An aeroelastic model for horizontal axis wind turbines

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    MATHEMATICS IN ENGINEERING, SCIENCE AND AEROSPACE

    MESA - www.journalmesa.com

    Vol. 4, No. 3, pp. 249-264, 2013

    c CSP - Cambridge, UK; I&S - Florida, USA, 2013

    An aeroelastic model for horizontal axis wind turbines

    Florin FRUNZULICA1,, Alexandru DUMITRACHE2, Horia DUMITRESCU2

    1 POLITEHNICA University of Bucharest, Faculty of Aerospace Engineering, Polizu 1-6, RO-

    011061, Bucharest, Romania,

    2 Gheorghe Mihoc - Caius Iacob Institute of Mathematical Statistics and Applied Mathematics,

    P.O. Box 1-24,RO-010145, Bucharest, Romania.

    Corresponding Author.E-mail: [email protected]

    Dedicated to the memory of late Professor Mihai Popescu.

    Abstract. In this paper an advanced aeroelastic numerical tool for horizontal axis wind turbines

    (HAWT) is presented. The tool is created by coupling an unsteady aerodynamic model based on the

    vortex method (using the vortex ring model for the lifting surface coupled with an unsteady free-wake

    vortex particle model) with an elastodynamic model based on the beam approximation. The coupling

    is non-linear in the sense that at every time step the two models interact through data transfer from

    the one to the other. The aeroelastic model is evaluated through comparisons of its predictions with

    experimental data as well as with predictions obtained by simpler models.

    1 Introduction

    The design problem of horizontal axis wind turbines is related to a number of physical processes of

    varying complexity. Due to the non-linear as well as stochastic (in some aspects), nature of these

    processes, a number of simplifications have been introduced up to now. Most of them lead to the

    decoupling of the various processes in order to treat them separately. In this connection, there are two

    dominant model problems: the aerodynamic problem and the elastodynamic one. Their combinationleads to the aeroelastic problem of a horizontal axis wind turbine (HAWT)[1]. Input to this problem is

    the wind inflow conditions. The solution of the aerodynamic and aeroelastic problems can be used to

    provide useful information to a number of design problems. Thus, the post-processing of the results

    can lead to a fatique and reability analysis, the analysis of wake effects for the design of wind parks,

    the prediction of power fluctuations, etc.

    In this work, the authors present a non-linear advanced aeroelastic model based on a vortex method

    as regards the aerodynamics, and a beam structural model adapted to this problem.

    2010 Mathematics Subject Classification: 76G25, 74B20, 74S05

    Keywords: vortex lattice method, beam theory, finite elements method, aeroelasticity, HAWT.

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    250 F. Frunzulica, Al. Dumitrache, H. Dumitrescu

    2 The numerical method

    The key point of the approach adopted herein is based on the formulation of the aeroelastic problemas an appropriate coupling of two different problems: the aerodynamic and the elastodynamic. In

    brief, the aerodynamic part aims at the calculation of the loads exercised on the structure due to the

    dynamics of the surrounding fluid.

    The loads are then introduced as forcing to the elastodynamic equations where from the defor-

    mations, the rates of deformations and the accelerations are calculated along the blade. The rates of

    deformations are feed back into the aerodynamic part as excess body velocities of the blade (in addi-

    tion to the rigid body motions). This results in a modification of the non-entry boundary condition for

    the aerodynamic part that represents the effects of flexibility on the fluid dynamics.

    Regarding the wind turbine and its surrounding fluid as one mechanical system, it is clear that

    the procedure just outlined defines a two-way channel of communication between the two parts of

    the system. This communication is achieved by means of two interfaces: one for the transfer of theaerodynamic loads from the aerodynamics to the elastodynamic part, and one for the transfer of the

    rats of deformations from the elastodynamics to the aerodynamic part. Note that in both cases the data

    that are transferred concern solely the solid surface of the blades, i.e. the domain of contact between

    and the solid part of the system. This is always the case regardless the type of approximation used

    for the either the fluid or the solid. In what follows, the flow problem is approximated by a free-wake

    aerodynamic model, whereas the elastic part is modeled by the beam approximation.

    2.1 The aerodynamic model

    For rotor computations, the blades element momentum methods are easily understandable and appli-

    cable, using minimum computation requirements [1,2]. Anyhow, there are cases when these methodsdo not provide the desired precision. The design interest cases include asymmetric aerodynamic un-

    steady flow (especially the dynamic effects of incident flow). An evident alternative is the detailed

    computation of the induced velocities field, based on the wake vortex distribution [3,4,5,6]. The

    vortex methods are interesting, even while requiring significant computation resources, due to their

    possibility to observe the vortex systems main structure. In the following sections, we will present

    a calculation algorithm where the near-wake strip elements are transformed into vortex particles and

    become part of the far-wake. Integrating the vorticity of each near-wake dipole element produces a

    vortex particle. The new vortex particles became part of the far wake which evolves prior to the next

    time step using a Lagrangean description of the flow .

    Hypothesis.The working fluid is a continuous barotropic ideal fluid which fills an unlimited,

    simple, contiguous domain

    . In the flow is adiabatic and non-rotational, where =

    R.The domainR is the rotational flow domain (i.e. for a blade this is represented by the solid bladesurface and the wake flow- field domain).

    The blades have a rotational motion related to the reference system attached to the airflow speed

    direction. In the calculation points the velocity is given by sum of three components: the cinematic

    velocity corresponding to blade motion, the induced velocities and the wake induced velocities. The

    generated free wake is attached to the leading edge of the blade.

    The time steps are chosen so that vortexes generated by the trailing/leading edge should not trans-

    ported on distance greater than the smallest panel dimension.

    The Vortex Lattice Method (VLM).When the blades lifting surface has a relatively reduced thick-

    ness (valid for most free rotor blades) it might be selected a scientific method requiring the vortex ring

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    An Aeroelastic Model for HAWT 251

    distribution on a surface built by means of the generatrix camber line. Therefore the numeric calcula-

    tion can determine the pressure jump p= pi pe between upper and lower surfaces.

    Figure 1 shows the blade decomposing into panels. The vortex element on the panel at front edge islocated at of the panels chord, while the collocation point is located at of panels chord. Numerically,

    the vortex rings are stored in a matrix with the indexes i and j. Each vortex ring is perfectly sitting on

    the mean wing surface, to enable a correct representation from the mathematical point of view. The

    induced velocity in a control pointP is calculated with the Biot-Savart formula [3].

    Fig. 1 Discretization of the blade into panels (a) and vortex rings distribution (b).

    To determine the vortex rings intensities, i,j, it will be imposed that the resulting speed in the

    calculation point shall be tangent to the mean blade surface:

    (M

    i=1

    N

    j=1

    (Vind,P(t,i,j))i,j+Mw,T E

    i=1

    N

    j=1

    (Vw,P(t,i,j))i,j+

    Mw,T E

    j=1

    Vw,P(t,j)) nP=Vk,P(t) nP (2.1)

    whereMand Nare the number of panels along the chord, respectively along the wing span, Mw,T Erepresent the number of free vortexes in each closed wake strip generated by the trailing edge and

    Mw,T Erepresent the number of particles generated in the wake by the trailing edge (the formula (1)

    includes the wake separation at leading edge for high angle of attack). Numerically, we will consider

    a finite wake (about 3 rotor diameters). Vortexes generated at the leading and trailing edges for each

    nearby adjacent panel will change their intensity in time and will move in space with local airflow

    speed. Equation (2.1) provides (at each time step) a linear algebraic system A = b. Solving thissystem by an exact or iterative method enables to determine the vortex rings intensity i,j,i=1,...,M,

    j=1...N. MatrixAis the influence coefficients matrix, while vector bis the right side of equation (2.1).

    Leading Edge Wake Model.To take into account the leading edge stall there is necessary to know

    the wake vortex near the leading edge at any time. Physically the phenomenon is a consequence of

    high incidence viscous flow and to introduce it in the numerical algorithm the ONERA method applies

    [1,7]. This gives the changes of the s circulation, while on blade elements (element strips along the

    chord), under stall conditions, by solving a second order differential equation:

    s+

    s+

    r

    2s=

    r

    2VtCL

    E

    Vn (2.2)

    where =2Vt/c,c is the blade element chord, Vtis the velocity component along the chord,Vnis thechord normal velocity component, CL is the lift coefficient difference between potential flow and

    stationary flow. Dumitrescu et al. present in detail the empiric coefficients r,E,[1].To determine CLit is necessary to find out each blade elements local angle of incidence. Usually,

    this is the global angle of incidence for a flow completely attached to the blade.

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    252 F. Frunzulica, Al. Dumitrache, H. Dumitrescu

    The differential equation (2.2) applied for each blade element enables determination of the first

    vortex ring in the leading edge generated wake, representing the support of the wake particles carrying

    vortices.T ELE= (at+s) (2.3)

    where T E is the trailing edge circulation, while at is circulation corresponding to the flow fully

    attached along the local blade strip.

    The Trailing Edge Wake Model.Expressing the (far) wake with particles means that each particle

    is defined by its position xi, its vortices i and its kernel radius i [4,7]. Thus, the local vorticity in

    wake can be determined with the formula:

    w(x, t) =i

    i(t) g (xxi(t) ,i(t)) (2.4)

    where g represents the vortices distribution function for the particle i (i= 1...Nw,p), while i is the

    length defining the particle kernels support domain. In three-dimensional space, the function g hasthe expression [5]:

    g (r,) = 3

    43exp

    (|r|/)3

    (2.5)

    Thus, the speed induced in a point by a set of particles will be:

    Vw(x, t) = 1

    4

    w

    (xx)w(x, t)

    |xx|3 d =

    1

    4

    Nw,p

    i=1

    i(t) (xxi)

    |xxi|3

    f(xxi,i) (2.6)

    where: f(r,) =1 exp(|r|/)3

    .

    Therefore, the evolution of a vortex lattice is reduced to the calculation of a particles assembly, j:

    Dxj(t)

    Dt=V (xj, t) ,

    Dj(t)

    Dt= (j(t) ) V (xj, t) (2.7)

    whereV is the total fluid velocity in the point xj.

    For a time period t, the Adams-Bashforth formula is approximating the trajectory of a fluid

    particle:

    xj(t+t) =xj(t) + [1.5V (xj(t) , t)0.5 V (xj(tt) , tt)] t (2.8)

    Changing a particles kernel radius due to viscous diffusion is similarly to the viscous diffusion of

    a vortex filament in a plan perpendicularly to this filament:

    D

    Dt =

    c2

    2t , c=2,242 (2.9)

    with the kernel radius at time,t+tdetermined by the relation:

    |t+t|=|t| (t/t+t)2

    (2.10)

    In applications, the near wake is including a single vortex ring line, usually the one generated by

    the trailing edge TE(a similar approach is available also for the leading edge ,LE, wake). Figure 2

    shows the particles transforming algorithm.

    At the time momentt,calculation to solving the systemA = b, provides the circulation intensityof the vortex ring tm1,jand of the neighbor rings, the location of the cross points 1 and 2 being from

    the previous time step:

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    An Aeroelastic Model for HAWT 253

    Fig. 2 Generation of aTEvortex ring (a), convection and transformation in an equivalent particle (b).

    x1=xm,j+ Vttm,j t , x2=xm,j+1+ V

    ttm,j+1t (2.11)

    On the edges 14 and 23, the effective circulation is equally distributed between the panels adja-cent to these edges, while on edge 12 the circulation is provided by the difference between current

    intensities and those of the previous time moment. The new positions of the cross points defining the

    panel 1234 is determined for each time step with the equation:

    x i=xi+ Vtit, i=1,2,3,4 (2.12)

    IfSis the panelSvorticity (in its new position), S(x) =Sdx, then the particlesjvorticity

    associated to panel,S, is determined with the relation:

    j=

    SSd (2.13)

    while the particles position in time will be determined with the relation:

    xjj=

    SxSd (2.14)

    The transport of the new particlejis further done according to the equations (2.7).

    Blade pressure calculation.To determine the pressure difference on the blade we will decompose

    the local velocity V on the blade surface, panel (i,j), related to two directions: i (tangent direction

    oriented along the chord) and tauj (tangent direction along the span). Defining the characteristic

    length for a panel (i,j) along the chord and the span, ci,j andbi,j, the pressure difference will be

    provided by the equation [1,3]:

    pi,j= (Vp)i,j ii,ji1,j

    ci,j+ (VP)i,j j

    i,ji,j1

    bi,j+i,j

    t (2.15)

    while the force on the panel (i,j) will be provided by:

    Fi,j=pi,jni,jSi,j= Di,ji +Fyi,jj +Li,jk (2.16)

    The next phase of the aerodynamic computation consists of calculations of blade forces. The first

    is the tangential force per unit blade length Ftacting along the chord line of a blade element in the

    direction of motion. The second is the normal force per unit blade lengthFnacting in the direction of

    the unit vector normal to the chord line. A complete set of two dimensional aerodynamic forces would

    also include a pitching moment about the spanwise axis. In general this moment is small and is thus

    neglected. From (2.16) we can compute in spanwise direction, lift coefficient CL and drag coefficient

    CD(including given airfoil drag and locally induced drag).

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    254 F. Frunzulica, Al. Dumitrache, H. Dumitrescu

    2.2 The elastodynamic model

    The aspect ratio of wind turbine blades is, usually large and, therefore, beam theory can be used

    to describe, the elastodynamic behaviour of the blade. Let O [Xe,Ye,Ze]denote the beam coordinatesystem.and it is assumed that the elastic axis is straight and coincides with axisYe.

    The beam theory. In this model three types of deformations are introduced: x(y)- the bendingdeformation along Ye direction (flapwise bending),z(y)- the bending deformation alongZe direction(leadwise bending) andy(y)- the spanwise torsional deformation [8,9].

    According to the linear beam theory, the equations for the equilibrium of forces and moments in

    the(X Z)eplane are as follows:

    2

    y2

    EIz

    2xy2

    +

    2xt2

    zcm2yt2

    + fxa+fxg+fxc= 0 (2.17)

    2

    y2

    EIx

    2

    zy2

    +

    2

    zt2 xcm

    2

    yt2 + fza+fzg+fzc=0 (2.18)

    y

    GIt

    yy

    Ip2yt2

    +xcm2zt2

    zcm2xt2

    + mya+ myg+ myc= 0 (2.19)

    where:E(y)- the Young modulus (N/m2),G (y)- the shear modulus (N/m2), (y)- the linear density(kg/m), xcm- the distance of the mass center from Ze axis (m), zcm- the distance of the mass centerfromXe axis (m),Ix(y)- the moment of inertia about Xe axis (m

    4),Iz(y)- the moment of inertia aboutZe axis (m

    4), Ip(y)- the polar moment of inertia about the elastic center (m4),It(y)- St. Venant tor-

    sional moment of inertia (m4), f(y)the bending distributed loads (N/m),m(y)the distributed torque(Nm/m), and subscripts a, g, c denotes the aerodynamic loads, gravitational loads and centrifugalloads respectively.

    The first step in structural computation is to calculate beam cross-sectional properties of thin-

    walled beam, multi-cell, nonhomogeneous, closed sections, within the framework of Bernoullis

    bending theory and St. Venant torsion theory [8,9]. The key idea is the approximation of the airfoils

    shape byne straight, homogeneous elements. The thickness of every element is considered constant

    and is evenly distributed across the two sides of its midline. For each element, the following data

    are necessary:Ee,Ge moduli (N/m2), densitye (kg/m

    3), thicknesste(m), coordinates of element in

    plane(X1e,Z1e)and(X2e,Z2e)(figure 3).

    Fig. 3 The discretized airfoil.

    At the beginning, the coordinates(X1e,Z1e) and (X2e,Z2e)can be given with respect to any co-ordinate system (figure 2), but after the calculation of the elastic center coordinates, we switch to the

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    An Aeroelastic Model for HAWT 255

    elastic coordinate system. Following the notations of figure 2, the section characteristics are obtained

    as follows:

    Le=

    (X2e X1e)2

    + (Z2e Z1e)2

    , Ae= Le te, A=

    ne

    e=1Ae (2.20)

    E=ne

    e=1

    EeAe/A, G=ne

    e=1

    GeAe/A (2.21)

    =ne

    e=1

    eAe (2.22)

    xel=ne

    e=1

    EeAe(X1e+X2e)

    2

    1

    EA, zel=

    ne

    e=1

    EeAe(Z1e+Z2e)

    2

    1

    EA(2.23)

    where Ae is the elements area, Le is the elements length, and ((xel,zel )) are the coordinates of the

    elastic center. Now, the whole analysis is referred to the elastic coordinate system. The remainingsectional properties are defined as follows:

    Xcm=ne

    e=1

    eAe(X1e+X2e)

    2

    1

    A, xcm=Xcm xsc

    Zcm=ne

    e=1

    eAe(Z1e+Z2e)

    2

    1

    A, zcm=Zcm zsc (2.24)

    where(Xcm,Zcm)are the coordinates of the mass center in the elastic coordinate system, and (xsc,zsc)are the coordinates of the shear center in the elastic coordinate system. The calculation of the shear

    center will be described later.

    St. Venant torsional constant It. The St. Venant torsional constant of a section is defined as:

    It= Mt/(G) (2.25)

    whereMtis the torque that acts on the plane of the section, and is the rate of twist due to this torque.

    In the case of a thin-walled, multi-cell section, the calculation of necessitates the calculation of

    the shear flows in the skin of the section. For three cells section (figure 4), we apply the following

    equations:

    -the equation of the equilibrium of moments (Bredt-Batho formula):

    2q11+ 2q22+ 2q33= Mt (2.26)

    -the equations for the shear flow balance at the junctions:

    q1= q4+ q2 , q2= q3+ q5 (2.27)

    -and the equations for the consistency of torsional deformations for every cell:

    1= 2= 3 (2.28)

    or in extended form

    1

    2G11(q11+ q44) =

    1

    2G22(q2(2+6)q44+ q55) =

    1

    2G33(q33 q55) (2.29)

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    256 F. Frunzulica, Al. Dumitrache, H. Dumitrescu

    where1,2,3 are the areas of cells,Gj the tangential modulus, averaged over cell j, and

    j=

    Sj

    ds

    t =iSj

    Li

    ti (2.30)

    The segment Sj represents the curvilinear segment where acting the shear flow qj, j= 1,2...6.Equations (2.26)-(2.29) form a 5x5 system from which the values ofqj, j= 1,2...6, can be computed.The torsional specific deformation of the section is equal to the torsional specific deformation of

    each one of the cells,

    = 1

    2G11(q11+ q44) (2.31)

    and now,Itcan be obtained by equation (2.25).

    Fig. 4 The shear flow for the thin-walled, three cell sections, under twisting moment.

    The shear center (SC).The shear center of the section represents the point through which the plane

    of the resultant loads must pass to prevent the development of twisting moments on the section. Tocalculate the coordinates of the SC we assume that a shearing force Tacts through the SC at distance

    dfrom the arbitrary reference point (the elastic center). Our section is three-celled and is three times

    statically indeterminate. We perform a cut in each cell and as consequences the structure is reduced

    to the thin-walled open section. To restore continuity at every cut, a supplementary shear flow is

    introduced in celli:

    qj= qj0+ qj (2.32)

    whereq j0 is the shear flow at any point of cell j assuming cuts at all cells, and qj is the constant

    shear flow which is developed if we close the cut of cellj. The shear flowqj0 is defined as [9]:

    qj0=IxTx IxzTz

    IxIz I2

    xz

    Qz IzTz IxzTx

    IxIz I2

    xz

    Qx (2.33)

    where

    Ixz= 1

    E

    ne

    e=1

    EeAeX1e+X2e

    2

    Z1e+Z2e2

    (2.34)

    and

    Qz= 1

    E

    s0

    E(s)x t(s)ds, Qx= 1

    E

    s0

    E(s)z t(s)ds (2.35)

    In equation (2.33),Qxand Qzare the only quantities which change from point to point.

    We evaluate the shear flowqj0 from the cut whereqj0=0 (the inferior limit of integrals (2.35))and we continue moving along the correspondent line until we meet a junction. In junction we apply

    a balance of shear flow (figure 5); for exemplification, in junction 1 we have

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    An Aeroelastic Model for HAWT 257

    Fig. 5 The shear flow for the thin-walled, three cell sections, under shear load.

    q14=q11b q

    12a (2.36)

    and now, the shear flowq40 in spar web 1-4 is

    q40=q14+

    IxTx IxzTzIxIz I2xz

    Qz IzTz IxzTx

    IxIz I2xzQx

    14

    (2.37)

    The final shear flow can be interpreted as algebraic sum of the shear flows qj0 in the opened

    section, and the corrective shear flows qj applied independently in each cell. The total relative warping

    at the three cuts is obviously zero if all cells are closed. Thus, if the rate of twist is set equal to zero,

    for cellj we have the following equation:

    1

    Gj

    Sj

    qj ds

    t=

    1

    Gj

    Sj

    qjds

    t

    Sjk

    qkds

    t

    Sji

    qi ds

    t+

    Sj

    qj0 ds

    t

    =0 (2.38)

    whereSjkis the web common to cells j and k. If we denote

    j0= 1

    Gj

    Sj

    qj0 ds

    t, j j=

    1

    Gj

    Sj

    ds

    t, ji=

    1

    Gj

    Sji

    ds

    t, jk=

    1

    Gj

    Sjk

    ds

    t(2.39)

    then the equation (2.38) becomes

    jiqi +j jq

    j+jkq

    k=j0 (2.40)

    and represents a 3x3 system which can be solved with respect to qi . Now we can obtain the shear

    flow distribution at any point of the section using eq. (2.32). The moment M0 produced by the shear

    flows about the arbitrary reference point (the elastic center) is

    M0=ne

    e=1

    qe(X1eZ2e X2eZ1e) (2.41)

    whereqeis the shear flow that correspond to thee-th element.

    For the x-coordinate of the shear center, an external load in the z direction must be imposed. In

    this case:

    xsc=M0/Tz (2.42)

    For thez-coordinate of the shear center, the load is imposed in the x direction:

    zsc=M0/Tx (2.43)

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    258 F. Frunzulica, Al. Dumitrache, H. Dumitrescu

    The finite element technique. By using Lagrange equations the following linear equations of

    motion are obtained [10,11]:

    MDn+ C

    Dn+ KDn= R

    ext

    n (2.44)where

    -the matrixM=

    VNTNdVis the mass matrix

    -the matrixC=

    VNTCNddV is the structural damping

    -the matrixK=

    VNTdE NddVis the stiffness matrix

    -the vectorRextis the load vector

    -the vector D is the displacement vector, which contains the degrees of freedom: x - edgewise

    bending, x - the bending slope at XY plane, z - flapwise bending, z - the bending slope at ZY

    plane,y - the torsional deformation at X Zplane, and

    -Nd- the derivative matrix of shape function

    -N- the matrix of shape function (the shape functions most commonly used are the third-degree

    polynomials and the first degree in the case of torsion).

    The time advancementof the equation (2.44) with the appropriate initial conditions is performed

    with the specialized algorithm (Crank-Nicolson) method [10]. This is an unconditionally stable im-

    plicit one-step method, which is second order accurate in time and relates the displacements, veloci-

    ties, and acceleration as

    Dn+1=Dn+t

    2

    Dn+ Dn+1

    , Dn+1= Dn+

    t

    2

    Dn+Dn+1

    (2.45)

    Subscript n corresponds to the old time and n+1 is the new time. t is the time step. Rearranging

    equations (2.45) gives

    Dn+1= 2t

    (Dn+1 Dn) Dn, Dn+1= 4t2

    (Dn+1 Dn) 4t

    Dn Dn (2.46)

    By combining equations (2.46) with the equations of motion (2.44) at timet= tn+1, we obtain:

    Ke f f Dn+1=Re f fn+1 (2.47)

    where the effective stiffness matrix, Ke f f, and the effective load vector,Re f fn+1, are, respectively,

    Ke f f = 4

    t2M +

    2

    tC + K (2.48)

    and

    Re f fn+1= R

    extn+1+ M

    4

    t2Dn+

    4

    tDn+ Dn

    + C

    2

    tDn+ Dn

    (2.49)

    2.3 Coupling models

    The solution of the aeroelastic problem requires the coupling of an aerodynamic and an elastodynamic

    model. In previous paragraphs a brief description of each part was done separately. In this paragraph

    the basic principles of the communication between the two parts will be discussed.

    As regards the elastodynamic part, the load vector must be input. This vector is calculated by

    superimposing the gravitational forces on the aerodynamic loads. The quantities that have to be trans-

    ferred from the aerodynamic part are, therefore, the aerodynamic forces that act on the blade.

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    The solution of equation (2.44) yields the vector D of the deformations, the vector D of the de-

    formation rates and the vector D of the accelerations at the nodes of the beam that simulates the

    blade.The feedback to the aerodynamic part are the deformations rates, which, in the case of non-linear

    coupling, are included in the aerodynamic problem along with the body motion velocities. This results

    in a change of the effective velocity of the blade seen by the fluid. Consequently, the angles of attack

    and, therefore, the lift and drag coefficients change.

    Within the context of linear elasticity, deformations are assumed small. On the other hand, it is

    not expected to encounter considerable deformations on a blade of a wind turbine. Therefore, it is

    approximately correct to retain the undeformed geometry of the blade throughout the whole analysis.

    The main modules can be summarized in the following flowchart (figure 6):

    Fig. 6 The flowchart of the coupling between aerodynamic and elastodynamic models.

    The flow chart of the aeroelastic code has the following steps: (a) initialize code; (b) perform same

    pure aerodynamic steps for the calculation of the circulation distribution. For every time step: (c.1)

    start time step; (c.2) calculate the aerodynamic forces distribution; (c.3) calculate the force and the

    velocity distribution on the blades; (c.4) perform elastodynamic steps for a period of time equal to

    aerodynamic time step; (c.5) circulation calculation step; (c.6) go to next time step.

    For a non-linear coupling, in the step c.2 the aerodynamic forces is fulfilled including the rates of

    elastodynamic deformations, which have been calculated during the previous time step. In the case of

    a linear coupling, there is no feedback from the elastodynamic part to the aerodynamic part.

    The only communication between the two parts is in step c.4 where the aerodynamic forces areimposed on the beam and the elastodynamic problem is solved.

    3 Results

    3.1 Test case 1: Modal analysis ( =25rev/min)

    In this numerical test we consider a reference blade [10] with complete structure. The blade is dis-

    cretized in finite elements (3094 nodes which define 2985 shells), metallic structures (figure 7). Using

    the complete model and equivalent model of the blade structure, we computed the natural frequencies

    and modal forms for both models. The firsts five modes are show comparatively in the figure 8, and

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    260 F. Frunzulica, Al. Dumitrache, H. Dumitrescu

    the correspondent frequencies are summarized in the table 1.

    Table 1. The natural frequencies (Hz): beam model vs. complete model.

    Mode Completestructure

    Complete structurewith centrifugal ef-

    fect

    Beammodel

    Beam model withcentrifugal effect

    Flapwise I 1,208 1,321 1,199 1,318

    Flapwise II 2,985 3,23 2,921 3,221

    Edgewise I 5,521 5,66 5,486 5,601

    Edgewise III 9,128 9,257 9,055 9,193

    Torsion I 13,951 14,877 13,804 14,698

    Fig. 7 The discretized structure of the blade in finite elements.

    3.2 Test case 2: Dynamic response

    In this test, we computed the dynamic response of HAWT (the same beam model as the test case 1)

    at impulsive wind speedVw= 15 m/s (nominal regime 12 m/s, = 25 rev/min) [10]. In the figure9 we show the wake development at nominal regime. The figure 10 presents the variation of the

    displacement and pitch angle at the blade tip, and flapwise and edgewise bending moment at the

    blade root, as a function of azimuth angle. The oscillations are quickly damping, after 210 degrees.

    3.3 Test case 3.

    The results presented in the sequel concern the two cases of double pitch steps for the Tjaereborg

    HAWT, for which experimental data are available [12] (figure 11). The parameters used for each case

    are (table 2): the inflow velocity - U (m/s), the starting time of first pitch step t1,st(s), - the ending

    time of first pitch step t1,end (s), the starting time of second pitch step t2,st(s), the ending time of

    second pitch stept2,end(s), the initial pitch angle 1 (deg), the pitch angle after the first pitch step2(deg).

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    Fig. 8 The comparison of the modal forms: beam model (b) vs. complete model (a).

    Fig. 9 The free-wake of the rotor.

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    262 F. Frunzulica, Al. Dumitrache, H. Dumitrescu

    Fig. 10 Test case 2: the dynamic response at impulsive wind.1. stationary nominal regime; 2. induced oscilation regime

    (transient regime); a. flap displacement of tip blade, b. flapwise bending moment at root blade, c. pitch angle variation, d.

    edgewise bending moment at root blade.

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    An Aeroelastic Model for HAWT 263

    Table 2. Comparison between experiment and numerical results.

    Case 3.1 Case 3.2Experiment Aeroelastic

    code

    Experiment Aeroelastic

    code

    U (m/s) 12.5 12.5 8.7 8.7

    t1,st (s) 4.70 14.0 2.0 21.0

    t1,end(s) 6.00 15.3 2.5 21.5

    t2,st (s) 34.58 24.0 32.0 34.0

    t2,end(s) 35.7 25.12 32.7 34.7

    1 (deg) -1.164 -1.164 -0.07 -0.07

    2 (deg) -3.19 -3.19 -3.716 -3.716

    Fig. 11 Comparison between experiment and aeroelastic code.

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    264 F. Frunzulica, Al. Dumitrache, H. Dumitrescu

    4 Conclusions

    A complete aeroelastic tool has been presented together with its self consistency tests and someresults. In this stage, we cannot conclude on its accuracy. However, the experience suggests that this

    could be expected.

    There are three points that must be underlined: (1) in some tests it appeared necessary to introduce

    artificial damping, (2) the coupling, within the context of approach described, must be non-linear and

    (3) the computational effort required to couple the aerodynamics with the structural part, is small

    compared to the whole.

    Prospective work: we will made a most elaborate model based on the coupling of the aerodynamic

    model with a structural code based on the complete structural model and composites materials.

    Acknowledgement

    Supports for this work by PCCA-PARTNERSHIP Program, with the support of ANCS, CNDI-

    UEFISCDI, project no. PN-II-PT-PCCA-2011-3.2-1670, are gratefully acknowledged.

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