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7/22/2019 2014-1-NS-ST PAUL-A
1/3
CONFIDENTIAL*
2014-1-NS-STPAUL-M
ARKINGSCHEME
MATHEMATICST954/1
Working
Marks
Note
1
D1
D1
[2]
Shape
Allcorrect
(a)
Substitute
intoy=kx
k=
M1
A1
[2]
(b)
A1
[1]
2(a)
Let
betwopointsonthe
curve,
TheGradientofPQ
EquationofchordPQ
(p2q+pq2)y+2x=2(p2+q2+pq)
Chordtangentwhe
nq=p,
EquationoftangentatPis
2p3y+2x=2(p2+p2
+p2)
M1
A1
M1
A1
[4]
Mustbesimplified.
(b)
B1
B1
[2]
Mustbeincoordinates
(c)
Mid-pointofQR(
8xy2
=27
Cartesianequationof
themid-pointofQRis
8xy2
=27
B1
M1
A1
[3]
Findthemid-point
Substituteoreliminatep
3-
-3-
+
-
+
x
y
CONFIDENTIAL*
2
3(a)
B1
CorrectAM
M1
M1
Equationsareconsistentif
k=3
A1
A1
[5]
Row-
echelonform
(b)
GeneralSolution,
B1
M1
A1
[3]
4(a)
sin
cos
1
i
z
=
2
sin
2
cos
2
i
z
+
=
2
sin
2
cos
12
i
z
=
cos
2
)
sin
(co
s
)
sin
(cos
1=
+
+
=
+
i
i
z
z
2
cos
2
)2
sin
2
(cos
)2
sin
2
(cos
12
2
=
+
+
=
+
i
i
z
zSquarebothsidesof
cos2
1=
+
z
z
B1
B1
M1
A1
A1
[5]
M1
(onecorrect)
(allcorrect)
(find
z
z
1+and
2
2
1z
z
+
)
7/22/2019 2014-1-NS-ST PAUL-A
2/3
CONFIDENTIAL*
3
1
2
cos
cos
2
cos
4
2
2
cos
2
cos
4
2
1
)
cos
2(
12
2 2
2
2
2
2
+
=
=
+
=
+
+
=
+
z
z
z
z
A1
[2]
5
SolveforA,BandC
A=2,B=-1,C=-1
=2-2x+2x21
+x2-x+...
=13x+3x2+...
M1
M1
A1
M1
M1
A1
[6]
M1
M1
A1
[3]
6(a)
=
=
M1
A1
[2]
(b)
B1
M1
CONFIDENTIAL*
4
A1
[3]
(c)
ExactAreaofParallelogramOAPB
=
=
M1
A1
[2]
7(a)
1sttermofGP=1sttermofA
P=a
2nd
termofGP=4thtermof
AP
ar=a+3d
.....(1)
3rd
termofGP=6thtermofA
P
ar2=a+5d......(
2)
B1
B1
M1
M1
A1
[5]
Substi
tute(1)into(2)
ortrytoeliminatea
(b)
(3r2)(r1)=0
Since
thegeometryseriesisconvergent.
M1
A1
A1
M1
A1
[5]
(c)
SinceS>4a
n219n+72