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Course Outline : Work Done by a Constant Force Work Done by aVarying Force Kinetic Energy and theWork-Kinetic EnergyTheorem Power Potential Energy of a System (Will be discussed in Chapter 8) Conservative and Non-conservative Forces (Will be discussed in Chapter 8) Chapter 7 Energy of a System

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Page 1: Chapter 7 Energy of a Systemunitenphyf115.weebly.com/.../74480909/chapter_7_phyf115.pdf7.5 Kinetic Energy One possible result of work acting as an influence on a system is that the

Course Outline :

Work Done by a Constant Force

Work Done by aVarying Force

Kinetic Energy and theWork-Kinetic EnergyTheorem

Power

Potential Energy of a System (Will be discussed in Chapter 8)

Conservative and Non-conservative Forces (Will be discussed in Chapter 8)

Chapter 7 Energy of a System

Page 2: Chapter 7 Energy of a Systemunitenphyf115.weebly.com/.../74480909/chapter_7_phyf115.pdf7.5 Kinetic Energy One possible result of work acting as an influence on a system is that the

What is Systems ?•A valid system:

– May be a single object or particle

– May be a collection of objects or particles

– May be a region of space

– May vary with time in size and shape

•A force applied to an object in empty space

– System is the object

– Its surface is the system boundary

– The force is an influence on the system from its environment

that acts across the system boundary.

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7.2 Work

•The work, W, done on a system by an agent exerting a constant force on the system is the product of the magnitude F of the force, the magnitude Dr of the displacement of the point of application of the force, and cos q, where q is the angle between the force and the displacement vectors.

W = F Dr cos q

– The meaning of the term work is distinctly different in physics than in everyday meaning.

– Work is done by some part of the environment that is interacting directly with the system.

– Work is done on the system.

Section 7.2

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W = F Dr cos q The displacement is that of the

point of application of the force.

A force does no work on the object if the force does not move through a displacement.

The work done by a force on a moving object is zero when the force applied is perpendicular to the displacement of its point of application.

Section 7.2

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Work Example

The normal force and the

gravitational force do no work

on the object.

cos q = cos 90°= 0

(perpendicular)

The force is the only force

that does work on the object.

F

Section 7.2

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F

The sign of the work depends on the direction of the force relative to the displacement.

Work is positive when projection of onto is in the same direction as the displacement.

Work is negative when the projection is in the opposite direction.

The work done by a force can be calculated, but that force is not necessarily the cause of the displacement.

Work is a scalar quantity.

The unit of work is a joule (J)

1 joule = 1 newton . 1 meter = kg ∙ m² / s²

J = N ·m

Dr

Section 7.2

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Work Is An Energy Transfer

This is important for a system approach to solving a problem.

If the work is done on a system and it is positive, energy is transferred to the system.

If the work done on the system is negative, energy is transferred from the system.

If a system interacts with its environment, this interaction can be

described as a transfer of energy across the system boundary.

This will result in a change in the amount of energy stored in

the system.

Section 7.2

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Example (7.1) : Mr. Clean

A man cleaning a floor pulls a vacuum cleaner with a force of magnitude F =50.0 N at an angle of 30.0o with the horizontal (Fig. (7.4a)). Calculate the workdone by the force on the vacuum cleaner as the vacuum cleaner is displaced 3.00m to the right.

Page 9: Chapter 7 Energy of a Systemunitenphyf115.weebly.com/.../74480909/chapter_7_phyf115.pdf7.5 Kinetic Energy One possible result of work acting as an influence on a system is that the

Example (7.2) : The Scalar Product

The vector A and B are given by A =2i + 3j and B =-i + 2j. (a) Determine the scalar productA ·B.b) Find the angle between A and B

Example (7.3) : Work Done by a Constant Force

A particle moving in the xy plane undergoes a displacement d = (2.0i + 3.0j) m as aconstant force F = (5.0i + 2.0j) N acts on the particle. Calculate the work done by force.

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7.3 Work Done By Varying Force

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Example (7.4) : Calculating Total Work Done from a Graph

A force acting on a particle varies with x, as shown in Figure (7.8). Calculate the workdone by the force as the particle moves from x = 0 to x = 6.0 m.

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Work Done By A Spring

A model of a common physical system for which the force varies with position.

The block is on a horizontal, frictionless surface.

Observe the motion of the block with various values of the spring constant.

Section 7.4

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Spring Force (Hooke’s Law)

The force exerted by the spring is

Fs = - kx x is the position of the block with respect to the equilibrium position (x = 0).

k is called the spring constant or force constant and measures the stiffness of the spring.

k measures the stiffness of the spring.

This is called Hooke’s Law.

Section 7.4

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The vector form of Hooke’s Law is

When x is positive (spring is stretched), F is negative

When x is 0 (at the equilibrium position), F is 0

When x is negative (spring is compressed), F is positive

Section 7.4

F = Fx i – kx i

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Hooke’s Law, final

The force exerted by the spring is always directed opposite to the displacement from

equilibrium.

The spring force is sometimes called the restoring force.

If the block is released it will oscillate back and forth between –x and x.

Section 7.4

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Work Done by a Spring

Identify the block as the system.

Calculate the work as the block moves from xi = - xmax to xf = 0.

The net work done as the block moves from -xmax to xmax is zero

Section 7.4

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2 21 1

2 2

f

i

x

s i fx

W kx dx kx kx

Assume the block undergoes an arbitrary displacement from x

= xi to x = xf.

The work done by the spring on the block is

If the motion ends where it begins, W = 0

Section 7.4

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Spring with an Applied Force

Suppose an external agent, Fapp, stretches the spring.

The applied force is equal and opposite to the spring force.

Work done by Fapp as the block moves from –xmax to x = 0 is equal to

-½ kx2max

For any displacement, the work done by the applied force is

2 21 1

2 2

f

i

x

app f ix

W kx dx kx kx

app app sF kx kx垐 ? F i F i i

Section 7.4

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E7.5a)If a spring is stretch 2.0 cm by a suspended object having a mass of 0.55kg, what is the force constant of the spring?b)How much work is done by the spring on the object as it stretches through this distance

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7.5 Kinetic Energy

One possible result of work acting as an influence on a system is that the system changes its speed.

The system could possess kinetic energy.

Kinetic Energy is the energy of a particle due to its motion.

K = ½ mv2

K is the kinetic energy

m is the mass of the particle

v is the speed of the particle

A change in kinetic energy is one possible result of doing work to transfer energy into a system.

Section 7.5

Page 21: Chapter 7 Energy of a Systemunitenphyf115.weebly.com/.../74480909/chapter_7_phyf115.pdf7.5 Kinetic Energy One possible result of work acting as an influence on a system is that the

Calculating the work:

f f

i i

f

i

x x

extx x

v

extv

ext f i

ext f i

W F dx ma dx

W mv dv

W mv mv

W K K K

2 21 1

2 2

D

Section 7.5

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Work-Kinetic Energy Theorem

The Work-Kinetic Energy Theorem states Wext = Kf – Ki = ΔK

When work is done on a system and the only change in the system is in its speed, the net

work done on the system equals the change in kinetic energy of the system.

The speed of the system increases if the work done on it is positive.

The speed of the system decreases if the net work is negative.

Also valid for changes in rotational speed

The work-kinetic energy theorem is not valid if other changes (besides its speed) occur in

the system or if there are other interactions with the environment besides work.

The work-kinetic energy theorem applies to the speed of the system, not its velocity.

Section 7.5

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Example (7.6) : A Block Pulled on a Frictionless Surface

A 6.0-kg block initially at rest is pulled to the right along a horizontal, frictionless surfaceby a constant horizontal force of 12 N. Find the speed of the block after it has moved 3.0m.

n vf

F

dmg

(a)

n vf

F

dmg

fk

(b)

Figure (7.16)

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7.5 Power

• Power is the time rate of doing work.

• Practically, it is important to know that how much work the

vehicles do, but also how rapidly the work is done.

• For example,

There is two types of automobile engine which are the normal

engine and the optional engine. Both of them do the same

amount of work, but the optional engine with highest-priced take

less time to complete the work.

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Example

An elevator car has a mass of 1000kg and is carrying passengers having

combined mass of 800 kg. A constant frictional force of 4000N retards

its motion upward.

a) What must be the minimum delivered by the motor to lift the elevator

at a constant speed of 3.00 m/s ?

b) What power must the motor deliver at the instant its speed is v if it is

designed to provide an upward acceleration of 1.00 m/s2 ?