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I II III II. Units of Measurement (p. 12) CH. 1.2 - MEASUREMENT

CH. 1.2 - MEASUREMENT

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CH. 1.2 - MEASUREMENT. II. Units of Measurement (p. 12). A. Number vs. Quantity. Quantity - number + unit. UNITS MATTER!!. B. SI Units. Quantity. Symbol. Base Unit. Abbrev. Length. l. meter. m. Mass. m. kilogram. kg. Time. t. second. s. Temp. T. kelvin. K. Amount. n. - PowerPoint PPT Presentation

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Page 1: CH. 1.2 - MEASUREMENT

I

II

III

II. Units of Measurement

(p. 12)

CH. 1.2 - MEASUREMENT

Page 2: CH. 1.2 - MEASUREMENT

A. Number vs. Quantity

Quantity - number + unit

UNITS MATTER!!

Page 3: CH. 1.2 - MEASUREMENT

B. SI Units

Quantity Base Unit Abbrev.

Length

Mass

Time

Temp

meter

kilogram

second

kelvin

m

kg

s

K

Amount mole mol

Symbol

l

m

t

T

n

Page 4: CH. 1.2 - MEASUREMENT

B. SI Units

mega- M 106

deci- d 10-1

centi- c 10-2

milli- m 10-3

Prefix Symbol Factor

micro- 10-6

nano- n 10-9

pico- p 10-12

kilo- k 103

BASE UNIT --- 100

Page 5: CH. 1.2 - MEASUREMENT

C. Derived Units

Combination of base units.

Volume (m3 or cm3) length length length

D = MV

1 cm3 = 1 mL1 dm3 = 1 L

Density (kg/m3 or g/cm3)mass per volume

Page 6: CH. 1.2 - MEASUREMENT

D. DensityM

ass

(g)

Volume (cm3)

Δx

Δyslope D

V

M

Page 7: CH. 1.2 - MEASUREMENT

Problem-Solving Steps

1. Analyze

2. Plan

3. Compute

4. Evaluate

Page 8: CH. 1.2 - MEASUREMENT

D. Density

An object has a volume of 825 cm3 and a density of 13.6 g/cm3. Find its mass.

GIVEN:

V = 825 cm3

D = 13.6 g/cm3

M = ?

WORK:

M = DV

M = (13.6 g/cm3)(825cm3)

M = 11,200 g

V

MD

Page 9: CH. 1.2 - MEASUREMENT

D. Density

A liquid has a density of 0.87 g/mL. What volume is occupied by 25 g of the liquid?

GIVEN:

D = 0.87 g/mL

V = ?

M = 25 g

WORK:

V = M D

V = 25 g

0.87 g/mL

V = 29 mLV

MD