371 PS 08a Sp04

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    CEE 371: Modeling of Structural Systems Spring 2004

    PROBLEM SET NUMBER 8a

    Date due: Wednesday, April 14, 2004, at the beginning of lecture.

    NOTES

    1. If you receive help on a Problem Set, acknowledge this assistance near the top of the firstpage of your written submission with a statement such as Assistance received from: [listof names].

    READING ASSIGNMENTAC10:5 and Lecture Notes on the Stiffness Method

    LEARNING OBJECTIVES1. Students should understand the need for local and global coordinate systems in structural

    analysis.2. Students should understand the concept of a transformation matrix, and be able to

    transform stiffness equations for an axial force element written in an element local systeminto a global coordinate system.3. Students should understand the equilibrium basis of the structural stiffness equations

    {P} = [K]{}.4. Students should understand the Direct Stiffness Method of structural analysis and be

    familiar with the vocabulary and definitions that describe this method.5. Students should know how to assemble the global stiffness matrix, [K], and the global

    load matrix {P} from contributions from each element.6. Students should know how to partition matrix equations used in the Direct Stiffness

    Method in particular transformation equations and, to isolate known and unknownquantities for solution, the structural stiffness equations.

    7. Students should be able to use the Direct Stiffness Method to analyze truss structures with

    a few kinematic unknowns by hand.

    ASSIGNMENT1. Study the attached handout on Summary of Element Transformation Matrices for the

    Stiffness Method, which covers the transformation matrices applicable to the elementstiffnesses you derived in Problem Set 7. Use the definition of the inverse of a matrix, [A]-1[A]= [I], to demonstrate that the transformation matrix for a beam-column element is anorthogonal matrix, that is, that []-1= []T. Also show that to demonstrate such orthogonalityis it sufficient to show that the submatrix [] is orthogonal.

    2. Evaluate numerically {Pf} and [Kff] for the three-bar truss problem depicted on the next page.Use consistent units. Cross sectional areas shown with each element are in mm2, and Eis 200kN/mm2 for all elements. You do not need to assemble the other submatrices of the globalequilibrium equation, andyou do not need to solve the stiffness equations. {Bonus question:Without doing any calculations, what is the vertical reaction at node c?} [Hint: To ease yourwork, for each element, use node a as the origin ofx'. Then evaluate only as many kij's of eachstiffness matrix as you will need for this limited assembly. Use the general form of the 4 by 4truss element stiffness matrix in global coordinates.] [MGZ Problem 3.1(a)]

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    CEE 371: Modeling of Structural Systems -2- Spring 2004

    3 m

    45

    30

    100 kN

    200 kN

    a

    b

    c

    d

    A = 30 x 10 mm

    15 x 10 mm

    20 x 10 mm

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    CEE 371: Modeling of Structural Systems Spring 2004

    SUMMARY OF ELEMENT TRANSFORMATION MATRICES

    FOR THE STIFFNESS METHOD

    Element transformation matrices, [], appear in the following relationships:

    Element nodal force transformation: { } [ ] { }F F

    =

    Element nodal displacement transformation: { } [ ] { } =

    Element stiffness matrix transformation: [ ] [ ] [ ] [ ]T

    k k=

    In these equations, primed quantities are in element (local) coordinates, while unprimedquantities are in global (structure, overall) coordinates. The transformation matrices for

    perpendicular coordinate are orthogonal, that is, [ ] [ ]1 T

    = regardless of whether [] is

    square or rectangular.

    For a frame element at orientation (measured counterclockwise from the x axis to the x'

    axis) the specialized forms of [] for various elements studied in this course are:

    2-DOF truss element:[ ] cos sin 0 0

    0 0 cos sin2 4

    =

    4-DOF truss element:[ ]

    cos sin 0 0

    sin cos 0 0

    0 0 cos sin4 40 0 sin cos

    =

    4-DOF beam element: Not applicable (or [I]) because beams have co-linearx and x'.

    6-DOF beam-column element:[ ]

    cos sin 0 0 0 0

    sin cos 0 0 0 0

    0 0 1 0 0 0

    0 0 0 cos sin 06 6

    0 0 0 sin cos 0

    0 0 0 0 0 1

    =

    Note that each of these transformation matrices for two-node elements can be partitioned andwritten in the general form:

    [ ][ ] [ ]

    [ ] [ ]

    0

    0

    =

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    CEE 371: Modeling of Structural Systems -4- Spring 2004

    in which [] is the orthogonal nodal transformation for a single node and [0] is a null matrix.