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Ceng-112 Data Structures I Turgut Kalfaoglu 2
Figure 3-2
Linear Lists
Operations are;1. Insertion2. Deletion3. Retrieval4. Traversal (exception for restristed lists).
Ceng-112 Data Structures I Turgut Kalfaoglu 3
Figure 4-1
Stacks
A stack is a Last in First out (LIFO) data structure in which all insertions and deletions are restricted to one end called top.
Ceng-112 Data Structures I Turgut Kalfaoglu 12
Create Stack
algorithm createStackAllocates memory for a stack head node from dynamic memory and returns its
address to the caller.Pre NothingPost Head node allocated or error returnedReturn pointer to head node or null pointer if no memory1. if (memory available)
1. allocate (stackPtr)2. stackPtrcount = 03. stackPtrtop = null
2. else1. stackPtr = null
3. return stackPtrend createStack
Ceng-112 Data Structures I Turgut Kalfaoglu 14
Push Stackalgorithm pushStack(val stack <head pointer>,
val data <data type>)
Insert (push) one item into the stack.
Pre stack is a pointer to the stack head structure.
data contains data to be pushed into stack.
Post data have been pushed in stack.
1. if (stack full)1. success = false
2. else1. allocate (newPtr)
2. newPtrdata= data
3. newPtrnext= stacktop
4. stacktop=newPtr
5. stackcount = stackcount+1
6. Success=true
3. return success
end pushStack
Ceng-112 Data Structures I Turgut Kalfaoglu 16
Pop Stackalgorithm popStack(val stack <head pointer>,
val dataOut <data type>)
Pops the item on the top of the stack and returns it to the user.
Pre stack is a pointer to the stack head structure.
dataOut is a reference variable to receive the data.
Post data have been returned to the calling algorithm.
1. if (stack empty)1. success = false
2. else1. dltPtr= stacktop
2. dataOut = stacktopdata
3. stacktop = stacktopnext
4. stackcount = stackcount – 1
5. recycle(dltPtr)
6. success=true
3. return success
end popStack
Ceng-112 Data Structures I Turgut Kalfaoglu 17
Destroy Stack
algorithm destroyStack(val stack <head pointer>)
This algorithm releases all nodes back to the dynamic memory.
Pre stack is a pointer to the stack head structure.
Post stack empty and all nodes recycled
1. if (stack not empty)
1. loop1. temp = stacktop
2. stacktop = stacktoplink
3. recycled(temp)
2. recycled (stack)
3. return null pointer
end destroyStack
Ceng-112 Data Structures I Turgut Kalfaoglu 18
Stack Applications
We can be classified stack applications into four categories:
1. Reversing data.
2. Parsing data.
3. Postponing data usage.
4. Backtracking steps.
Ceng-112 Data Structures I Turgut Kalfaoglu 19
Stack ApplicationsReversing Data
1 2 3 4 5 5 4 3 2 1
12345Push Pop
Ceng-112 Data Structures I Turgut Kalfaoglu 20
Figure 4-11
Stack ApplicationsParsing Data
Breaks the data into independent pieces for further processing.
source program Compiler machine language
Ceng-112 Data Structures I Turgut Kalfaoglu 21
Stack ApplicationsParsing Data
3.Pop )2.Push (1.Push (
3.Pop )2.Pop )1.Push (
Ceng-112 Data Structures I Turgut Kalfaoglu 22
Stack ApplicationsPosponement
Arithmetic expression can be represent three different formats:
1. Prefix + a b
2. Infix a + b
3. Postfix a b +
Arithmetic precedence;
multiply and divide
before
add and subtract!
Ceng-112 Data Structures I Turgut Kalfaoglu 23
Stack ApplicationsPosponement
A + B * C
Place the paranthesis
( A + ( B * C))
Replace it in postfix format
(A(BC*)+)
Remove all paranthesis
ABC*+
Implementation by computer is too hard!
Ceng-112 Data Structures I Turgut Kalfaoglu 24
Figure 4-12, Part I
Stack ApplicationsPosponement
* and / operators have higher priority than the operator at the top of the stack.
Ceng-112 Data Structures I Turgut Kalfaoglu 26
Figure 4-13
Stack ApplicationsEvaluation of Postfix Expression
Ceng-112 Data Structures I Turgut Kalfaoglu 27
Excercise
• Change the following infix expression to postfix expression using the algoritmic method (a stack).
a+b*c-d
Solution: abc*+d-
Ceng-112 Data Structures I Turgut Kalfaoglu 28
• Infix String : a+b*c-d
• The first character scanned is 'a'. 'a' is added to the Postfix string. The next character scanned is '+'. It being an operator, it is pushed to the stack.
• Next character scanned is 'b' which will be placed in the Postfix string. Next character is '*' which is an operator. Now, the top element of the stack is '+' which has lower precedence than '*', so '*' will be pushed to the stack.
• The next character is 'c' which is placed in the Postfix string. Next character scanned is '-'. The topmost character in the stack is '*' which has a higher precedence than '-'. Thus '*' will be popped out from the stack and added to the Postfix string. Even now the stack is not empty. Now the topmost element of the stack is '+' which has equal priority to '-'. So pop the '+' from the stack and add it to the Postfix string. The '-' will be pushed to the stack.
• Next character is 'd' which is added to Postfix string. Now all characters have been scanned so we must pop the remaining elements from the stack and add it to the Postfix string. At this stage we have only a '-' in the stack. It is popped out and added to the Postfix string. So, after all characters are scanned, this is how the stack and Postfix string will be :
• End result :
• * Infix String : a+b*c-d
• * Postfix String : abc*+d-
Ceng-112 Data Structures I Turgut Kalfaoglu 33
Figure 4-20
Array Implementation of Stacks
stackstackAry <pointer to array of dataType>count <integer>stackMax <integer>top <index>
end stack
Ceng-112 Data Structures I Turgut Kalfaoglu 34
Hw-5
Write a program that accepts parentheses and brackets characters, one per line on standard input. Use a stack to determine whether pairs of characters are matching or not. Therefore complete the body of below function.
bool balanced(const char p[ ], size_t n) // Precondition: p[0]...p[n-1] contains n characters, each of which // is '(', ')', '{' or '}'. // Postcondition: The function returns true if the characters form a // sequence of correctly balanced parentheses with each '(' matching // a ')' and each '{' matching a '}'. Note that a sequence such as // ( { ) } is NOT balanced because when we draw lines to match the // parentheses to their partners, the lines cross each other. On the // other hand, ( { } ) amd { ( ) } are both balanced.
Load your HW-5 to FTP site until 13 Apr. 07 at 09:00 am.