Chpt09SG.vapour Power Cycle

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    Chapter 9-1

    Chapter 9: Vapor and Combined Power Cycles

    We consider power cycles where the working fluid undergoes a phase

    change. The best example of this cycle is the steam power cycle where

    water (steam) is the working fluid.

    Carnot Vapor Cycle

    The heat engine may be composed of the following components.

    Steam Power Cycle

    Turbine

    2

    Pump

    Condenser

    Wturb

    1

    3

    QI n

    Qout

    4

    Boiler

    Wp

    Heat source

    TH> TL

    QH

    QL

    Heat Sink

    TL

    Heat

    engineWnet

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    Chapter 9-2

    The working fluid, steam (water), undergoes a thermodynamic cycle from

    1-2-3-4-1. The cycle is shown on the following T-sdiagram.

    The thermal efficiency of this cycle is given as

    th Carnotnet

    in

    out

    in

    L

    H

    W

    Q

    Q

    Q

    T

    T

    , = =

    =

    1

    1

    Note the effect of THand TLon th, Carnot.

    The larger the THthe larger the th, Carnot The smaller the TLthe larger the th, Carnot

    0.0 1.0 2.0 3.0 4.0 5.0 6.0 7.0 8.0 9.0 10.0

    0

    100

    200

    300

    400

    500

    600

    700700

    s [kJ/kg-K]

    T

    [C]

    6000 kPa

    100 kPa

    Carnot Vapor Cycle Using Steam

    1

    2 3

    4

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    Chapter 9-3

    To increase the thermal efficiency in any power cycle, we try to increase the

    maximum temperature at which heat is added.

    Reasons why the Carnot cycle is not used:

    Pumping process 1-2 requires the pumping of a mixture of saturatedliquid and saturated vapor at state 1 and the delivery of a saturated liquid

    at state 2.

    To superheat the steam to take advantage of a higher temperature,

    elaborate controls are required to keep THconstant while the steam

    expands and does work.

    To resolve the difficulties associated with the Carnot cycle, the Rankine

    cycle was devised.

    Rankine Cycle

    The simple Rankine cycle has the same component layout as the Carnot

    cycle shown above. The simple Rankine cycle continues the condensation

    process 4-1 until the saturated liquid line is reached.

    Ideal Rankine Cycle Processes

    Process Description1-2 Isentropic compression in pump

    2-3 Constant pressure heat addition in boiler

    3-4 Isentropic expansion in turbine

    4-1 Constant pressure heat rejection in condenser

    The T-sdiagram for the Rankine cycle is given below. Locate the processes

    for heat transfer and work on the diagram.

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    Chapter 9-4

    Example 9-1

    Compute the thermal efficiency of an ideal Rankine cycle for which steam

    leaves the boiler as superheated vapor at 6 MPa, 350oC, and is condensed at

    10 kPa.

    We use the power system and T-sdiagram shown above.

    P2=P3= 6 MPa = 6000 kPa

    T3= 350oC

    P1=P4= 10 kPa

    Pump

    The pump work is obtained from the conservation of mass and energy for

    steady-flow but neglecting potential and kinetic energy changes and

    assuming the pump is adiabatic and reversible.

    ( )

    m m m

    m h W m h

    W m h h

    pump

    pump

    1 2

    1 1 2 2

    2 1

    = =

    + =

    =

    0 2 4 6 8 10 1212

    0

    100

    200

    300

    400

    500

    s [kJ/kg-K]

    T[C]

    6000 kPa

    10 kPa

    Rankine Vapor Power Cycle

    1

    2

    3

    4

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    Chapter 9-6

    w v P P

    m

    kg kPa

    kJ

    m kPa

    kJ

    kg

    pump =

    =

    =

    1 2 1

    3

    30 00101 6000 10

    6 05

    ( )

    . ( )

    .

    Now, h2is found from

    h w h

    kJ

    kg

    kJ

    kg

    kJ

    kg

    pump2 1

    6 05 19183

    197 88

    = +

    = +

    =

    . .

    .

    Boiler

    To find the heat supplied in the boiler, we apply the steady-flow

    conservation of mass and energy to the boiler. If we neglect the potentialand kinetic energies, and note that no work is done on the steam in the boiler,

    then

    ( )

    m m m

    m h Q m h

    Q m h h

    in

    in

    2 3

    2 2 3 3

    3 2

    = =

    + =

    =

    We find the properties at state 3 from the superheated tables as

    P kPa

    T C

    h kJ

    kg

    s kJ

    kg K

    o

    3

    3

    3

    3

    6000

    350

    30430

    6335

    =

    =

    UVW

    =

    =

    R

    S||

    T||

    .

    .

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    Chapter 9-7

    The heat transfer per unit mass is

    q

    Q

    m h h

    kJ

    kg

    kJ

    kg

    in

    in

    = =

    =

    =

    ( . . )

    .

    3 2

    30403 19788

    28452

    Turbine

    The turbine work is obtained from the application of the conservation of

    mass and energy for steady flow. We assume the process is adiabatic and

    reversible and neglect changes in kinetic and potential energies.

    ( )

    m m m

    m h W m h

    W m h h

    turb

    turb

    3 4

    3 3 4 4

    3 4

    = =

    = +

    =

    We find the properties at state 4 from the steam tables by notings4=s3and

    asking three questions.

    at P kPa s kJ

    kg Ks

    kJ

    kg K

    is s s

    is s s s

    is s s

    f g

    f

    f g

    g

    4

    4

    4

    4

    10 0 6483 81502= =

    =