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Cable Protection Cable Protection Matching Protection Devices Matching Protection Devices to a Cable to a Cable

Cable Protection

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Cable Protection. Matching Protection Devices to a Cable. Definitions. When current flows heat is generated The longer the current flows the greater the heat build up. H I R t. = Heat = Current = Resistance = Time. Definitions. Short Circuit:. Very high current. - PowerPoint PPT Presentation

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Page 1: Cable Protection

Cable ProtectionCable ProtectionMatching Protection Devices to a CableMatching Protection Devices to a Cable

Page 2: Cable Protection

DefinitionsDefinitionsWhen current flows heat is generated

The longer the current flows the greater the heat build up

RtIH 2H

I

R

t

= Heat

= Current

= Resistance

= Time

Page 3: Cable Protection

DefinitionsDefinitionsShort Circuit: Very high current

Bobby pin in power point

Value dependant on impedance of cables

Cure: Magnetic section of Circuit Breaker

Page 4: Cable Protection

DefinitionsDefinitionsOverload: Higher than normal current

Too many appliances plugged in

Cure: Thermal section of Circuit Breaker

Page 5: Cable Protection

Cable CharacteristicsCable CharacteristicsIf a cable carries high currents it will heat up

See AS/NZS 3008.1.1:1998 Table 52See AS/NZS 3008.1.1:1998 Table 52 V-75 = 160˚C

If the temperature goes too high the insulation will be damaged

If a 2.5 mm2 copper cable carries a current of 40A. How long will it take to reach 160˚C?

Scenario 1:

Page 6: Cable Protection

Initial temperature of cable = 75 ˚C

2

22

I

SKt

See AS/NZS 3008.1.1:1998 Table 51See AS/NZS 3008.1.1:1998 Table 51

K = 111

If a 2.5 mm2 copper cable carries a current of 40A. How long will it take to reach 160˚C?

t = 48 seconds

See AS/NZS 3008.1.1:1998 5.3See AS/NZS 3008.1.1:1998 5.3

2

22

40

5.2111 t

The circuit breaker must trip in less than 48 seconds to protect the cable

Therefore:

And AS/NZS 3000:2007 2.5.4.5And AS/NZS 3000:2007 2.5.4.5

K

S

I

t

= Constant

= CSA of cable in mm2

= Current

= Time

Page 7: Cable Protection

An Easier WayAn Easier WayA cable’s current carrying capacity must be equal or larger than

the load current

See AS/NZS 3000:2007 2.5.3.1See AS/NZS 3000:2007 2.5.3.1

Load Current

Circuit protection must be equal to or smaller than the cable’s current carrying capacity

IB ≤ IN ≤ IZ

≤ Protection ≤ Cable Current carrying capacity

Page 8: Cable Protection

Load Current

10 Amps

Maximum Current

Cable can supply

CurrentRating of

Protection

15 Amps

20 Amps

XCable will be

damaged

IB IN IZ

Page 9: Cable Protection

Load Current

10 Amps

Maximum Current

Cable can supply

CurrentRating of

Protection

15 Amps

20 Amps

XCable will be

damaged

IB IN IZ

Protection will nuisance trip

Page 10: Cable Protection

HoweverHoweverA cable can withstand a overload current of 1.45 x it’s rating

before the insulation is damaged

10 Amps

Maximum Current

Cable can supply

IZ

A1045.1 14.5 Amps

14.5 Amps

Page 11: Cable Protection

A Circuit breaker’s trip curve is matched to a cable’s curve

10 Amps

Maximum Current

Cable can supply

IZ A1045.1 14.5 Amps

14.5 Amps

Tripping current is 1.45 x rated current

CurrentRating of

Protection

IN

Circuit BreakersCircuit Breakers

Page 12: Cable Protection

A Fuse’s trip curve is different to a cable’s curve

10 Amps

Maximum Current

Cable can supply

IZ A106.1 16 Amps

14.5 Amps

CurrentRating of

Protection

IN

FusesFuses

Tripping current is 1.6 x rated current16 Amps

Cable will be damaged

X

Page 13: Cable Protection

10 Amps

Maximum Current

Cable can supply

IZ

6.1

5.149 Amps

14.5 Amps

CurrentRating of

Protection

IN

FusesFuses16 Amps

1.6

Page 14: Cable Protection

10 Amps

Maximum Current

Cable can supply

IZ 9.010 9 Amps

14.5 Amps

CurrentRating of

Protection

IN

FusesFuses16 Amps

0.9