Burbank, Osage County, Oklahoma

I. Background of the Field II. Primary Recovery: Solution-Gas Drive

III. Secondary Recovery: WaterfloodIV. Enhance Oil Recovery: MIcellar Polymer Flooding

Introduction

Location of Burbank Field on the Map

The burbank field is located principally in Osage County, but with a small extension into Kay

County

Some of the companies involved in Burbank Field

History

Elbridge Ayer Burbank

Ernest Witworth Marland

The Osage Tribe

Reservoir Geology

East Burbank Pool

Fluid and Rock Properties

Solution Gas Drive

Stages of Production

Stage 1

Production while undersaturated

Stage 2

Production while saturated but the free gas is immobile

Stage 3

Production while saturated and the free gas is mobile and the producing gas-oil ratio (GOR) is increasing

Stage 4

Production while saturated and the free gas is mobile and the producing GOR is decreasing

Waterflood

III. Secondary Recovery: Waterflood

A. Reservoir Geology Considerations

• understanding the reservoir rocks • the diagenetic history of the reservoir rocks must be

ascertained• the structure and faulting of the reservoir must be

determined • the water/oil/rock characteristics need to be

understood

B. Waterflooding Considerations

• Oil properties • viscosity and density at reservoir

conditions• the mobility of a fluid is defined as its

endpoint relative permeability divided by its viscosity

THE FORMULA FOR OVERALL WATERFLOOD OIL-RECOVERY EFFICIENCY ER

C. Rationale for Waterflooding• The waterflood performance of this stratified reservoir can

prove reasonably accurate. • Permeability values in this reservoir range from less than 0.1

md to nearly 3 darcys and 90 percent of the permeability capacity is contained in approximately 26 percent of the reservoir volume.

• Nearly 70 percent of the recovery can be achieved at water-cut values greater than 95 percent.

D .Reservoir Data & Criteria Comparison

E. Waterflood Production Facilities• 250-600 psia• Equipped either with staged centrifugal pumps or

multistage pot turbine pump• Water treatment- sodium hexametaphospate

THE OIL PRODUCTION WILL BE GATHERED AND MONITORED AT SEPARATE FACILITIES. THEIR LOCATIONS WILL BE EQUIPPED WITH LACT UNITS AND CONVENTIONAL TANK BATTERIES.

The high productivity indices of most of the

producing wells have permitted wide application of

large-volume, submergible, multi-stage centrifugal

pumps. Individual producing well potentials of 3,000 to

4,000 BFPD are not uncommon and several will be

operated in the 5,000 to 7,000 BFPD range.

OIL RECOVERY

• Ultimate primary and secondary will be 302 bbl/acre-ft which is approximately 40 percent of the OSTOIP

Enhanced Oil Recovery

Micellar Polymer Flooding

A. Screening Criteria for Micellar Polymer Flooding

• API Gravity >20o

• Viscosity <35cp• Composed of light and/or intermediate oils• Oil Saturation >35%• Net Thickness is no critical• Average Permeability of >10md• Depth of >9000ft• Temperature >80oF

B. Reservoir Data & Criteria Comparison

C. Surfactant Design

The proposed surfactant-polymer project will

cover approximately 90 acres, and would

comprise of inverted five-spot patterns of

approximately ten acres each.

Major Concerns and Solutions:

1. High salinity and hardness of the formation

water

2. Fractures

3. Oil-wet nature of rocks

D. Recovery Efficiency

Volumetric Determination of Original Oil in Place

Calculation of N:

N = 7758Aho(1-Sw)/Boi

= 7758(164,816 acre-ft)(0.18)(0.22)/1.050

= 48.2231 MMSTB

Sweep Efficiency

• Vertical Sweep Efficiency

• Areal Sweep Efficiency

Displacement Efficiency

Vertical Sweep Efficiency• Using production data and the Dykstra-

Parsons Chart

Vertical Sweep Efficiency

The Ev value is approximately 0.27.

Areal Sweep Efficiency

Inverted Five-Spot Pattern

Areal Sweep Efficiency

Displacement Efficiency

Displacement Efficiency

Core Data

Calculation of Ed

Ed = (So – Sor)/So

= (1-0.63) / 1

Ed = 0.37

Calculation of Recovery Efficiency

Formula for overall flood oil-recovery efficiency ER

Calculation of ER

ER = EDEIEA

= 0.37 x 0.27 x 1.17

ER = 0.1169 = 11.69%

Volume of Oil that can be further Recovered

NR = NER

Calculation of NR

NR = NER

= 48.2231 x 0.1169

NR = 5.6373 MMSTB