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7/25/2019 Analytical Solutions for Magneto Electro Elastic Beams Under Uniform or Linear Electric and Magnetic Potential
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Aanalytical Solutions for Magneto-electro-
elastic Beams under Uniform or Linear
Electric and Magnetic Potential
Jiang Ai-min, Wu Yi-li
West Branch of Zhejiang University of Technology
Quzhou,324000, P. R.China
E-mail: [email protected]
Abstract-For the orthotropic magneto-electro-elastic
plane problem, a series of magneto-electro-elastic
beams is solved and the corresponding exact or
analytical solutions are obtained with the trial-
and-error method on the basis of the general solution
in the case of four distinct eigenvalues, in which all
physical quantities are expressed by four
displacement functions in terms of harmonic
polynomials. These are magneto-electro-elastic
rectangular beam with rigid body displacements,
identical electric and magnetic potential, beams of
free ends under uniform electric potential and
magnetic potential, and cantilever beam under linear
electric potential and magnetic potential. The exact
and analytical solutions obtained in this paper are
also useful for study of other problems relating to
more complicated loads and boundary conditions by
the superposition principle.
Key words-analytical solution; magneto
-electro-elastic beam; harmonic function
INTRODUCTION
Magneto-electro-elastic materials possess
simultaneously magneto-electro-elastic, piezo-
magnetic and magnetoelectric effects. Liu,et
al.[1] obtained Greens functions for an infinite
two-dimensional anistropic magneto-electro-
elastic medium containing an elliptical cavity
based on the extended Stroh Formalism. Pan[2]
derived three-dimensional Greens functions in
anisotropic magneto-electro-elastic full space,
half space, and bi-materials based on the
extended Stroh formalism by applying the
two-dimensional Fourier transforms. Wang and
Shen[3] obtained the general solution expressed
by five harmonic functions and applied the
derived general solution to find the fundamental
solution for a generalized dislocation and also to
derive Greens functions for a semi-infinite
magneto-electro-elastic solid. Hou,et al.[4]
analyzed the elliptical Hertizan contact of
transversely isotropic magneto-electro-elastic
bodies with the general solutions in terms of
harmonic functions. Chen,et al[5] obtained
analytical solutions of simply supported
magneto-electro-elastic circular plate under
uniform loads with a general solution in forms of
harmonic functions. Ding and Jiang[6] obtained
the fundamental solution of infinite magneto-electro-elastic solid with the method of trial-and-
error on the basis of the general solution in the
case of distinct eigenvalues , which is expressed
in five harmonic functions and the same as in
Wang and Shen[3], and derived the boundary
integral formulation. Jiang and Ding[7] derived
the general solution in terms of four harmonic
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displacement functions for magneto-
electro-elastic plane problem and solved a series
of problems by the trial-and-error method.
In this paper, we continue to obtain the
analytical solutions for the magneto-electro-elastic
plane problems on the basis of Jiang and Ding[7].
With the trial-and-error method, the exact solution
for beam of free ends under uniform electrical
potential and magnetic potential are derived.
Furthermore, we also give out the analytical
solutions in harmonic polynomials to cantilever
beam under linear electric potential and magnetic
potential on the upper and bottom surfaces. All
these solutions can serve as benchmarks for
numerical methods such as the finite element
method, the boundary element method, etc.
. GENERAL SOLUTION TO THE PLANE
PROBLEM OF
MAGNETO-ELECTRO-ELASTIC SOLID
For the magneto-electro-elastic plane-strain
problems, the general solution in the case of
distinct eigenvalues has been derived and
expressed in four harmonic functions in Jiangand Ding[7] as follows:
=
=
4
1j
j
xu
,
= =
4
1j j
j
mjjm zksw
,
=
=
4
12
2
4
j j
j
jxz
,
=
=
4
12
2
j j
j
mjmz
,
=
=
4
1
2
j j
j
mjjmzx
s
, )3,2,1( =m (1)
where the generalized displacements and stresses
are defined as follows:
ww =1 , w2 = , =3w ,
z =
1 ,
zD=2 , zB=3 ,
xz =
1 ,
xD=2 , xB=3 (2)
),(),( wuxzz )( zx DD and )( zx BB are the
components of stress, displacement, electric
displacement and magnetic induction,
respectively; and are the electric
potential and magnetic potential, respectively.
The functions j in (1) satisfy the
following equations :
02
2
2
2
=
+
j
jzx , )4~1( =j (3)
where zsz jj = , js are the four roots of the
following equations (We take Re ( js )0) :
052
4
4
3
6
2
8
1 =++ asasasasa (4)
where the coefficients )3~1(, =mk mjmj
in (1) and )5~1( =nan in (4) are the same as
those listed in Hou, et al.[4].
.EXACT SOLUTIONS FOR TWO
SIMPLE PROBLEMS
A. Rigid Body Displacements Identical Electric
Potential and Magnetic Potential
In the paper of Jiang and Ding[7], we have
obtained the exact solution as follows :
zuu 00 += , xww 00 = ,
0= , 0= (5)
0===xzzx , 0== zx DD ,
0==zx BB (6)
where 0000 ,,, wu and 0 are constants
denoting rigid body displacements, rigid body
rotation, identical electric potential and magnetic
potential .
Beam of Two Free Ends under Uniform
Electrical Potential and Magnetic Potential
we constitute the displacement function as
)( 222 jjj zxA = , )4~1( =j 7
where jA2 are unknown constants to be
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determined.
Substituting (7) into (1), we will have
==
==4
1
2
4
1
22,2
j
jjmjjm
j
j zAkswAxu
,2,04
1
24=
==j
jjxm A
=
=4
1
22
j
jmjm A , )3~1( =m (8)
The boundary conditions are
2/hz = 0=z 0=xz
2/0
= , 2/0
= (9a)
2/Lx = 0=x 0=xz
0=x
D , 0=x
B 9b
Substituting the expressions of x , z ,
and into (9) leads to :
==
==
==
==
,2,0
,2,0
0
4
1
23
24
1
24
0
4
1
22
24
1
21
j
jjj
j
jj
j
jjj
j
jj
AkshA
AkshA
10
The four unknown constants jA2 can be
calculated from (10). Superposing the solutionabove on the exact solution (5, 6) for a
rectangular beam with identical electrical
potential, and taking 000 ==wu and
00 = , we will have the following solution
,2,24
1
21
24
1
2 ==
==j
jjj
j
j AkszwAxu
=
=
4
1
22
2
0 ,2j
jjj Aksz
,2
4
123
2
0
== jjjj Aksz
,0===xzzx
,24
1
22=
=j
jjz AD
,0,0 ==xx BD
=
=4
1
23 ,2j
jjz AB (11)
Because 0 and 0 are two arbitrary
constants, one can appoint arbitrary uniform
electrical potentials on the two surfaces
( 2/hz = ). For the same reason, one can also
appoint arbitrary uniform magnetic potentials as
0 and 0 are arbitrary constants. The
solution (11) is the exact one for beam of two
free ends under uniform electrical potential.
. CANTILEVER BEAM WITH CROSS
FORCE, POINT CHARGE AND POINT
CURRENT AT FREE END
The boundary conditions of a cantilever
beam with cross force P in zdirection, pointcharge Q and point current Jat free end, are
2/hz = 0=z 0=xz
0=z
D 0=z
B (12a)
0=x 0=x 12/
2/Qdz
h
h xz =
+
2
2/
2/QdzD
h
h x =
+
3
2/
2/QdzD
h
h x =
+
(12b)
Lx= , 0=z 0=u 0=w
0/ = xw (12c)
where QQPQ == 21 , and JQ =3 .
In the paper of Jiang and Ding[7], the
corresponding analytical solution has been
obtained to constitute the displacement function
and superposing the solution for magneto-
electro-elastic beam with rigid body
displacements, identical electric potential and
magnetic potential.
. CANTILEVER BEAM UNDER
LINEARELECTRICAL AND MAGNETICPOTENTIAL ON THE SURFACES
we constitute the displacement function:
)3( 2332 jjjjj xzxAxzB +=
)4~1( =j 13
where jB2 and jA3 are unknown constants to
be determined.
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Substituting (13) into (1), we have
=
+=4
1
3
22
2 ])33([j
jjjj AzxBzu
=
=
4
1
32 )6(j
jjjmjjm AxzxBksw ,
== ==4
13
4
134 6,6
jjmjm
jjjx AxAx
=
=4
1
32 )6(j
jjjmjjm AzBs
)3~1( =m 14The boundary conditions are:
2/hz += 0=z xh
x 1)2
,( =+
0=xz xhx 2)2/,( =+ (15a)
2/hz = 0=z xh
x 1)
2
,( = ,
0=xz xhx 2)2/,( = (15b)
0=x +
=
2/
2/0
h
h xdz
+
=
2/
2/0
h
h xzdz
+
==
2/
2/)3~1(,0
h
h m mdz (15c)
0, == zLx 0=u 0=w
0/ = xw 15dSubstituting (14) into (15a, 15b) and the
second equation of (15d), yields
,01
1 31==
j jj
A ,03
1 31
2
==
j jjj
As
,2/)(34
1
1132
2=
=j
jjj Aksh
2/)(34
1
2233
2=
=j
jjj Aksh 16
,04
1
21=
=j
jjj Bs ,0
4
1
21=
=j
jjj Bks
,2/)(4
1
1122=
+=j
jjj Bks
2/)(4
1
2223=
+=j
jjj Bks 17
Then,jA3 can be determined from (16) and jB2
from (17). Furthermore, in order to satisfy the
third equation of (15c), one should superpose the
solution above on the corresponding analytical
solution for a cantilever magneto-electro-elastic
beam under loads at free end discussed in
Section, and let
+
=
==2/
2/
4
1
2
h
hj
jmjjmm BshdzQ ,
)3~1( =m 18Furthermore, the first equation of (15d) can be
satisfied by superposing on the rigid body
displacement determined as follows
=
==4
1
3
2
0 3j
jALuu (19)
ACKNOWLEDGMENT
The work was supported by Zhejiang Natural
Science Foundation (No.Y605040, Y608118).
REFERENCES
[1] J. X. Liu, X. L. Liu, and Y. B. Zhao,Greens functions
for anisotropic magneto-electro-elastic solids with an
elliptical cavity or a crack, Int. J. Eng. Sci. vol.39,
pp.1405-1418, 2001.
[2] E. Pan, Three-dimensional Greens function in
anisotropic magneto-electro-elastic bimaterials , Z.
angew. Math.Phys, vol.53, pp.815-838, 2002.
[3] X. Wang, Y. P. Shen, The general solution of
three-dimensional problems in magneto-electro-elastic
media, Int. J. Eng. Sci. vol.40, pp.1069-1080, 2002.
[4] P. F. Hou, Y. T. Leung Andrew, and H. J. Ding, The
elliptical Hertizan contact of transversely isotropic
magneto-electro-elastic bodies, Int. J. Solids Struct. ,
vol.40, pp.2833~2850, 2003.
[5] J. Y. Chen, H. J. Ding, and P. F. Hou, Analytical
solutions of simply supported magneto-electro-elastic
circular plate under uniform loads, Journal of Zhejiang
University SCIENCE, vol.4(5), pp.560-564, 2003.
[6] H. J. Ding, A. M. Jiang, Fundamental solutions for
transversely isotropic magneto-electro-elastic media
and boundary integral formulation , Science in
China(Series E), vol.46(6), pp.607-619, 2003.
[7] A. M. Jiang, H. J. Ding, Analytical solutions to
magneto-electro-elastic beams, Structural Engineering
and Mechanics, vol.18(2), pp.195-209, 2004
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