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Capacitors Part I

Capacitors Part I

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Capacitors Part I. Capacitor. Composed of two metal plates. Each plate is charged one positive one negative Stores Charge. SYMBOL. A simple Capacitor. TWO PLATES. WIRES. Battery. INSIDE THE DEVICE. d. Air or Vacuum. E. - Q +Q. Symbol. Area A. - PowerPoint PPT Presentation

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Page 1: Capacitors  Part I

Capacitors Part I

Page 2: Capacitors  Part I

Capacitor

Composed of two metal plates. Each plate is charged

one positive one negative

Stores Charge

SYMBOL

Page 3: Capacitors  Part I

A simple Capacitor

TWO PLATES

Battery

WIRES

Page 4: Capacitors  Part I

INSIDE THE DEVICE

Page 5: Capacitors  Part I

Two Charged Plates(Neglect Fringing Fields)

d

Air or Vacuum

Area A

- Q +QE

V=Potential Difference

Symbol

ADDED CHARGE

Page 6: Capacitors  Part I

Where is the charge?

d

Air or Vacuum

Area A

- Q +QE

V=Potential Difference

------

++++++

AREA=A

=Q/A

Page 7: Capacitors  Part I

One Way to Charge: Start with two isolated uncharged plates. Take electrons and move them from the +

to the – plate through the region between. As the charge builds up, an electric field

forms between the plates. You therefore have to do work against the

field as you continue to move charge from one plate to another.

Page 8: Capacitors  Part I

Capacitor

Page 9: Capacitors  Part I

More on Capacitorsd

Air or Vacuum

Area A

- Q +QE

V=Potential Difference

GaussianSurface

000

0

0

0

)/(

0

AQ

A

QE

EAQ

QEAAEA

qd

Gauss

AE

Same result from other plate!

Page 10: Capacitors  Part I

DEFINITION The Potential Difference is

APPLIED by a battery or a circuit.

The charge q on the capacitor is found to be proportional to the applied voltage.

The proportionality constant is C and is referred to as the CAPACITANCE of the device.

CVq

orV

qC

Page 11: Capacitors  Part I

NOTE

Work to move a charge from one side of a capacitor to the other is qEd.

Work to move a charge from one side of a capacitor to the other is qV

Thus qV=qEd E=V/d (Hold this thought.)

Page 12: Capacitors  Part I

UNITSUNITS A capacitor which

acquires a charge of 1 coulomb on each plate with the application of one volt is defined to have a capacitance of 1 FARAD

One Farad is one Coulomb/Volt

CVq

orV

qC

Page 13: Capacitors  Part I

Continuing…

d

AC

sod

AVEAAq

V

qC

0

00

The capacitance of a parallel plate capacitor depends only on the Area and separation between the plates.

C is dependent only on the geometry of the device!

Page 14: Capacitors  Part I

Units of 0

mpFmF

andm

Farad

Voltm

CoulombVoltCoulombm

Coulomb

Joulem

Coulomb

Nm

Coulomb

/85.8/1085.8 120

2

2

2

2

0

pico

Page 15: Capacitors  Part I

Simple Capacitor Circuits Batteries

Apply potential differences Capacitors Wires

Wires are METALS. Continuous strands of wire are all at the same

potential. Separate strands of wire connected to circuit

elements may be at DIFFERENT potentials.

Page 16: Capacitors  Part I

Size Matters! A Random Access Memory stores

information on small capacitors which are either charged (bit=1) or uncharged (bit=0).

Voltage across one of these capacitors ie either zero or the power source voltage (5.3 volts in this example).

Typical capacitance is 55 fF (femto=10-15) Question: How many electrons are stored

on one of these capacitors in the +1 state?

Page 17: Capacitors  Part I

Small is better in the IC world!

electronsC

VF

e

CV

e

qn 6

19

15

108.1106.1

)3.5)(1055(

Page 18: Capacitors  Part I

TWO Types of Connections

SERIES

PARALLEL

Page 19: Capacitors  Part I

Parallel Connection

VCEquivalent=CE

321

321

321

33

22

1111

)(

CCCC

therefore

CCCVQ

qqqQ

VCq

VCq

VCVCq

E

E

E

Page 20: Capacitors  Part I

Series Connection

V C1 C2

q -q q -q

The charge on eachcapacitor is the same !

Page 21: Capacitors  Part I

Series Connection Continued

21

21

21

111

CCC

or

C

q

C

q

C

q

VVV

V C1 C2

q -q q -q

Page 22: Capacitors  Part I

More General

ii

i i

CC

Parallel

CC

Series

11

Page 23: Capacitors  Part I

Example

C1 C2

V

C3

C1=12.0 fC2= 5.3 fC3= 4.5 d

(12+5.3)pf

series

(12+5.3)pf

Page 24: Capacitors  Part I

More on the Big C We move a charge

dq from the (-) plate to the (+) one.

The (-) plate becomes more (-)

The (+) plate becomes more (+).

dW=Fd=dq x E x d+q -q

E=0A/d

+dq

Page 25: Capacitors  Part I

So….

2222

0

2

0

2

0 0

0

00

2

1

22

)(

1

22

1

1

CVC

VC

C

QU

ord

Aq

A

dqqdq

A

dUW

dqdA

qdW

A

qE

Gauss

EddqdW

Q

Page 26: Capacitors  Part I

Not All Capacitors are Created Equal

Parallel Plate

Cylindrical Spherical

Page 27: Capacitors  Part I

Spherical Capacitor

???

4)(

4

02

0

2

0

surprise

r

qrE

qEr

qd

Gauss

AE

Page 28: Capacitors  Part I

Calculate Potential Difference V

drr

qV

EdsV

a

b

platepositive

platenegative

20

.

.

1

4

(-) sign because E and ds are in OPPOSITE directions.

Page 29: Capacitors  Part I

Continuing…

ab

ab

V

qC

ab

abq

ba

qV

r

q

r

drqV

b

a

0

00

02

0

4

4

11

4

)1

(44

Lost (-) sign due to switch of limits.