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8/4/2019 BmE_05
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1
Prof. Dr. Nizamettin AYDIN
[email protected] [email protected]
http://www.yildiz.edu.tr/~naydin
Biomedical Instrumentation
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Amplifiers and Signal Processing
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Applications of Operational Amplifier
In Biological Signals and Systems
• The three major operations done on biologicalsignals using Op-Amp:
– Amplifications and Attenuations – DC offsetting:
• add or subtract a DC
– Filtering:
• Shape signal’s frequency content
3
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Ideal Op-Amp
• Most bioelectric signals are small and require amplifications
Op-amp equivalent circuit:
The two inputs are 1 and 2. A differential voltage between them causes
current flow through the differential resistance Rd. The differential voltage
is multiplied by A, the gain of the op amp, to generate the output-voltage
source. Any current flowing to the output terminal vo must pass through the
output resistance Ro.4
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Inside the Op-Amp (IC-chip)
20 transistors
11 resistors
1 capacitor
5
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Ideal Characteristics
• A = (gain is infinity)
• V o = 0, when v1 = v2 (no offset voltage)
• Rd = (input impedance is infinity)
• Ro = 0 (output impedance is zero)
• Bandwidth = (no frequency response limitations) and no
phase shift
6
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Two Basic Rules
• Rule 1
– When the op-amp output is in its linear range, the two input terminalsare at the same voltage.
• Rule 2
– No current flows into or out of either input terminal of the op amp.
7
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Inverting Amplifier
(a) An inverting amplified. Current flowing through the inputresistor Ri also flows through the feedback resistor Rf .
(b) The input-output plot shows a slope of - Rf / Ri in the central
portion, but the output saturates at about±13 V.
8
Ri i
o
i
Rf
i
+
-
(a)
10 V
10 V
(b)
i
o
Slope = - Rf / Ri
-10 V
-10 V
i
f
i
oi
i
f
o R
R
v
vGv
R
Rv --
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Summing Amplifier
9
-
2
2
1
1
R
v
R
v Rv f o
1
o
-
+
R2
R1 Rf
2
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Example 3.1
• The output of a biopotential preamplifier thatmeasures the electro-oculogram is an undesired
dc voltage of ±5 V due to electrode half-cell
potentials, with a desired signal of ±1 V
superimposed. Design a circuit that will
balance the dc voltage to zero and provide a
gain of -10 for the desired signal without
saturating the op amp.
10
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Answer 3.1
• We assume that vb, the balancing voltage at vi=5 V. For vo=0,
the current through R f is zero. Therefore the sum of the currents
through Ri and Rb, is zero.
11
i
v b
i
o
o
-
+
+15V
+10
0 Time
i + b /2
-10
(a) (b)
5 k W
-15 V
Rb
20 k W
Ri
10 k W
Rf
100 k W
V o l t a g e , V
W--
-
44
1025
)10(100
i
bi
bb
b
i
o
v
v R R
R
v
R
v
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Follower ( buffer)
• Used as a buffer, to prevent a high source resistance
from being loaded down by a low-resistance load. In
another word it prevents drawing current from the
source.
12
o i +
-
1 Gvv io
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Noninverting Amplifier
13
o
10 V
10 V
i
Slope = ( Rf + Ri )/ Ri
-10 V
-10 V
Rf
o i
i
+
-
i
Ri
i
f
i
i f
i
i
i f
o R
R
R
R RGv
R
R Rv 1
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Differential Amplifiers
• Differential Gain G d
• Common Mode Gain G c – For ideal op amp if the inputs are equal
then the output = 0, and the Gc = 0.
– No differential amplifier perfectly rejects
the common-mode voltage.
• Common-mode rejection ratio CMMR
– Typical values range from 100 to 10,000
• Disadvantage of one-op-amp differential amplifier is its low
input resistance
14
3
4
34 R
R
vv
vG o
d -
v3
v4
)( 34
3
4 vv R
Rvo -
c
d
GGCMRR
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Instrumentation Amplifiers
Differential Mode Gain
Advantages: High input impedance, High CMRR, Variable gain
15
1
12
21
43
121
21243
2
)(
R
R R
vv
vvG
iRvv
R R Rivv
d
-
-
-
-
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Comparator – No Hysteresis
o
i ref
10 V
-10 V
-10 V
v2
+15
-15
i
o
-
+
R1
R1
R2
ref
If (vi+vref ) > 0 then vo = -13 V else vo = +13 V
R1 will prevent overdriving the op-amp
v1 > v 2, v o = -13 V
v1 < v 2, v o = +13 V
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Comparator – With Hysteresis
• Reduces multiple transitions due to mV noise levels
by moving the threshold value after each transition.
Width of the Hysteresis = 4VR3
17
i
o
-
+
R1
R1
R2
R3
ref
o
i- ref
10 V
-10 V
With hysteresis
-10 V 10 V
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Rectifier
• Full-wave precision rectifier:
– For i > 0, D2 and D3 conduct, whereas
D1 and D4 are reverse-biased.Noninverting amplifier at the top is active
18
10 V
(b)
-10 V
o
i
-10 V 10 V
(a)
D2
v o
i
-
+
xR (1-x)R
-
+
(a)
D3
R
R
i
-
+
D2 D1
D4
xR (1- x) R
x
vv io
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Rectifier
• Full-wave precision rectifier:
– For i < 0,
D1 and D4 conduct, whereas D2 and D3 arereverse-biased.
Inverting amplifier at the bottom is active
19
10 V
(b)
-10 V
o
i
-10 V 10 V -
+
(a)
D3
R
R
i
-
+
D2 D1
D4
xR (1- x) R
x
vv io
(b)
D4
v o i
-
+
xRi R
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One-Op-Amp Full Wave Rectifier
• For i < 0, the circuit behaves like the inverting
amplifier rectifier with a gain of +0.5. For i > 0, theop amp disconnects and the passive resistor chain
yields a gain of +0.5.
20
(c)
D
v o
i
-
+
Ri = 2 k W Rf = 1 k W
RL = 3 k W
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Logarithmic Amplifiers
• Uses of Log Amplifier
– Multiply and divide variables – Raise variable to a power
– Compress large dynamic range into small ones
– Linearize the output of devices
(a) A logarithmic amplifier makes use of the fact that a transistor's V BE is
related to the logarithm of its collector current.
For range of Ic equal 10-7 to 10-2 and the range of vo is -.36 to -0.66 V.
21
(a)
Rf
I c R f /9
o
Ri i
-
+
-13
10
log06.0
i
io
R
vv
S
C BE
I I V log06.0
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Logarithmic Amplifiers
(a) With the switch thrown in the alternate position, the
circuit gain is increased by 10. (b) Input-outputcharacteristics show that the logarithmic relation is
obtained for only one polarity; 1 and 10 gains are
indicated.
22
(b)
10 V
-10 V
v o
i
-10 V
1
10
10 V
(a)
Rf
I c R f /9
o
Ri i
-
+
VBE
VBE
9VBE
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Integrators
23
f f
c
i
f
i
o
C R f
R
R
v
v
2
1
-
for f < f c
C R j R R jV
jV
C R R j R
R
jV
jV
Z
Z
jV
jV
vdt vC Rv
i
f
ii
o
i f i
f
i
o
i
f
i
o
t
ici f i
o
-
-
-
-
1
)(
)(
1 1
0
A large resistor Rf is used to prevent saturation
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• A three-mode integrator
With S1 open and S2 closed, the dc circuit behaves as an inverting amplifier.
Thus o = ic and o can be set to any desired initial conduction. With S1
closed and S2 open, the circuit integrates. With both switches open, the
circuit holds o constant, making possible a leisurely readout.
24
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Differentiators
• A differentiator
– The dashed lines indicate that a small capacitor must
usually be added across the feedback resistor to prevent
oscillation.
25
RC j jV
jV Z
Z
jV
jV
dt
dv RC v
i
o
i
f
i
o
io
-
-
-
)(
)()(
)(
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Active Filters- Low-Pass Filter
• A low-pass filter attenuates high frequencies
26
f f i
f
i
o
C R j R
R
jV
jV
-
1
1 GGain
|G|
freq f c = 1/2RiCf
Rf /Ri
0.707 Rf /Ri
+
- Ri
Rf
(a)
i
o
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Active Filters (High-Pass Filter)
• A high-pass filter attenuates low frequencies
and blocks dc.
27
C i
+
- Ri
i o
(b)
Rf ii
ii
i
f
i
o
C R j
C R j
R
R
jV
jV
-
1 GGain
|G|
freq f c = 1/2RiCf
Rf /Ri
0.707 Rf /Ri
A i i ( i )
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Active Filters (Band-Pass Filter)
• A bandpass filter attenuates both low and high
frequencies.
28
ii f f
i f
i
o
C R jC R j
C R j
jV
jV
-
11
|G|
freq f
cL= 1/2R
iC
i
Rf /Ri
0.707 Rf /Ri
f cH
= 1/2Rf C
f
+
- i
o
(c)
Rf C i Ri
C f
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Frequency Response of op-amp and Amplifier
• Open-Loop Gain
• Compensation
• Closed-Loop Gain
• Loop Gain
• Gain Bandwidth Product• Slew Rate
29
I d O R i
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Input and Output Resistance
30
d
i
iai R A
i
v R )1(
+
-
Rdii
Ro
RL C L
io A d
d o
i
+
-
1
A
R
i
v R o
o
oao
Typical value of Rd = 2 to 20 MW Typical value of Ro = 40 W
Phase Modulator for Linear variable differential
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Phase Modulator for Linear variable differentialtransformer LVDT
31
+
-
+
-
Phase Modulator for Linear variable differential
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Phase Modulator for Linear variable differentialtransformer LVDT
32
+
-
+
-
Ph S iti D d l t
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Phase-Sensitive Demodulator
33
Used in many medicalinstruments for signal detection,
averaging, and Noise rejection
Th Ri D d l t
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The Ring Demodulator
• If vc is positive then D1 and D2 are forward-biased and vA = vB. So vo = vDB
• If vc is negative then D3 and D4 are forward-biased and vA = vc. So vo = vDC