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Chapter 11
Counting Methods
© 2008 Pearson Addison-Wesley.All rights reserved
© 2008 Pearson Addison-Wesley. All rights reserved
11-2-2
Chapter 11: Counting Methods
11.1 Counting by Systematic Listing
11.2 Using the Fundamental Counting Principle
11.3 Using Permutations and Combinations
11.4 Using Pascal’s Triangle
11.5 Counting Problems Involving “Not” and
“Or”
© 2008 Pearson Addison-Wesley. All rights reserved
11-2-3
Chapter 1
Section 11-2Using the Fundamental Counting
Principle
© 2008 Pearson Addison-Wesley. All rights reserved
11-2-4
Using the Fundamental Counting Principle
• Uniformity and the Fundamental Counting Principle
• Factorials
• Arrangements of Objects
© 2008 Pearson Addison-Wesley. All rights reserved
11-2-5
Uniformity Criterion for Multiple-Part Tasks
A multiple-part task is said to satisfy the uniformity criterion if the number of choices for any particular part is the same no matter which choices were selected for the previous parts.
© 2008 Pearson Addison-Wesley. All rights reserved
11-2-6
Fundamental Counting Principle
When a task consists of k separate parts and satisfies the uniformity criterion, if the first part can be done in n1 ways, the second part can be done in n2 ways, and so on through the k th part, which can be done in nk ways, then the total number of ways to complete the task is given by the product
1 2 3 .kn n n n
© 2008 Pearson Addison-Wesley. All rights reserved
11-2-7
Example: Two-Digit Numbers
How many two-digit numbers can be made from the set {0, 1, 2, 3, 4, 5}? (numbers can’t start with 0.)
Solution
Part of Task Select first digit Select second digit
Number of ways 5
(0 can’t be used)
6
There are 5(6) = 30 two-digit numbers.
© 2008 Pearson Addison-Wesley. All rights reserved
11-2-8
Example: Two-Digit Numbers with Restrictions
How many two-digit numbers that do not contain repeated digits can be made from the set {0, 1, 2, 3, 4, 5} ?
SolutionPart of Task
Select first digit
Select second digit
Number of ways
5 5
(repeated digits not allowed)
There are 5(5) = 25 two-digit numbers.
© 2008 Pearson Addison-Wesley. All rights reserved
11-2-9
Example: Two-Digit Numbers with Restrictions
How many ways can you select two letters followed by three digits for an ID?
SolutionPart of Task
First letter
Second letter
Digit Digit Digit
Number of ways
26 26 10 10 10
There are 26(26)(10)(10)(10) = 676,000 IDs possible.
© 2008 Pearson Addison-Wesley. All rights reserved
11-2-10
Factorials
For any counting number n, the product of all counting numbers from n down through 1 is called n factorial, and is denoted n!.
© 2008 Pearson Addison-Wesley. All rights reserved
11-2-11
Factorial Formula
For any counting number n, the quantity n factorial is given by
! ( 1)( 2) 2 1.n n n n
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11-2-12
Example:
Evaluate each expression.
a) 4! b) (4 – 1)! c)5!
3!Solution
a) 4! 4 3 2 1 24
b) (4 1)! 3 2 1 6
5! 5 4 3!c) 5 4 20
3! 3!
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11-2-13
Definition of Zero Factorial
0! 1
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Arrangements of Objects
When finding the total number of ways to arrange a given number of distinct objects, we can use a factorial.
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Arrangements of n Distinct Objects
The total number of different ways to arrange n distinct objects is n!.
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Example: Arranging Books
How many ways can you line up 6 different books on a shelf?
Solution
The number of ways to arrange 6 distinct objects is 6! = 720.
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11-2-17
Arrangements of n Objects Containing Look-Alikes
The number of distinguishable arrangements of n objects, where one or more subsets consist of look-alikes (say n1 are of one kind, n2 are of another kind, …, and nk are of yet another kind), is given by
1 2
!.
! ! !k
n
n n n
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11-2-18
Example: Distinguishable Arrangements
Determine the number of distinguishable arrangements of the letters of the word INITIALLY.
Solution
9!30240.
3!2!9 letters total
3 I’s and 2 L’s