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Bell Ringer 2/20/15
Completely Factor & Check your answer.
1.Factor: 2x2 - 14x + 12
2.Factor: y2 + 4y + 4
3.Factor: 75x2 – 12
ObjectiveThe student will be able to:
factor perfect square trinomials.
Factoring ChartThis chart will help you to determine
which method of factoring to use.Type Number of Terms
1. GCF 2 or more
2. Grouping 4
3. Trinomials 3
First terms:
Outer terms:
Inner terms:
Last terms:
Combine like terms.
y2 + 4y + 4
y2
+2y+2y+4
Review: Multiply (y + 2)2
(y + 2)(y + 2)Check this out…whaaat!!
(a + b)2 = a2 + 2ab + b2
(a - b)2 = a2 – 2ab + b2
Using the formula, (y + 2)2 = (y)2 + 2(y)(2) + (2)2
(y + 2)2 = y2 + 4y + 4
Which one is quicker?
1) Factor x2 + 6x + 9
Does this fit the form of our perfect square trinomial?
1) Is the first term a perfect square?
Yes, a = x2) Is the last term a perfect
square?Yes, b = 3
3) Is the middle term twice the product of the a and b?Yes, 2ab = 2(x)(3) = 6x
Perfect Square Trinomials(a + b)2 = a2 + 2ab + b2
(a - b)2 = a2 – 2ab + b2
Since all three are true, write your answer!
(x + 3)2
You can still factor the other way but this is quicker!
2) Factor y2 – 16y + 64
Does this fit the form of our perfect square trinomial?
1) Is the first term a perfect square?
Yes, a = y2) Is the last term a perfect
square?Yes, b = 8
3) Is the middle term twice the product of the a and b?Yes, 2ab = 2(y)(8) = 16y
Perfect Square Trinomials(a + b)2 = a2 + 2ab + b2
(a - b)2 = a2 – 2ab + b2
Since all three are true, write your answer!
(y – 8)2
Factor m2 – 12m + 36
1. (m – 6)(m + 6)
2. (m – 6)2
3. (m + 6)2
4. (m – 18)2
3) Factor 4p2 + 4p + 1
Does this fit the form of our perfect square trinomial?
1) Is the first term a perfect square?
Yes, a = 2p2) Is the last term a perfect
square?Yes, b = 1
3) Is the middle term twice the product of the a and b?Yes, 2ab = 2(2p)(1) = 4p
Perfect Square Trinomials(a + b)2 = a2 + 2ab + b2
(a - b)2 = a2 – 2ab + b2
Since all three are true, write your answer!
(2p + 1)2
ObjectiveThe student will be able to:
factor using difference of squares.
Factoring ChartThis chart will help you to determine
which method of factoring to use. Type Number of Terms1. GCF 2 or more
2. Grouping 4
3. Trinomials 3
4. Difference of Squares 2
Determine the pattern1
4
9
16
25
36
…
= 12
= 22
= 32
= 42
= 52
= 62
These are perfect squares!
You should be able to list the first 15 perfect
squares …
Perfect squares1, 4, 9, 16, 25, 36, 49, 64, 81, 100, 121, 144, 169, 196, 225
Review: Multiply (x – 2)(x + 2)
First terms:
Outer terms:
Inner terms:
Last terms:
Combine like terms.
x2 – 4
x -2
x
+2
x2
+2x
-2x
-4
This is called the difference of squares.
x2
+2x-2x-4
Notice the middle terms
eliminate each other!
Difference of Squares
a2 - b2 = (a - b)(a + b)or
a2 - b2 = (a + b)(a - b)
The order does not matter!!
4 Steps for factoringDifference of Squares
1. Are there only 2 terms?2. Is the first term a perfect square?3. Is the last term a perfect square?4. Is there subtraction (difference) in the
problem?If all of these are true, you can factor
using this method!!!
1. Factor x2 - 25When factoring, use your factoring table.
Do you have a GCF?
Are the Difference of Squares steps true?Two terms?
1st term a perfect square?
2nd term a perfect square?
Subtraction?
Write your answer!
No
Yes x2 – 25
Yes
Yes
Yes
( )( )5 xx + 5-
2. Factor 16x2 - 9When factoring, use your factoring table.
Do you have a GCF?
Are the Difference of Squares steps true?Two terms?
1st term a perfect square?
2nd term a perfect square?
Subtraction?
Write your answer!
No
Yes 16x2 – 9
Yes
Yes
Yes
(4x )(4x )3+ 3-
When factoring, use your factoring table.
Do you have a GCF?
Are the Difference of Squares steps true?Two terms?
1st term a perfect square?
2nd term a perfect square?
Subtraction?
Write your answer!
(9a )(9a )7b+ 7b-
3. Factor 81a2 – 49b2
No
Yes 81a2 – 49b2
Yes
Yes
Yes
Factor x2 – y2
1. (x + y)(x + y)
2. (x – y)(x + y)
3. (x + y)(x – y)
4. (x – y)(x – y)
Remember, the order doesn’t matter!
Factor 18c2 + 8d2
1. prime
2. 2(9c2 + 4d2)
3. 2(3c – 2d)(3c + 2d)
4. 2(3c + 2d)(3c + 2d)
You cannot factor using difference of squares because there is no
subtraction!
ObjectiveThe student will be able to:
use the zero product property to solve equations
Zero Product Property
If a • b = 0 then
a=0,
b=0,
or both a and b equal 0.
1. Set the equation equal to 0.2. Factor the equation.3. Set each part equal to 0 and
solve.4. Check your answer on the
calculator if available.
4 steps for solving a quadratic equation
Set = 0Factor
Split/SolveCheck
Using the Zero Product Property, you know that either x + 3 = 0 or x - 5 = 0
Solve each equation.
x = -3 or x = 5
{-3, 5}
1. Solve (x + 3)(x - 5) = 0
2. Solve (2a + 4)(a + 7) = 02a + 4 = 0 or a + 7 = 0
2a = -4 or a = -7
a = -2 or a = -7
{-2, -7}
3. Solve (3t + 5)(t - 3) = 0
3t + 5 = 0 or t - 3 = 0
3t = -5 or t = 3
t = -5/3 or t = 3
{-5/3, 3}
4. Solve x2 - 11x = 0
GCF = x
x(x - 11) = 0
x = 0 or x - 11 = 0
x = 0 or x = 11
{0, 11}
Set = 0Factor
Split/SolveCheck