Crystal Basics

  • Upload
    raisa81

  • View
    219

  • Download
    0

Embed Size (px)

Citation preview

  • 8/2/2019 Crystal Basics

    1/9

    I. Basics of Crystal Plasticity

    Plastic deformation

    deformation which remains after load is removed

    atomic rearrangements (change of neighbours)

    Plastic deformation of crystals preserves lattice structure.

    shearing of lattice planes against each other (slip)

    plastic displacements are quantized in terms of multiple lattice vectors

    At low temperatures / high stresses: Deformation of crystals occurs exclusively

    by slip of lattice planes

    Slip system is characterized by:

    slip plane normal slip direction

    slip vector (a lattice vector in the slip direction)

    often: slip planes are most densely packed lattice planes

    slip directions are most densely packed lattice directions

    n

    r

    sr

  • 8/2/2019 Crystal Basics

    2/9

    On surface: slip can be seen in the form of slip steps along lines where

    the slip planes intersect the surface

    Example: Slip lines on the surface

    of a polycrystalline Ni specimen. Slip

    traces from two slip systems are visible

    A

    F

    F

    No shear stress if slip direction or slip plane normal are perpendicular

    to the tensile axis

    Maximum shear stress if slip plane and slip direction are under 45o

    to the tensile axis.In single crystals: Slip starts on slip system with

    highest resolved shear stress

    Driving force for slip: Tensile stress

    leads to resolved shear stress in slip system

    coscosR =

    nr

    sr

    AF/=R

  • 8/2/2019 Crystal Basics

    3/9

    How do lattice planes slip?

    Not: breaking all bonds simultaneously (this would imply a perfectly strong, but

    also perfectly brittle material!)

    Instead: slip involves motion of defects: Dislocations

    Side view of the motion of an edge dislocation

    Dislocation is characterized by slip vector (Burgers vector) and slip plane

    Burgers vector: when you make a closed circuit around a dislocation,

    there is a mismatch of one lattice vector. This is the Burgers vector

  • 8/2/2019 Crystal Basics

    4/9

    Type of dislocation depends on orientation of the dislocation line

    with respect to the Burgers vector.

    Screw dislocation: line is parallel to Burgers vector

    Edge dislocation: line is perpendicular to Burgers vector

    Some top views of dislocations: (blue = atoms above slip plane

    red = atoms below slip plane)

    an edge dislocation a screw dislocation

    A dislocation loop

    Dislocation = boundary ofslipped area

    (follow a vertical row of blue atoms

    to see the displacement

  • 8/2/2019 Crystal Basics

    5/9

    Stress required to move dislocations:

    1) Stress required to displace dislocation by one Burgers vector (stress to

    break bonds): Peierls stress

    2) Stress required to move dislocation across obstacles

    A dislocation pinned

    by a localized obstacle

    Introduction of dislocation obstacles: solution/precipitation hardening

    3) Stress required to overcome dislocation interactions: work hardening

    Dislocations: Internal stresses and dislocation interactions

    Dislocations create lattice distorsions and stress and strain fields

    Typically 5% of work done during deformation is stored as elastic energy

    of the dislocation stress fields

    Elastic energy per unit length of dislocation line:(Consequence: only dislocations with smallest Burgers vectors occur)

    Stress fields decay like where ris the vertical distance

    from the dislocation

    2

    L ~ GbE

    rGb /~

  • 8/2/2019 Crystal Basics

    6/9

    Stress fields lead to dislocation interactions

    Estimating the magnitude of dislocation interactions:

    Dislocation density

    Mean dislocation spacing

    Characteristic interaction stress

    areaunit

    pointsonintersectiofnumber

    eunit volum

    linesndislocatiooflength

    ==

    /1=d

    GbdGb ~/~

  • 8/2/2019 Crystal Basics

    7/9

    Rate of deformation by slip (shearing rate ):

    proportional to

    dislocation density

    Burgers vector modulus b

    dislocation velocity v

    Orowans equation:

    Dislocation velocity depends on stress, temperature and presence

    of dislocation obstacles

    Often: thermally activated process with activation energy

    Empirical relation for dislocation glide velocity:

    whereNG = stress exponent for glide (typically ~10), T temperature

    bvdt

    d

    =

    dt

    d

    E

    =kT

    E

    Gvv G

    NG

    exp0

    Dislocation climb:

    Dislocation can move perpendicular to its glide plane only if matter

    is added or removed: climb motion

    By climbing, dislocations can move past obstacles

    Climb is possible if diffusion processes lead to transport of matter

    Usually: vacancy diffusion

    Rate of climb depends on concentration and diffusivity of

    lattice vacancies : proportional to self-diffusion rate

    climb velocity:

    whereNC= stress exponent for climb (typically ~3),ESD activation energy

    for self-diffusion (formation + migration energies of vacancies)

    =kT

    E

    Gvv SD

    NC

    exp0

  • 8/2/2019 Crystal Basics

    8/9

    Diffusional creep:

    No motion of dislocations, deformation due to matter transport by

    point-defect diffusion

    Stress exponent is small (1 or 2)

    Often grain boundary diffusion: activation energy is small)

    Creep rate

    =kT

    E

    G

    D

    ND

    exp0

    &&

    Different deformation mechanisms are characterized by different

    activation energies and stress exponents

    Determination of stress exponents:

    Experiments at constant

    temperature but varying stress

    Plot log(deformation rate)

    vs. log(stress)

    Determination of activation energies:

    Experiments at constant stress

    but varying temperature

    Plot log(deformation rate)

    vs 1/temperature

  • 8/2/2019 Crystal Basics

    9/9

    Different deformation mechanisms operate in general simultaneously

    But: Usually one mechanism (the fastest) prevails

    Boundaries between different deformation

    mechanisms: Equate respective rates

    For rates in the form

    we get for the boundary between two mechanisms i and j

    hence

    choose semi-logarithmic representation of stress vs. temperature

    =kT

    E

    Gdt

    d iN

    i

    i

    i

    exp0

    &

    =

    kT

    E

    GkT

    E

    G

    j

    N

    j

    i

    N

    i

    ji

    expexp 00

    &&

    kT

    EE

    GNN

    ji

    ji

    j

    i

    =

    +

    ln)(ln0

    0

    &

    &

    Result: Deformation mechanism maps (Example: Ni-base superalloy)