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7/27/2019 Chapter 2 - Part 1 Pressure
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CHAPTER 2
Part 1:PressurePart 1:Pressure
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Fluid Statics Fluid Statics deals with problems
associated with fluids at rest.
In fluid statics, there is no relativemotion between adjacent fluid layers.
Therefore, there is no shear stress inthe fluid tr in to deform it.
The only stress in fluid statics isnormal stress
Normal stress is due to pressure
Variation of pressure is due only to the
weight of the fluid fluid statics is onlyrelevant in presence of gravity fields.
Applications: Floating or submergedbodies, water dams and gates, liquidstorage tanks, etc. 2
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Pressure Pressure is defined as anormal
force exerted by a fluid per unitarea.
Unit of pressure is N/m2, which iscalled pascal (Pa).
P = F/A
Since the unit Pa is too small forpressures encountered in practice,
kilopascal(1 kPa = 103 Pa) and
megapascal(1 MPa = 10
6
Pa) arecommonly used.
Other units includebar,atm,
kgf/cm2
, lbf/in2
=psi.3
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Pressure at a PointPressure ?
Indicating the normal force per unitarea at a given point acting on agiven plane within the fluid mass ofinterest.
ow t e pressure at a po nt var eswith the orientation of the planepassing through the point ?
In fluid at rest, pressure at any pointis the same at all direction.
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The pressure at a point in a fluid atrest, or in motion, is independent ofthe direction as long as there are noshearing stresses present.
Pressure at any point in a fluid is thesame in all directions.
Pressure has a magnitude, but not aspecific direction, and thus it is ascalar quantity.
The result is known asPascals lawnamed in honor ofBlaise Pascal(1623-1662).
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Absolute, gauge, andvacuum pressures
Actual pressure at a give point
is called the absolute pressure.
Most pressure-measuring
devices are calibrated to read
,
therefore indicate gauge
pressure,
Pgauge= Pabs - Patm.
Pressure below atmospheric
pressure are called vacuum
pressure, Pvac= Patm - Pabs. 6
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Absolute, gauge, and
vacuum pressures
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Atmospheric Pressure, Patm
* Pressure due to weight of airabove it.
* Standard value (1 atm =)
10.35 mH2O water (34 ftH2O)
760 mmHg
14.7 si
101.3 kN/m2
can be measured by P = gh
* Fluid pressure at free surfaceis equal to atmosphericpressure.
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Gauge Pressure, Pg
* Measured using pressure gauge.
* Can be positive (above atm pressure) ornegative (below atm pressure)
* Gauge negative pressure is referred tosuction pressure ofvacuum pressure.
ero pressure means e pressure sequal to atmospheric pressure.
* Gauge pressure units:
N/m2
gaugepsig
kPa gauge
barg
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Pressure Head of Fluid
* Pressure head of fluid is a pressure and it isinterpreted as the height of a column offluid of specific weight required.
* A basic equation is a relationship amongpressure, density and depth. P = gh
* Consider an element of fluid as shownbelow.
dA : cross sectional area of element : fluid density
P : pressure
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In equilibrium;
Upward Force = Downward Force
(P + dP) dA = PdA + mg
dPdA = mg
But;
m = v (v = element volume = dAdh)
dPdA = vg = gdAdh
dP = gdh
Integrated it;
P2 - P1 = g (h2 - h1)
=2
1
2
1
h
h
P
PdhgdP
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But;
h2 - h1 = h
Then
P2 - P1 = g h
If h1 = 0 and P1 = 0 (atmospheric pressure), then
P2 = gh
Based on the above equation, pressure isproportional to depth ( P h ) regardless of shapeof container.
O In pressure head, the above equation become
and its unit is in e.g.; mmHg or mmH20
21 pph
=
12
Specific weight
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Variation of Pressurewith Depth
Pressure in a fluid at rest is
independent of the shape of the
container.
Pressure is the same at all points on
a horizontal plane in a given fluid.
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Absolute pressure (atm)
on diver at 100 ft?
( ),2 3 21
998 9.81 1003.28
1
gage
kg m mP gz ft
m s ft
atm
= =
Scuba Diving and HydrostaticPressure
100 ft
1
Danger of emergency
ascent?
,2 ,2
. .
101.3252.95 1 3.95
abs gage atm
kPaP P P atm atm atm
= + = + =
2
1 1 2 2
1 2
2 1
3 . 9 54
1
P V P V
V P a tm
V P a tm
=
= =
Boyles lawIf you hold your breath on ascent, your lungvolume would increase by a factor of 4,would result in embolism and/or death.
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Example;
Change a pressure of 350 kN/m2 gauge into pressure
head of water and mercury.
Water
OHmsmxmkg
mNx
g
Ph
water
223
23
68.35/81.9/1000
/10350===
ercury
Hgmsmxmkg
mNx
g
Ph
mercury
62.2/81.9/13600
/1035023
23
===
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Transmission of Fluid Pressure
* If a fluid remaining constant in the horizontal direction,the pressure applied to a confined fluid increases thepressure throughout by the same amount. This iscalled Pascals Law.
* The transmission of fluid pressure throughout astationary fluid is the principle upon which manyhydraulic devices are based.
P1 = P2
Note : The pressure force exerted by the fluid is
always normal to the surface at the
specified points
11
222211 F
A
AFpAFpAF ===
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Pascals Law
Pressure applied to aconfined fluid
increases the pressure
throughout by the
same amount.
In picture, pistons areat same height:
Ratio A2/A1 is called
ideal mechanical
advantage
1 2 2 21 2
1 2 1 1
F F F AP P
A A F A= = =
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Example;Example;
Dimension of hydraulic jack is shown in figure below.
If a force of 100 N applied onto the jet handle,determine a maximum force F2 would be support.
Free Body Diagram of handle
100 N x 33 cm - F1 x 3 cm = 0
F1 = (100 N x 0.33 m/0.03 m) = 1100 N
100 N
F1
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Pressure at small piston (left site);
Based on transmission principle;
26
2
1
1
1m/N10x22.6
4
d
N1100
A
FP =
==
Therefore;
kN22.124
dx10x22.6APF
2
6
222===
19
P1 = P2 = 6.22 x 106
N/m2
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ExampleExample;;
Oil with a specific gravity of 0.9 is used
in a hydraulic apparatus as shown in
figure below. If a gauge indicate that a
pressure of 2.15 bar, determine thevalue of W so that the system is in
equilibrium condition.
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At x x
2
2325
'
/232658
)2)(/81.9)(/1000(9.0/1015.2
mN
msmmkgmNx
ghPP oilgaugex
=
+=
+=
AreaxessureForce Pr=
Based on transmission principle;
Px = Px' = 232658 N/m2
N66.730916
)2(4
xm/N232658 22
=
=
kg30.74507
s/m81.9
N66.730916W
2==
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