1: Current sharing in parallel diodes - STMicroelectronics · Current sharing AN4381 6/16 DocID025436 Rev 1 Equation 11 VF1(IF1,Tj1) = VF2(IF2,Tj2) = … = VFn(IFn,Tjn) Tj2 = … = Tjn

July 2014 DocID025436 Rev 1 1/16

16

AN4381Application note

Current sharing in parallel diodes

IntroductionThe use of diodes in parallel is commonly found in power electronic design. An important consideration for this practice is the current sharing between diodes due to the difference of electrical characteristics. This application note highlights the cause of the behavior of several diodes are connected in parallel. Some recommendations will be given to help the designer to produce a safe design. An electro-thermal model is described which simulates the current and junction temperature of each diode for given application conditions. This tool is illustrated using an example.

www.st.com

Page 2: Current sharing in parallel diodes - STMicroelectronics · Current sharing AN4381 6/16 DocID025436 Rev 1 Equation 11 VF1(IF1,Tj1) = VF2(IF2,Tj2) = … = VFn(IFn,Tjn) Tj2 = … = Tjn

Contents AN4381

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Contents

1 Current sharing . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 3

1.1 The basics . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 3

1.2 Thermal effects . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 4

1.2.1 Thermal effects due to the negative temperature coefficient of VF . . . . . . . 4

1.2.2 Thermal effects due to the dependency of ⍺ VF versus VF . . . . . . . . . . . . . . . 5

1.3 Worst case configuration . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 5

1.4 VF and QRR of diodes connected in parallel . . . . . . . . . . . . . . . . . . . . . . . . 6

1.5 Considerations of maximum dispersion: ∆VFmax (I0, 25 °C) . . . . . . . . . . . 9

1.6 Layout recommendation . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 10

2 Electro-thermal model of diodes in parallel . . . . . . . . . . . . . . . . . . . . . 11

2.1 DC Forward characteristic model . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .11

2.2 Full system model . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 13

2.3 Simulation results . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 13

2.4 Comments about simulation . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 15

3 Conclusions . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 15

4 Revision history . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 15

Page 3: Current sharing in parallel diodes - STMicroelectronics · Current sharing AN4381 6/16 DocID025436 Rev 1 Equation 11 VF1(IF1,Tj1) = VF2(IF2,Tj2) = … = VFn(IFn,Tjn) Tj2 = … = Tjn

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1 Current sharing

1.1 The basicsConsider a simple example of two 5 A, 600 V ultrafast diodes in a TO-220 package (STTH5R06) connected in parallel and mounted on a common heat sink. Figure 1 shows the forward voltage VF of two STTH5R06 diodes (D1 and D2) versus forward current IF at different junction temperatures. Diodes D1 and D2 have a difference of forward voltage equal to 550 mV at Tj1 = Tj2 = 25 °C. This reference value will be expressed as:

∆VF(5A, 25 °C) = 550 mV.

This system satisfies the equations:

Equation 1

IT(t) = IF1(t) + IF2(t)

Equation 2

VF1(t,IF1,Tj1) = VF2(t,IF2,Tj2)

In this first example IT(t) = 10 A = cst. For diode D1, having a lower forward voltage characteristic than D2, IF1 will be higher than IF2. When Tj1 = Tj2 = 25 °C (for example when the converter starts up) we get:

Equation 3

IF1 = 6.7 A, IF2 = 3.3 A (IT = 10 A)

and

Equation 4

VF1(6.7 A, 25 °C) = VF2(3.3 A, 25 °C) = 2.18 V

Figure 1. Two 5 A, 600 V ultrafast diodes (STTH5R06) connected in parallel

IT(t)

IF1(t)

VF1

D1

Tj1

(a)

IF2(t)

VF2

D2

Tj2

0

2

4

6

8

10

12

0 0,5 1 1,5 2 2,5 3 3,5

D1(125°C) D2(125°C) D1(25°C) D2(25°C)

ΔV (5A,25F °C)=550mV

ΔV (5A,125F °C)=200mV

IF1=6.7A

IF2=3.3A

VF1(6.7A,25°C) = VF2(3.3A,25°C)=2.18V

D1(150°C)

1.25V

IF1=6.1 A

IF2=3.9A

IF1=6.7A

IF2=3.3A

VF1(6.1A,125°C) = VF2(3.9A,125°C)=1.33V

I (A)F

(b)

IT=IF1 + IF2 =10A

VF(V)

Page 4: Current sharing in parallel diodes - STMicroelectronics · Current sharing AN4381 6/16 DocID025436 Rev 1 Equation 11 VF1(IF1,Tj1) = VF2(IF2,Tj2) = … = VFn(IFn,Tjn) Tj2 = … = Tjn

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1.2 Thermal effectsTwo thermal effects need to be considered. The first one due to the negative temperature coefficient of VF is very well known. The second one, due to dependency of ⍺ VF on VF is practically unknown.

1.2.1 Thermal effects due to the negative temperature coefficient of VF

Assume that in thermal steady state equilibrium the junction temperature of these two diodes is equal to 125 °C. From Figure 1.b we can deduce:

Equation 5

IF1 = 6.1 A, IF2 = 3.9 A (IT = 10 A)

and

Equation 6

VF1(6.1 A, 125 °C) = VF2(3.9 A, 125 °C) = 1.33 V

For D1, having higher forward current than D2, Tj1 will be higher than Tj2. Assuming now Tj1 = 150 °C and Tj2 = 125 °C we get:

Equation 7

IF1 = 6.7 A, IF2 = 3.3 A (IT = 10 A)

and

Equation 8

VF1(6.7 A, 150 °C) = VF2(3.3 A, 125 °C) = 1.25 V

The negative temperature coefficient of the forward voltage drop ( ⍺ VF < 0) increases the current unbalance between each diode. It is practically true for every technology of diode excepted for silicon carbide diodes for which ⍺ VF > 0 in the operating area. The negative impact of this well-known thermal effect is in practice limited by the fact that all the diodes are generally mounted on a common heat sink (see Figure 12). The case temperature being approximately the same for each diode, the difference of junction temperature ∆Tj can be determined by:

Equation 9

∆Tj = RTH(j-c)∆P

Where RTH(j-c) is the junction to case thermal resistance and ∆P the difference of power losses between each diode. Generally ∆Tj is lower than 25 °C, limiting the current unbalance due to the temperature.

Page 5: Current sharing in parallel diodes - STMicroelectronics · Current sharing AN4381 6/16 DocID025436 Rev 1 Equation 11 VF1(IF1,Tj1) = VF2(IF2,Tj2) = … = VFn(IFn,Tjn) Tj2 = … = Tjn

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1.2.2 Thermal effects due to the dependency of ⍺ VF versus VF

The second thermal effect is linked to the dependency of temperature coefficient ⍺VF versus forward voltage drop VF. Figure 1.b shows that diode D1, having a lower voltage drop than D2, has at the same time, a lower absolute value of ⍺ VF. This law is confirmed by Figure 2 giving the relationship between ⍺ VF and VF for different STTH5R06. Each point corresponds to one diode. ⍺ VF is measured for a forward current of 5 A.

This second thermal effect is favorable for current equilibrium and partially counteracts the first thermal effect.

Figure 2. Dependency of ⍺ VF versus VF for STTH5R06

1.3 Worst case configurationTo produce a safe design it is important to consider the worst case situation represented in Figure 3. D1 has the lower VF and diodes D2 to Dn have the higher VF. We will define by ∆VFmax(I0, 25 °C) the maximum forward voltage dispersion of all the diodes at 25 °C and at current rating I0, for example I0 = 5 A for an STTH5R06. This configuration is defined by: diode D1 with VF1(I0, 25 °C) and diodes D2 to Dn with:

Equation 10

VF2(I0, 25 °C) = VFn(I0, 25 °C) = VF1(I0, 25 °C) + ∆VFmax(I0, 25 °C)

At the thermal steady state equilibrium we now get:

IT(t) = IF1(t) + IF2(t) + … + IFn(t)

IF2(t) = … = IFn(t)

Tj1 > Tj2 … Tjn

7,5

8,0

8,5

9,0

9,5

10,0

10,5

2 2,1 2,2 2,3 2,4 2,5

-�VF (5A) (mV/ °C)

(V)VF

Page 6: Current sharing in parallel diodes - STMicroelectronics · Current sharing AN4381 6/16 DocID025436 Rev 1 Equation 11 VF1(IF1,Tj1) = VF2(IF2,Tj2) = … = VFn(IFn,Tjn) Tj2 = … = Tjn

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Equation 11

VF1(IF1,Tj1) = VF2(IF2,Tj2) = … = VFn(IFn,Tjn)

Tj2 = … = Tjn

Figure 3. Worst case situation of n diodes connected in parallel

To ensure a safe design, the more stressed diode (D1) has to work within its specified limits in terms of junction temperature, rms current, and transient surge current capability. The goal of the simulation tool presented in Section 2 is to address this question.

1.4 VF and QRR of diodes connected in parallelWe first compare the forward voltage characteristic of the two diodes D1 and D2 connected in parallel with the case of two medium diodes also connected in parallel. Figure 4.a shows again the forward characteristic of D1 and D2 with the corresponding medium characteristic. Figure 4.b shows VF of D1 connected with D2 when Tj1 = Tj2 = 125 °C and when Tj1 = 150 °C and Tj2 = 125 °C (∆Tj = 25 °C corresponding to the worst case with a common heat sink) which can be compared with the two medium diodes at Tj1 = Tj2 = 125 °C. The curves from Figure 4.b can be deduced from the curves of Figure 4.a. For example, VF at 8 A of D1 connected with D2 when and Tj1 = 150 °C and Tj2 = 125 °C is defined by:

Equation 12

VF1(5.3 A, 150 °C) = VF2(2.7 A, 125 °C) = 1.15 V

In this particular case, the resulting forward characteristic of the 2 medium diodes is approximately the same as for D1 connected with D2 at Tj1 = Tj2 = 125 °C but is higher when Tj1 = 150 °C and Tj2 = 125 °C.

IT

IF1(t)

VF1

D1

Tj1

IF2(t)

VF2

D2

Tj2

IFn-1(t)

VFn-1

Dn-1

Tjn-1

IFn(t)

VFn

Dn

Tjn

n-1 diodes withsame higher VF

D1 with lower VF

Page 7: Current sharing in parallel diodes - STMicroelectronics · Current sharing AN4381 6/16 DocID025436 Rev 1 Equation 11 VF1(IF1,Tj1) = VF2(IF2,Tj2) = … = VFn(IFn,Tjn) Tj2 = … = Tjn

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Figure 4. Worst case situation of n diodes connected in parallel

We now use, the same approach to compare reverse recovery charges: QRR at IT = 10 A and VR = 400 V, versus dIF/dt for different configurations. Consider the method employed with an example. In the case of diode D1 (Tj1 = 150 °C) in parallel with D2 (Tj2 = 125 °C) for IT = 10 A we get IF1 = 6.7 A and IF2 = 3.3 A. Since IT = IF1 + IF2, we have:

Equation 13

dIT/dt =dIF1/dt + dIF2/dt

If dIT/dt = 300 A/µs, we get dIF1/dt = 200 A/µs and dIF2/dt = 100 A/µs. Figure 5.b shows the switching oscillograms of D1 at IF1 = 6.7 A, dIF1/dt = 200 A/µs, Tj1 = 150 °C and that of D2 at IF2 = 3.3 A, dIF2/dt = 100 A/µs, Tj2 = 125 °C. In these conditions accurate measurements give:

Equation 14

QRR(D1)(6.7 A, 200 A/µs, 150 °C) = 125 nC, QRR(D2)(3.3 A, 100 A/µs, 125 °C) = 59 nC

So QRR of D1 in parallel with D2 is:

Equation 15

QRR(D1 + D2) = QRR(D1) + QRR(D2) = 184 nC

Assume now two diodes D1 are connected together. Obviously the current will be well balanced so we have: IF1 = 5 A, dIF1/dt = 150 A/µs, Tj1 = 125 °C. Measurements give:

Equation 16

QRR(D1)(5 A, 150 A/µs, 125 °C) = 80 nC

Equation 17

So QRR(2 D1) = 2 • QRR(D1)(5 A, 150 A/µs, 125 °C) = 160 nC

0

2

4

6

8

10

12

14

16

0,0 0,2 0,4 0,6 0,8 1,0 1,2 1,4 1,6

IF(A)

0

2

4

6

8

10

12

0 0,5 1 1,5 2 2,5 3 3,5

D1 with D2

TJD1 =150°C TJD2=125°C

2 medium diodes

TJD1 =TJD2=125°C

D1 with D2

TJD1 =TJD2=125°C

IF1+IF2=8A

D1(125°C)D2(125°C)

D1(25°C)

D2(25°C)D1(150°C)

IF1=5.3A

IF2=2.7A

VF1(5.3A,150°C) = V F2(2.7,125°C) = 1.15V

IF(A)

(a) (b)

VF(V)VF(V)

VF1(5.3A,150°C) = V F2(2.7,125°C) = 1.15V

Page 8: Current sharing in parallel diodes - STMicroelectronics · Current sharing AN4381 6/16 DocID025436 Rev 1 Equation 11 VF1(IF1,Tj1) = VF2(IF2,Tj2) = … = VFn(IFn,Tjn) Tj2 = … = Tjn

Current sharing AN4381

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In the same way we obtain:

Equation 18

So QRR(2 D2) = 2 • QRR(D2)(5 A, 150 A/µs, 125 °C) = 150 nC

It is interesting to note that while D1 has a lower forward voltage drop than D2, the reverse recovery charges are higher for D1.

Figure 5. Switching oscillograms of D1 and D2

Using this method for different dIT/dt we get the diagrams shown in Figure 6.

Figure 6. QRR at IT = 10 A and VR = 400 V versus dIT/dt for different configurations

TJD2=125°C

dIT/dt =300A/µs

IT = 10A

VR=400V

IF1=IF2=5A

dIT/dt =150A/µs

ID2

ID1

IT=10A

IF1=6.7A

IF2=3.3A

dIT/dt =300A/µs

IT = 10A

VR=400V300A/µs

200A/µs, TJD1 =150°C

100A/µs, TJD2=125°C

5A/div

50 ns/div

2A/div

10 ns/div

(a) (b)

100

120

140

160

180

200

220

240

100 200 300 400 500 600

QRR (nC)

dIT/dt (A/µs)

D1 in parallel with D2T = 150 °C, T = 125 °Cj(D1) jD2

D1 in parallel with D2T = T = 125 °Cj(D1) jD2

2 D1 in parallelT = 125 °Cj(D1)

2 D2 in parallelT = 125 °Cj(D2)

Page 9: Current sharing in parallel diodes - STMicroelectronics · Current sharing AN4381 6/16 DocID025436 Rev 1 Equation 11 VF1(IF1,Tj1) = VF2(IF2,Tj2) = … = VFn(IFn,Tjn) Tj2 = … = Tjn

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AN4381 Current sharing

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To summarize, the VF and QRR comparison between two STTH5R06 in parallel having a dispersion of ∆VF(5A, 25 °C) = 550 mV with the ideal case constituted by medium diodes indicates that these characteristics are close when junction temperatures are identical. When the junction temperature difference between D1 and D2 increases, VF tends to decrease slightly and QRR tends to increase slightly. We cannot make a general conclusion from a particular case, but this example shows the general trend and illustrates a method which can be employed for others configurations.

1.5 Considerations of maximum dispersion: ∆VFmax (I0, 25 °C)The above considerations show the key impact of the maximum dispersion ∆VFmax(I0, 25 °C) on the current imbalance. For a designer it is not always easy to know this value. However, the following information can be given:

• ∆VFmax(I0, 25 °C) increases with the voltage rating (VRRM). That means the forward voltage dispersion of 600 V ultrafast diodes will be higher than the dispersion of 200 V ultrafast diodes. The same consideration can be applied between 200 V ultrafast diodes and 100 V Schottky diodes and between 100 V Schottky diodes versus 45 V Schottky diodes.

• For ultrafast diodes having the same VRRM ∆VFmax(I0, 25 °C) is higher for faster diode families. For example, If we consider 600 V ST ultrafast diodes, R family (Rapid) has higher dispersion than the L family (Low VF).

• Practically all ST common cathode diodes in the same package can be connected in parallel without any precaution. Since these diodes are on the same die, ∆VFmax(I0, 25 °C) is very low.

• Low voltage Schottky diodes (VRRM < 60 V) can also be connected in parallel without precaution.

• Sometimes, designers fix by establishing a maximum ∆VFmax(I0, 25 °C) for all diodes connected in parallel to ensure a safe design. A good value can be: ∆VFmax(I0, 25 °C) = 40 mV. With this value, the current will be equitably shared between each diode and the thermal effects will become negligible.

Page 10: Current sharing in parallel diodes - STMicroelectronics · Current sharing AN4381 6/16 DocID025436 Rev 1 Equation 11 VF1(IF1,Tj1) = VF2(IF2,Tj2) = … = VFn(IFn,Tjn) Tj2 = … = Tjn

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1.6 Layout recommendationThe basic recommendation is to use a symmetrical layout as illustrated in Figure 7.

Figure 7. Good and bad layouts

If the layout is not symmetrical, the connection resistors will increase the current imbalance. In contrast, a symmetrical layout will balance the current in each diode. To have a real impact, the values of these resistors have to be of the same order as the resistance of the diodes. Adding the small resistance in series with each diode can be a good way to balance the current. On the other hand this solution will generate more power losses and will decrease the efficiency of the converter. We can observe in Figure 4.b that the resistance of the diode RD increases with lower forward current IF. So paralleling will be easier for lower current. The dependency of RD versus IF can also be considered as a compensation effect

IF2 IF3D3

VF2

D2IF1

VF1

D1

VF3

RS1 RS2 RS3

IT

IF2IF3

D3VF2

D2

IF1

VF1

D1VF3

RS1

RS2 RS3

IT

Good layout

Same RS1=RS2=RS3

Bad layout

Different RS1 RS2 ≠ RS3≠

Page 11: Current sharing in parallel diodes - STMicroelectronics · Current sharing AN4381 6/16 DocID025436 Rev 1 Equation 11 VF1(IF1,Tj1) = VF2(IF2,Tj2) = … = VFn(IFn,Tjn) Tj2 = … = Tjn

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AN4381 Electro-thermal model of diodes in parallel

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2 Electro-thermal model of diodes in parallel

2.1 DC Forward characteristic modelThe first step is to construct a forward characteristic model of the diode (see Figure 8).

Figure 8. Model of the forward characteristic of the diode

This is defined by the following current generator IF depending on Tj and VF

Equation 19

Each coefficient ai(Tj) is of the form:

Equation 20

a0(Tj) = a00 + a01Tj + a02Tj2 + a03Tj

3

Figure 9 and Figure 10 give respectively ai(25 °C) and a0j coefficients for a STTH5R06.

Figure 9. ai(25 °C) coefficients of STTH5R06

VF

Tj

IF =(VF,Tj)

IF =(VF,Tj )

I (V ,T) = a (T) + a (T)V + a (T)V + a (T)V + a (T)V + a (T) VF F j 0 j 1 j F 2 j F 3 j F 4 j F 5 j F

2 3 4√

0

5

10

15

20

25

30

35

40

0 1 2 3 4

IF(A) Example: Tj = 25°C

a0(25°C) 0.443113633610841

a1(25°C) 1.823450442549035

a2(25°C) -1.596962213365812

a3(25°C) 1.497001749151565

a4(25°C) -0.139628758047056

a5(25°C) -1.59534418112371

VF(V)

D1(25°C)

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Electro-thermal model of diodes in parallel AN4381

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Figure 10. a0i coefficients of STTH5R06

Figure 11 illustrates the precision of this model.

Figure 11. Forward characteristic comparison between model and measurement

a00 1.330314150823049

a01 -0.040753310751888

a02 0.000157525320538

a03 0.000000033311313-1,4

-1,2

-1

-0,8

-0,6

-0,4

-0,2

0

0,2

0,4

0,6

0 25 50 75 100 125 150 175 200

a0(Tj)

Original curve

Fitted curve

Tj(°C)

1 2 3 40

10

20

30

40IF(A)

VF(V)

O MeasurementModeling

25°C50°C75°C100°C125°C150°C175°C

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2.2 Full system modelHaving now obtained a good model of the forward characteristic of the diode, we can construct the model of the total system. Without loss of generality, we consider the simple example represented in Figure 12. It consists of two STT5R06 diodes mounted on the same heat sink. The total current IT(t) is rectangular with a switching period TS = 10 µs, a duty cycle δ = 0.5 and a peak current IP = 10 A. The full model of this system is also shown in Figure 12. We can distinguish the electrical model defined in the previous paragraph from the thermal model. In this example the case temperature of the heat sink is constant and is equal to Tcase = 100 °C. It is important to understand that these two models will work together. VF1 and VF2 depend on Tj1 and Tj2 which depend on the power losses in the diodes (P1 and P2). Thus Tj1 and Tj2 depend upon VF1 and VF2

Figure 12. Full system model

In this application note we consider only conduction losses. This hypothesis is justified not only for Schottky and silicon carbide diodes but also for the major applications using ultrafast diodes. Effectively, major switching losses, due to reverse recovery charges, are generally dissipated in the companion switch (MOSFET or IGBT) and do not affect the current imbalance of the diodes. For applications for which switching losses generated in the diodes are not negligible versus conduction losses, it is possible to complete the model. This more complex model is not covered in this application note.

2.3 Simulation resultsThe simulations were performed with STTH5R06 having different values of ∆VFmax(5 A, 25 °C). Figure 13 shows the forward voltage characteristic of seven STTH5R06 diodes at Tj = 25 °C and gives ∆VFmax(5 A, 25 °C) versus the reference diode Dref having the highest VF.

D1 D2

Tj1 Tj2

Tcase

IT

=0.5

Ts=10 µs

10A

Time

Thermal Model

Rth(j-c) Rth(j-c)Cth(j-c)

Cth(j-c)

Tj1 Tj2

Tcase

P1(t)=VF1 (t).IF1 (t) P2(t)=VF2 (t).IF2 (t)

Rth(j-c)=3°C/W

Cth(j-c)=0.27sW/°C

IF1 IF2

D2

VF1

D1

Electrical Model

IT

VF2

Tj1 Tj2

δ

Page 14: Current sharing in parallel diodes - STMicroelectronics · Current sharing AN4381 6/16 DocID025436 Rev 1 Equation 11 VF1(IF1,Tj1) = VF2(IF2,Tj2) = … = VFn(IFn,Tjn) Tj2 = … = Tjn

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Figure 13. STTH5R06 with different ∆VFmax(5 A, 25 °C)

Figure 14 represents the variation current and junction temperature versus time of each diode for respectively ∆VFmax(5 A, 25 °C) equal to 100 mV, 300 mV, 400 mV and 600 mV. The current imbalance and the difference of junction temperature between Dref and the other diode increase with ∆VFmax(5 A, 25 °C). Even for ∆VFmax(5 A, 25 °C) = 600 mV, the difference of junction temperature is low (< 6 °C), in this example the thermal effect of negative ⍺ VF < 0 is weak. Up to ∆VFmax(5 A, 25 °C) = 300 mV the current imbalance is low (IDref = 4.37 A, I6 = 5.63 A).

Figure 14. Simulation results

0

1

2

3

4

5

6

7

8

0,5 1 1,5 2 2,5 3

IF(A) D8D7D6D5D4D3 D Ref

ΔVF(5A,25°C)=100mV

VF(V)

28/10/2013PROTECTION - Industrial Applications

IT

TjD3

TjD_Ref = 107,84°C

TjD1= 113,68°C

TjD_Ref = 109,56°C

TjD4= 112,86°C

ID_Ref =4,27A

ID5=5,74A

IT

TjD5

ID_Ref =3,67A

ID3=6,41A

TjD_Ref = 111 °C

TjD1= 112°C

ID_Ref =4,8A

ID8=5,2A

ΔVF(5A,25°C)=100mV

TjD_Ref = 109,9°C

TjD3= 112,7°C

ID_Ref =4,37A

ID6=5,63A

IT

TjD_Ref

TjD8

IT

TjD6

TjD_Ref

TjD_Ref TjD_Ref

ΔVF(5A,25°C)=300mVΔVF(5A,25°C)=300mV

ΔVF(5A,25°C)=300mVΔVF(5A,25°C)=600mVΔVF(5A,25°C)=300mVΔVF(5A,25°C)=400mV

Tj(°C)Tj(°C) IF(A)IF(A)

120120

110110

100100

9090

8080

2020

1515

1010

55

00

Tj(°C)IF(A)

120

110

100

90

80

20

15

10

5

05004003002001000

Time (ms)

5004003002001000Time (ms)

5004003002001000Time (ms)

5004003002001000Time (ms)

Tj(°C)IF(A)

120

110

100

90

80

20

15

10

5

0

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DocID025436 Rev 1 15/16

AN4381 Conclusions

16

2.4 Comments about simulationThis simulation can be easily extrapolated to more complex configurations integrating n diodes, more accurate thermal models (for example Cauer type circuit thermal model) including models of the heat sink, layout resistors, more complex IT(t) current wave forms. If designers are only interested in knowing steady state current and junction temperature it is possible to reduce the calorific capacity (CTH) to gain simulation time. This tool can be used to analyze both current imbalance and difference of temperature for transient surge currents.

3 Conclusions

This application note shows the impact of forward voltage dispersion is generally more critical than thermal effects for the current imbalance problem. To perform a safe design it is important to be sure the most stressed diode works within its specified limits in the worst case situation. The simulation tool described allows estimation of the junction temperature and current of each diode for transient and steady state phases.

4 Revision history

Table 1. Document revision history

Date Revision Changes

30-Jul-2014 1 Initial release.

Page 16: Current sharing in parallel diodes - STMicroelectronics · Current sharing AN4381 6/16 DocID025436 Rev 1 Equation 11 VF1(IF1,Tj1) = VF2(IF2,Tj2) = … = VFn(IFn,Tjn) Tj2 = … = Tjn

AN4381

16/16 DocID025436 Rev 1

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