Canal Outlets&Modules Worked Out Exampes

8/18/2019 Canal Outlets&Modules Worked Out Exampes

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TRAINING PROGRAMME ONTRAINING PROGRAMME ON

ENGINEERING DESIGNS-CANAL STRUCTURESENGINEERING DESIGNS-CANAL STRUCTURES

GENERAL DESIGN PRINCIPLESGENERAL DESIGN PRINCIPLES

Off Take Sluices,Off Take Sluices,

Canal outlets and ModulesCanal outlets and Modules

!!

ROUT"U SAT!ANARA!ANAROUT"U SAT!ANARA!ANA

#ORMER#ORMER C"IE# ENGINEERC"IE# ENGINEER

#ORMER AD$ISOR, GO$ERNMENT O# A%P#ORMER AD$ISOR, GO$ERNMENT O# A%P


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Modular Outlets

DESIGN - EXAMPLES

HYDRAULIC DESIGN

OFM – APM - PSM


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Cross Masonry Works- ModularOutlets

Semi-Modular outlets or Flexible modules

• Open Flume Outlet (OFMs)

• Crump’s Adjustable proportional Module(Crump’s APM)

• Adjustable Orifce Semi module (AOSM)

• Pipe Semi Module – Pipe Out let (PSM)


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Modular Outlets

& T'e suita(ilit) of t'e t)*e of t'e se+i +odule outlet is dete+ined (ased on t'e atio of *aentcanal disc'ae ./0 to t'e disc'ae of t'e out let .10 and t'e t'oat 2idt' .t0 as detailed

(elo2%

i0 fo ./31 0 4 o 5 67 and t 8 9 c+ O*en #lu+e Module. O#M0

ii0 fo ./31 0 4 o 5 67 and t 4 9 c+ Ad:usta(le Po*otional +odule . APM 0

fo ./31 0 ; 67

& If t'e a(o7 ++%


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Modular Outlets

& The above conditions are further explained as below

Ai


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Canal Outlets & ModularOutlets

Open Flume Module(OFM)

! A smoot" #eir #it" a t"roat constricted su$cientl% to ensure &elocit%abo&e critical' and lon enou" to ensure t"at t"e controllin sectionremain #it" in t"e parallel t"roat at all disc"ares up to t"e maximum

! A raduall% expanded *ume is pro&ided at t"e out+all to reco&er t"e"ead

! ,"e entire #or can be built in bric' but t"e controllin section ispro&ided #it" cast iron or steel bed and c"ec plates

! ,"roat #idt" .t ne&er ept less t"an /cm "ence it is necessar% to raiset"e crest le&el o+ t"e out let muc" abo&e bed le&el

! 0orin "ead re1uired #it" a 2 in 3 lacis and side #alls spla%in at 2 in3 is 456 o+ dept" o+ #ater abo&e t"e crest o+ out let

! Formation o+ "%draulic jump maes t"e out let independent o+ #ater

le&el in t"e out let c"annel


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Canal Out lets & ModularOutlets

Open Flume Module (OFM)

& 7 in Cumecs 8 9 .t :;


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Canal Out lets & Modular Outlets

"!"DRAULIC DESIGN O# O#M


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HYDRAULIC PARTICULARS

S.No.

Details Unit

Parent Canal Off Take

KopparamMaor

!" R Minor

1Discharge (Required) Cumecs 0.939 0.080

2Bed Width m 1.200 0.300

3F.S. Depth m 0.30 0.310

!Free B"ard m 0.#10 0.!#0

$Bed Fa%% 1 i& 2#!0 2000

#Side S%"pes 1.$ ' 1 1.$ ' 1

e%"cit m*sec 0.$#1 0.339

8& 0.020 0.020

9CB+ m 81.$89 81.##210FS+ m 82.319 81.92

11,B+ m 82.929 82.!32

12-+ m 82.929 82.!32


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Desin of O#M


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Hydraulic Design:

Ratio of /31 5 7%B 3 7%7@

5 ==%B@ 4 67

"ence O%#%M% is Po*osed%

#SD in t'e *aent c'annel, D 5 7%B7 +

Depth of flow in the parent channel at 2/3 rd discharge:

Dn = 0!"# $ %assu$ed&

#o 63Bd Disc'ae in Paent Canal /n 5 63B / 5 7%969 cu+ecs

Let Dn 5 7%> + , Aea 5 =%66 +6

Pei+ete 5 B%B6 +, R 5 7%B6, and R63B 5 7%>=

$elocit) 5 7%>7 +3sec

Disc'ae 5 7%969 cu+ecs

"ence Dn i%e%, de*t' of flo2 of 7%> + in t'e *aent c'annel assu+ed fo63Bd disc'ae is coect%

Diffeence in de*t's of flo2 fo full disc'ae and 63B d disc'ae

5 D - Dn 5 7%B7 - 7%> 5 7%=B9 +


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The discharge of the outlet q (in cumecs) is given by the formula:q = K x Bt x H3!

"here K = #onstant de$ending u$on the %idth of flume

Bt = Throat %idth of %eir

H = Head over crest in meters

Hn = Head over crest at !3 & = ( H ' x )

or full discharge q = K x Bt x H3! ( * )

or !3 discharge q = K x Bt x (Hn)3! = K x Bt x (Hx)3! ( ! ) By dividing equation (*) by equation (!)

q !3 q = K x Bt x H3! !3 (q) K x Bt x (H x)3!

3! = (H3! (H x)3! ) !3

(3!)!3 = (H3! (H x)3! ) !3

*+3*, = H (H x)

,+3* + H = *+3* + x

H = -+!!. xx = ,+*3/ m

Hence0 H = -+!!. x ,+*3/ = ,+.1. m

#rest 2evel = ++2+ of 4arent #hannel H

= 5!+3*6 ,+.1. = 5*+1-- m


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7inimum Head required (modular) = ,+! x H = ,+! x ,+.1. = ,+**. m

8vailable "or9ing Head = ifference of 2;s in 4arent #anal and as $er ?: *!33**655 = *+/-

Bt = q (K + H3!)

= ,+,5, *+/- x (,+.1.)3! = ,+**! m

q = K x Bt x H3!

= *+/- x ,+**! x ,+.1.3!

= ,+,5, cumecs


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Desin of O#M


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Open Flume Module


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Canal Out lets & Modular Outlets

"!"DRAULIC DESIGN O# APM


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Canal outlets F Modules

• Adjustable Orifce Semi Module (A.O.S.M) orAdjustable Proportional Module (APM)

• Discharge through outlet in cumecs

! ".#$ %t & 's*

D 8:ei"t o+ openin in meters.t 8,"roat #idt" (minimum 55/ m )

: 8Bept" o+ #ater in parent canal o&er t"e crest in meters

:s 8 Bept" to under side o+ t"e roo+ bloc belo# FS o+ parent canal

:s 8 : – D ' :s E 55 B

% ? (4


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Canal outlets F Modules

Settin o+ crest s"all not be belo# B


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Desin of APM

& ")daulic Paticulas

S%No% Details Hu**a+ Ma:o DP =-R Hu**a+ +a:o DP =-R

At #S Disc'ae Condition At 63B #S Disc'ae Condition

=% Disc'ae in Cu+ecs 7%9B9 7%7=@ 7%6 7%7=6

6% ed 2idt' in + =%=77 7%B77 =%=77 7%B77

B% #SD in + 7%9=7 7%=>7 7%> 7%=67

% ed fall = in 6>77 6777 6>77 6777

>% $alue of n 7%767 7%767 7%767 7%767

9% $elocit) in +3s 7%>=@ 7%6B= 7%9 7%=@B

% Side slo*es =%> = =%> = =%> = =%> =

@% #ee (oad in + 7%9=7 7%>7 7%9=7 7%>7

% CL + @7%69 @7%66 @7%69 @7%66

=7% #SL + @7%@ @7%>6 @7%9 @7%>6

==% TL + @=%@ @=%766

=6% GL + @=%@ @=%@

Po*ose APM if / 3 1 4 67, o / 3 1 ; 67, and t 4 97 ++

Ratio of / 3 1 5 7%9B9 3 7%7=@ 5 B>%BBB ; 67

"ence APM is *o*osed%


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Desin of APM


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Desin of APM

& ")daulic Desin of APM

Po*ose APM if /31 4 67 and t 4 9 o /31 ;67

Ratio of /31 5 7%9B9 3 7%7=@ 5 B>%BBB ; 67 Hence ' ( ) is proposed

* = #03 x +t x y x Hs,/2

?'ee ! 5 "ei't of o*enin in +etes

t 5 T'oat 2idt'

" 5De*t' of 2ate in *aent canal o


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Desin of APM

& Discharge through the outlet in cu$ecs * = #03 x +t x y x % Hs & .Pae ==, Clause 9%B%= of IS @9-=90

T'oat 2idt' t 5 1 3 .%7B ."s0K !0

Let t 5 7%79 +

1 5 %7B t ) "s=36 --------------e1uation .=0

63B .10 5 5 %7B t ) ."sn0=36 --------------e1uation .60

?'ee "sn 5 "s - .D - Dn0 5 %7B t ) ."s - .7%9=7 - 7%>00=36

5 %7B t ) ."s - 7%==>0=36

Di0 K

B36 5 "s=36 3 ."s - 7%==>0=36

5 6 "s=36 5 B ."s - 7%==>0=36

"s 5 ."s - 7%==>0

> "s 5 =%7BB6

"s 5 7%67 + and "s=36 5 7%>>

"sn 5 "s . D Dn 0 5 7%67 . 7%9=7 7%> 0 5 7%76+


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Desin of APM

= * 3 03x+tx%Hs&,/2

5 7%7=@ 3 #03 x 7%79 0#!!

= 0,.# $ say 0,.! $

1 = #03 +t % Hs & = #03 x 00. x 0,.! x 0#!! = 00, cu$ecs

1n 5 %7B t ! . "sn 0 K = #03 x 00. x 0,.! x 0303 = 00,2 cu$ecs

T'e follo2in Paa+etes +a) (e ado*ted

t 5 7%797 +

Cest Le +

"s 5 7%67 +

?5 Settin fo2ad of t'e D3S 2in 2all of t'e a**oac' 57%=>

T'e settin of t'e ?in 2all ? 5 H 13/ .u D360


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Desin of APM


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CRUMPS ADUSTALE PROPORTIONAL MODULE


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Canal Outlets F Modules

• Pipe semi module (PSM)

• Design criteria

,"e disc"are t"rou" pipe semi module is i&en b%

7 8 Cd A (4 "c )2


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Modular Outlets D4567 8- (5( 4)5 )8D9 %for D5;


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Modular Outlets

Disc'ae t'ou' t'e Pi*e Outlet () usin Oifice fo+ula

/ 5 CA .6 'cnt0=36

2'ee C 5 6% 9

/ 5 Disc'ae of Out Let

A 5 Coss section Aea of Pi*e

'.cnt0 5 "ead of U3s 2ate suface o7 + ; =%> ti+es dia of *i*e

(rovide did of pipe = 200$$


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")daulic Desin of PSM

T'e Cente line of t'e Pi*e 5 %=>> 7%B>7 5 B%@7>+

Pi*e sill le7 - 7%7@ .*i*e adius0

5 B%6>+"ei't of *i*e a(o >%9>> 5 7%77+

Pi*e in


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Desin of PSM


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TH'7> 89TH'7> 89

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Canal Outlets&Modules Worked Out Exampes