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Catalyst 9/15/11Objective:IWBAT review for the Unit 2 test.
Agenda1. Catalyst2. Gun practice3. White board practice
Homework4. Study for the TEST!!!
Identify the atom the following atom. 9 p+
11 no
How long is the paper clip?a. Write the measurement b. Convert the measurement into metersc. Convert your answer from part b into scientific notation
Math PracticeConvert to scientific notation:1) 0.0000023892) 234000Find the answer in correct significant digits.3) 9.735 x 1.44) (2.21 x 10 5) x (1.807 x 10-7)Convert using dimensional analysis.5) 9587 g = __________ cg6) 547 kL = __________ mL
Math PracticeConvert to scientific notation:1) 0.000002389 2.389 x 10-6
2) 234000Find the answer in correct significant digits.3) 9.735 x 1.44) (2.21 x 10 5) x (1.807 x 10-7)Convert using dimensional analysis.5) 9587 g = __________ cg6) 547 kL = __________ mL
Math PracticeConvert to scientific notation:1) 0.000002389 2.389 x 10-6
2) 234000 2.34 x 105
Find the answer in correct significant digits.3) 9.735 x 1.44) (2.21 x 10 5) x (1.807 x 10-7)Convert using dimensional analysis.5) 9587 g = __________ cg6) 547 kL = __________ mL
Math PracticeConvert to scientific notation:1) 0.000002389 2.389 x 10-6
2) 234000 2.34 x 105
Find the answer in correct significant digits.3) 9.735 x 1.4 = 13.629 144) (2.21 x 10 5) x (1.807 x 10-7)Convert using dimensional analysis.5) 9587 g = __________ cg6) 547 kL = __________ mL
Math PracticeConvert to scientific notation:1) 0.000002389 2.389 x 10-6
2) 234000 2.34 x 105
Find the answer in correct significant digits.3) 9.735 x 1.4 = 13.629 144) (2.21 x 10 5) x (1.807 x 10-7) = 0.0399 = 3.99 x10-2
Convert using dimensional analysis.5) 9587 g = __________ cg6) 547 kL = __________ mL
Math PracticeConvert to scientific notation:1) 0.000002389 2.389 x 10-6
2) 234000 2.34 x 105
Find the answer in correct significant digits.3) 9.735 x 1.4 = 13.629 144) (2.21 x 10 5) x (1.807 x 10-7) = 0.0399 = 3.99 x10-2
Convert using dimensional analysis.5) 9587 g = 958700 = 9.587 x 105 cg6) 547 mL = __________ kL
Math PracticeConvert to scientific notation:1) 0.000002389 2.389 x 10-6
2) 234000 2.34 x 105
Find the answer in correct significant digits.3) 9.735 x 1.4 = 13.629 144) (2.21 x 10 5) x (1.807 x 10-7) = 0.0399 = 3.99 x10-2
Convert using dimensional analysis.5) 9587 g = 958700 = 9.587 x 105 cg6) 547 mL = 0.000547 = 5.47 x 10-4kL
PracticeElement Atomic # Atomic
Mass# of p+ # of e- # of n
11 P
613
PracticeElement Atomic # Atomic
Mass# of p+ # of e- # of n
Na 11 22.990 11 11 12P
613
PracticeElement Atomic # Atomic
Mass# of p+ # of e- # of n
Na 11 22.990 11 11 12P 15 30.974 15 15 16
613
PracticeElement Atomic # Atomic
Mass# of p+ # of e- # of n
Na 11 22.990 11 11 12P 15 30.974 15 15 16C 6 12.011 6 6 6
13
PracticeElement Atomic # Atomic
Mass# of p+ # of e- # of n
Na 11 22.990 11 11 12P 15 30.974 15 15 16C 6 12.011 6 6 6Al 13 26.982 13 13 14
Ionic and Covalent Formulas
1) aluminum oxide2) heptaphosphorus tetranitride
Ionic and Covalent Formulas
1) aluminum oxide Al2O3
2) heptaphosphorus tetranitride
Ionic and Covalent Formulas
1) aluminum oxide Al2O3
2) heptaphosphorus tetranitride P7N4
Ionic and Covalent Naming
1) SO4
2) Ba3N2
Ionic and Covalent Naming
1) SO4 sulfur tetraoxide
2) Ba3N2
Ionic and Covalent Naming
1) SO4 sulfur tetraoxide
2) Ba3N2 barium nitride
Classification of the Elements
