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ANSWERS
1)antimony tribromide _______SbBr3___
2)hexaboron silicide ____________B6S____________
3)chlorine dioxide ____________ClO2__________
4) iodic acid ________________HIO3______________
5) iodine pentafluoride ________IF5_______________
6)dinitrogen trioxide ____________N2O3______________
7)ammonia ________________NH3_________
8)hypophosphorous acid ______________H3PO2_____________
ANSWERS
9)P4S5 ___tertaphosphorous pentasilicide____ 10) O2 ___oxygen__________ 11) HNO4 _____pernitric acid______ 12) Si2Br6 _____disilicon hexabromide____________ 13) SCl4 _____silicon tertachloride__________ 14) CH4 _____carbon tetrahydride___(methane)______ 15) H2SO3 ______sulfurous acid__________ 16) NF3 ________nitrogen trifluoride_____________
General Lewis Structure Rules
1) Predict Atom locationsa) H is always terminalb) Lowest Electronegativity
is central atom
H C2.55
O3.44
C4H8O2
General Lewis Structure Rules
1) Predict Atom locationsa) H is always terminalb) Lowest Electronegativity is
central atom
2) Find total number of bonding e-
H –
C –
O – 36
1 x 8 = 8
4 x 4 = 16
6 x 2 = 12
C4H8O2
General Lewis Structure Rules
1) Predict Atom locationsa) H is always terminalb) Lowest Electronegativity
is central atom
2) Find total number of bonding e-
3) Find number of pairs
36/2=18
C4H8O2
General Lewis Structure Rules
1) Predict Atom locationsa) H is always terminalb) Lowest Electronegativity
is central atom
2) Find total number of bonding e-
3) Find number of pairs4) Place one bond
between central atom and each outer atom
C4H8O2 18
C
C
C
C
H
H
H
HH
H
H
H
O
O
-13
5
General Lewis Structure Rules
1) Predict Atom locationsa) H is always terminalb) Lowest Electronegativity is
central atom
2) Find total number of bonding e-
3) Find number of pairs4) Place one bond between
central atom and each outer atom
5) Place remaining e- pairs around outer atoms
C4H8O2 18
C
C
C
C
H
H
H
HH
H
H
H
O
O
-13
5
General Lewis Structure Rules
1) Predict Atom locationsa) H is always terminalb) Lowest Electronegativity is central
atom
2) Find total number of bonding e- 3) Find number of pairs4) Place one bond between
central atom and each outer atom
5) Place remaining e- pairs around outer atoms
6) Form double (triple) bonds to give central atom an octet
C4H8O2
C
C
C
C
H
H
H
HH
H
H
H
O
O
Polyatomic Ions
CationsNH4
+
AnionsSulfate
H – 1x4=4N – 5x1=5 9
(+) = -1 8
8
S – 6x1 = 6O – 6x4 = 24
30
(2-) = 232
26
Resonance Structures
A molecule has resonance when you can draw multiple Lewis Structures
NO3-
N
O O
O-
Resonance Structures
A molecule has resonance when you can draw multiple Lewis Structures
NO3-
N
O O
O-
Exceptions
I. Odd number of e-
II. Fewer than 8 e-
III. Expanded Octet
NO2
BH3
SF6
O N O
H B H
H
SF
FF
F
F
F