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Aim: Geometric Sequence & Series Course: Alg. 2 & Trig.
Do Now:
Aim: What are geometric sequences?
Annie deposits $1000 in a bank at 8%. interest is compounded quarterly. How much does Annie earn after 1 year?
Balance A, Principal P, rate r, # of compoundings n, time t
A P(1 r
n)nt
Compound Interest
1000(1 + 0.02)4 • 1 = 1082.43
Aim: Geometric Sequence & Series Course: Alg. 2 & Trig.
Money in the Bank 1,2,3 Years
Annie deposits $1000 in a local bank at 8%. Interest is compounded annually. How Much does Annie earn after 1 year?Simple interest - paid only on the initial principal
1000 + 1000(0.08) = $1080principal End of year
balanceinterest earned
interest rate
How much does Annie earn after 2 years?
$1000(1.08)(1.08) = 1166.40
How much does Annie earn after 3 years?
$1000(1.08)(1.08) (1.08) = 1259.7121166.40
1080
or 1000(1.08)
Aim: Geometric Sequence & Series Course: Alg. 2 & Trig.
Exponential Growth
Principal(1 + interest rate)number of years = Ending balance for 3 years
Post growth y, Pre-growth A
rate r, time t
y = a • bx
y = A(1 + r)t
Exponential function
recall:
In general terms
year 1 2 3
geometric sequence
1166.40 1259.712amount $1080
Aim: Geometric Sequence & Series Course: Alg. 2 & Trig.
positive integers 1 2 3 4 · · · n
Definition of Geometric Sequence
A sequence is geometric if the ratios of consecutive terms are the same.Sequence
a1, a2, a3, a4, . . . . . an, . . .
is geometric if there is a number r, r 0, such that
and so on. The number r is the common ratio of the geometric sequence.
,,,3
4
2
3
1
2 ra
ar
a
ar
a
a
1
n
n
ar
a
terms of sequence a1 a1r a1r2 a1r3 a1rn - 1
Aim: Geometric Sequence & Series Course: Alg. 2 & Trig.
2, 4, 8, 16, . . . .,
12, 36, 108, 324, . . . . r = 3
r = 2
Definition of Geometric Sequence
A sequence is geometric if the ratios of consecutive terms are the same.Sequence
a1, a2, a3, a4, . . . . . an, . . .
is geometric if there is a number r, r 0, such that
and so on. The number r is the common ratio of the geometric sequence.
,,,3
4
2
3
1
2 ra
ar
a
ar
a
a
r = ?,....81
1,
27
1,
9
1,
3
1 nth? ,....
3
1n
r = -1/3
2n, . . .
4(3)n, . . .
1
n
n
ar
a
Aim: Geometric Sequence & Series Course: Alg. 2 & Trig.
The nth term of an geometric sequence has the form
where r is the common ratio between consecutive terms of the sequence. Thus ever geometric sequence can be written in the following form
The nth Term of a Geometric Sequence
a1 a2 a3 a4 . . . . . an . . . .
a1 a1r a1r2 a1r3 . . . .
an = a1rn – 1,
a1rn - 1 . . . . r0
50
40
30
20
10
1 2 3 4
2, 6, 18, 54 r = 3
Aim: Geometric Sequence & Series Course: Alg. 2 & Trig.
nth Term of a Geometric Sequence
Find the first five terms of the geometric sequence whose first term is a1 = 3 and whose common ratio is r = 2.
an = a1rn – 1
a1 = a1r1 – 1
a2 = a1r2 – 1
a3 = a1r3 – 1
a4 = a1r4 – 1
a5 = a1r5 – 1
= 3(2)0
= 3(2)1
= 3(2)2
= 3(2)3
= 3(2)4
= 3= 6
= 12
= 24
= 48
Aim: Geometric Sequence & Series Course: Alg. 2 & Trig.
Finding a Term
Find the 12th term of the geometric sequence 5, 15, 45, . . .
an = a1rn – 1
a12 = 5(3)11 = 885,735r = 15/5 = 3
Find the 15th term of the geometric sequence whose first term is 20 and whose common ratio is 1.05.an = a1rn – 1 a15 = 20(1.05)14 39.599r = 1.05
The 4th term of a geo. sequence is 125, and the 10th is 125/64. Find the 14th.
4th term times r6 = 10th term or a10= a4r6
61
64r
2
1r
1024
125
2
1
64
1254
14
a
Consider the 4th term as if it were the 1st term
910 1
61
62 3 41
1 2 3
64
a a r
a r r r r
a a aa r
a a a
a r
Aim: Geometric Sequence & Series Course: Alg. 2 & Trig.
Model Problems
Find the seventh term of the geometric progression 32, -16, 8, . . . .
an = a1rn – 1
a7 = 32(-1/2)6 = 1/2r = -16/32 = -1/2
Aim: Geometric Sequence & Series Course: Alg. 2 & Trig.
Model Problems
There are three number such that the second is two more than the first and the third is nine times the first. The numbers form a geometric sequence. Find the numbers.
let x = 1st number
x + 2 = 2nd number
9x = 3rd number
2 9
2
x x
x x
,,,3
4
2
3
1
2 ra
ar
a
ar
a
a
1
n
n
ar
a
2 22 9x x
2 2
2
2
9 4 4
8 4 4 0
2 1 0
2 1 1 0
1 / 2, 1
x x x
x x
x x
x x
x x
-½, 1½, -4½
1, 3, 9
Aim: Geometric Sequence & Series Course: Alg. 2 & Trig.
Model Problem
A company purchases $50,000 worth of copiers on Jan. 1, 1996. This asset depreciates at a rate of 45% per year. What is the value of this asset at the end of 2001 (or 1/1/02)?
an = a1rn – 1,
(note: a 45% depreciation rate means the asset retains 55% of its value)
a1 = 50,000 r = .55 n = 2002. . . 1996 = 7
a7 = 50000(.55)7-1
a7 1384.032031
Asset is worth approximately $1384.03
Aim: Geometric Sequence & Series Course: Alg. 2 & Trig.
Do Now:
Aim: Is it possible to find the sum of a geometric sequence?
Aim: Geometric Sequence & Series Course: Alg. 2 & Trig.
Find the sum of the first eight terms of the geometric sequence 1, 3, 9, 27, . . .
The Sum of a Finite Geometric Sequence
r = ?3
a1 a2 a3 a4 . . . . . an . . . .
a1 a1r a1r2 a1r3 . . . . a1rn - 1 . . . .
1 3 9 27 . . . . 1(3)7
1 + 3 + 9 + 27 +. . .+ 1(3)7 = 3280
Is there an easier way to find the sum of a geometric sequence?
Aim: Geometric Sequence & Series Course: Alg. 2 & Trig.
Find the sum of the first eight terms of the geometric sequence 1, 3, 9, 27, . . .
previous problem
The Sum of a Finite Geometric Sequence
The sum of the finite geometric sequence a1, a1r2, a1r3, a1r4, . . . . a1rn - 1 . . . . with common ratio r 1 is given by
1
1
1
n
n
rS a
r
31
311
8
S 32802
6560
r = 3
divergent series – the sum of the series is infinite when |r| > 1
Aim: Geometric Sequence & Series Course: Alg. 2 & Trig.
The Sum of a Infinite Geometric Sequence
Find the sum of 1 + 1/2 + 1/4 + 1/8 + . . .
a1 = 1 and r = ?0.5
S =?1
1
1
n
n
rS a
r
sum of the finite
geometric sequence
n = 4 1 + 1/2 + 1/4 + 1/8 = 1 7/8
n = 5 1 + 1/2 + 1/4 + 1/8 + 1/16 = 1 15/16
n = 6 1 + 1/2 + 1/4 + 1/8 + 1/16 + 1/32 = 1 31/32
n = 3 1 + 1/2 + 1/4 = 1 3/4
as n S approaches 2
1 11
aS r
r
Aim: Geometric Sequence & Series Course: Alg. 2 & Trig.
The Sum of a Infinite Geometric Sequence
Find the sum of 3 + 0.3 + 0.03 + 0.003 + . . .
1
1
aS
r
1
1
aS
r
a1 = 3 and r = ?0.1
3 + 3(0.1) + 3(0.1)2 + 3(0.1)3 + . . .
3
1 (0.1)
3
0.9
13
3
Aim: Geometric Sequence & Series Course: Alg. 2 & Trig.
Interest Problems
Suppose at the beginning of each quarter you deposit $25 in a savings account that pays an APR of 2% compounded quarterly. Banks post interest at end of quarters. What would be the balance at year’s end?
Date of Deposit
1st year Additions Value at end of
Quarter
Jan 1
April 1
July 1
Oct 1
Account balance at end of year
nt
n
rPA
1
4005.125
3005.125
2005.125
1005.125
25.50
25.38
25.25
25.13
$101.26
The sum represents a finite geometric series where a1 = 25.13, r = 1.005 and n = 4
27.101005.11
005.1113.25
4
S
Aim: Geometric Sequence & Series Course: Alg. 2 & Trig.
Model Problems
Find the sum of the series.
160 + 80 + 40 + . . . , n = 6
Find the sum of the infinite series.
160 + 80 + 40 + . . . .
Aim: Geometric Sequence & Series Course: Alg. 2 & Trig.
Model Problems
Find the sum of the geometric series.
2 3
3 1, , 5
8 4a a n
Aim: Geometric Sequence & Series Course: Alg. 2 & Trig.
Model Problems
Find a1.
Sn = -55, r = -2/3, n = 5
Aim: Geometric Sequence & Series Course: Alg. 2 & Trig.
A company purchases $50,000 worth of copiers on Jan. 1, 1996. This asset depreciates at a rate of 45% per year. What is the value of this asset at the end of 2001 (or 1/1/02)?
an = a1rn – 1,
Model Problems
Aim: Geometric Sequence & Series Course: Alg. 2 & Trig.
Find the nth term of the geometric sequence.
a2 = -18; a5 = 2/3; n = 6
Model Problems