Crypt Logic

Hello friends

This file is basically issued to make your mind to believe that crypt arithmetic is really easy if and only if you practice on it .try to solve questions after clearing your basics well from previous elit papers practice well from that den after that pick questions from

m4maths.com

and practice well keep patience with crypt problem until u get answer it may take 2-3 hr first time to solve and understand take your time don’t think dnt get frustrated that while solving you taking much time it happens for first time that you may take even whole day its ok your priority is to get in depth and understand how to hit and trial values after solving paper look in websites cryptarithmetic.in and many such like to see their way of solving also if you wish

I under admin elitmus pattern based 2014 super vision able to crack elitmus crypts problem I will give few steps and would explain in more better manner if you not satisfied with this then I request take help from admin he is excel is this

Aap sab log jab sabse pehle crypt problem ke bare me sunte hai toh sab yahi bolte honge ki ye bahut tough hai .. ya fir jab aap kisi se puchte honge ki elitmus me sabse tough part problem solving hota hai and usme bhi sabse jayada tough crypt hota fir ab online google karte honge abt crypt problems den u look it and u make your mind ohh its really tough kaise hoga ..

Friends nothing is impossible in this world

Coming to Crypt arithmetic …

See guys u have seen in m4maths.com or cryptarithmetic.in many crypts are given to solve but its not right approach to solve them because if you notice in elitmus there are three questions given with the crypt puzzle these questions are associated with your solution only

Copy right @ shivi bhatt

So first step whenever first time you try to solve crypt look back to previous year paper of elitmus

Crypt arithmetic ka koi pattern nahi hai ki follow kara jaye

Except few

Like

1. 5 x odd no = 52. 5x1= 5 3. 5x3=15 4. 5x7=35 5. 5x9=45

No guys I ‘ll make u understand in lay man language

Mene upar sirf ye hi kyu use kiya hai u must be thinking

Crypt me hare k alphabet ka ek hi value hota hai

Ex: a=1 so b!= 1 means B ka value and A ka value same nahi hoga and ye rule A ya B me hi nahi sabhi letters me apply hoga

Upar jo mene odd no ka funda bataya hai

Wo apko crypt me check karna hota hai

Like

A xB =A

Toh is ko dekhte hai apke dmag me ye ana chaiye ki ha A ka value 5 hona chaiye and B ka value koi bhi odd no hona chaiye

Now mene odd no . 1,3,5,7,9 hi kyu liya hai

Because digit 0to9 hi hote hai and isme odd no 1 ,3,5,7,9 hi hai

Toh ab mjhe AxB =A me hit and trial use karna hai


Friends crypt is totally Hit and trial koi method nahi hai particular its just u have to trouble your mind with hit and trial ab ye apko sochna hai ki mjhe number ko kis tarah set karna hai ki woe k hi value ho alphabet ki and repeat na ho so you have to check with

Another important think don’t directly start with solving crypt

first read all three question in your exam

and if you practicing at home as a beginner then first try to solve previous year paper and from their first read those three question don’t directly jump on solving crypt you may analyse that question and start thinking how I achieve this answer if value of A is asked and options 3,7,9,1 are given den its really easy because A can be 3,7,9,1 only

so half of your hit and trial solved here u got four number to hit and trial with A like this you should think while looking in to questions what ever it comes to you

another important rule or sequence u can see

even no. x6 = even no.

now I give a solution and make you understand one crypt problem basically I ‘ll give you the approach which you can use rest you find your own way to start crypt

yester day 12 oct 2014 exam I got this crypt

ABW* BPA______________HXRFFXWXWWHH______________WPHWBF

I’ll tell you my approach of solving


1.

First har ek multiply ko alag alag kardo means

Set 1-ABW x A = HXRF

Set 2-ABWxP=FXWX

Set 3- ABWxB=WWHH

Friends this I done because now you have three sets and if you choose any of set you will get any of single correct value your whole crypt is done

Set 1 ex I showed below look

Now see if you try to solve this

You will first see

Wxa=f

Ab apko hit and trial dalna hai isme ki


W= 3 a=4 : F= 12 hai so F is two digit number so hum 12 ka 2 lange yaani unit digit hamesha lena hai and 1 hamesha ya koi bhi tens digit carry ho jata hai next me,next me means ab AxB +1(carry) = R

Aise karte karte

AxA = HX aa rha hai toh number aise plugin kar ne hai jisse koi bhi number repeat na ho ..

Jab bhi value lena start karo ya toh

W=2 and A=3 se hit and trial lo

Ya W= 9 and A=8 coz 9,8 will cause carry 7 as 9x2= 72 ,7 is in tens place

Set -2

Set 3-


Friends set 1 mene bas explain kiya number ko kaise hit and trial karna hai

1. First crypt ko aise divide kardo as I have divided above in three parts

2. U need to pick any one set now you will think how you will pick that set which will give you answer fast and save your time also

3. After dividing in three parts start reading the three of questions what they asking

4. Suppose they ask value of A now you to pick that set where max number of A is been used or if ques is not like this it can be any and u dnt knw any approach look to any three of set and see which alphabet is used more in each set

5. Matlab ki teeno set me individually dekhna hoga dat kaunsa alphabet bahut bar repeat ho raha hai


6. Ex; 7. Is set me W teen bar repeat hua toh apko kuch bhi agar nahi pata

kaise start karna hai solve karna toh ye method bhi soch sakte ho kyu ki W ka value apko mil gya so u left with B,A ,H and if you solve this set fir aap jo main crypt hai usme ye values daal ke fir dekhna hai ki ab kaun kaun se value generate ho sakta hai in value ko use karke and you will solve whole crypt like this

8. When I started to solve above question 9. I looked into question and read each and every question coz our

moto is to get solution of those three question 10. I read third ques which says

W+W+H+H ???So isko dekhte hi u have to see in crypt where this value is their so looking in crypt problem This WWHH was in


So friends now you got to know that ABWxB= WWHHToh offcourse hai First wxb=h dekhogeFir again u seeBxb=hNow start thinkingKi bxw=h and bxb =h hai So aise kaunse number aane chaiye ki ye do condition satisfy ho jaye offcourse hit and trial hi use karna hai friends every body knws 1 to 9 table coz we have to use this only Isn’t simple Now start thinking First u may be thinking ohh 2x2=4( Bxb=h) so B can be 2But if you apply this 2 in Bxw=H u may not get solution coz condition is not satisfyingSo try to find that condition think your self it can be like this B=7,W=3


Bxw=H7x3=212 carry to BxB =HAnd H=1 for Bxw Means Bxw=h 7x3=1 (2 carry ) (7x3=21)one is used as value of H and 2 is used as carry for next multiplicationAb 2 carry hua hai toh now you have to think with 2 carry wat combination of number I can use to get value of H exactly u got in BxwMeans now you have to think H=1 kaise aayegi BxB and B value should not get changeSo friends above u have used B=7Now here also in BxB =7x7 means 49 +2(carry)=51 see in unit digit you got 1 which is exactly H=1 is in Bxw=h (h=1)And 5 is carry forward to next multiplicationSo you satis fied both condtion well and you got answer Now again W=3 u knowNow multiplying AxB +5(carry)=wwMeans AxB multiply aisa hona chaiye ki carry 5 add karke you should get ans as two digit with same value same value means WW = 2 digit number like (11,22,33,44…)Like this.Suppose A=2 but B=77x2=14+5=19 so its not satisfying equation coz we need WW means same digits..So take A=4 ,B=7AxB=7x4=28 +5(carry) this carry you got from previous multiplication that is 7x7+2=515 carry above hua AxB me jaise hum normally multiply karte hi hai and carry hote hai numbers waise hi .Now come to eqn7x4+5=28+5=33Hey you got answer WW=33 and


W value you used in first multiplication remember (B=7,W=3)Also satisfiesNow u got each individual value of each alphabet in set 3Lets conclude this valueA=4,H=1,B=7,W=3And your third ques saysW+W+H+H ??You have value of W and H Plugin those value here3+3+1+1 = 8You solved your 1 question in problem solving and now put these values in main crypt problem And den start thinking now what all values you can find by using these value Remember friends carry generation is also important in this After solving set oneWhen you apply these value in main crypt and you see this

R +X=7 (this R+X comes wen u done with multiplication part and u add as u do in normal multiplication)So think that it is originally 17 Why wen ever we adding it must have carry either 2 or 1 , 2 in case wen 9 number is used So while doing addition keep this thought in mind ohh it can be addition and unit place in above case is 7 and tens place is 1 so tens place always get carried forward to next multiplicationNow plugin these value in crypt


A=4,B=7,W=3,f=2,H=1,X=8

P=6,R=9In main crypt problem you will get your answerHope this will help all And if you not able to understand this discuss with admin he will help you out surely

Thank You


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Crypt Logic