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I Geometry Review Jeopardyilt S,,;;;ester Ch;5: Ang!e I' Ch.5: ." en, 7: Radicals, ";:''"'r Review
_bisectors,~.Properti'es of
Pythag.Thm.• Ch.7:
,Questionsmedians,
triangles Special Trigonometryattitudes Triangles
100 100 100 100 100
11
200 200 200 200 200
'1300 300 300 300 300
400 400 400 400 400
1500 500 500 500 500
1st Semester Review: 200 points
Find y if B is between A and C, AB is 2y, BC is 6y,and AC is 48. Draw the line segment.
IANSWER: y=6
I I •l
1st Semester Review: 400 points
P(13x + l~T
C "RRC and RD are opposite rays.R(Q bisects LWRV.
1)IIFind y if mLWRQ= 48and mLQRV= 7y+ 6.2) What is the mLWRV?
ANSWER: y=6, mLWRV=96°
oV
3/28/2012
1st Semester Review: 100 points
Find the length of PQ.
1--3S.3cm--1. ..P Q12.6cm R
ANSWER: 25.7
1st Semester Review: 300 points
The vertices of a triangle are located at P(O, 0),0(8, 6), and R(-3, 4).What is the perimeter of this triangle?Round to the nearest hundredth.
ANSWER: 26.18
1st Semester Review: 500 points
If J..ABC is an isosceles triangle, LB is the vertexangle, AB = 6x + 3, BC = 8x - 1, and AC = 10x -10, find x and the measures of each side of thetriangle.
ANSWER: x=2, AB=AC=15, AC=19
1
I(th. 5: Angle bisectors, medians, altitudes: 100 points
t Find x and the measure of angle ~£I COE. '2) Ray OF is called a ~
,~'" (4x+ 30)'
DF bisects LCDE.
ANSWER: x=7.5, Angle bisector
Ch. 5: Angle bisectors, medians, altitudes: 300 points
Find the value of x and v:
/;:yo 3x"~gY-4t:,.CDF is equilateral.
ANSWER: x=10, y=2
J5, Angl. """,0". medians, altitudes. 500 points1) Find x, y, and z.2) TP. MS, and RN
are called
R~~--~p~~--~S
V is the centroid of t:,.RST:TP = is: !i1S = 15:RN = 24
ANSWER: (1) x=6, y=5, z=8 (2) Medians
3/28/2012
Ch. 5: Angle bisectors, medians, altitudes: 200 points
l)Find x and v:3) Segment EH is a _
3. E 9x _ 2
F~G
EH=FH=HG
ANSWER: x=3, y=5, Median
Ch. 5: Angle bisectors, medians, altitudes: 400 points
a,b,and c are perpendicular bisectors of triangleRPQ. Find x, V,and z.
p
ANSWER: x=l, y=6, z=2
Properties of triangles: 100 points
List the angles in order from least to greatest:
B
3~
A 4.0 C
ANSWER: C, B, A
•
2
Properties of triangles: 200 points
qetermine whether it is possible to draw at~iangle with sides of the given measures.'trite yes or no and explain why!
23, 16, 7
ANSWER: No!
Properties of triangles: 400 points
Find the measures of angle 1 and angle 2.
i6~ \
\~\;0'\
ANSWER: 1= 100° ,2=40°
•
Irdicals, Pythag. Thm, Special Triangles: 100 points
I Solvefor x:
~~S 15 T
ANSWER: 8
•
3/28/2012
Properties of triangles: 300 points
Determine the relationship between the lengthsof the given sides.
Be and DB.
.4ANSWER: BC>DB
Properties of triangles: 500 points
Find all missing angles.
ANSWER: 1=40°,2=45°,3=135°,4=73°,5=70°,6=30°
Radicals, Pythag. Thm, Special Trialges: 200 points
Solve for x:
K~60·
~ x 30. J
ANSWER: x=10
3
jadicalS & Pythag. Thm., Special Triangles: 300 points
~eterminewhether each set of measuresII can be the measures of the sides of a
right triangle.0) 5,12,14
b) 65,72,97
ANSWER: a) no b) yes
Radicals & Pythag. Thm.: 500 points
The length of the diagonal of a square is 20 inches.Find the perimeter of the square.
(leave answer as a simplified radical)
ANSWER: perimeter- 40"'2
II -II
~ Trigonometry: 200 points
Fihd x and y using a trigonometric ratio. Round to thenearest tenth..:
5 &plY
IANSWER: x=6.0, y=7.8 .,
3/28/2012
Radicals & Pythag. Thm., Special Triangles: 400 points
The perimeter of an equilateral triangle is 18centimeters. Find the length of an altitude of the
triangle.(leave answer as simplified radical)
ANSWER: 3"'3
Trigonometry: 100 points
Find: sin D, cas D, and tan D.
~:o 12 F
ANSWER: sin 0= 5/13,cos 0=12/13, tan 0=5/12
Trigonometry: 300 points
Find the value of angle x and angle y. Round to thenearest degree.
ANSWER: x= 18°, y=72°
4
Trigonometry: 400 points
Fljnd the angle of elevation of the sun when a 22-meter-talltelephone pole casts a 17-meter-long shadow. Round tothe nearest tenth of a degree.
ANSWER: 52.3°
3/28/2012
Trigonometry: 500 points
A ski run is 2000 yards long with a vertical drop of142 yards. Find the angle of depression from thetop of the ski run to the bottom. Round youranswer to the nearest degree.
ANSWER: 4°
5