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Chapter 12. Static Equilibrium and Elasticity. Introduction. Equilibrium- a condition where an object is at rest OR its center of mass moves with a constant velocity. Static Equilibrium (former def.) is a common practice in engineering disciplines, critical for civil, arch, and mech eng. - PowerPoint PPT Presentation
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Chapter 12
Static Equilibriumand Elasticity
Introduction
• Equilibrium- a condition where an object is at rest OR its center of mass moves with a constant velocity.
• Static Equilibrium (former def.) is a common practice in engineering disciplines, critical for civil, arch, and mech eng.
• Elasticity- we will look at how objects deform under load conditions
12.1
• The conditions for Equilibrium– Translation Eq. (from Ch 5)
• Only works (by itself) for objects modeled as particles (point masses)
– Rotational Eq- now that we can deal with extended objects…(about ANY axis)
• Implies that the object is either not rotating or rotating with a constant speed.
0F
0
12.1
• We will be looking at Static Equilibrium only, which implies both
• Quick Quizzes p 364
0cmv 0
12.1
• The vector expressions result in six scalar expressions (three for each axis for both Force and Torque)
• We will keep motion limited to a single 2D plane for practical purposes.
0 xF 0 yF 0 z
12.1
• If the object is in translational equilibrium and the net torque is zero about one axis, then the net torque is zero about any axis.
• In other words, when problem solving, any location can be chosen for the axis of rotation.
12.2 More on Center of Gravity
• The location of a force’s application is critical in evaluating equilibrium conditions.
• The force of gravity on a given object (assuming a constant gravitational field) acts at the center of mass.
• One single gravitational force at the center of mass is equivalent to the sum of all the individual gravitational forces on each particle.
12.2
12.2
• The center of gravity can be located via a number of methods both experimental and calculated.
• Be careful not to confuse an object’s center of gravity and a system’s center of gravity.
• A system will balance so long as the support is underneath the center of gravity of the system.
• Quick Quiz p 366
12.3 Examples of Static Equilibrium
• Remember
• Examples 12.1-12.5
0 xF 0 yF 0 z
12.4 Elastic Properties of Solids
• Up to this point we have assumed solid objects remain rigid under external forces.
• In reality solid objects deform under external forces.
• Two Key Ideas– Stress- the amount of force acting on an object per
unit area– Strain- the result of stress, a measure of
deformation.
12.4
• Materials can be rated with an Elastic Modulus, a constant of proportionality between stress and strain. – Depends on the material, and type of deformation– Generally determined by
– Relates what is done to an object, to how the object responds.
StrainStressModulus Elastic
12.4
• Different Types of Deformation result in unique elastic moduli.– Young’s Modulus- resistance of a solid to changes
in length.– Shear Modulus- resistance of a solid to a shift in
parallel planes.– Bulk Modulus- resistance of a solids or fluids to
changes in volume (opposite of compressibility)/
12.4
• Young’s Modulus- (Tensile Modulus)– The bar is stretch from aninitial length Li by a change in length ΔL.– The Stress on the bar is theratio of the tension force andthe cross sectional area of the bar.
12.4
– The strain on the bar is the ratio of the change in length and the initial length.
• Youngs Modulus also applies to compression forces.
iLLAFY
Strain TensileStress Tensile
12.4
• Objects can be stressed to their elastic limit, at which point it will be permanently deformed, and beyond to their breaking point.
12.4
• Shear Modulus– When a force acts on theface of an object parallel to a another face held fixed byan opposite force. – The stress is the ratio of force and parallel surface area.
12.4
– The strain the is ratio of displacement of the sheared face, and the height of the object.
hxAFG
StrainShear StressShear
12.4
• Bulk Modulus– When a force of uniformmagnitude is applied perpendicularly to all surfaces.– The object will undergo a change in volume but not shape.– The volume stress is the ratio of the Force to the
surface area of the object. (Also known as pressure).
12.4
– The volume strain is the ratio of the change in volume and the initial volume.
– The negative indicates that an increase in pressure, will result in a decrease volume.
• The inverse of Bulk Modulus is compressibility, and is more commonly used.
ii VVP
VVAFB
Strain VolumeStress Volume
BK 1
12.4
• Prestressed Concrete
• Quick Quizzes p 375• Examples 12.6-12.7