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Chemistry M.4 Lesson 1
Atom and Periodic Table
by Angka Teprattananan
1angka teprattananan 2
conclude conductivitymatter voltage
divide pressure
agree electric current
made up electric field
theory negative
compose charge to mass
destroy appear
combine discover
definite positive
Vocabulary
angka teprattananan
Greek Model Over 2,000 years ago Democritus concluded that
matter could not be divided into smaller and smaller pieces forever
Named the smallest piece �atomos�
But Aristotle didn�t agree with the concept of atoms.
Aristotle thought the earth was composed of matter - which made up of four elements:
�earth, air, fire, and water�.
Democritus (c460-371 BC)
3
Aristotle (384-322 BC)
angka teprattananan
¨oË �¹ ´oŵ a¹ ( John Dalton )
Dalton�s Atomic model1. All elements are composed of atoms.
It is impossible to divide or destroy an atom.2. All atoms of the same elements are
alike. 3. Atoms of different elements are
different. 4. Different atoms combine to form a
compound in definite whole number ratios. e.g. H2O , CO2 (Expect Na ,H2 , Br2 , P4 , S8)
4angka teprattananan
(Dalton�s atomic model)
oaµoÁÁÕÃٻà �Ò§e» �¹·Ã§¡ÅÁ ÁÕ¢¹Ò´eÅç¡ äÁ �ÊÒÁÒÃ¶æº �§æ¡æÅaÊÙËÒÂä´ �
5angka teprattananan
e¨ e¨ ·oÁÊ a¹ (J.J. Thomson)
6
J.J. Thomson Studied electrical conductivity of gases
by using a cathode ray tube in high voltage and low pressure.
Passing an electric current makes a beam appear to move from the cathode to the anode end.
angka teprattananan
Thomson�s Experiment
+‐voltage sourceOFF
ON
+
‐By adding an electric field ,
he found that the moving pieces were negative.
And negative particle was called �Electron�
Thomson was able to measure the charge to mass ratio of the electron
q/me = 1.76 x 108 coulombs/gram
7angka teprattananan
Discovery of the Proton– Discovered by Eugen Goldstein– He observed �Canal rays� and found that they
are composed of positive particles � Proton.
8
Eugen Goldstein
angka teprattananan
Canal RaysCanal Rays passed through holes, or channels, in
the reverse direction as the cathode ray.
9
__cathode anode
+
angka teprattananan
¨Ò¡¡Ò÷´Åo§¢o§o¡Å´ �Êäµ¹ Êà u»ä´ �Ç �Ò - à a§ÊպǡËà oo¹ uÀÒ¤ºÇ¡e¡ i ¨Ò¡æ¡ �Ê·ÕèºÃè uÀÒÂã¹ËÅo´Ã a§ÊÕ
æ¤o·´ « è§eºÕè§eº¹e¢ �ÒËÒ¢ aéÇÅºä´ �· aé§ã¹Ê¹ÒÁä¿¿ �ÒæÅaʹÒÁæÁ �eËÅç¡- à a§ÊպǡÁÕ¤ �ÒoaµÃÒÊ �ǹ»Ãa¨ uµ �oÁÇÅäÁ �¤§·Õè ¢ é¹oÂÙ�¡ aºª¹ i´¢o§
æ¡ �Ê·ÕèºÃè uoÂÙ�ÀÒÂã¹ËÅo´Ã a§ÊÕæ¤o·´- ¶ �Òe»ÅÕèÂ¹æ¡ �Êe» �¹äÎo´Ãe¨¹ ¨a¾ºÇ �Òo¹ uÀÒ¤ºÇ¡·Õèe¡ i ¢ 鹨aÁÕ
¤ �Ò»Ãa¨ ue· �Ò¡ aºoieÅ硵Ão¹¾o´Õ ¨ §eÃÕ¡o¹ uÀÒ¤ºÇ¡¹ÕéÇ �Ò �o»Ãµo¹�
10angka teprattananan
Mass of the Electron
Millikan determines the charge of the electron : 1.60 x 10-19 C and the mass of the electron: 9.1 x 10-28 g
The oil drop apparatus
11angka teprattananan
Calculate mass of the Electron1. charge to mass ratio = 1.76x108 coulombs/gram2. charge of electron: = 1.60 x 10-19 g
12angka teprattananan
Thomson�s Atomic Model(Plum Pudding Model)
�oaµoÁe» �¹·Ã§¡ÅÁ »Ãa¡oº´ �ÇÂo»Ãµo¹·ÕèÁÕ»Ãa¨ uºÇ¡æÅaoieÅ硵Ão¹·ÕèÁÕ»Ãa¨ uźoÂÙ�o �Ò§¡Ãa¨ a´¡Ãa¨Ò æÅaÊíÒËà aºoaµoÁ·Õèe» �¹¡ÅÒ§·Ò§
ä¿¿ �Ò¨aÁÕ¨íҹǹo»Ãµo¹e· �Ò¡ aº¨íҹǹoieÅ硵Ão¹¾o´Õ�13angka teprattananan 14
bombarded emit
experiment symbol
gold foil atomic number
spread out mass number
passed through subatomic particlerefract
reflect equal
empty space
distribute
occupy
Vocabulary
angka teprattananan
Discovery of Nucleus
Tested Thomson�s model of atomic structure with the �gold foil� experiment.
Bombarded thin gold foil with a beam of �alpha� particles.
If the positive charge was evenly spread out, the beam should have easily. passed through.
Ernest Rutherford
15angka teprattananan
Most of the particles passed through A few particles were refracted VERY FEW were greatly reflected
16angka teprattananan
Based on his experimental evidence:
The atom is mostly empty space All the positive charge, and
almost all the mass is in a small area in the center. He called this a �nucleus� The electrons distributed around
the nucleus, and occupy most of the volume His model was called a �nuclear
model�
17angka teprattananan
Rutherford's Atomic Model
�oaµoÁ»Ãa¡oº´ �ǹ iÇe¤ÅÕÂÊ« è§ÁÕ»Ãa¨ uºÇ¡(o»Ãµo¹)oÂÙ�µÃ§¡ÅÒ§ ÁÕ¢¹Ò´eÅç¡ÁÒ¡æÅaÁÕÁÇÅÁÒ¡ Ê �ǹoieÅ硵Ão¹·ÕèÁÕ»Ãa¨ uźæÅaÁÕÁÇŹ �o e¤Å èo¹·ÕèÃoº¹ iÇe¤ÅÕÂÊe» �¹ºÃ iedz¡Ç �Ò§"
18angka teprattananan
The Discovery of the Neutron Chadwick bombarded alpha particles at
Beryllium.Neutrons were emitted and in turn hit parafin
and ejected protons from the parafin.Neutrons have mass similar to protons. No electrical charge.
19
James Chadwick
angka teprattananan
The Subatomic particlesSubparticle symbol charge mass(g) mass(amu)
electron e -1 9.1x10-27 0.0005proton p +1 1.67x10-24 1.0072neutron n 0 1.67x10-24 1.0086
THE MASS OF THE NEUTRON IS 1839 times greater than an electron.
Composition of the Nucleus:• nuclei are composed of "nucleons": protons and neutrons • atomic mass units: 1 amu = exactly 1/12 the mass of a carbon-
12 nucleus 20angka teprattananan
¤ÇÒà �¡ ¤ o o¹ uÀÒ¤·ÕèeÅç¡·ÕèÊu e·�Ò·ÕèÁÕ¡ÒÃÂoÁÃaº »�¨¨ uºa¹ÁÕ ¡Òä �¹¾º ¤ÇÒà �¡ 6 µaÇ ¤ o up quark, down quark, strange quark, charmed quark, bottom quark æÅa top quark
- ¹ iǵÃo¹ »Ãa¡oº �Ç up quark 1 µ aÇ æÅa down quark 2 µ aÇ - o»Ãµo¹ »Ãa¡oº �Ç up quark 2 µ aÇ æÅa down quark 1 µaÇ
21angka teprattananan
Atomic Symbol (Nuclear Symbol)• Contain the symbol of the element, the mass number
and the atomic number.
A
ZXMassnumber
Atomicnumber
Element Symbol
• Atomic number = number of protons– Same as the number of electrons in a neutral atom
• Mass number = the number of protons + neutrons
22angka teprattananan
Fill in the blanks for the following nuclear symbols:
Element94Be 14
6C 3517Cl- 74
33As3- 4420Ca2+ 67
31Ga3+
Atomic Number
Mass Number
# of Protons
# of Neutrons
# of Electrons
23angka teprattananan
Isotope , Isotone , Isobar and Isoelectronic
• Isotope are atoms of the same element having different masses, due to varying numbers of neutrons.11H Subatomic particles p = 1 , e = 1 , n = 021H Subatomic particles p = 1 , e = 1 , n = 1
• Isotone are atoms of the different element having equal neutrons.115B Subatomic particles p = 5 , e = 5 , n = 6
126C Subatomic particles p = 6 , e = 6 , n = 6
24angka teprattananan
• Isobar are atoms of the different element having equal mass number.
3616S mass no. of 3616S is 36
3618Ar mass no. of 3618Ar is 36
• Isoelectronic are atoms of the different element having equal electron.20
10Ne Subatomic particles p = 10 , e = 10 , n = 10 24
12Mg2+ Subatomic particles p = 12 , e = 10 , n = 12
25angka teprattananan
Neclear symbols isotope isotone isobar isoelectronic14
6C & 147N
3919K & 40
20Ca35
17Cl & 3717Cl
3818Ar & 32
16S2-
168O & 18
8O40
18Ar & 4020Ca
3517Cl- & 39
19K+
3115P & 32
16S
For each of the following ,check the blank for isotope , isotone , isobar or isoelectronic
26angka teprattananan
27
spectrum excited State
electromagnetic wave
describe
relationship energy levels
wavelength quantize
frequency less-stable
energy absorbing
ground State releasing
Vocabulary
angka teprattananan
Max Plank
studied a spectrum of Electromagnetic Wave. The relationship among the wavelength (λ), the frequency (ν), and the energy (E) are:
or
where c is Speed of light = 3 x 108 m/sh is Planck's Constant = 6.626 x 10-34 J.s
is Frequency (Hz) λ is wavelength (m)
Max Plank
28angka teprattananan
Energy and frequency of Electromagnetic Wave
Êe»¡µÃ aÁ ¤ o 涺ÊÕ·Õèe¡ i ¨Ò¡¡ÒÃe»ÅÕè¹æ»Å§¾Å a§§Ò¹¢o§¤Å è¹æÁ �eËÅç¡ä¿¿ �Ò
Color of spectrum Wavelength (nm) Energy (kJ) frequency(Hz)
Violet Blue Green Yellow Orange
Red
400 - 420420 - 490490 - 580580 - 590590 - 650650 - 700
4.96x10-22 - 4.73x10-22
4.73x10-22 - 4.05x10-22
4.05x10-22 - 3.42x10-22
3.42x10-22 - 3.36x10-22
3.36x10-22 - 3.05x10-22
3.05x10-22 - 2.83x10-22
7.49x1014 - 7.14x1014
7.14x1014 - 6.12x1014
6.12x1014 - 5.17x1014
5.17x1014 - 5.08x1014
5.05x1014 - 4.16x1014
4.61x1014 - 4.28x1014
29angka teprattananan
Calculate about Electromagnetic WaveEx1 Êe»¡µÃ aÁÊÕÁ�ǧ¤ÇÒÁÂÒÇ¤Å è¹ 500 nm ¨aÁÕ¤ÇÒÁ¶Õèe·�Òã´
Ex2 Êe»¡µÃ aÁÊÕæ´§ÁÕ¤ÇÒÁÂÒÇ¤Å è¹ 500 nm ¨aÁÕ¤ÇÒÁ¶ÕèæÅa¾Åa§§Ò¹e·�Òã´
30angka teprattananan
Ex3 The energy of electromagnetic wave is 3x10-22 KJ , Find the color
Ex4 The frequency is 5x1014 Hz , calculate the wavelength , energy and find the color of this spectrum.
31angka teprattananan
Niels Bohr studied a spectrum of Hydrogen atom. discovered the four lines of Hydrogen
spectrums Violet , Blue , Blue-green ,and Red.
How did the spectrum appear ?
Niels Bohr
32angka teprattananan
Bohr used the term energy levels (or shells) to describe. He said that the energy of an electron is quantized, meaning electrons can have one energy level or another but nothing in between.
The energy level an electron normally occupies is called �ground state�. But it can move to a higher-energy (less-stable) by absorbing energy. This higher-energy is called �excited state�.
33angka teprattananan
After it�s done being excited, the electron can return to its original ground state by releasing the energy it has absorbed, as shown in the diagram below.
34angka teprattananan
• Table show the energy of Hydrogen spectrum
Color of Spectrum
Wavelength (nm)
Energy (kJ)
ΔE
Red
Bluegreen
Blue
Violet
656
486
434
410
3.02 x 10-22
4.08 x 10-22
4.57 x 10-22
4.84 x 10-22
10.6 x 10-23
4.9 x 10-23
2.7 x 10-23
35angka teprattananan 36angka teprattananan
Bohr�s Atomic Model
oaµoÁ»Ãa¡oº´ �ÇÂo»Ãµo¹æÅa¹ iǵÃo¹ oÂÙ�ÀÒÂã¹¹ iÇe¤ÅÕÂÊ Ê �ǹoieÅ硵Ão¹Ç iè§oÂÙ�Ãoº æ ¹ iÇe¤ÅÕÂÊe» �¹ª aé¹æ Ëà oe» �¹Ãa´ aº¾Å a§§Ò¹« è§ÁÕ¤ �ÒäÁ �µ �oe¹ èo§¡ a¹
37angka teprattananan
Electron Configuration (o¤Ã§æººoieÅ硵Ão¹)Electrons orbit the nucleus in definite principle
energy levels (7 principle energy levels).The principle energy level can hold only a specific
number of electrons.
Rule ; 2n2
n = principle energy levels
38angka teprattananan
Principle energy levels Maximum Electrons
n = 1 2 en = 2 8 en = 3 18 en = 4 32 en = 5 50 en = 6 72 en = 7 98 e
39angka teprattananan
Rule; Arrangements of electrons in an atom.1. Lowest levels are filled first.
2. Once a level is full, the electrons start filling the next level.
3. Outer level (valence electrons) has maximum electrons equal 8 and next outer level has maximum 8 or 18 electrons.
e.g. 11Na: has 11 electrons First energy level 1 (n =1) can fill 2 electrons
Second energy level 2 (n =2) can fill 8 electrons
Third energy level 3 (n =3) can fill 1 electronOr shot hand 11Na : 2 , 8 , 1
40angka teprattananan
Arrangements of electrons in an atom.1. 3Li : ��������������� 2. 12Mg : ���������������3. 19K : ���������������4. 33As : ���������������5. 53I : ���������������6. 55Cs : ���������������7. 82Pb : ��������������� 8. 88Ra : ��������������� 9. 22Ti : ��������������� 10. 28Ni : ���������������
41angka teprattananan 42
explain sub-energy levels
surround exclusion
electron cloud principle
closest spin
outermost unpair
impossible configuration
exact location notation
predict indicate
Vocabulary
angka teprattananan
Modern Atomic model
Atom has a small positively charged nucleus surrounded by a region of negatively charged electrons to make the entire atom neutral.
called the �electron cloud�.
43
Bohr�s model could not explain complex atoms(can explain Hydrogen atom only).
angka teprattananan
Electron Cloud Model Electrons with the lowest
energy are found in the energy level closest to the nucleus.
Electrons with the highestenergy are found in the outermost energy levels, farther from the nucleus.
It is impossible to determine the exact location of an electron only predict where is could be based on how much energy it has.
44Erwin Schrodinger angka teprattananan
The region of electrons move around the nucleus in other shapes, called �Orbital�
There are 4 kind of orbitals (sub-energy levels) e.g. s , p , d and f
s
p
d
f45angka teprattananan
Electron configurationsBy using ,1. Pauli exclusion principle;
Each orbital can have only 2 electrons and have not the same spin. 2. Aufbau principle;
Electron fill lowest energy levels first.3. Hund�s Rule;
For atoms in ground state, the number of unpaired electrons is the maximum possible and have the same spin.
46angka teprattananan
Arrangements of electrons in Orbital
principle energy levels
(shell)sub-energy levels
(subshell)maximum electron
n = 1 s 2
n = 2 s , p 8
n = 3 s , p , d 18
n = 4 s , p , d , f 32
n = 5 s , p , d , f 32
n = 6 s , p , d 18
n = 7 s , p 8
n = 8 s 247angka teprattananan
Lower energy Higher energy1s 2s 2p 3s 3p 4s 3d 4p �.
48angka teprattananan
1S
2S
3S2P
3P
4S
3d
4P5S
4d
Ex. Give the full electron configuration of 27Co
NOTE. principle energy levelsOr 27Co;
49angka teprattananan
Chemists use a standard notation to indicate the
electron configurations of atoms and molecules.1) Orbital Diagram.
2) Long notation or spdf configuration.1s22s22p63s2....
3) Shorthand Notation or noble gas core.[Ne]3s23p4
s1
s2
50angka teprattananan
Using Orbital Diagram1. 3Li : �� ����.�
2. 12Mg : ��������������������
3. 18Ar : ��������������������
4. 19K : ��������������������
5. 25Mn : ��������������������
6. 26Fe : ��������������������
7. 24Cr : ��������������������
51
1S 2S
angka teprattananan
Using Long Notation or spdf configuration 1. 12Mg : ��1s2 2s2 2p6 3s2���2. 18Ar : �����������������3. 19K : �����������������4. 33As : �����������������5. 38Sr : �����������������6. 55Cs : �����������������7. 28Ni : �����������������8. 24Cr : �����������������9. 29Cu : �����������������
52angka teprattananan
Using Short hand Notation or Noble Gas core.1. 3Li : ���� [He]2s1 ����2. 12Mg : ������������������ 3. 18Ar : ������������������4. 19K : ������������������ 5. 33As : ������������������ 6. 28Ni : ������������������ 7. 37Rb : ������������������8. 53I : ������������������
53angka teprattananan
(Ç iÇ a²¹Ò¡Òâo§µÒÃÒ§¸Òµ u)
The History of the Periodic Table
54angka teprattananan
55
similar property conductor
middle element electricity
roughly luster
publish ductile
organize malleable
increasing reflect
regular except
interval semiconductor
according to stair step
clear up
Vocabulary
angka teprattananan
He noticed that chlorine, bromine and iodine had similar properties. And the atomic mass of the middle element was roughly the average of the masses of the others .
He called �Law of Triads�
Cl Chlorine mass = 35.5Br Bromine mass = 79.9I Iodine mass = 126.9
Average mass of chlorine and iodine= (35.5 + 126.9) / 2= 81.9 (close to Br!)
Dobereiner�s other triads included lithium (Li), sodium (Na) and potassium (K), along with calcium (Ca), strontium (Sr) and barium (Ba).
Johaun Dobereiner
56angka teprattananan
He noticed that every 8th element had similar properties, a bit like a musical scale. He listed some of the known elements in rows of 7 as shown below.He called �Law of Octaves� .
His law of octaves work today with the first 20 elements.57
John Newlands
angka teprattananan
Dmitri Mendeleev In 1869 he published a table of the elements
organized by increasing atomic mass. Noticed similar properties appeared at regular
intervals --> �periodic�
Lothar Meyer At the same time, he published his
own table of the elements organized by increasing atomic mass.
58
Mendeleev
Lothar Meyer
angka teprattananan
Mendeleev’s discovery
59angka teprattananan
The table below compares Mendeleev�s prediction with the actual data.
60angka teprattananan
Henry mosely
The Periodic Table was then arranged according to increasing atomic number. The table was as it is now and cleared up the
Tellurium and Iodine problem.Periodic Law : the physical and chemical
properties of elements are periodic functions of their atomic number and electrons arrangement.
61
Henry mosely
angka teprattananan
Three classes of elements are Metals, Nonmetals and Metalloids
Modern Periodic Table
62angka teprattananan
Metal Elements Good conductors of heat and electricity Have luster, are ductile , malleable , good reflect light All metals are solids at room temperature ,except for
mercury(Hg) Found on left side of periodic table and some on right
side of table
Gold
63angka teprattananan
Nonmetal Elements Have properties that are opposite to those of metals Not good conductors of heat and electricity, poor
reflect light Usually brittle solids or gases ,except for bromine(Br) Found on right side of periodic table � AND hydrogen
SulphurBromine 64angka teprattananan
Metalloids Sometimes called semiconductors Form the �stairstep� between metals and nonmetals Have properties of both metals and nonmetals Examples: B, Si , Ge , As , Sb, Te and, At
65angka teprattananan
Some properties of Metalloids , Al(metal) and I(nonmetal)
IE1(kJ/mol)
EN Density(g/cm3)
melting�boiling point(oC)
ElecticalConductivity
Type of Compound
Al 584 1.61 2.70 660-2519 √ ionic
B 807 2.04 2.34 2075-4000 √ ionic and covalent
Si 793 1.90 2.33 1414-3265 √ ionic and network covalent
Ge 768 2.01 5.32 938-2833 √ ionic and covalent
As 951 2.18 5.75 358-603 √ ionic and covalent
Sb 840 2.05 6.68 631-1587 √ ionic and covalent
I 1015 2.66 4.93 114-184 X ionic and covalent
66angka teprattananan
- B Si Ge As Sb Te Po At have high first ionization energy(IE1) , electronegativity (EN) and can form Ionic and Covalent compounds same nonmetals.
- High melting point and boiling point , high density and can electrical conductivity same metals.
- So this elements will called �Metalloids�(Po and At is radioactive element)
67angka teprattananan
Location of Hydrogen in the periodic table
Some properties of Hydrogen , group IA and VIIA
chemist will arrange Hydrogen in group IA and VIIA in the periodic table.
properties Group IA H group VIIA1. # valence electron 1 1 72. Oxidation number in compounds
+1 +1 , -1 +1 , +3 , +5+7 , -1
3. IE1 (kJ/mol) 382-526 1318 1015-16874. EN 0.7-1.0 2.1 2.2 -4.05. phase solid gas 3 phase6. Electric conductivity can cannot cannot
68angka teprattananan
69
vertical gain
horizontal consist
shiny pale
silvery diatom
react monoatom
characteristic inert gases
flame incapable
soluble synthesis
encounter order
discharge digit
Vocabulary
angka teprattananan
The vertical columns of the periodic table are called GROUP, or FAMILY. (18 groups)
The elements in same group of the periodic table have similar physical and chemical properties!
Periodic Table
70angka teprattananan
The horizontal rows of the periodic table are called PERIOD.(7 periods)
Periodic Table
71angka teprattananan
The s and p block elements are called �REPRESENTATIVE ELEMENTS (Group A)�
The d and f block elements are called �TRANSITION ELEMENTS (Group B)�
s pd
f
72
Periodic Table
angka teprattananan
REPRESENTATIVE ELEMENTS (Group A ; 8 groups)
73
Alkali MetalsAlkali Earth Metals Halogens
Noble GasesInert Gases
angka teprattananan
Group IA (Alkali Metals)
� Group I metals are shiny , silvery solids.� All are soft and can easily cut with a knife.� Have low density.� react easily in air. They are kept under oil. � Group I elements are called �alkali metals� because
they react with water to give alkaline solution.e.g.
2Na(s) + 2H2O(l) 2NaOH(aq) + H2(g)
74angka teprattananan
� Alkali Metals can react with oxygen to give different oxide compounds :
4Li(s) + O2(g) 2Li2O(s) (oxide)
2Na(s) + O2(g) Na2O2(s) (peroxide)K(s) + O2(g) KO2(s) (superoxide)
� Alkali Metals emit a characteristic color when placed in a flame.
� All alkali compounds can soluble in water.� Group I elements become more reactive down the
group.
75angka teprattananan
Group IIA (Alkali Earth Metals)
� Alkali Earth Metals have higher density than Alkali Metals
� carbonate , phosphate , sulphid , sulphite compounds of Alkali Earth Metal cannot soluble in water.
� Be does not react with water , Mg react slowly with water and Ca and the elements below it react readily with water:
Mg(s) + 2H2O(l) Mg(OH)2(aq) + H2(g)Ca(s) + 2H2O(l) Ca(OH)2(aq) + H2(g)
76angka teprattananan
Group VIA (Chalcogen)
� Oxygen , Sulphur and Selenium are nonmetals , Tellurium is Metalloid and Polonium is radioactive element.
� Oxygen is encountered in two molecular forms , O2 and O3.
� O3 is also formed from O2 in electrical discharges, such as in lightning storms:
3O2(g) 2O3(g) H = +284.6 kJ� Ozone is toxic. 77angka teprattananan
Group VIIA (Halogens)� Halogen always gain one electron to form anion:
X2 + 2e- 2X-
� Fluorine is most reactive in the group:
2F2(g) + 2H2O(l) 4HF(aq) + O2(g) • Each element consists of diatom molecules ; F2 , Cl2
, Br2 and I2� Fluorine gas is pale yellow , Chlorine gas is yellow-
green , Bromine liquid is red-brown and solid iodine is black (violet vapor)
78angka teprattananan
• Fluorine and Chlorine are more reactive than Bromine and Iodide
2Cl-(aq) + F2(g) 2F-(aq) + Cl2(g)2Br-(aq) + Cl2(g) 2Cl-(aq) + Br2(g)
2I-(aq) + Br2(g) 2Br-(aq) + I2(g)2F-(aq) + Cl2(g) X2Cl-(aq) + Br2(g) X2Br-(aq) + I2(g) X
In fact, fluorine removes electrons from almost any substance with which it come into contact.
79angka teprattananan
Group VIIIA(Noble gases)• Noble gases are monoatom (He Ne Ar Kr Xe Rn)• Noble gases have completely filled s and p
subshell.• 1960s the elements were called the �inert gases�
because they were thought to be incapable of forming chemical compounds.
• Today we can synthesis some of noble gas compounds ; XeF2 XeF4 XeF6 KrF2 and HArF
80angka teprattananan
TRANSITION ELEMENTS (Group B ; 8 groups)
81
Transition Metals
InnerTransition MetalsRare-earth elements
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Electron Configuration and Properties
82angka teprattananan
Phisical Properties of Potassium - Zinc
83angka teprattananan
Oxidation Number of Transition Metals(Stable Oxidation Number in red)
84angka teprattananan
Nomenclature of Elements with Atomic Numbers Greaterer than 100
The Rules for Naming Elements 1. Name directly from the atomic number of the element using the following numerical roots
0 = nil , 1 = un , 2 = bi , 3 = tri , 4 = quad , 5 = pent , 6 = hex , 7 = hept , 8 = oct , 9 = enn
2. The roots are put together in the order of the digits and terminated by �ium� to spell out the name.
Example Atomic Number : 112 Element Name: Ununbium
Element Symbol: Uub 85angka teprattananan
Write the element symbol and name :1. Atomic Number : 102 Element Name : ___________
Element Symbol : ___________2. Atomic Number : 110 Element Name : ___________
Element Symbol : ___________3. Atomic Number : 115 Element Name : ___________
Element Symbol : ___________4. Atomic Number : 118 Element Name : ___________
Element Symbol : ___________5. Atomic Number : 120 Element Name : ___________
Element Symbol : ___________86angka teprattananan
Location of atoms in the periodic table
87
For representative elements (group A)group no. = no. of valence electron
= sum of electron outer levelperiod no. = no. of principle energy levels
Ex. 17Cl : 1s2 2s2 2p6 3s2 3p5
: 2 , 8 , 7
So, 17Cl is in group 7A and period 3
valence electron
Outer level
Three shells
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For Transiton metals (group B)group no. = sum of two last sub-energy levels
(subshell)period no. = no. of principle energy levels
e.g. 21Sc : 1s2 2s2 2p6 3s2 3p6 4s2 3d1
So, Sc is in group 3B and period 4.
88
/2+1 = 3
4 principle energy levels
angka teprattananan
Fill in the blank , Determine Group No. and Period No.
1. 7N : �������������� 6. 25Mn : ��������������group ���� period ���� group ���� period ����
2. 11Na : ������������� 7. 26Fe : ��������������group ���� period ���� group ���� period ����
3. 18Ar : ������������� 8. 22Ti : ��������������group ���� period ���� group ���� period ����
4. 20Ca : ������������� 9. 53I : ��������������group ���� period ���� group ���� period ����
5. 35Br : ������������� 10. 29Cu : �������������group ���� period ���� group ���� period ����
89angka teprattananan 90
Radioactive turned into
unstable falls down
radiation equation
Ionising ability Balancing
Penetrating half life
behavior undergo
electric field decrease
excessive collide
repulsion Fission
Decay Fussion
Vocabulary
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A radioactive elements are an elements with an unstable nucleus, which radiates alpha, beta or gamma radiation and gets converted to a stable element.
3 Types of Radiation
Radioactive Elements
91angka teprattananan
Properties of radiation
Type of Radiation Alpha particle Beta particle Gamma ray
Symbol
(can look different,depends on the font)
Mass (atomic mass units) 4 1/2000 0
Charge +2 -1 0
Speed slow fast very fast (speed of light)
Ionising ability high medium 0
Penetrating power low medium high
Stopped by: paper aluminium lead
Penetrating power
92angka teprattananan
The behavior of three types of radioactive emissions in an electric field.
93angka teprattananan
Alpha DecayThe reason alpha decay occurs is because the
nucleus has too many protons which cause excessive repulsion.
94angka teprattananan
Beta DecayBeta decay occurs when the neutron to proton ratio
is too great in the nucleus and causes instability. In basic beta decay, a neutron is turned into a proton and an electron. The electron is then emitted.
95angka teprattananan
Gamma Decay
Gamma decay occurs because the nucleus is at too high an energy. The nucleus falls down to a lower energy state and, in the process, emits a high energy photon known as a gamma particle.
32He* 32He + γ
96angka teprattananan
Partical Symbol Charge mass(amu)*
Alpha α , 42He + 2 4.00276
Beta β , 0-1e - 1 0.000540
Gamma γ 0 0
Positron β+ , 0+1e + 1 0.000540
Neutron n , 10n 0 1.0087
Proton P , 11H + 1 1.0073
Deuteron D , 21H + 1 2.0136
Tritron T , 31H + 1 3.0219
Symbol charge and mass
97angka teprattananan
Nuclear equationA nuclear equation shows how a nucleus gains
or loses subatomic particles.Balancing Nuclear Equations
Ex. 1:1
1H + 94Be ---> 63Li + 42He
Rule: The sum of the mass numbers of the reactants equals the sum of the mass numbers of the products.
98angka teprattananan
Balancing Nuclear Equations
A. 2714Si _______ + 0-1e
B. 6629Cu _______ + 0-1e
C. 2713Al + 42He 30
14Si + _______D. 14
6C 136C + ________
E. 22689Ac 226
88Ra + ________
F. 22689Ac 222
87Fr + __________
99angka teprattananan
G. 21383Bi _______ + 42He
H. 20981Tl 209
82Pb + _______I. 23
11Na + 42He 2612Mg + _______
J. 23892U + 16
8O ________ +510n
K. 23892U + 16
8O 23994Pu + ________
L. 23592U + 10n 90
38Sr + 14354Xe + ________
100angka teprattananan
100 g 50 g 25 g14 วน 14 วน
Half life ; t½is the period of time it takes for the amount of
a substance undergoing decay to decrease by half.
Ex. P-32 has a half life 14 days
101angka teprattananan
Radioactive ElementsElements Half life Radiation Benefit
U-235 7.1x109 years Alpha Gamma Treatment of Cancers
C-14 5,760 years Beta Archeology
Co-60 5.26 years Gamma Treatment of Cancers
Au-198 2.7 days Beta Gamma Medical Diagnostics
I-125 60 days Gamma Medical Diagnostics
I-131 8.07 days Beta Gamma Medical Diagnostics
P-32 14.3 days Beta Treatment of Cancers
Pu-239 24,000 years Alpha Gamma Generation of Electricity
K-40 1x109 years Beta ArcheologyRa-226 1,600 years Alpha Gamma Treatment of Cancers
102angka teprattananan
µaÇo �Ò§ ¶ �Ò· ié§äoo«o·»¡ aÁÁa¹µÃ a§ÊÕª¹ i´Ë¹ è§ 20 ¡Ã aÁ äÇ �¹Ò¹ 28 Ç a¹ »ÃÒ¡¯Ç �ÒÁÕäoo«o·»¹ aé¹eËÅooÂÙ� 1.25 ¡Ã aÁ ¤Ã 觪ÕÇ iµ¢o§äoo«o·»¹ÕéÁÕ¤ �Òe·�Òã´
µaÇo �Ò§ ¨§Ëһà iÁÒ³ I-131 eà ièÁµ�¹ eÁèo¹íÒ I-131 ¨íҹǹ˹ è§ÁÒÇÒ§äÇ �e»�¹eÇÅÒ 40.5 Ç a¹ »ÃÒ¡¯Ç �Ò ÁÕÁÇÅeËÅo 0.125 ¡ÃaÁ ¤Ã 觪ÕÇ iµ¢o§ I-131 e·�Ò¡ aº 8.1 Ç a¹
103angka teprattananan
1. After 42 days a 2.0 g sample of phosphorus-32 contains only 0.25 g of the isotope. What is the half-life of phosphorus-32?
2. In 5.49 seconds, 1.20 g of argon-35 decay to leave only 0.15 g. What is the half-life of argon-35?
104angka teprattananan
5. Polonium-214 has a half-life of 164 seconds. How many seconds would it take for 8.0 g of this isotope to decay to 0.25 g?
6. How many days does it take for 16 g of palladium-103 to decay to 1.0 g? The half-life of palladium-103 is 17 days.
105angka teprattananan
Calculations base on half life
Nt = N0 2n
n = T / t1/2
Nt = number remainingN0 = initial numberT = timen = no. time of decayt1/2 = half life
µaÇo �Ò§ ¨§Ëһà iÁÒ³¢o§ Tc-99 ·ÕèeËÅoeÁèoÇÒ§ Tc-99 ¨íҹǹ 18 ¡Ã aÁäÇ �¹Ò¹ 24 ª aèÇoÁ§ æÅa Tc-99 Áդà 觪ÕÇ iµ 6 ªaèÇoÁ§
106angka teprattananan
1. After 42 days a 2.0 g sample of phosphorus-32 contains only 0.25 g of the isotope. What is the half-life of phosphorus-32?
2. Polonium-214 has a half-life of 164 seconds. How many seconds would it take for 8.0 g of this isotope to decay to 0.25 g?
107angka teprattananan
Nuclear ReactionNuclear Reaction is process in which two nuclei,
or else a nucleus of an atom and a subatomic particle (such as a proton, or high energy electron) from outside the atom, collide to produce products different from the initial particles.
1. Nuclear Fission
2. Nuclear Fussion
2 Types of nuclear reaction
108angka teprattananan
Nuclear FissionA heavy nucleus such as Uranium-235 absorbs an extra
neutron, it becomes unstable and splits into two lighternuclei. The energy is released as kinetic energy of thefission products.
109angka teprattananan
Nuclear Fussion
When two light nuclei such as Hydrogen or Deuterium are forced to combine forming a new, heavier nucleus. The energy is released as kinetic energy of the fusion products.
110angka teprattananan
Atomic Properties and
Periodic Trends
111
(ÊÁº aµ i¢o§¸Òµ uæÅaæ¹Ço¹ �Á¢o§¸Òµ uµÒÁµÒÃÒ§¸Òµ u)
angka teprattananan
Atomic radius (¢¹Ò´oaµoÁ) Ion size (à aÈÁÕäooo¹) Ionization energy (IE) (¾Å a§§Ò¹äoooä¹e«ª a¹) Electron affinity (EA) (Ê aÁ¾ÃäÀÒ¾oieÅ硵Ão¹) Electronegativity (EN) (oieÅç¡o·Ãe¹¡Òµ iÇ iµÕ) Melting point(m.p.) (¨ u´ËÅoÁeËÅÇ)
and Boiling point(b.p.) (¨ u´e´ o´) Oxidation Number(O.N.) (eÅ¢oo¡« ie´ª a¹)
112
Atomic Properties and Periodic Trends
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113
distance discontinuity
repulsion endothermic
attraction exothermic
trend tendency
Cation combine
anion Network structure
require indicate
inversely giant molecules
proportional
Vocabulary
angka teprattananan 114
The atomic radius is one half of the distance between the nuclei of two atoms of the same element when the atoms are joined.
Atomic Radius (Atomic Size)
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115
A Kind of Radius1. Covalent Radius(à aÈÁÕo¤eÇeŹµ �) used for Covalent
compounds. e.g. H2 , F2 , Cl2 , O2
2. Van der Waals Radius(à aÈÁÕæǹe´oà �ÇÒÅÊ �) used for Noble gases. e.g. He , Ne , Ar
3. Metallic Radius(Ã aÈÁÕoÅËa) used for Metal atoms. e.g. Li , Mg , Cu
Cl - Cl
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Atomic Radius
Group trends :The atoms get bigger as we go down a group.
Because the increase in the principal energy levels.
Period Trends :The atoms get bigger as we go from right to left
in a period at same energy level. Because the decrease of nucleus attraction.
116angka teprattananan
Atomic Radius
117angka teprattananan
1. Which element in each pair has the larger atoms? 1.1 12Mg or 20Ca 1.2 3Li or 8O
1.3 17Cl or 35Br 1.4 11Na or 16S
2. Arrange these atoms in order of increasing size?
11Na , 13Al , 6C , 20Ca
3. Arrange these atoms in order of increasing size?
33As , 37Rb , 18Ar , 15P
118angka teprattananan
The Octet RuleThe �goal� of most atoms is to have an
octet or group of 8 electrons in their valence energy level.
Metals generally give(lose) electrons, Nonmetals take(gain) electrons from other atoms.
Atoms that have gained or lose electrons are called �ion�.
119angka teprattananan
Ions size Metals elements lose valence electrons to form cation.
Cation radius are always smaller than atomic radius.
Non-metal elements gain valence electrons to form anion. Anion radius are always larger than atomic radius.
6.3
120angka teprattananan
Group trends The ions get bigger as we go down a group.
Because the increase in the principal energy levels.Period Trends
The ions get bigger as we go from right to left in a period at same energy level. Because the decrease of nucleus attraction.
Li+
Be2+
B3+
C4+N3- O2- F-
121angka teprattananan
Atoms and Ions size
122angka teprattananan
1. Which atoms or ions in each pair are larger? 1. 12Mg or 12Mg2+ 2. 8O or 8O2-
3. 7N3- or 9F- 4. 11Na+ or 12Mg2+
2. Arrange these atoms and ions in order of increasing size?
12Mg2+ , 13Al3+ , 15P3- , 17Cl-
3. Arrange these atoms and ions in order of increasing size?
3Li+ , 11Na+ , 12Mg , 16S2-
123angka teprattananan
Ionization Energy(IE) The energy required to remove an electron from
an atom in gas phase. Ionization energy and atomic radius are inversely
proportional. e.g.
First Ionization Energy(IE1)
Na(g) --> Na+(g) + eSecond Ionization Energy(IE2)
Na+(g) --> Na2+(g) + e
124angka teprattananan
Write IE1 � IE5 of Boron______ __________________ : IE1 = 807 KJ/mol______ __________________ : IE2 = 2,433 KJ/mol______ __________________ : IE3 = 3,666 KJ/mol______ __________________ : IE4 = 25,033 KJ/mol______ __________________ : IE5 = 32,834 KJ/mol
125
IE3 and IE4 is more different , why ?
angka teprattananan
Find the group number from ionization of following element ?
IE1(MJ/mol)
IE2(MJ/mol)
IE3(MJ/mol)
IE4(MJ/mol)
IE5(MJ/mol)
IE6(MJ/mol)
IE7(MJ/mol)
IE8(MJ/mol)
group
0.744 1.457 7.739 10.547 13.636 18.001 21.710 25.663
1.687 3.381 6.057 8.414 11.029 15.171 17.874 92.047
1.093 2.359 4.627 6.229 37.838 47.285
0.906 1.763 14.855 21.013
126angka teprattananan
Trends in First Ionization Energies of First 20 Elements
First ionization energy tends to increase from bottom to top within a group. And increase from
left to right across a period.
However, there are two apparent discontinuities in this trend.
127angka teprattananan
Trends in First Ionization Energies of Elements
128angka teprattananan
1. Which element in each pair has the greater ionization energy?
1. 12Mg or 13Al 2. 4Be or 5B
3. 6C or 14Si 4. 2He or 53I
2. Arrange these atoms in order of increasing IE1 ?
33As , 37Rb , 18Ar , 15P , 16S 3. Arrange these atoms in order of increasing IE1 ?
19K , 13Al , 11Na , 12Mg , 20Ca
129angka teprattananan
Electron Affinity(EA) Electron affinity is the energy change when an
atom gains one electron. Where ionization energy is always endothermic,
electron affinity is usually exothermic, but not always.
Example ;O(g) + e O- (g) : EA = -142 KJ/mol
O-(g) + e O2- (g) : EA = 780 KJ/mol
130angka teprattananan
in Electron affinity of Elements If the atom has more tendency to accept an
electron then the energy released will be large and electron affinity will be high. Atoms with large ionization energy have negative
electron affinity. If there are no empty spaces, a new orbital, making
the process endothermic (Group IIA and VIIIA).e.g.
12Mg : 1s22s22p63s2 Group IIA
18Ar : 1s22s22p63s23p6 Group VIIIA
131angka teprattananan
Trends in Electron Affinity
132angka teprattananan
1. Which element in each pair has the greater electron affinity? 1. 12Mg or 13Al 2. 3Li or 8O
3. 6C or 32Ge 4. 18Ar or 53I
5. 11Na or 19K 6. 9F or 53I
2. Arrange these atoms in order of increasing EA ?
19K , 20Ca , 11Na , 15P , 9F
133angka teprattananan
Electronegativity (EN) Electronegativity is the tendency for an atom to
attract electrons to itself when it is chemically combined with another element. High electronegativity means it pulls the
electron toward it.
134angka teprattananan
Trends in Electronegativity of Elements
Electronegativity tends to increase from bottom to top within a group. And increase from left to right across a period.
Because the increase of nucleus attraction. Note; Noble gases are NOT assigned
electronegativities
135angka teprattananan
Trends in ElectronegativityRepresentative Elements in Groups 1A through 7A
6.3
136angka teprattananan
1. Which element in each pair has the greater electronegativity?
1. 11Na or 15P 2. 3Li or 8O 3. 6C or 32Ge 4. 9F or 53I
2. Draw arrow to show the bond polarity in each pair elements N---F C---Br O----Cl
Br---Br C---S C----I
3. Arrange these atoms in order of increasing EN ?
12Mg , 20Ca , 17Cl , 9F
137angka teprattananan
Melting Point and Boiling Point
The melting point is the temperature at which thetransition from the solid phase to the liquid phase.
- Helium has the lowest melting point (-272.2oC).- Carbon has the highest melting point (3550oC).
The boiling point is the temperature at which the transition from the liquid to the gas phase.
- Helium has the lowest boiling point (-268.9oC). - Tungsten has the highest boiling point (5927oC).
138angka teprattananan
For metals ;The melting point and boiling point tends to
increase from bottom to top within a group (the increase metallic bond).
And increase from left to right across a period(the metallic bond increase when increase of outerelectrons or valence electron).
139angka teprattananan
For nonmetals ;The melting point and boiling point tends to
increase from top to bottom within a group. And increase from right to left across a period.
(the increase van der waals' forces)
But, the group IVA ; high melting point and boiling point because they have giant molecules(Network structure).
140angka teprattananan
Arrange these atoms in order of increasing melting � boiling point ?
1. 19K , 15P , 17Cl
2. 3Be , 10Ne , 13Al
3. 6C , 11Na , 3Li
4. 9F , 53I , 11Na , 13Al
5. 7N , 14Si , 9F , 10Ne
141angka teprattananan
Periodic trendssummary
Ioni
zatio
n en
ergy
Elec
tron
affi
nity
Elec
tron
egat
ivity
m.p
. and
b.p
. of m
etal
Electron affinity
Ionization energy
Electronegativity
m.p. and b.p. of metal
Atom
ic radius
metallic character
m.p. and b.p. of nonm
etal
Atomic radius
metallic character
m.p. and b.p. of nonmetal142angka teprattananan
143
Oxidation numberThe oxidation number of an element indicates the number of electrons lost, gained, or shared as a result of chemical bonding.
Rules of Oxidation Number1. Elements have an oxidation number of zero.
E.g. Na , K , Pb , H2 , O2 , P42. The oxidation number of simple ion is the charge on the ion.
E.g. Li+ = +1 , Fe3+ = +3 , O2- = -2 , Cl- = -1
angka teprattananan
3. The oxidation number of some elements in their compounds is fixed
E.g. Hydrogen in most of its compound = +1Oxygen in most of its compound = -2all group I elements = +1all group II elements = +2
4. The sum of the oxidation numbers of the elements in a molecule or ion is equal to the charge on the molecule or ion.
E.g. OH- (-2) + (+1) = -1
144angka teprattananan
HCO3-
O = H =
Oxidation numbers of C in HCO3
- ?
145
Find the Oxidation Number of S in SOCl4 ?O.N. of Oxygen = O.N. of Chlorine =
angka teprattananan
Determine the oxidation number of underline element :
1. SO2
2. CaSO4
3. PO43-
4. NH4+
5. Pb(OH)4
6. KMnO4
7. Cu(NO3)
8. K2[Fe(CN)3H2O]
146angka teprattananan
Determine the oxidation number of underline element : 1. CO 2. CH4 3. SO34. Al2O3 5. S2Cl2 6. BaSO47. MgCrO4 8. Sr(NO3)2 9. IF310. K2MnO4 11. [Fe(CN)6]3- 12. Cr(OH)313. NiCl2.6H2O 14. K3[Fe(CN)6]15. [Cu(NH3)4]SO4 16. [Mn(H2O)6]3+
17. (NH4)2[NiCl4]
147angka teprattananan