Bryton Real Erick

8/12/2019 Bryton Real Erick

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Career: Aeronautical Engineering

Cuatrimestre: 8A

Teacher: Dr. Pablo Alejandro Arizpe Carren

Student: Erick Alberto Trejo Ziga

Subject: Fundamentals of rotary engine.Homework: Real Simple Joule Brayton Cycle


2/21

0

100

200

300

400

500

2 4 6 8 10 12 14 16 18 20 22 24 26 28 30

Wc

Wc

T=800C

T=900C

T=1000C

T=1100C

T=1200C

T=1300C

T=1400C

As can be seen, the compression work increases relative to the pressure ratio, this is due to having more pressure ratio

(compression), we are saying that the air entering at a constant ambient pressure passing through the compressor, compressed

more times in relation to the inlet pressure to produce a greater compression work.


3/21

Real form, the compression work is increased in relation to the compression ratio but is higher than the ideal work because air to

pass right through the compressor, friction occurs, which increases the temperature at the output thereof causing the energy

produced by friction increases the compression work.

0

100

200

300

400

500

600

2 4 6 8 10 12 14 16 18 20 22 24 26 28 30

Wc'

Wc'

T=800C

T=900C

T=1000C

T=1100C

T=1200C

T=1300C

T=1400C


4/21

As can be seen, the work turbine is affected by the temperature change of design, as it is the temperature at the turbine inlet, the

pressure ratio also increases and the work of turbine does likewise due that ideally the compression ratio is equal to the ratio

expansion, so having more expansion turbine work increases, because the combustion gases to exit with greater pressure increase

turbine work

0

200

400

600

800

1000

1200

0 5 10 15 20 25 30 35

Wt

Wt

T=800C

T=900C

T=1000C

T=1100C

T=1200C

T=1300C

T=1400C


5/21

.

As can be seen, the work of actual turbine is greater than the ideal job, this is because the friction, additional energy is produced,

there will be more heat which results in more work, the actual work increase for the same reasons that the ideal job, since increasing

the expansion ratio of the turbine moves with greater magnitude turbine producing more work.

0

200

400

600

800

1000

1200

0 5 10 15 20 25 30 35

Wt'

Wt'

T=800C

T=900C

T=1000C

T=1100C

T=1200C

T=1300C

T=1400C


6/21

The heat supplied to each T3 increases with increasing temperature but the pressure ratio decreases the heat this is because the

expansion ratio is inversely proportional to T3.

0

200

400

600

800

1000

1200

1400

0 5 10 15 20 25 30 35

qs

qs

T=800C

T=900C

T=1000C

T=1100C

T=1200C

T=1300C

T=1400C


7/21

Real form, qs is higher than ideal due to the friction of mechanical parts and production of friction, creating more heat because the

energy that is sent to the combustion chamber is larger and increases the heat supplied.

0

200

400

600

800

1000

1200

1400

1600

1800

0 5 10 15 20 25 30 35

qs'

qs'

T=800C

T=900C

T=1000C

T=1100C

T=1200C

T=1300C

T=1400C


8/21

As shown in the graph as the heat supplied increases as the design temperature grows, as this is said to be a higher inlet temperature

(the temperature of the turbine exhaust gases), having a higher temperature in the turbine the more heat will be rejected, decreases

with respect to the pressure ratio.

0

200

400

600

800

1000

1200

0 5 10 15 20 25 30 35

qr

qr

T=800C

T=900C

T=1000C

T=1100C

T=1200C

T=1300C

T=1400C


9/21

As you can observe the actual heat rejected is much higher than ideal, this because in the real rejected heat is taken into account fuel

and energy produced by friction, this means that in reality the turbine exit the heat rejection is greater, also as can be seen as the

pressure ratio (expansion) increases this decreases this is because the temperature of the turbine outlet is inversely proportional to

the expansion ratio so that exceed this the temperature 4 decreases.

0

200

400

600

800

1000

1200

1400

1600

0 5 10 15 20 25 30 35

qr'

qr'

T=800C

T=900C

T=1000C

T=1100C

T=1200C

T=1300C

T=1400C


10/21

The useful work is increased depending on the temperature of the turbine inlet (T3) that due to the temperature increase that inject

more energy to the turbine to produce more work, to produce greater turbine work and constant compression work, work be much

more useful, as can be seen with increasing T3 ideally more useful work starts to become constant, but at lower temperatures reach

a peak and then begins to lower himself there because this passes the opt peaking useful work that can be produced with this

design temperature after their began to decrease.

0

100

200

300

400

500

600

0 5 10 15 20 25 30 35

Wutil

Wutil

T=800C

T=900C

T=1000C

T=1100C

T=1200C

T=1300C

T=1400C


11/21

Para el trabajo til real, esto disminuye porque en realidad no todo el trabajo producido puede ser explotado porque hay prdidas por

friccin, ya que en realidad se puede observar a pesar del aumento de la temperatura de diseo esta alcanza un mximo y luego

empieza a disminuir, lo mismo que sucede como con el ideal llega a su relacin de presin ptima que experiment el mximo

trabajo til y luego comenz a disminuir.

0

100

200

300

400

500

600

0 5 10 15 20 25 30 35

Wutil'

Wutil

T=800C

T=900C

T=1000C

T=1100C

T=1200C

T=1300C

T=1400C


12/21

As shown, the specific fuel consumption is maintained almost constant for each T3 but by increasing the pressure ratio begins to

decrease this due to having more compression and expansion respectively greater energy and labor in the compressor occurs and

the turbine, doing this is that as the energy increased fuel consumption is increasingly smaller to meet the required power.

0

0.1

0.2

0.3

0.4

0.5

0.6

0.7

0.8

0.9

0 5 10 15 20 25 30 35

SFC

SFC

T=800C

T=900C

T=1000C

T=1100C

T=1200C

T=1300C

T=1400C


13/21

In the specific case of actual fuel consumption is the same, but here depend on the increase in T3 and friction, as can be seen as

having a lower temperature and with increasing pressure ratio declining but this anger reached a point where consumption begins to

increase, and if we increase the temperature at the turbine inlet and increase the pressure ratio that will produce more work so less

fuel is needed to meet the required power.

0

0.1

0.2

0.3

0.4

0.5

0.6

0.7

0.8

0.9

0 5 10 15 20 25 30 35

SFC'

SFC'

T=800C

T=900C

T=1000C

T=1100C

T=1200C

T=1300C

T=1400C


14/21

As can be seen, the f of fuel will be increased for each increase in T3 but decrease with increased pressure ratio, this is due to having higher

pressure ratio greater work in the turbine and the compressor occurs, the increase work due to this condition the fuel to meet growing power

will be lower but for maximum temperature increasing f will be greater.

0

0.005

0.01

0.015

0.02

0.025

0.03

0.035

0.04

0.045

0 5 10 15 20 25 30 35

f

f

T=800C

T=900C

T=1000C

T=1100C

T=1200C

T=1300C

T=1400C


15/21

0

50

100

150

200

250

300

0 10 20 30 40

a

a

T=800C

T=900C

T=1000C

T=1100C

T=1200C

T=1300C

T=1400C0

50

100

150

200

250

300

350

0 10 20 30 40

a'

a'

T=800C

T=900C

T=1000C

T=1100C

T=1200C

T=1300C

T=1400C

As can be seen, the mass flow is inversely proportional to the useful work, this means that a constant power to meet and have a

useful work increasing the mass flow will decrease, this encompasses that when you reach the maximum useful work also reaches

the minimum mass flow as the useful work begins to decrease the mass flow increase to meet a fixed power can be increased in area

and increase the mass flow which we create the need for a less useful work in a real way the mass flow is needed is greater as the

frictional losses have useful W decreases.


16/21

0

1

2

3

4

5

6

0 10 20 30 40

f

f

T=800C

T=900C

T=1000C

T=1100C

T=1200C

T=1300C0

1

2

3

4

5

6

0 10 20 30 40

f'

f'T=800C

T=900C

T=1000C

T=1100C

T=1200C

T=1300C

T=1400C

As seen in the graphs, as the specific fuel consumption by increasing the pressure ratio as already mentioned turbine work therefore

increases the need for more fuel to meet the power requirement decreases, have less fuel mass flow thereof also decrease real way,

he knows there are friction losses which makes the actual work is less than ideal so really the fuel mass flow increase, unlike the

perfect flow actual fuel mass for smaller design temperature will be greater at lower temperatures because the turbine will p roduce

less work.


17/21

0

0.1

0.2

0.3

0.4

0.5

0.6

0 10 20 30 40

t

t

T=800C

T=900C

T=1000C

T=1100C

T=1200C

T=1300C

T=1400C 0

0.05

0.1

0.15

0.2

0.25

0.3

0.35

0.4

0.45

0 10 20 30 40

t'

t'T=800C

T=900C

T=1000C

T=1100C

T=1200C

T=1300CT=1400C

As shown in the graphs, the efficiency increases as the pressure ratio and ideally for each design temperature is nearly equal, this

increases efficiency and lower design temperature remains almost constant, but the actual efficiency shows that design temperature

low and increased the pressure ratio, this reached a maximum and then there will decrease, this is because in reality not all work

produced can be tapped, there lost with those produced by the friction causing the efficiency real turbine is less than ideal.


18/21

0

500

1000

2 4 6 8 10 12 14 16 18 20 22 24 26 28 30

T2

T2

T=800C

T=900C

T=1000C

T=1100C

T=1200C

T=1300C

T=1400C

0

500

1000

2 4 6 8 10 12 14 16 18 20 22 24 26 28 30

T2'

T2'

T=800C

T=900C

T=1000C

T=1100C

T=1200C

T=1300C

T=1400C

The T2 increases due to increased pressure ratio that is because air enters the compressor and to deflect this higher temperature

occurs, actually the temperature at the compressor outlet is higher because when air enters and pink party mechanical friction

occurs by increasing the temperature.


19/21


20/21

0

2000

4000

2 4 6 8 10 12 14 16 18 20 22 24 26 28 30

P2=P3

P2=P3

T=800C

T=900C

T=1000C

T=1100C

T=1200C

T=1300C

T=1400C

As shown, the pressure 2 and 3 of the pressure are equal ideally even compression and expansion ratios are also, to increase the

pressure ratio of the pressure increase linear 3 in any real pressure relationships are not are equal pressure losses due to friction so

that the actual manner p3 is less than ideal p3.

0

1000

2000

3000

2 5 8 11 14 17 20 23 26 29

P3'

P3'

T=800C

T=900C

T=1000C

T=1100C

T=1200C

T=1300C

T=1400C


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CONCLUSIONS:

With the completion of work, it was observed that the ideal conditions vary too much from the real, this due to an effect called friction, the

friction present in the component produces heat which causes variations in parameters such as turbine and compression works by altering cycle,

that is why the actual temperatures are higher but that does not mean it's good because the energy is lost in heat which makes the real

efficiencies decrease and vary from ideal.

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Bryton Real Erick