2.2 Temperature

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General, Organic, and Biological Chemistry Copyright © 2010 Pearson Education, Inc. 1

Temperature




Temperature

Temperature

is a measure of how hot or cold an

object is compared to another

object indicates that heat flows from the

object with a higher temperature to

the object with a lower temperature

is measured using a thermometer




Temperature Scales

Temperature scales

are Fahrenheit,

Celsius, and Kelvin

have referencepoints for the boiling

and freezing points

of water




A. What is the temperature of freezing water?

1) 0 °F 2) 0 °C 3) 0 K

B. What is the temperature of boiling water?1) 100 °F 2) 32 °F 3) 373 K

C. How many Celsius units are between the boiling and

freezing points of water?

1) 100 2) 180 3) 273

Learning Check




A. What is the temperature of freezing water?

2) 0 °C

B. What is the temperature of boiling water?3) 373 K

C. How many Celsius units are between the boiling and

freezing points of water?

1) 100

Solution




On the Fahrenheit scale, there are 180 °F between the

freezing and boiling points, and on the Celsius scale,

there are 100 °C.

180°F = 9

°F = 1.8

°F

100 °C 5 °C 1 °C

In the formula for the Fahrenheit temperature, adding

32 adjusts the zero point of water from 0 °C to 32 °F.

TF = 9 (TC ) + 32° 5

or TF = 1.8(TC ) + 32 °

Fahrenheit Formula




TC is obtained by rearranging the equation for T

F .

TF = 1.8(T

C ) + 32 °

Subtract 32 from both sides.

TF –

32 ° = 1.8(TC) + (32 ° –

32 °)TF – 32 ° = 1.8(TC )

Divide by 1.8. TF – 32 ° = 1.8 T

C

1.8 1.8

TF – 32 ° = TC

1.8

Celsius Formula




Solving a Temperature Problem

A person with hypothermia has a

body temperature of 34.8 °C. What

Is that temperature in °F?

TF = 1.8(T

C ) + 32 °

TF = (1.8)(34.8 °C) + 32 °

exact tenth’s exact

= 62.6 ° + 32 °

= 94.6 °Ftenth’s




The normal temperature of a chickadee is 105.8 °F.

What is that temperature on the Celsius scale?

1) 73.8 °C

2) 58.8°C

3) 41.0 °C

Learning Check




The normal temperature of a chickadee is 105.8 °F.

What is that temperature on the Celsius scale?

3) 41.0 °C

TC = TF –

32 ° 1.8

= (105.8 – 32 °)

1.8

= 73.8 °F = 41.0 °C

1.8 ° tenth’s place

Solution




A pepperoni pizza is baked at 455 °F. What

temperature is needed on the Celsius scale?

1) 423 °C

2) 235°C

3) 221 °C

Learning Check




A pepperoni pizza is baked at 455 °F. What

temperature is needed on the Celsius scale?

2) 235 °C

TF –

32° = TC

1.8

(455 – 32 °) = 235 °C

1.8 one’s place

Solution



General, Organic, and Biological Chemistry Copyright © 2010 Pearson Education, Inc.

13

On a cold winter day, the temperature is –15 °C.

What is that temperature in °F?

1) 19 °F

2) 59°F

3) 5 °F

Learning Check




3) 5 °F

TF = 1.8T

C + 32 °

TF = 1.8( –

15 °C) + 32 ° = – 27 + 32 °

= 5 °F

one’s place

Note: Be sure to use the change sign key onyour calculator to enter the minus ( –) sign.

1.8 x 15 +/ – = –27

Solution




The Kelvin temperature

is obtained by adding 273 to the Celsius temperature

TK = TC + 273

In the Kelvin temperature scale:

There are 100 units between the freezing and boiling

points of water.

100 K = 100 °C or 1 K = 1 °C 0 K (absolute zero) is the lowest possible

temperature.

0 K = –273 °C

Kelvin Temperature Scale




Temperatures




What is normal body temperature of 37 °C in kelvins?

1) 236 K

2) 310 K

3) 342 K

Learning Check




What is normal body temperature of 37 °C in kelvins?

2) 310 K

TK = TC + 273= 37 °C + 273

= 310. K

one’s place

Solution

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2.2 Temperature