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By using the mesh analysis method, calculate the mesh currents and the asked quantities. Circuit 1. C1.1. Current in the 10 V source?. C1.2. Current in the 3K resistance?. C1.3. Current in each of the 2K resistances. connected in paralell?. C1.4. Potential drop from point A to point B?. - PowerPoint PPT Presentation
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1
K 4
V 01K 1
K 3
K 5 K 2 K 2
V 4
B
AC1.1. Current in the 10 V source?
C1.2. Current in the 3K resistance?
C1.3. Current in each of the 2K resistancesconnected in paralell?
C1.4. Potential drop from point A to point B?
K 5V 2
K 3K 2
V 4
B
A
C2.1. Current in the 3K resistance?
C2.2. Current in the 2K resistance?
C2.3. Current in the 8K resistance?V 2
K 8
Circuit 1
Circuit 2
C2.4. Potential drop from point A to point B?
K 5.3
K .50K 1
V 02
B
A
V 01
K 1
V 01
C3.1. Current in the 1K resistance (the one in the middle)?
C3.2. Current in the 20 V source?
C3.3. Current in the 1K resistance (the one on the right)?
Circuit 3
C3.4. Potential drop from point A to point B?
By using the mesh analysis method, calculate the mesh currents and the asked quantities.M
ES
H A
NA
LY
SIS
. EX
ER
CIS
ES
2
K 2 K 7
V 01
B
A
V 01
K 3
V 5
C4.1. Current in the 7K resistance?
C4.2. Current in the 5 V source?
C4.3. Current in the 2K resistance?
Circuit 4
C4.4. Potential drop from point A to point B?
By using the mesh analysis method, calculate the mesh currents and the asked quantities.
K 1
K 4
A
K 9V 5
K 1
K 2
K 4
K 3B
A
C5.1. Current in the 9K resistance?
C5.2. Current in the 1K resistance?
C5.3. Current in the 5 V source?
Circuit 5
C5.4. Potential drop from point A to point B?
ME
SH
AN
AL
YS
IS. E
XE
RC
ISE
S
3
K 4
V 01K 1
K 3
K 5
V 4A
C1.1. Current in the 10 V source?
C1.2. Current in the 3K resistance?
C1.3. Current in each of the 2K resistancesconnected in paralell?
C1.4. Potential drop from point A to point B?
Circuit 1
K 2 K 2
K 1pRSOLUTIONS
1i 2i
Equation of the circuit
4
10
101
15
2
1
i
i
101
15
104
1101
41
1052
mA 12.211
i
mA 61.022
i
C1.1. Current in the 10 V source? mA 12.21V10 ii
C1.2. Current in the 3K resistance? mA 61.023 ii K
C1.3. Current in each of the 1K resistancesconnected in paralell?
mA 305.022
1 i
i K (current divider)
C1.4. Potential drop from point A to point B?
V 55.12
243 22
iiVAB
BA VV
V 55.151 221 iiiVAB
Mesh currents
ME
SH
AN
AL
YS
IS. E
XE
RC
ISE
S K 1
B
K 12i
K 2 K 2
B
2i2/2i 2/2i
4
SOLUTIONS
K 5V 2
K 3K 2
V 4
B
A
C2.1. Current in the 3K resistance?
C2.2. Current in the 2K resistance?
C2.3. Current in the 8K resistance?V 2
K 8
Circuit 2
C2.4. Potential drop from point A to point B?
1i 2i
Equation of the circuit
4
2
22
24
102
210
2
1
i
i
102
210
104
221
42
2102
mA 29.011
i
mA 46.022
i
C2.1. Current in the 3K resistance?
C2.2. Current in the 2K resistance?
C2.3. Current in the 8K resistance?
C2.4. Potential drop from point A to point B?
mA 29.013 ii K
mA 17.046.029.0212 iii K (Same direction as i2)
mA 46.028 ii K
V 12.3225 211 iiiVAB
BA VV V 12.334 1 iVAB
Mesh currents
ME
SH
AN
AL
YS
IS. E
XE
RC
ISE
S
5
SOLUTIONS
K 5.3
K .50K 1
V 02
B
A
V 01
K 1
V 01
C3.1. Current in the 1K resistance (the one in the middle) ?
C3.2. Current in the 20 V source?
C3.3. Current in the 1K resistance (the one on the right) ?
Circuit 3
C3.4. Potential drop from point A to point B?
1i 2i
Equation of the circuit
20
20
1010
20
21
15
2
1
i
i
21
15
220
1201
201
2052
mA 22.211
i
mA 89.822
i
C3.1. Current in the 1K resistance (the one in the middle)?
C3.2. Current in the 20 V source?
C3.3. Current in the 1K resistance (the one on the right)?
C3.4. Potential drop from point A to point B?
mA 1.11211 iii K
The same direction as i2, opposite direction to i1.
mA 22.21V20 ii This minus sign means that the direction is
mA 89.821 ii K
V 11.1110 21 iiVAB
BA VV V 11.1101 2 iVAB
Mesh currents
ME
SH
AN
AL
YS
IS. E
XE
RC
ISE
S
6
SOLUTIONS
K 2 K 7
V 01
B
A
V 01
K 3
V 5
C4.1. Current in the 7K resistance?
C4.2. Current in the 5 V source?
C4.3. Current in the 2K resistance?
Circuit 4
C4.4. Potential drop from point A to point B?K 1
K 4
A
1i 2i
3i
Equation of the circuit
5
15
10
5
510
10
501
0107
1710
3
2
1
i
i
i
mA 980.311
i
mA 286.422
i
505
01015
1710
1
551
0157
11010
2
501
15107
10710
3
mA 204.033
i
C4.1. Current in the 7K resistance?
C4.2. Current in the 5 V source?
C4.3. Current in the 2K resistance?
C4.4. Potential drop from point A to point B?
mA 306.0217 iii KThe same direction as i2, opposite direction to i1.
mA 490.4325 iii VThe same direction as i2, opposite direction to i3.
mA 980.312 ii K
V 86.2310 2 iVAB
BA VV V 86.24210 31 iiVAB
501
0107
1710
Mesh currents
ME
SH
AN
AL
YS
IS. E
XE
RC
ISE
S
7
SOLUTIONS
K 9
V 5
K 1
K 2
K 4
K 3B
AC5.1. Current in the 9K resistance?
C5.2. Current in the 1K resistance?
C5.3. Current in the 5 V source?
Circuit 5
C5.4. Potential drop from point A to point B?1i
2i
3i
Equation of the circuit
5
5
0
503
054
3416
3
2
1
i
i
i
503
054
3416
505
055
340
1
553
054
3016
2
503
554
0416
3
C5.1. Current in the 9K resistance?
C5.2. Current in the 1K resistance?
C5.3. Current in the 5 V source?
C5.4. Potential drop from point A to point B?
mA 091.011
i
mA 073.122
i
mA 946.033
i
mA 091.019 ii K
mA 073.121 ii K
mA 019.2325 iii VThe same direction as i2, opposite direction to i3.
V 07.11 2 iVAB
BA VV V 07.129 31 iiVAB
Mesh currents
ME
SH
AN
AL
YS
IS. E
XE
RC
ISE
S
8
K 3
V 5.4
K 4K 2
A
K 4
K 3
C
B
For you to solveM
ES
H A
NA
LY
SIS
. EX
ER
CIS
ES
C6.1. Potential drop from point A to point B?
C6.2. Potential drop from point B to point C?
C6.3. Potential drop from point A to point C?
Circuit 6
C6.4. Equivalent resistance of the set?
(Note that this set is neither a series nor a parallel association).
