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1 Channel Element resource model
1.1 Number of users per site If the number of users (simultaneously connected) per site is known the following expression can be applied to calculate the number of channel elements needed:
{nCE ,UL=∑i
N i ΓUL , i ¿¿¿¿
where
Ni is the number of currently connected users per site for service i.
i is the channel element factor for service i.
1.2 Channel element cost modelTable 1 gives an example of channel element factors, showing the channel element consumption for different services on different radio bearers. Please note that this is an example and the cost-model may differ depending on Node B and CE licensing.
Table 1. Example of channel element factors
Service CE factor
UL DL
AMR12.2 1 1
PS64 4 2
PS128 8 4
PS384 16 8
2 Examples
2.1 R99, only conversational traffic admitted in busy hour
2.1.1 Purpose
The purpose of this example is to show calculations for a mix of conversational and R99 best effort traffic. This example assumes that only conversational traffic
is admitted in busy hour. This means a throughput degradation for best effort traffic.
For simplicity there is only one type of conversational traffic (speech). This example assumes maximum impact of Enhanced Soft Congestion, which means that only 64 kbps radio bearers will be used for best effort traffic. Re-transmissions are included in the best effort traffic. The grade of Service (GoS) for conversational and best effort traffic is assumed to be 2%.
For simplicity complete partitioning is used, which gives an overestimation of the required resources.
2.1.2 Traffic input
Table 2. Example 1: traffic input
Service RAB RB
Offered traffic per site, A
Activity factor KAF
SHO factor κUL DL
Speech Speech 6 Erlang 6 Erlang - 0.3
R99 best effort PS data
PS interactive64, 128,
38450MB 500 MB 0.7 0.3
2.1.3 Identifying the number of simultaneous users
Step 1: Converting best effort traffic to Erlang
A64/64,UL = ((5010000008)/3600)/(640000.7) = 2.5 Erlang
A64/64,DL = ((50010000008)/3600)/(640000.7) = 24.8 Erlang
Step 2: Max traffic
A64/64 = max(24.8, 2.5) = 24.8 Erlang
Step 3: Soft handover factor
ASHO,Speech = 61,3 = 7.8 Erlang
ASHO,64/64 = 24.81,3 = 32.2 Erlang
Step 4: Estimating the maximum number of simultaneous users from offered traffic
MSpeech = ErlangB(7.8, 0.02) = 14
2.1.4 Calculating number of CEs
Step 1a: Calculating nCE,Peak per service
nCE,Speech,UL = 141 = 14 CE
nCE,Speech,DL = 141 = 14 CE
Step 1b: Calculating total nCE,Peak for busy hour
nCE,Peak,UL = 14 + 0 = 14 CE
nCE,Peak,DL = 14 + 0 = 14 CE
Step 2: Calculating nCE,AVE
nCE,AVE,UL = 7.81(10.02) = 7.6 CE
nCE,AVE,DL = 7.81(10.02) = 7.6 CE
Step 3: Calculating nCE,BE
nCE,BE,UL = 32.24 = 128.8 CE
nCE,BE,DL = 32.22 = 64.4 CE
Step 4: Finding the total number of CEs required
nCE,TOT,UL = max(14, (7.6+128.8)) = 136.4 CE
nCE,TOT,DL = max(14, (7.6+64.4)) = 72 CE
2.2 R99, conversational and best effort traffic admitted in busy hour
2.2.1 Purpose
The purpose of this example is to show calculations for a mix of conversational and R99 best effort traffic on the site. This example assumes that conversational as well as best effort traffic is admitted in busy hour. This gives no degradation of the peak throughput for best effort traffic in busy hour, since no impact of Enhanced Soft Congestion is assumed.
For simplicity there is only one type of conversational traffic (speech). Re-transmission is included in the best effort traffic. Grade of Service (GoS) for conversational and best effort traffic is assumed to be 2%.
For simplicity complete partitioning is used, which gives an overestimation of the required resources.
2.2.2 Traffic input
Table 3. Example 2: traffic input
Service RAB RBTraffic distri-bution
Offered traffic per site, A
Activity factor KAF
SHO factor κUL DL
Speech Speech 6 Erlang 6 Erlang n/a 0.3
R99 best effort PS data
PS interactive
64/64 70% 50MB 500 MB 0.7 0.3
R99 best effort PS data
PS interactive
64/128 20% 50MB 500 MB 0.7 0.3
R99 best effort PS data
PS interactive
64/384 10% 50MB 500 MB 0.7 0.3
2.2.3 Identifying number of simultaneous users
Step 1: Converting best effort traffic to Erlang + best effort traffic distribution
A64/64,UL = ((0.705010000008)/3600)/(640000.7) = 1.7 Erlang
A64/128,UL = ((0.205010000008)/3600)/(640000.7) = 0.5 Erlang
A64/384,UL = ((0.105010000008)/3600)/(640000.7) = 0.25 Erlang
A64/64,DL = ((0.7050010000008)/3600)/(640000.7) = 17.4 Erlang
A64/128,DL = ((0.2050010000008)/3600)/(1280000.7) = 2.5 Erlang
A64/384,DL = ((0.1050010000008)/3600)/(3840000.7) = 0.4 Erlang
Step 2: Max traffic
A64/64 = max(17.4, 1.7) = 17.4 Erlang
A64/128 = max(2.5, 0.5) = 2.5 Erlang
A64/384 = max(0.4, 0.25) = 0.4 Erlang
Step 3: Soft handover factor
ASHO,Speech = 61,3 = 7.8 Erlang
ASHO,64/64 = 17.41,3 = 22.6 Erlang
ASHO,64/128 = 2.51,3 = 3.2 Erlang
ASHO,64/384 = 0.41,3 = 0.5 Erlang
Step 4: Estimating the maximum number of simultaneous users from offered traffic
MSpeech = ErlangB(7.8, 0.02) = 14
M64/64 = ErlangB(22.6, 0.02) = 31
M64/128 = ErlangB(3.2, 0.02) = 8
M64/384 = ErlangB(0.5, 0.02) = 3
2.2.4 Calculating number of CEs
Step 1a: Calculating nCE,Peak per service
nCE,Speech,UL = 141 = 14 CE
nCE,Speech,DL = 141 = 14 CE
nCE,64/64,UL = 314 = 124 CE
nCE,64/64,DL = 312 = 62 CE
nCE,64/128,UL = 84 = 32 CE
nCE,64/128,DL = 84 = 32 CE
nCE,64/384,UL = 34 = 12 CE
nCE,64/384,DL = 38 = 24 CE
Step 1b: Calculating total nCE,Peak for busy hour
nCE,Peak,UL = 14+124+32+12 = 182 CE
nCE,Peak,DL = 14+62+32+24 = 132 CE
Step 2: Calculating nCE,AVE
nCE,AVE,UL = 7.81(10.02) = 7.6 CE
nCE,AVE,DL = 7.81(10.02) = 7.6 CE
Step 3: Calculating nCE,BE
nCE,64/64,UL = 22.64 = 90.4 CE
nCE,64/64,DL = 22.62 = 45.2 CE
nCE,64/128,UL = 3.24 = 12.8 CE
nCE,64/128,DL = 3.24 = 12.8 CE
nCE,64/384,UL = 0.54 = 2.0 CE
nCE,64/384,DL = 0.58 = 4.0 CE
Step 4: Finding the total number of CEs required
nCE,TOT,UL = max(182, (7,6+90.4+12.8+2.0)) = 182 CE
nCE,TOT,DL = max(132, (7,6+45.2+12.8+4.0)) = 132 CE
2.3 R99 + HSPA, only conversational traffic admitted in busy hour
2.3.1 Purpose
The purpose of this example is to show CE calculations for HSPA. For simplicity it is assumed that there is no R99 best effort traffic on the site. UL E-DCH traffic has not been specified. This example assumes that only conversational traffic is admitted in busy hour. This gives a throughput degradation for best effort traffic in busy hour. The example assumes no impact of Enhanced Soft Congestion.
2.3.2 Traffic input
Table 4. Example 1: traffic input
Service RAB RBTraffic distri-bution
Offered traffic per site, A
Activity factor KAF
SHO factor κUL DL
Speech Speech 6 Erlang 6 Erlang n/a 0.3
R99 best effort PS data
PS interactive
64/HS 60% 50MB 500 MB 0.7 0.3
R99 best effort PS data
PS interactive
384/HS 15% 50MB 500 MB 0.7 0.3
R99 best effort PS data
PS interactive
EUL/HS 25% 50MB 500 MB 0.7 0.3
HS target rate 500 kbps
EUL target rate 128 kbps (8CE)
Reservation of CE for EUL SHO 128 kbps (8CE)
2.3.3 Identifying the number of simultaneous users
Step 1: Converting best effort traffic to Erlang
ADL,HS = ((50010000008)/3600)/(5000000.7) = 3.2 Erlang
Step 2: UL A-DCH & EUL traffic distribution
A64HS,UL = 0.750.83.2 = 1.9 Erlang
A384HS,UL = 0.750.23.2 = 0.5 Erlang
AEUL = 0.253.2 = 0.8 Erlang
Step 3: Soft handover factor
ASHO,Speech = 61.3 = 7.8 Erlang
A64HS,UL = 1.31.9 = 2.5 Erlang
A384HS,UL = 1.30.5 = 0.65 Erlang
AEUL,Serving = 10.8 = 0.8 Erlang
AEUL,nonServing = 0,30.8 = 0.24 Erlang
Step 4: Estimating the maximum number of simultaneous users from offered traffic
MSpeech = ErlangB(7.8, 0.02) = 14
M64HS,UL = ErlangB(2.5, 0.02) = 7
M384HS,UL = ErlangB(0.65, 0.02) = 4
MEUL,Serving = ErlangB(0.8, 0.02) = 4
MEUL,nonServing = ErlangB(0.24, 0.02) = 3
2.3.4 Calculating number of CEs
Step 1a: Calculating nCE,Peak per service
nCE,Speech,UL = 141 = 14 CE
nCE,Speech,DL = 141 = 14 CE
Step 1b: Calculating total nCE,Peak for busy hour
nCE,Peak,UL = 14+0 = 14 CE
nCE,Peak,DL = 14+0 = 14 CE
Step 2: Calculating nCE,AVE
nCE,AVE,UL = 7.81(10.02) = 7.6 CE
nCE,AVE,DL = 7.81(10.02) = 7.6 CE
Step 3: Calculating nCE,BE
nCE,64HS,UL = 2.54 = 10
nCE,384,UL = 0,6516 = 10.4
nCE,EUL,Serving = 0,88 = 6.4
nCE,EUL,nonServing = 0,258 = 2
Step 4: Finding the total number of CEs required
nCE,TOT,UL = max(14, (7,6+10+10.4+6.4+2)) = 36.4 CE
nCE,TOT,DL = max(14, (7,6+0)) = 14 CE