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Chapter 9 Chapter 9 Balancing Balancing Equations Equations Part 1 Part 1

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Chapter 9. Balancing Equations Part 1. Terms. A chemical reaction is the process by which one or more substances are changed into new substances. A chemical equation uses symbols to represent a chemical reaction. A reactant or reagent is a substance used to begin a chemical reaction. - PowerPoint PPT Presentation

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Page 1: Chapter 9

Chapter 9Chapter 9Balancing EquationsBalancing Equations

Part 1Part 1

Page 2: Chapter 9

Terms• A chemical reaction is the process by which

one or more substances are changed into new substances.

• A chemical equation uses symbols to represent a chemical reaction.

• A reactant or reagent is a substance used to begin a chemical reaction.

• A product is a substance that forms during chemical reaction.

Page 3: Chapter 9

Potassium metal is added to water.

Page 4: Chapter 9

K + HK + H22OO

Page 5: Chapter 9

Water can also be written HOHWater can also be written HOH

Page 6: Chapter 9

K + HOHK + HOH

Page 7: Chapter 9

What are the products?

Page 8: Chapter 9

What gas might be produced?

Page 9: Chapter 9

What has happened to the liquid?

Page 10: Chapter 9

The litmus test

• Blue litmus paper turns red under acidic conditions.

• Red litmus paper turns blue under basic conditions.

• If both litmus tests result in no change then the solution is neutral.

Page 11: Chapter 9

The resulting liquid is a base.

Most common bases contain hydroxide (OHˉ).

Page 12: Chapter 9

What are the products?

Page 13: Chapter 9

K + HK + H22O → KOH + HO → KOH + H

→+

What is wrong here?What is wrong here?

Page 14: Chapter 9

K + HK + H22O → KOH + HO → KOH + H

→+

H,O,N,Cl,F,I,Br mean H should be HH,O,N,Cl,F,I,Br mean H should be H22

Page 15: Chapter 9

K + HK + H22O → KOH + HO → KOH + H

→+

H,O,N,Cl,F,I,Br mean H should be HH,O,N,Cl,F,I,Br mean H should be H22

22

Page 16: Chapter 9

K + HK + H22O → KOH + HO → KOH + H22

→+

Now what is wrong?Now what is wrong?

Page 17: Chapter 9

Because of the principle of the Because of the principle of the

conservation of matterconservation of matter, ,

an an equation must be equation must be balancedbalanced..

It must have the same It must have the same number and type of atoms number and type of atoms

on both sides of the equation.on both sides of the equation. Lavoisier, 1788Lavoisier, 1788

Chemical EquationsChemical Equations

Page 18: Chapter 9

– When balancing a chemical reaction you may add coefficients in front of the compounds to balance the reaction, but

you may notnot change the subscripts.

• Changing the subscripts changes the compound.

Balancing EquationsBalancing Equations

Page 19: Chapter 9

Subscripts vs. Subscripts vs. CoefficientsCoefficients

• The subscripts The subscripts tell you how tell you how many atoms of many atoms of a particular a particular element are in a element are in a compound. The compound. The coefficient tells coefficient tells you about the you about the quantity, or quantity, or number, of number, of molecules of molecules of the compound.the compound.

Page 20: Chapter 9

K + HOH → KOH + HK + HOH → KOH + H22

→+

We must balance the equation.We must balance the equation.

Page 21: Chapter 9

There are four basic steps to balancing a chemical equation.1. Write the correct formula for the reactants and the

products. DO NOT TRY TO BALANCE IT YET! You must write the correct formulas first. And most importantly, once you write them correctly DO NOT CHANGE THE FORMULAS!

2. Find the number of atoms for each element on the left side. Compare those against the number of the atoms of the same element on the right side.

3. Determine where to place coefficients in front of formulas so that the left side has the same number of atoms as the right side for EACH element.

4. Check your answer to see if:– The numbers of atoms on both sides of the

equation are now balanced.– The coefficients are in the lowest possible whole

number ratios. (reduced)

Steps to Balancing Steps to Balancing EquationsEquations

Page 22: Chapter 9

_K + _HOH → _KOH + _H_K + _HOH → _KOH + _H22

Page 23: Chapter 9

2K + 2HOH → 2KOH + H2K + 2HOH → 2KOH + H22

Page 24: Chapter 9

2K + 2H2K + 2H22O → 2KOH + HO → 2KOH + H22

→+

Consider the form of these substances.Consider the form of these substances.

Page 25: Chapter 9

2K + 2H2K + 2H22O → 2KOH + HO → 2KOH + H22

→+

solid

liquid

gas

Page 26: Chapter 9

2K2K(s)(s) + 2H + 2H22OO(l)(l) → 2KOH + H → 2KOH + H2(g)2(g)

→+

solid

liquid

gas

What about the KOH?What about the KOH?

Page 27: Chapter 9

potassium hydroxide (KOH) is a solid at room temperature.

• However KOH is soluble in water. Substances dissolved in water are said to be aqueous and are indicated as such by an (aq) in the equation.

Page 28: Chapter 9

2K2K(s)(s) + 2H + 2H22OO(l)(l) → 2KOH + H → 2KOH + H2(g)2(g)

→+

solid

liquid

gas

aqueous solutionaqueous solution

(aq)(aq)

Page 29: Chapter 9

• Solid (cr) or (s)

• Precipitate (↓)

• “Heated”

• Escaping gas () • Catalyst H2SO4

• A word may be written above an arrow to indicate something is necessary for the reaction to occur.

Other Symbols Used in Other Symbols Used in EquationsEquations

electricity