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Cube Calculus

Cube Calculus

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Cube Calculus . Overview Of This Presentation. A Brief Review of Cube Calculus. Summary of Cube Calculus operations. Positional notation concept for Cube Calculus operations. Summary of Positional Notation concept for Cube Calculus operations. - PowerPoint PPT Presentation

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Page 1: Cube Calculus

Cube Calculus

Page 2: Cube Calculus

Overview Of This Presentation

• A Brief Review of Cube Calculus.• Summary of Cube Calculus operations.• Positional notation concept for Cube Calculus

operations.• Summary of Positional Notation concept for

Cube Calculus operations.• Why we need hardware realization of Cube

Calculus?

Page 3: Cube Calculus

Brief Review Of Cube Calculus

Page 4: Cube Calculus

Representation of cubes in (Binary logic)

• For the function f(a,b,c,d)= A + B = a’bc’+ac’d we have two cubes (a’bc’ and ac’d) Cube is a Product of literals.

• In binary logic, they can be represented as A = a{0} .b{1} .c{0} .d{0,1} and B = a{1} .b{0,1} .c{0} .d{1}

Page 5: Cube Calculus

General Representation of cubes in (n valued logic)

• A = x1s1A. x2

s2A………xnsnA

• B = x1s1B. x2

s2B……….xnsnB

• where x1s1A …..xn

snA.,x1s1B, .…xn

snB are literals.• n is the number of variables.• siA, siB are true sets of literal xi .• An example of a ternary logic is: A = x1

{0}. x2{0,2}. x3

{1}. x4{1,2}

B = x1{1}. x2

{1}. x3{2} . x4

{0,1}

Page 6: Cube Calculus

Comparison of Notations for ternary logic

Set-theoretical: A = x1{0}. x2

{0,2}. x3{1}. x4

{1,2}

Positional: 100-101-010-011

Page 7: Cube Calculus

Cube Calculus Operations

Page 8: Cube Calculus

Cube Calculus OperationsThe cube calculus operations are classified as :

• Simple Combinational operations (e.g. Intersection, SuperCube ).

• Complex Combinational operations (e.g. Prime, Consensus, Cofactor).

• Sequential operations (e.g. Crosslink, Sharp(non-disjoint), Sharp (disjoint)).

• Let us discuss these operations..

Page 9: Cube Calculus

Simple Combinational Cube Operations

Page 10: Cube Calculus

Simple Combinational Operations• Defined as a SINGLE set operation on all pairs of

true sets and produces one resultant cube.• Intersection and Supercube are simple

combinational cube operations.• These operations are fast in software and very fast

when realized in hardware.• Have various applications in two-level synthesis,

set covering, graph coloring and all kinds of basic algorithms

Page 11: Cube Calculus

Example Of Binary Function

Page 12: Cube Calculus

Kmap representation of Intersection

• B= ab• A= bc’• Set theory :

B = ab = abx = a{1}b{1}c{0,1} • A= bc’ = xbc’ =

a{0,1}b{1}c{0}

• B A=a{1}{0,1}b{1}{1} c{0,1} {0} = abc’

Page 13: Cube Calculus

Kmap representation of Intersection

• Fig 1: Input Cubes A and B to be Intersected. Here A = x2*x3 B = x1*x2

• Fig 2:Resultant Cube C = A B =

x1*x2 *x3

A

B

Page 14: Cube Calculus

Kmap representation of SupercubeSupercube

• A and B has 3 variables.

• A = ab• B = bc’• In set theory A= abx

B=xbc’• A B = b

Page 15: Cube Calculus

K-map representation of Super cube

• Input Cubes A and B to be supercubed. A=x1’x2’x4

B= x1x3x4 • Resultant Cube

C=A B = x4

Supercube has applications in SOP and ESOP minimization to find primes or product terms for best covers.

Page 16: Cube Calculus

Examples Of Cube Operations for

Multi-Valued Functions

Page 17: Cube Calculus

K-map representation of Supercube

• For 4 valued input logic.

• Input Cubes A and B to be supercubed. A=a01b1. B=a12b2

• Resultant Cube C=A B = a012b12

)

Page 18: Cube Calculus

K-map representation of Intersection

• For 4 valued input logic.

• Input Cubes A and B for Intersection. A=a12b12. B=a2b012

• Resultant Cube C=A B = a2b12

You have to be familiar with different notations and representations when reading research papers

Page 19: Cube Calculus

Definitions of Simple Combinational Cube

Operations

Page 20: Cube Calculus

Intersection of two cubes : Is the largest cube that is included in both A and B.

Supercube of two cubes : Is the smallest cube that includes both cubes.

You have to understand meaning of operators when you create new algorithms

You have to understand mathematical formalism of operators to realize them efficiently in software or hardware.

Page 21: Cube Calculus

Simple Combinational Operation• Intersection operation mathematically is

defined as

AB= x1s1

As1

B……xnsn

Asn

B if siAsi

B

= otherwise.

• Union (supercube) operation mathematically is defined as

A B = x1s1As

1B……xn

snAs

nB

Page 22: Cube Calculus

Complex Combinational Cube Operations

Page 23: Cube Calculus

Complex combinational cube operations

• They have two set operations and one set relation.• All variables whose pair of true sets satisfy a relation are said to

be Special Variables.• Two set operations are called before(bef) and active(act),the

active set operation is applied on true sets of special variables and before set operation to others

• All Combinational cube operations (Complex and Simple) produce one resultant cube, all special variables taken at a time.

• The examples are prime operation, cofactor operation, consensus operation.

Page 24: Cube Calculus

Examples of Complex Combinational Cube

Operations

Page 25: Cube Calculus

Example Of Binary Function

Page 26: Cube Calculus

Example of prime operation

• A&B has 4binary variables• A=x1’x2x3x4

• B=x1x3’• Step 1Step 1: Find intersection

operation(set relation) on all true sets(si

AsiB )

• Step 2Step 2: If the set relation is satisfied apply active set operation(si

A siB ) else

before set operation( siA ).

Notation of “prime” operation on cubes A and B

Page 27: Cube Calculus

Explanation of the Example• Using set theory B=x1

{1} x2{0,1}x3

{0}x4{0,1}

A=x1{0}x2

{1}x3{1}x4

{1}

Step 1Step 1. Find if set relation (si

AsiB ) is satisfied or not .

x2 and x4 are special variables.

Step 2.Step 2. As the given set relation is satisfied for the variables x2 and x4

to these variables active set operation (si

A siB ) is applied

and to the others (x1 , x3 ) before set operation ( siA ) is applied

A’B = x1{0}x3

{1} = x1’x3

B = x1{1} x2

{0,1} x3{0} x4

{0,1} A = x1

{0} x2{1 } x3

{1} x4{1}

----------------------------------------------------

A’B = x1{0} x2

{0,1} x3{1} x4

{0,1} = x1’x3

Page 28: Cube Calculus

Example of another complex combinational operation: consensus

• A & B have 4 binary variables– A = x1x2x3’– B = x1x2’

• Steps: find the set relation siAsiB=.

• If satisfied then it is a special variable.

• Active operation (siAsiB) applied to special variables.

• And to remaining variables (before variables) the set operator siAsiB is applied

Page 29: Cube Calculus

Explanation of consensus operation• In set theory

A = x1{1}x2

{1}x3{0}x4

{0,1}

B = x1{1}x2

{0}x3{0,1}x4

{0,1}

• Applying the set relation siAsiB= on all the true set of variables x2 is a special variable and to x2 active operation (siAsiB) is applied

• and to x1 ,x3 ,x4 before set operator (siAsiB ) is applied

A * B = x1{1} x3{0} = x1x3’

A = x1{1} x2

{1} x3{0} x4

{0,1}

B = x1{1} x2

{0} x3{0,1} x4

{0,1}

----------------------------------------------------

A*B = x1{1} x2

{0,1} x3{0} x4

{0,1}

Page 30: Cube Calculus

Use of consensus to prove tautologyYZ

WX 00 01

00

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11 10

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141513

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YZ

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Cube of minterms YZ

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YZ

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1 1

Table of all ones

Page 31: Cube Calculus

Proving tautology• By using consensus I combine step-by-step

larger and larger cubes of ones.• Ultimately, the cube of ones that covers the

whole map is created.• Thus the function is a tautology.• The process of combining cubes can be

represented as a tree

The same Cube Calculus has dual meaning when applied to cubes of zeros (maxterms)

It is called resolution and used in automatic theorem proving to derive empty clause = cube of all zeros

Page 32: Cube Calculus

Use of consensus to derive empty clauseYZ

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YZ

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Cube of maxterms (zeros)

YZ

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11 10

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8 9 11 10

141513

11

10

YZ

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11 10

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8 9 11 10

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Table of all zeros

Cube representing empty clause

Page 33: Cube Calculus

Proving non-satisfiability is deriving empty clause

• By using resolution operator (dual to consensus) I combine step-by-step larger and larger cubes of zeros.

• Ultimately, the cube of zeros that covers the whole map is created. This is empty clause.

• Thus the function is always zero.• The process of combining cubes can be represented as a

tree.• This is used in automatic theorem proving to prove that a

set of clauses is inconsistent

•Please do a complete example with all formulas applied in formal way , step by step.

•What would be a program?

Page 34: Cube Calculus

Example of cofactor operation• A and B have 4 binary

variables.– A = x1x2x3

– B= x1

• Steps: Find siAsiB

(If satisfied special variable)

• Apply U(Universal set(0,1)) for special variables and siAsiB for others

Page 35: Cube Calculus

Explanation• Set theory:

A = x1{1}x2

{1}x3{1}x4

{0,1}

B = x1{1}x2

{0,1}x3{0,1}x4

{0,1}

• Testing the relation siAsiB for the variables. x1 and x4 are special variables. Universal set operator applied to these variables.

• To the rest of the variables the intersection operation is applied. The result is x2 x3.

• In K-map apply the intersection operator and remove the special variables.

Page 36: Cube Calculus

Example Of Complex

Combinational Operations for Multi-

Valued Functions

Page 37: Cube Calculus

K-map representation of Consensus

• A= X 01234 Y01

• B = X012 Y23

• A * B = X 01234Y01*X012Y23 =

X012 Y0123

Page 38: Cube Calculus

Definitions of Complex

Combinational Cube Operations

Page 39: Cube Calculus

General Description of Consensus Cube

Operation

Page 40: Cube Calculus

Complex combinational cube operation• The consensus operation on cubes A and B is defined as

A B when distance (A,B) = 0A * B = when distance (A,B) > 1 A *basic B when distance (A,B) = 1

• where A *basic B =

x1s1 A s1B ….xk-1

sk-1 A sk-1B xkskA skB

xk+1sk+1 A sk+1B…… xn

sn A snB. • Set relation: sisiAAsisiB B = = , if satisfied, a special variable • Active set operation : sisiAAsisiBB

• Before set operation : sisiAAsisiB B

Page 41: Cube Calculus

Complex combinational cube operation• Application of consensus theorem:

– For finding prime implicants (Used for two-level logic minimization),

– three level,– multilevel minimization,– and machine learning.

Most applications are in few-level circuit design, basic operations and automatic theorem proving in AND/OR logic

Page 42: Cube Calculus

General Description of Cofactor Cube

Operation

Page 43: Cube Calculus

Complex combinational cube operation• Cofactor operation of two cubes A and B is A| B = A |basic B when A B

= otherwise

Set relation for cofactor operation =

sisiA A si siBB Active set operator = U (Universal

set(0,1)) Before set operator = sisiA A si siBB

• Application: – Used in recursive paradigms– Used to create trees and DDs– Used in functional decomposition.

Page 44: Cube Calculus

General Description of Prime Operation

Page 45: Cube Calculus

Complex combinational cube operations

• Prime operation of two cubes A and B is defined as A’B=x1

s1A…xk-1sk-1Axk

skAskBxk+1sk+1A….xn

snA

where set relation : siAsi

B is applied to true sets and if satisfied active set operation is applied

else before set operation is applied.

• Active set operation(act):siA si

B

• Before set operation(bef): siA

• Application: Used in ESOP minimization .

Page 46: Cube Calculus

Sequential Cube Operations

Page 47: Cube Calculus

Sequential cube operations• They have three set operations and one set relation.• All variables whose pair of true sets satisfy a relation are said to

be Special Variables.• Three set operations are called before(bef),active(act) and

after(aft)• The active set operation is applied on true sets of special variable

• The before set operation to variables before the special variable • The after set operation to variables after the special variable.

• Every special variable is taken once at a time.

Page 48: Cube Calculus

Sequential cube operations

• All sequential cube operations produce ‘n’ resultant cubes, where nn is the number of special variables.

• The examples are:– sharp operation,

–cross link operation.

Page 49: Cube Calculus

Examples of Sequential Cube

Operations

Page 50: Cube Calculus

Example Of Binary Function

Page 51: Cube Calculus

Let us consider the following example, where the relation operation is SA SB =

b is a special variable

Page 52: Cube Calculus

Cubes A and B are of 4 variables

Let us consider the following two cubes,Cube A = x1 x2 x3’ = x1{1}*x2{1}*x3{0} *x4{0,1}

Cube B = x1 x2’ = x1{1}*x2{0}*x3{0,1} *x4{0,1}

Page 53: Cube Calculus

These two variables (x1 and x3) are the so called special variables , and we find them out by checking the relation between every literal in both cubes for a relation which is for the crosslink ( is the intersection between these two variables is empty?).

Cube A x1{0} x2{0,1} x3{0} x4{0,1}

|| || || || Cube B x1{1} x2{0,1} x3{1} x4{0,1}

We can see that the intersection is empty for only X1 and X3

therefore they are special variablesspecial variables.

Page 54: Cube Calculus

Example of crosslink operation

• A and B has 4 binary variables.

• A = x1’x3’ = x1

{0}x2{0,1}x3

{0}x4{0,1

• B = x1x3 = x1

{1}x2{0,1}x3

{1}x4{0,1}

• A c B = x1’x3’ + x1x3 = x3’ + x1

Page 55: Cube Calculus

Example

• Cubes : • x1

{0}x2{0,1} x3

{0}x4{0,1}

• x1{1}x2

{0,1}x3{1} x4

{0,1}

• Set Relation: siAsiB = x1 and x3 are special variables..

Act:Act: siAsiB, Bef:Bef: siA, Aft:Aft: siB

• x1{0} {1}x2

{0,1} x3{0}x4

{0,1} and

x1 {1}x2

{0,1} x3{0} {1} x4

{0,1}

Two resultant cubes one for each special variable.

A B = x3’ x1

x1{0}x2

{0,1} x3{0} x4

{0,1}

x1

{1}x2{0,1}x3

{1} x4{0,1}

------------------------------------------

x1{} x2

{0,1}x3{} x4

{0,1}

First check relation

x1{0} x2

{0,1} x3{0} x4

{0,1}

x1

{1} x2{0,1}x3

{1} x4{0,1}

------------------------------------------

x1{0,1} x2

{0,1}x3{0} x4

{0,1}

x1{0} x2

{0,1} x3{0} x4

{0,1}

x1

{1} x2{0,1} x3

{1} x4{0,1}

------------------------------------------

x1{1} x2

{0,1} x3{0,1} x4

{0,1}

active activebefore

after

Since the order of argument cubes is arbitrary, the result is not unique

Page 56: Cube Calculus

Non-uniqueness of crosslink operation

One variant of crosslink

Another variant of crosslink

Page 57: Cube Calculus

Complex crosslink example

• A,B,C,D are 4 cubes

• F = ABCD• F = ABEF• F = GH

Page 58: Cube Calculus

Graphical Crosslink in Karnaugh Maps

Y

X 0 1

0

1

0 1

32

Y

X 0 1

0

1

0 1

32

Y

X 0 1

0

1

0 1

32

Y

X 0 1

0

1

0 1

32

Y

X 0 1

0

1

0 1

32

Y

X 0 1

0

1

0 1

32

Y

X 0 1

0

1

0 1

32

Y

X 0 1

0

1

0 1

32

Y

X 0 1

0

1

0 1

32

Y

X 0 1

0

1

0 1

32

Page 59: Cube Calculus

Use of crosslink to derive minimum ESOPYZ

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Cube of minterms (ones)

YZ

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Table of all zeros

a a=0

Page 60: Cube Calculus

Use of Crosslink for ESOP minimization

• Please write formulas for the previous example

• The solution is not unique• You have to use backtracking, heuristics, or

probabilistic methods to obtain good solution

• Look-ahead methods.• Start from several starting points.

Page 61: Cube Calculus

Example of nondisjoint

sharp

• A and B has 4 binary variables.

• A=x3’=x1{0,1}x2

{0,1}x3{0}x4

{0,1}

• B = x2x4 x1{0,1}x2

{1}x3{0,1}x4

{1}

• Set relation: (siAsiB)

– 1.x1{0,1} x2

{0,1}n({1}} x3{0}x4

{0,1}

Act: Act: siA siB, Bef:Bef: siA, Aft:Aft: siA

– 2. x1{0,1}x2

{0,1} x3{0} x4

{0,1}n({1}}

Act: Act: siA siB, Bef:Bef: siA,

Aft:Aft: siA

• A # B= x2’x3’+ x3 ’x4’

Page 62: Cube Calculus

Example of disjoint sharp

• A and B has 4 binary variables.

• A=x3’= x1

{0,1}x2{0,1}x3

{0}x4{0,1}

• B = x2x4 x1{0,1}x2

{1}x3{0,1}x4

{1}

• Set relation: (siAsiB)• x1

{0,1}n{0,1}x2{0,1}n({1}} x3

{0}x4{0,1}

Act: Act: siA ( siB), BefBef: siA, AftAft: siA siB

• x1{0,1}n{0,1}x2

{0,1}n{1} x3{0}n{0,1} x4

{0,1}n({1}}

• Act:Act: siA ( siB), Bef:Bef: siA, Aft:Aft: siA siB

• A #d B= x2’x3’+ x2x3 ’x4’

Page 63: Cube Calculus

Example Of Multi-Valued

Function

Page 64: Cube Calculus

Example of crosslink operation

• Let A=x0y1 and B=x2y3

X and Y are special variables. x{0}U {2}

y1 and x {2} y{1}U{3}

Resultant cubes:x02y1+x2y13

Page 65: Cube Calculus

Definitions of Sequential Cube

Operations

Page 66: Cube Calculus

General Description of Nondisjoint sharp

Operation

Page 67: Cube Calculus

Sequential cube operations.• The nondisjoint sharp operation on cubes A and B

A # B = A when A B = when A B = A #basic B otherwise

• A #basic B = x1s1A…xk-1

sk-1AxkskA(skB)xk+1

sk+1A….xnsnA for such

that k=1,….n for which the set relation is true.• Set relation: (si(siAAsisiBB).).

Active set operation: sisiAA(( si siBB),), After set operation: sisiAA,, Before set operation: sisiAA

• Used in tautology problem.

Page 68: Cube Calculus

General Description of disjoint sharp

operation

Page 69: Cube Calculus

Sequential cube operations.

• The disjoint sharp operation on cubes A and BA # d B = A when A B = when A B = A #dbasic B otherwise

• A #dbasic B = x1s1A…xk-1

sk-1AxkskA(skB)xk+1

sk+1A….xnsnA for

such that k=1,….n for which the set relation is true.• Set relation: (siAsiB)

Active Active set operation: siA( siB), AfterAfter set operation: siA siB , BeforeBefore set operation: siA

• Used in tautology problem, conversions between SOP and ESOP representations

Page 70: Cube Calculus

General Description of Crosslink Operation

Page 71: Cube Calculus

Sequential cube operations.• Generalized equation of Crosslink operation:

A B = x1s1B…xk-1

sk-1BxkskAskBxk+1

sk+1A….xnsnA

where k=1,….n for which the set relation is true.• Set relationSet relation: siAsiB = ,• ActiveActive set operation : siAsiB, • After After set operation : siB, • BeforeBefore set operation : siA.• Used in the minimization of logic function on

EXOR logic, Generalized Reed-Muller form.

Page 72: Cube Calculus

Applications of Crosslink

Page 73: Cube Calculus
Page 74: Cube Calculus
Page 75: Cube Calculus

And we all know that the answer is that we are looking for two cubes as shown down here,

so that our function is to be expressed in the ESOP form as follows: f=ED

Page 76: Cube Calculus

So the solution is to find these two cubes out (Cubes E, D).

Let us see how the crosslink operation does that!!!

Here is the K map for the original function again

Here if we think about it, we are looking for literals, in which the intersection of these literals in both cubes is empty, that is

X1 and X3, Because in the first cube we have

Page 77: Cube Calculus

Summary of the

Cube Calculus Operation

Page 78: Cube Calculus

Summary of cube calculus operation

Page 79: Cube Calculus

PositionalNotation

Page 80: Cube Calculus

Positional notation

• Cube operations were broken into several set relations and set operations. Easy to carry out by hand.

• To Process set operations efficiently by computers, we use positional notation.

• Positional notation : Possible value of a variable is 0 or 1.• P valued variable a string of p bit• Positional notation of binary literals:x’ x{0} x10 10 x

x{1} x01 01, don’t care x x{0,1} x11 11, contradiction x{} x00 00

Page 81: Cube Calculus

Set operations in positional notation

• Three basic set operations are executed using bit wise operations in positional notation.

• Set intersection bitwise AND• Example A = ab B=bc’ A B = abc’• In positional notation: A = 01-01-11 B = 11-01-10 A

B = (01/11)-(01/01)-(11/10) 01-01-10(abc’)• Set union bitwise OR• Example A = ab B=bc’ A B = b• In positional notation: A = 01-01-11 B = 11-01-10 A

B = (01/11)-(01/01)-(11/10) 11-01-11(b)

Page 82: Cube Calculus

Positional notation

• Set complement operation bitwise NOT• Example: A= ab then A’ = (ab)’• In positional notation: A = 01-01 A’ = 10-10• Example of multi valued variable:A= x{0,1,2} B=x{0,2,3}

A B = {0,2}, A B = {0,1,2,3}• In positional notation: A=1110, B=1011 A B

=1110/1011=1010{0,2},A B =1110/1011=1111{0,1,2,3 A’=0001{3}, B’=0100{1}

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Set relations in positional notation

• 1 True and 0 False• Set relation cannot be done by bit wise operation as it is a

function of all bits of operands.• Set relation is broken into Partial relation and Relation

type. The partial relation determine whether or not the two literals satisfy the relation locally. The relation type determines the method of combining partial relations.

• Relation(A,B) = (a0’+b0’).(a1’+b1’)…………(an’-1+ bn’-1) for crosslink operation Partial relation ai’+bi’and relation type is AND.

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Table of partial relation

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Summary of cube operations in positional notation

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Why We Need Cube Calculus Hardware?

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Why Using Cube Calculus Machine?• The cube calculus Operations can be

implemented on general-purpose computers, • But in general-purpose computers, the control is

located in the program that is stored in the memory.

• This results in a considerable control overheadoverhead. • Since the instructions have to be fetched from the

memory, if an algorithm contains loops, the same instruction will be read many times.

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That makes the memory interface the bottleneck of these architectures.

The cube calculus operations involve nested loops, it leads to poor performance on these general-purpose computers.

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Nouraddin Alhagi&Syeda Mohsina

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Lecture on Oct 8,2001